what force to be required to accelerate a car of mass 120 kg from 5 m/s to 25m/s in 2s​

Answers

Answer 1

Answer:

[tex]f = m \frac{v1 - v2}{t} \\ = 120 \times \frac{25 - 5}{2} \\ = 120 \times \frac{20}{2} \\ = 120 \times 10 \\ = 1200N \\ thank \: you[/tex]


Related Questions

The capacity of an RD bottle is 100 cc and its mass is 45 g. Find the mass of the bottle when it is filled with a liquid of density 600 kg/m3.​

Answers

Answer:

The capacity of an RD bottle is 100cc and its mass is 45g. Find the mass of the bottle when it is filled with a liquid of density 600kg/[tex]m^{3}[/tex]

 

EXPLANATION:

100cc=100[tex]cm^{3}[/tex]

density of liquid=600Kg/  =0.6gm/

 so mass of 100cc liquid will be m=d×V=0.6×100=60gm

So mass of bottle filled with liquid will be bottle+liquid=45gm+60gm=105gm  

Answer is 105gm.

define one standard kg ​

Answers

Answer:

The mass of platinum iridium rod whose diameter and height are equal an kept at international bureau of weight and measurement in Paris of France is called as one standard kg.

The coefficient of kinetic friction between an 100-kg desk and the wood floor is 0.4. What force (in Newtons) must be applied to move the desk at a constant speed? help now

Answers

Assuming the applied force is exerted parallel to the floor, by Newton's second law both the net vertical and net horizontal forces would be zero:

F (horizontal) = p - f = 0 … … … because the desk is pushed at a constant speed

F (vertical) = n - mg = 0 … … … because the desk doesn't move up or down

where p is the magnitude of the applied force, f is the mag. of kinetic friction, n is the mag. of the normal force due to contact between the floor and desk, and mg is the weight of the desk. We have

n = mg = (100 kg) g = 980 N

and the mag. of friction is proportional to n according to

f = 0.4 n = 392 N

Then the applied force p has magnitude

p = f = 392 N

010) Identify the true statement. Group of answer choices The height of waves is determined by wind strength and fetch. Wave base is the lowest sea surface elevation attained during the passage of a wave. Waves have no effect on the seafloor near the shoreline. Waves speed up as they enter shallower water.'

Answers

Answer:

The height of the wave is determined by the wind strength and fetch.

Explanation:

The height of the wave is determined by the wind strength and fetch.

The more the strength and the more the fetch size the more will be the height of the wave.

Remember as the wave approaches the coast its wavelength decreases and the wave height increases, whereas when the wave goes away from the coast its wavelength increases and height decreases.

what is measurement?​

Answers

Answer:

The comparison of unknown quantity with known quantity is called measurement

Answer:

the size, length or amount of something is a measurement.

Explanation:

Measurements help in daily life and are important to development, accuracy and making decisions.


4 A student says that he has made a magnetic field with some iron filings. What would
you say to him?

Answers

Answer:

Yes but no

Explanation:

Here the kid cant say that he has created s magnetic field as iron fillings do not have magnetic properties

Pls help me with this fast. I will mark brainiest

Answers

Answer:

a) 70, 95

b) 95-70= 25cc

c) density= mass/volume

102/25

=4.08g/cc

Which of the following processes occurs in a battery?

Batteries convert mechanical energy into chemical energy.
Batteries convert chemical energy into kinetic energy.
Batteries convert mechanical energy into electric energy.
Batteries convert chemical energy into electric energy.

Answers

Answer:

Batteries convert chemical energy into electric energy.

Explanation:

As seen, batteries have chemical energy in them stored which when used in any electronics produces electricity.

Thus, we can conclude that a battery converts chemical energy into electric energy.

The rate of chage of displacement is called __________​

Answers

Answer:

Velocity is the rate of change of displacement.

Why is velocity proportial to pressure?​

Answers

Answer:

Pressure and velocity are inversely proportional to each other because if pressure increase, the velocity decrease to keep the algebraic sum of potential energy, kinetic energy and pressure constant.

300 ml of a gas at 27°C is Cooled at -3°c at Constant pressure the final volume is plzz answer fast i will mark brainliest ​

Answers

Answer:V₁=300ml

T₁=27°C

V₂=?

T₂= -3°C

as we know

V₁T₁=V₂T₂

By putting values in formula

300ml×27°C=V₂×(-3°C)

300ml×27°C/-3°C=V₂

8100ml/-3=V₂

-2700ml=V₂

or V₂=  -2700ml

What is an effect of continental drift?

