what happens if I increase the height of a skater

Answer:

52.802

Explanation:

"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.

The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.

Explanation:

five significant of 52.8015=52.801 ..

Explanation:

what is time in this question

Answer:

3240000000 Joules

Explanation:

Answer:

weight at height = 100 N .

Explanation:

The problem relates to variation of weight  due to change in height .

Let g₀ and g₁ be acceleration due to gravity , m is mass of the object .

At the surface :

Applying Newton's law of gravitation

mg₀ = G Mm / R²

At height h from centre

mg₁ = G Mm /h²

Given mg₀ = 400 N

400 = G Mm / R²

400 = G Mm / (6400 x 10³ )²

G Mm = 400 x (6400 x 10³ )²

At height h from centre

mg₁ =  400 x (6400 x 10³ )²/ ( 2 x 6400 x 10³)²

= 400 / 4

= 100 N .

weight at height = 100 N

Answer: C: The moons orbit around the earth.

Explanation:

Naw ur pretty accurate, heck collage is the only football worth watching most the time. Hook'um horns!

Answer:

1.  -0.863 kgm/s 2. -1.438 kgm/s

Explanation:

1. What is the change in momentum of the bullet if it embeds in the block?

Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s

Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)

= -8.625 × 10⁻¹ kgm/s

= -0.8625 kgm/s

≅ -0.863 kgm/s

2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?

If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.

So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)

= -14.375 × 10⁻¹ kgm/s

= -1.4375 kgm/s

≅ -1.438 kgm/s

Answer:

An object at rest is described by Newton's First Law of Motion. An object in static equilibrium has zero net force acting upon it. The First Condition of Equilibrium is that the vector sum of all the forces acting on a body vanishes.

Explanation:

Answer:

see below

Explanation:

the first condition means that the light ray inside the optically denser medium hits the surface of the optically less dense medium.

this in simple words means, light must be travelling from am optically denser medium to an optically less dense medium

hope this helps :)

Answer: macroscopic outputs

Explanation:

When fireworks explode, sound and light are produced. These are examples of macroscopic outputs. Because, explosion from fireworks is an exothermic process which releases massive heat energy to the surroundings.

Exothermic reaction are those which evolve heat energy to the surroundings.  The change in enthalpy of the reaction is negative here. Whereas, in an endothermic reaction energy is absorbed by the reactants.

Exothermic reactions sometimes results in massive explosion. The heat energy released to the surroundings from the fire works is macroscopic level.

The small scale process or quantity that cannot be measured using normal scales are called microscopic units. Therefore, the sound, light, and heat from the explosion all are macroscopic outputs.

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Answer:

b. at the top

Explanation:

At the top of the climb, the vertical velocity of Jeff's throw has a value of zero.

Vertical velocity in this instance is acting against the acceleration due to gravity.

Answer:

i would say the neuron

Answer:

3.15m³

Explanation:

To solve this problem, let us first find the mass of the petrol from the given dimension.

       Mass  = density x volume

Volume of petrol  = 4.2m³

Density of petrol  = 0.3kgm⁻³  

       Mass of petrol  = 4.2 x 0.3  = 1.26kg

So;

      We can now find the volume of the alcohol

 Volume of alcohol = [tex]\frac{mass}{density}[/tex]  

Mass of alcohol  = 1.26kg

Density of alcohol  = 0.4kgm⁻³  

  Volume of alcohol  = [tex]\frac{1.26}{0.4}[/tex]   = 3.15m³

Answer:

The volume of a regular object can be calculated by multiplying its length by its width by its height. Since each of those is a linear measurement, we say that units of volume are derived from units of length.

Explanation:

Answer:

length×Width×Height

Explanation:

Length×Width×Height is the formula for volume

a.

b.

c.

e.

f.

g.

character limit thing

Answer:

(a) the total momentum of the system before the collision = -2m kg.m/s.

(b) the total momentum of the system after the collision = -2m kg.m/s.

(c) puck 1's velocity after the collision in component form = (5.44 i, 2.54 j)

Explanation:

Given;

mass of Puck 1 , = m

mass of Puck 2, = m (since they have the same mass m)

initial velocity of Puck 1, u₁ = 10 m/s to the left

initial velocity of Puck 2, u₂  = 8 m/s to the right

Let the rightward direction be positive direction

Let the leftward direction be negative direction

(a) the total momentum of the system before the collision;

P₁ = (initial momentum of Pluck 1) + (initial momentum of Pluck 2)

P₁ = (-mu₁) + mu₂

P₁ = mu₂ - mu₁

P₁ = m(u₂ - u₁)

P₁  = m(8 - 10)

P₁  = -2m kg.m/s

(b) the total momentum of the system after the collision;

Based on the principle of conservation of linear momentum, the total momentum before collision is equal to the total momentum after collision.

