An electromagnet converts electrical energy to magnetic energy, therefore this is the energy change that occurs.
What is an example of a electromagnet?An epr is a substance that is ordinarily non-magnetic but turns into a magnet when an electrical current flows through it. A curled loop and insulated loop of wire like a spring is a typical illustration of an electromagnet.
What are electromagnets and how do they operate?Electromagnets and armature windings are not always the same thing. Emitting energy from coils of wire, electromagnetic fields are created. Because moving charges create magnetic fields, an electromagnet's create compelling behave similar magnets when an electrical current passes through them.
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Two equal-mass stars maintain a constant distance
of 8.0 x 10^10 m and rotate about a point mid-
way between them at a rate of one revolution every
12.6 yr.
(a) Why don't the two stars crash into one
another due to the gravitational force between
them?
(b) What must be the mass of each star?
A. Centripetal force acting on the two stars is the reason why the two stars will not crash into one another
B. The mass of each stars, given they maintain a constant distance of 8×10¹⁰ m is 7.68×10²⁷ Kg
A. Why don't the two stars crash into one another?
Centripetal force is the force that acts to keep an object moving in a circle. Since the two stars undergoes revolution, this means they rotate in a circle. Thus, centripetal force is acting on them.
Therefore, we can say that the two stars will not crash into one another due to the centripetal force
B. How do I determine the mass of each stars?
We can obtain the mass of each stars as illustrated below:
F = GM₁M₂ / r²
Note: They rotate mid-way. Thus distance apart (r) = 2r
F = GM₁M₂ / (2r)²
F = GM₁M₂ / 4r²
Also, centripetal force is given as:
F = mv² / r
Thus, we have:
mv² / r = GM₁M₂ / 4r²
But
v = 2πr / T
v² = (2πr / T)² = 4π²r² / T²
M₁ = M₂ = m
Thus, we have
m4π²r² / rT² = Gmm / 4r²
4π²r / T² = Gm / 4r²
Cross multiply
mGT² = 4r² × 4π²r
mGT² = 16π²r³
Divide both sides by GT²
m = 16π²r³ / GT²
From the question given, we have:
Distance (r) = 8×10¹⁰ mPeriod (T) = 12.6 years = 12.6 × 3.154×10⁷ = 3.97×10⁸ sGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Pi (π) = 3.14Mass of each stars (m) =?m = 16π²r³ / GT²
m = [16 × 3.14² × (8×10¹⁰)³] / [6.67×10¯¹¹ × (3.97×10⁸)²]
m = 7.68×10²⁷ Kg
Thus, the mass of each stars is 7.68×10²⁷ Kg
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PLEASE HELP
Suri, a scientist at NASA, created models of each planet. The models contain the same properties as the actual planets, but at a smaller scale. The first property being tested is the density of the planets. Suri places each planet into a container of water. Which planet will float on top of the water?
A) Mercury
B) Venus
C) Neptune
D) Saturn
Answer:
Explanation:
Let's turn to the table of planetary densities:
Saturn will float in the water ( 0.7 g/cm³ < 1.0 g/cm³)
Obtain an expression for the viscous force acting on a sphere of radius r moving in a viscous fluid with velocity v, if the viscosity coefficient is η.
The force of viscosity is F = k r v η. Spherical balls of radius R are falling in a viscous fluid of viscosity η with a velocity v.
What is viscous force?
Viscosity refers to a material's capacity to resist movement between its layers. It is the force that resists relative motion between the layers. It is also known as viscous force.
What is viscous force formula?
In the above equation, the shear force is the viscous force, which is the only internal resistance that causes shear stress to develop along with the fluid layers. As a result, the viscous force formula will be given as. F=Aμdudy.
Hence F = k r v η is a correct answer.
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which best explains the law of conservation of mass
The law of conservation of mass emphasizes the fact that it is not possible to create or destroy the mass in this universe. Mass just changes its form from one to another, it is never created nor destroyed.
The statement mentioned above states that the mass of reactants and products have equal mass irrespective of the physical state.If the mass of reactants and products becomes unequal, then it would contradict the law of conservation. However, it is clearly mentioned that the mass of reactants and products will remain the same, hence complimenting the law of conservation of motion.Therefore, the law of conservation of mass is best described by - The mass of the reactants and products is equal and this mass is not dependent on the physical state of the substances.
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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: Which best describes the law of conservation of mass?
(A) The coefficients in front of the chemicals in the reactants should be based on the physical state of the products.
(B) Products in the form of gases are not considered a part of the total mass change from reactants to products.
(C) When reactants contain both a solid and a liquid, the solid counts toward the overall mass and the liquid does not.
(D) The mass of the reactants and products is equal and is not dependent on the physical state of the substances.]
Part A
Choose the correct free body diagram for the case when the ball is at its lowest point
The correct free body diagram for the case when the ball is at its lowest point is tension pointing upwards and weight of the object pointing downwards.