Answers

Answer:  An effect of continental drift is causing tectonic plates resting upon the convecting mantle to move which results in natural disasters like earthquakes, volcanic eruptions, and more.

what you filling your heart with
oxygen and blood

Answers

Answer:

Explanation:

                    The right side of your heart receives oxygen-poor blood from your veins and pumps it to your lungs, where it picks up oxygen and gets rid of carbon dioxide. The left side of your heart receives oxygen-rich blood from your lungs and pumps it through your arteries to the rest of your body.

        #I AM ILLITERATE

Ben works as a medical assistant. He needs to take a patient's vitals, but the patient is refusing to cooperate. He hasn't experienced this before, so he decides to ask a nurse for advice on how to handle it. This is making a decision by O a) delegation. O b) command. c) vote. O d) consult. Question

Two manned satellites approach one another at a relative velocity of v=0.190 m/s, intending to dock. The first has a mass of m1=4.00×103 kg and the second a mass of m2=7.50×103 kg. If the two satellites collide elastically rather than dock, what is their final relative velocity?

Answers

Answer:

Their final relative velocity is 0.190 m/s

Explanation:

The relative velocity of the satellites, v = 0.190 m/s

The mass of the first satellite, m₁ = 4.00 × 10³ kg

The mass of the second satellite, m₂ = 7.50 × 10³ kg

Given that the satellites have elastic collision, we have;

[tex]v_2 = \dfrac{2 \cdot m_1}{m_1 + m_2} \cdot u_1 - \dfrac{m_1 - m_2}{m_1 + m_2} \cdot u_2[/tex]

[tex]v_2 = \dfrac{ m_1 - m_2}{m_1 + m_2} \cdot u_1 + \dfrac{2 \cdot m_2}{m_1 + m_2} \cdot u_2[/tex]

Given that the initial velocities are equal in magnitude, we have;

u₁ = u₂ = v/2

u₁ = u₂ = 0.190 m/s/2 = 0.095 m/s

v₁ and v₂ = The final velocities of the satellites

We get;

[tex]v_1 = \dfrac{2 \times 4.0 \times 10^3}{4.0 \times 10^3 + 7.50 \times 10^3} \times 0.095 - \dfrac{4.0 \times 10^3- 7.50\times 10^3}{4.0 \times 10^3+ 7.50\times 10^3} \times 0.095 = 0.095[/tex]

[tex]v_2 = \dfrac{ 4.0 \times 10^3 - 7.50\times 10^3}{4.0 \times 10^3 + 7.50 \times 10^3} \times 0.095 + \dfrac{2 \times 7.50\times 10^3}{4.0 \times 10^3+ 7.50\times 10^3} \times 0.095 = 0.095[/tex]

The final relative velocity of the satellite, [tex]v_f[/tex] = v₁ + v₂

∴ [tex]v_f[/tex] = 0.095 + 0.095 = 0.190

The final relative velocity of the satellite, [tex]v_f[/tex] = 0.190 m/s

Define SI units. Also mention their importance. SI unit The​

Answers

Answer:

SI unit is an internationally accepted system and have the same value all over the world .

I don't know the importance sotry

Answer:

SI unit is an internationally accepted system that have same value all over the world.

an athlete had lifts a load with a mass of 150kg.

1) calculate the gravitational potential energy gained

2) if the mass of the load is increased to 200kg, calculate the gravitational potential energy gained by the load.

3) based on answers in 1&2, state the relationship between the mass of the load and the gravitational potential energy.

Answers

Mass=150kg=mHeight=h=2mAcceleration due to gravity=g=10m/s^2

[tex]\\ \sf\longmapsto P.E=mgh[/tex]

[tex]\\ \sf\longmapsto P.E=150(2)(10)[/tex]

[tex]\\ \sf\longmapsto P.E=3000J[/tex]

In 2nd case

Mass =m=200kgHeight=h=2mg=10m/s^2

[tex]\\ \sf\longmapsto P.E=200(2)(10)[/tex]

[tex]\\ \sf\longmapsto P.E=4000J[/tex]

We can observe that

If mass of body increases gravitational potential energy will increase.

the velocity of a body is increases from 10 m/s ti 15 m/s in 5seconds calculate its acceleration​

Answers

Answer:

acceleration = v-u/ t

= 15-10/5

= 5/5

= 1 m/s2

Explanation:

hope this helped you.