Thus, the total momentum of the system after the collision is -2m kg.m/s.

(c) puck 1's velocity after the collision in component form

[tex]v = (v_x, v_y)\\\\v = (vcos \theta , vsin \theta)\\\\v = (6cos 25^0 , 6sin25^0)\\\\v = (5.44i, 2.54j)m/s[/tex]

Answer:

0.35

Explanation:

According to Newton's second law;

\sum Fx = ma

Fm - Ff =ma

Fm is the moving force = Wsin theta

Fm = 4(9.8)sin55

Fm = 32.1N

Ff is the frictional force = nmgcos theta

Ff = n(4)(9.8)cos55

Ff = 22.48n

Acceleration a = 6.0m/s²

Substitute the given values into the formula and get the coefficient of friction

32.11-23.48n = 4(6)

32.11-24= 23.48n

8.11 = 23.48

n = 8.11/23.48

n = 0.35

Hence the coefficient of friction is 0.35

The centripetal force is the force that keeps a body moving in a circular path.

The centripetal force is given by; F = mv^2/r

1) We have;

F = 5,600 N

v = 20 m/s

r =?

m = 700 kg

Making r the subject of the formula;

r =mv^2/F

r = 700 × (20)^2/5,600

r = 50 m

2) F = mv^2/r

F = 900 × (5)^2/30

F = 750 N

3) Making r the subject of the formula;

r =mv^2/F

r = 800 × (40)^2/ 16,000

r = 80 m

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Answer:

39225J

Explanation:

Given parameters:

Mass of water  = 375grams of water

Change in temperature  = 25°C

Specific heat capacity of water  = 4.184J/g°C

Unknown:

Amount of heat absorbed  = ?

Solution:

To solve this problem, we use the expression below:

      H  = m c Ф  

H is the heat absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

  Insert the parameters and solve;

      H  = 375 x 4.184 x (25) = 39225J

Answer:

Explanation:

El campo eléctrico provocado por una carga puntal sobre determinado punto viene dado por la ecuación:

E  = K * Q /r²       en esa ecuación E es el campo eléctrico (un vector), K es una constante K = 1/4*π*ε₀   Q es la carga que origina el campo, y r la distancia entre la carga y el punto donde se quiere determinar el campo. La fuerza de origen eléctrico y el campo eléctrico van en la dirección de la recta de unión entre carga y punto ( es decir según r) y esta fuerza sera repulsiva o de atracción según que la carga que la origina sea positiva o negativa (respectivamente, ya que en la determinación de fuerza y campo, se asume que se coloca una carga de prueba positiva en el punto ).

Siendo así, si dos cargas elécticas son iguales y están separadas una distancia r ; en el punto medio (r/2) los campos producidos por cada una de las cargas serán de la misma magntud.

Carga Q₁  = Carga Q₂  = Q

E₁ = K * Q₁ / (r/2)²   y    E₂  = K * Q₂/(r/2)²

Y además tendran direcciones totalmente opuestas, por lo que se anularan

En el segundo caso las cargas son iguales en magntud pero de diferentes signos ( una positiva y la otra negativa ). En este caso los campos eléctricos continuaran siendo de la msma magnitud pero dado que la carga positiva repele la carga de muestra (teorica) y la negativa la atrae los dos campos coinciden en su dirección y resultará una campo de magnitud doble. La dirección del campo será en la tendencia de acercarse a la caga negativa, así si la carga negativa está a la derecha la fuerza de origen eléctrico y el campo van hacia la derecha y si la carga negativa está a la izquierda pues esa será la diercción del campo

Answer:

I believe you are correct but we just started this unit

Explanation:

Answer:

50 Mph.

Explanation:

According to the National Severe Storms Laboratory, winds can really begin to cause damage when they reach 50 mph. But here’s what happens before and after they reach that threshold, according to the Beaufort Wind Scale (showing estimated wind speeds): - at 19 to 24 mph, smaller trees begin to sway.

Answer:

Gravity is an ever present force, and therefore acceleration is guaranteed to happen at every single one of those points (and in fact, everywhere in the universe).

On top of that, friction will be present in all four spots (friction with the rails, with the air, with the axles, etc.), and friction is a perfectly acceptable force that will cause acceleration, slowing the roller coaster down.

So the correct answer is every single point, regardless of what answer the teacher expects.