What is the tension in the string at the lowest point in circular path?
The tension in the string at the lowest point in a circular path is equal to weight added to centripetal force required.
Mathematically, the formula for the tension in the string is given as;
T = W + ma
where;
W is the weight on the stringm is the mass of the objecta is the acceleration of the objectAt the lowest point the acceleration of the object is zero, a = 0. The new equation becomes the following;
T = W
The free body diagram of the tension and the weight of the object is given as;
↑ T
Ф
↓ W
Thus, the correct free body diagram consist of the tension force pointing upwards and the weight of the object pointing downwards.
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Explain the difference between Pavlov's classical Conditioning, and Skinner's Operant
Conditioning, give examples to illustrate how behavior can be learned according to each
one of those conditioning. Explain the example after explaining the process.
Skinner's Operant Conditioning focus stressed that the consequences of a behavior will indicate if there is possibility of it being repeated and also the human behavior can be attributed to something in a person's environment.
Pavlov's classical Conditioning stressed that two stimuli can be linked together so that there can be new learned response in indivisuals .
Example of Pavlov's classical Conditioning is that a dogs could be conditioned to salivate at the sound of a bell if it was programmed to ring at the time of food.
Example of Skinner's Operant Conditioning is that of negative reinforcement which was demonstrated by placing a rat in Skinner box which then subjected to unpleasant electric current and make it to experience some discomfort.
What is Classical conditioning?Classical conditioning can as well be described as the Pavlovian or respondent conditioning which is the learning that do take place when two stimuli are linked together and they can bring about new learned response in a person or animal.
Operant conditioning was the one that stressed that the cause of human behavior can be linked to the something in a person's environment.
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11. Why do the lights in your home come on almost instantaneously when you turn, on the switch?
A - When the circuit is completed, there is a rapid rearrangement of surface charges in the circuit.
B - Charges store energy. When the circuit is completed, the energy is released.
C - Charges in the wire travel very fast.
D - The circuits in a home are wired in parallel. Thus, a current is already flowing.
E - Charges in the wire are like marbles in a tube. When the circuit is completed, the charges push each other through the wire.
Answer:
because its like that which do not hencintrate and prostate in the future work per week-20 Earning in the future and we are keen on the walls of our english and would like the same to happen as soon.
what hazard class are automotive batteries walmart
The automative batteries are the corrosive hazard class.
The chemical present inside the battery are very corrosive and poisonous in nature.
Also if the batteries are excessively charged they can burst and cause a huge damage.
There is also very huge disposal problem associated with the battery because the chemical present inside the battery contain acidic material which will decrease the quality of the soil if they are buried in soil.
The human skin is also very sensitive towards the corrosive material of the battery.
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A 4,155 kg car moving at 28.3 m/s hits a stationary truck with a mass of 3,172 kg. If the two vehicles become stuck together in the collision, how fast do they move away from the point of impact?
Answer:
Approximately [tex]16.0\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of that object will be [tex]p = m\, v[/tex].
In this example, the momentum of the car before the collision will be:
[tex]\begin{aligned}p &= m\, v \\ &= (4155\; {\rm kg})\, (28.3\; {\rm m\cdot s^{-1}}) \\ &\approx 1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}} \end{aligned}[/tex].
Since the truck was initially not moving, the initial momentum of the truck will be [tex](3172\; {\rm kg})\, (0\; {\rm m\cdot s^{-1}}) = 0\; {\rm kg \cdot m\cdot s^{-1}}[/tex].
Momentum is conserved in collisions. In other words, the sum of the momentum of the truck and the car will be the same right before and after the collision.
The sum of the momentum of the truck and the car was approximately [tex]1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}[/tex] right before the collision. By the conservation of momentum, the sum of the momentum of the two vehicles right after the collision will also be [tex]1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}\![/tex].
The velocity of the two vehicles right after the collision will be the same since the vehicles are stuck together. Let [tex]v[/tex] denote this velocity.
The sum of the mass of the two vehicles is [tex]m = (4155\; {\rm kg}) + (3172\; {\rm kg}) = 7327\; {\rm kg}[/tex]. Divide the total momentum of the two vehicles by their total mass to find the velocity:
[tex]\begin{aligned}v &= \frac{p}{m} \\ &\approx \frac{1.17587\times 10^{5}\; {\rm kg \cdot m\cdot s^{-1}}}{7327\; {\rm kg}} \\ &\approx 16.0\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
A mass on the end of a length of rope is being swung in a circle of radius 3.2 m at an angular velocity of 0.71 rad/s. How fast is it moving?
Answer:
[tex]\huge\boxed{\sf v = 2.27\ m/s}[/tex]
Explanation:
Given data:Angular velocity = ω = 0.71 rad/s
Radius = r = 3.2 m
Required:Linear velocity = v = ?