Answer:

[tex]\boxed {\boxed {\sf 1 \ m/s^2}}[/tex]

Explanation:

Acceleration is the change in velocity over the change in time. Therefore, the formula for calculating acceleration is:

[tex]a= \frac{v_f-v_i}{t}[/tex]

Since the body's velocity increased from 10 meters per second to 15 meters per second 15 m/s is the final velocity and 10 m/s is the initial velocity. The time is 5 seconds.

[tex]v_f[/tex]= 15 m/s [tex]v_i[/tex]= 10 m/s t= 5 s

[tex]a= \frac{ 15 \ m/s - 10 \ m/s}{5 \ s}[/tex]

Solve the numerator.

15 m/s - 10 m/s = 5 m/s

[tex]a= \frac{ 5 \ m/s }{5 \ s}[/tex]

Divide.

[tex]a= 1 \ m/s/s[/tex]

[tex]a= 1 m/s^2[/tex]

The acceleration is 1 meter per second squared.

: 1 khối khi lý tưởng nhận được nhiệt lượng 200J, khi đó khí nở ra đẩy pittong bằng 1 công 80J.
Vậy nội năng Của khí là bao nhiêu

Answers

Answer:

DU = 120 Joules

Explanation:

Given the following data;

Quantity of energy = 200 J

Work = 80 J

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

DU is the change in internal energy.

Q is the quantity of energy.

W is the work done.

Substituting into the formula, we have;

DU = 200 - 80

DU = 120 Joules

A 5.41 kg ball is attached to the top of a vertical pole with a 2.37 m length of massless string. The ball is struck, causing it to revolve around the pole at a speed of 4.75 m/s in a horizontal circle with the string remaining taut. Calculate the angle θ, between 0∘ and 90∘, that the string makes with the pole. Use g=9.81 m/s2.

Answers

Answer:

θ = 66º

Explanation:

This exercise of Newton's second law must be solved in part, let's start by finding the slowing down acceleration of the ball

           a = v² / r

the radius of the circle is

          sin θ = r / L

          r = L sin θ

           

we substitute

          a = v² /L sin θ

now let's write Newton's second law

vertical axis

            T_y -W = 0

             T_y = W

radial axis

            Tₓ = m a                 (1)

let's use trigonometry for the components of the string tension

             cos θ = T_y / T

             sin θ = Tₓ / T

             Tₓ = T sin θ

we substitute in 1

            T sin θ = [tex]\frac{m \ v^2}{L \ sin \theta}[/tex]

             T L sin² θ = m v²

we write our system of equations

             T cos θ  = m g

             T L sin ² tea = m v²

we divide the two equations

             L [tex]\frac{sin^2 \theta}{cos \theta}[/tex] = v² / g

             (1 -cos²)/ cos θ  = [tex]\frac{v^2 }{g \ L}[/tex]

             1 - cos² θ  =  [tex]\frac{4.75^2}{9.81 \ 2.37}[/tex]   cos θ

             cos² θ + 0.97044 cos θ -1   = 0

we change variable    cos  θ = x

             x² + 0.97044 x - 1 =0

             x= [tex]\frac{-0.97 \pm \sqrt{0.97^2 - 4 1} }{2}[/tex]

           since the square root is imaginary there is no real solution to the problem, suppose that the radius is 1 m r = 1 m

           T sin θ = [tex]\frac{m \ v^2}{ r}[/tex]

           T cos θ  = m g

resolved

           tan θ =  [tex]\frac{v^2}{ r g}[/tex]

           θ = tan⁻¹ ( 4.75²/ 1 9.81)

           θ = 66º

there is a dropping of a coconut of 2kg mass. the speed of the coconut at the moment before it hits the ground is 40m s-1.

calculate the kinetic energy of the coconut at the moment.

Answers

Mass=2kgVelocity=40m/s

We know

[tex]\boxed{\sf K.E=\dfrac{1}{2}mv^2}[/tex]

m denotes to mass v denotes to velocity

[tex]\\ \sf\longmapsto K.E=\dfrac{1}{2}\times 2\times 40^2[/tex]

[tex]\\ \sf\longmapsto K.E=40^2[/tex]

[tex]\\ \sf\longmapsto K.E=1600J[/tex]

The unit of work in terms of Newton and metre is _______

Answers

Answer:

Joule

Explanation:

the unit of work is Joule determined by the letter J.

Answer:

Joule

Explanation:

Joule is defined as the work done by a force of one newton causing a displacement of one meter. Sometimes, newton-metre (N-m) is also used for measuring work.