Formula:v = rω
Solution:v = (3.2)(0.71)
v = 2.27 m/s
[tex]\rule[225]{225}{2}[/tex]
A coin is tossed vertically upward and reaches a maximum height of 0.90 m before it comesback down. With what velocity was it thrown, and how long was it in the air?
with explanation please
Answer:
how long the coin was in the air was about 45 how I got your answer was by dividing 900 by 20 bc when u divide u have to add a 0 so that's how I got 900 then I just divided and got 45
1000 cm³ of air at 20 °C and 101.35 kPa is heated at constant pressure until its volume doubles. a) Use the ideal gas equation to calculate the final temperature of the gas.
From Charles's law, the magnitude of the final temperature is 586 K
What is an Ideal Gas ?An Ideal gas is a gas which obeys ideal gas equation at all pressures, volumes and temperatures. The ideal gas equation can be express as
PV = nRT
Where
P = pressureV = volumen = number of moleR = universal molar gas constantT = TemperatureGiven that 1000 cm³ of air at 20 °C and 101.35 kPa is heated at constant pressure until its volume doubles.
From the ideal gas equation,
P1 = P2 = 101.35 kPaV1 = 1000 cm³V2 = 2000 cm³T1 = 20 + 273 = 293 KT2 = ?To calculate the final temperature of the gas, we will use the formula below
V1/T1 = V2/T2
Since Pressure is constant
Substitute the necessary parameters into the formula
1000/293 = 2000/T2
Cross multiply
1000T2 = 586,000
T2 = 586,000/1000
T2 = 586 K
Therefore, the final temperature of the gas is 586 K
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is lithium batteries a limited quantity item
Lithium and lithium-ion batteries are transported in both large and small volumes.
For instance, a single box could contain as little as five batteries, whereas a pallet could hold over 1,000, or the batteries could be enclosed in or packed with equipment.
On the other hand, lithium batteries, which contain lithium metal, cannot be recharged. Lithium-ion batteries can be recharged but do not contain lithium metal.
Lithium and lithium-ion batteries are mostly utilized in consumer applications and are exempt from dangerous goods/hazardous materials rules. Small lithium batteries are often used in timepieces and cameras. Lithium-ion batteries are extensively used in laptops and cell phones.
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Microwave ovens operte at 2.45 GHz, Bluetooth electronics and internet routers work at2.4 GHz.Predict which object has the longer wavelength, showing your calculations evidence, to support your prediction .
Answer:
The object with the longer wavelength is the microwave oven. This can be determined using the equation λ = c/f, where λ is the wavelength, c is the speed of light (3 x 10^8 m/s), and f is the frequency.
For a microwave oven:
λ = (3 x 10^8 m/s) / (2.45 GHz)
λ = 1.22 x 10^-2 m
For a Bluetooth electronic/internet router:
λ = (3 x 10^8 m/s) / (2.4 GHz)
λ = 1.25 x 10^-2 m
Therefore, the microwave oven has a longer wavelength.
Explanation:
Questions 14-16
The following diagrams each show an object of mass m moving with instantaneous velocity v. in
each case, F is the applied force, and f is the frictional force exerted on the object. In case I, the
object moves in a circle with constant speed.
(A) None
(B) I only
(C) II only
(D) III only
(E) I, II, and III
14. In which of these cases are velocity and the acceleration in the same direction at the
instant shown?
15. In which of these cases are the velocity and acceleration in opposite directions at the
instant shown?
16. In which of these cases are the velocity and the net force perpendicular to each other at
the instant shown?
14. None of these cases are velocity and the acceleration in the same direction at the instant.
15. I, II, and III of these cases are the velocity and acceleration in opposite directions at the instant
16. case I of these cases are the velocity and the net force perpendicular to each other at the instant.
When is acceleration and velocity in same direction?If the velocity and acceleration are in the same direction (both have the same sign and both positive or negative), the object is accelerating. If the velocity and acceleration are opposite (with opposite signs), the object is slowing down.
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When you are sitting in a chair your body exerts a on the chair and the chair exerts the force back?
When we sit on the chair, the chair is actually plying a force back on us in response to our force wielded upon the president because of Newton's third law.
What is Newton's third law?
The third law of Newton asserts that when bodies interact, they ply forces that are equal in size and directed in the contrary direction. Another name for the third law is the law of action-reaction law. This law is pivotal for understanding issues with static balance, where all pressures are in balance, but it also remains true for bodies moving at a constant or accelerated speed.
It does not only use secretary styles the forces it represents are factual forces. For illustration, a book laying on a table exerts downcast pressure equal to the weight of the book on the table. The table produces an equal and contrary force on the book in agreement with the third law.
Thus, According to Newton's third law there's an equal and contrary action and counteracts us so that neither move.
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