A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror?
• -5.0 cm
• 7.5 cm
• -7.5 cm
• 5.0 cm

Answers

Answer:

5.0cm

Explanation:

To get the height of the image, we will use the magnification formula as shown:

m = Hi/H = v/u

Hi is the image height

H is the object height

v is the image distance

u is the object distance

First, we need to get the image distance v

Using the mirror formula;

1/f = 1/v+ 1/u

1/-6 = 1/v + 1/12

1/v = -1/12 - 1/6

1/v = -1-2/12

1/v = -3/12

v = 12/-3cm

v = -4cm

Next is to get the image height Hi

Using the expression;

Hi/H = v/u

Hi/15 = 4/12

Hi/15 = 1/3

3Hi = 15

Hi = 15/3

Hi = 5.0cm

Hence the image height is 5.0cm

Answer:

D. 5.0 cm

Explanation:

got it correct on the test

define inertia.mention it's types​

Answers

Answer:

It is the inability of the body to change by itself its state of rest or uniform motion or direction. Types of Inertia- It is of three types-(1)Inertia of rest (2) Inertia of motion(3) Inertia of direction. (1) Inertia of rest - It is the inability of the body to change by itself its state if rest.

for minimum deviation inside the prism the angle of emergence should be equal to ​

Answers

Answer:

Originally Answered: Why should angle of incidence be equal to angle of refraction for minimum deviation in a triangular glass prism? The angle of incidence is equal to angle of refraction only if the angle od deviation is 0.

Explanation:

not sure but

Don't Forget To Follow, Brainliest, And Give Me Heart :)

maize is a monocotyledonous seed and pea is a dicotyledonous seed why? give short and the suitable answer I will mark you as a brainelist​

Answers

Answer:

A dicot is a flowering plant that has one seed leaves. The monocot plants have a single cotyledon. Maize only has one cotyledon in their seed, so it's a monocot. Seeds having two Cotyles are mainly called a Dicot. A pea is a dicotyledonous plant, the seed (the pea itself) has two halves, cotyledons, hence dicot being 2.

Explanation:

One or more of the cotyledons are the first to appear from a germinating seed. Based on the number of cotyledons, botanists classify flowering plants (angiosperms) into :

a) plants with one embryonic leaf, termed monocotyledonous (monocots).

b) plants with two embryonic leaves, termed dicotyledonous (dicots).

Helpful Link:

https://www.vedantu.com/question-answer/in-pea-caster-and-maize-the-number-of-cotyledons-class-11-biology-cbse-5f626a17e5bde9062ff6d2a3

what is the role of the communicator in a dc generator?

A) it keeps the electric current flowing in one direction
B) it keeps the magnetic fields of the permanent magnet steady
C) it causes the magnetic fields of the permanent magnets to reverse
D) it causes the electric current to constantly reverse its direction

Answers

Answer:

C

Explanation:

Answer:

A)

Explanation:

it keeps the electric current flowing in one direction

Please help me. I need this in a few hours.

Answers

Answer:

A) The population of prey is greater than that of predator

help me with this one​

Answers

Answer:

may be d)45°

Explanation:

What is 98.907 rounded to 1 significant figure?

Answers

The answer to the digits rounded to one significant figure is 100.

Significant figures are the most important figures in a number of digits.

The closer a digit is to the beginning of a number, the more important  or significant  it is.

But, the rule for rounding up a set of numbers to the first significant or to one significant figure is that:

If the next number is 5 or more, we round up.If the next number is 4 or less, we do not round up.

From the numbers 98.907, 9 is the most significant digit followed by 8.

8 is greater than 5 so we should round up by adding one to 9 making the number 100.

learn more here:

https://brainly.com/question/11566364

Answer me as much as you can

Answers

Answer:

b) Fluorescent powder.
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Job 306 is sold for $635,000 cahs in April.Costs of the three jobs worked on in April follow: Job 307 Job 307 Job 308Balances on March 31 Direct materials $29,000 $35,000 Direct labor 20,000 18,000 Applied overhead 10,000 9,000 Costs during April Direct materials 135,000 220,000 $100,000Direct labor 85,000 150,000 105,000Applied overhead Status on April 30 Finished (sold) Finished (unsold) In processa. Materials purchases on creditb. Direct materials used in productionc. Direct labor paid and assigned to Factory Overheadd. Indirect labor paid and assigned to Factory Overheade. Overhead costs applied to Work In Process Inventoryf. Actual overhead costs incurred, including indirect materials. (Factory rent and utilities are paid in cash)g. Transfer of Jobs 306 and 307 to Finished Goods Inventoryh. Cost of goods sold for Job 306i. Revenue from the sale of Job 306j. 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