The object will be moving faster if the acceleration and velocity are pointing in the same direction. The object will also slow down if the acceleration is pointing in the opposite direction as the velocity.

When an object's speed, direction of motion, or both change, it accelerates. Even while it may appear to be virtually immediate in some circumstances, such as when a golf ball is struck by a club or during car collisions, changes in an object's speed are always continuous.

Since gravity is a constant force, acceleration will unavoidably occur at each of those locations and throughout the whole universe.

Therefore, In addition, there will be friction at all four locations—friction with the axles, the air, the rails, etc.—and friction is a completely normal force that will accelerate the roller coaster, slowing it down.

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Complete question :

A flight attendant pulls her 70 N flight bag a distance of 318 m along a level airport floor at a constant velocity. The force she exerts is 41 N at an angle of 57° above the horizontal.

(a) Find the work she does on the flight bag.

(b) Find the work done by the force of friction on the flight bag.

(c) Find the coefficient of kinetic friction between the flight bag and the floor.

Answer:

7107 J ; - 7107 J ; 0.55

Explanation:

Given that :

Distance, d = 318m

Applied force = 41 N

θ = 57°

A.) Workdone = Force exerted along direction of motion

Workdone = applied Force * distance * cosθ

Workdone = 41 * 318 * cos57 = 7101.0037

Workdone = 7,101 J

B.) Workdone by force of friction on flight bag:

- 7,101 J (since the body moves at constant velocity)

C.)

Coefficient of kinetic friction (μ) = Frictional force / normal reaction)

μ = F / N

Frictional force, F = Workdone by friction / distance

F = 6200 / 318

F = 19.47N ;

Ff = weight of Flight bag = 70 N

N = Ff - Fsinθ

N = 70 - applied Force sinθ

N = 70 - 41sin57

N = 70 - 34.385493

N = 35.614506

μ = 19.47 / 35.614506

μ = 0.5466873

Answer:

D is the correct answer

Explanation:

Ek=m*g*h=50*9.8*5=2450

The kinetic energy right before she hits the water is 2450J. So, the correct option is D.

Kinetic energy is defined as the energy that is due to the motion of an object. If we want to accelerate an object, we must apply a force, by applying a force we need to do work. After the work is done, energy has been transferred to the object, and the object will continue to move with a new constant speed.

A 50Kg girl jumps off a 5-meter-high diving board.

We need to find the kinetic energy of the girl before she enters the water which means that the kinetic energy becomes equal to the potential energy such that,

P.E.=K.E. = mgh

where, m=mass of the object

g= acceleration due to gravity [tex](9.8m/s^2)[/tex]

h= height

So, K.E= 50* 9.8*5 = 2450 J

Thus, the kinetic energy right before she hits the water is 2450J. So, the correct option is D.

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Appliances connected so that they form a single pathway for charges to flow are connected in a(n)

A. Series circuit

Appliances connected so that they create a single pathway for charges to flow are connected in a series circuit. Therefore, option (A) is correct.

In a series combination of appliances, they are connected end-to-end. Consider two resistors, R₁ and R₂ which are connected in a series combination then their effective resistance can be given by:

Total Resistance of the series circuit, R =  R₁ + R₂

In a series combination, the current flows through one appliance and then through another appliance. The same current flows through each appliance in one direction. The total voltage of the series circuit is equal to the sum of all the voltage drops across all appliances.

A potential difference of the series circuit, V  = V₁ + V₂

Therefore, when appliances are connected in a series circuit they form a single pathway for charges to flow.

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Answer:

5.65 m/s²

Explanation:

We'll begin by calculating the mass of PJ when in San Diego (i.e Earth). This can be obtained as follow:

Weight of PJ on Earth (Wₑ) = 545 N

Acceleration due to gravity (g) on Earth (gₑ) = 10 m/s²

Mass of PJ on Earth (mₑ) =.?

Wₑ = mₑ × gₑ

545 = mₑ × 10

Divide both side by 10

mₑ = 545 / 10

mₑ = 54.5 Kg

Thus, the mass of PJ on San Diego (i.e Earth) is 54.5 Kg

Finally, we shall determine the acceleration due to gravity of planet Koja. This can be obtained as follow:

Weight of PJ on Koja (Wₖ) = 308 N

Mass of PJ on Koja (mₖ) = mass of PJ on Earth (mₑ) because mass is constant irrespective of location.

Mass of PJ on Earth (mₑ) = 54.5 Kg

Mass of PJ on Koja (mₖ) = 54.5 Kg

Acceleration due to gravity of on Koja (gₖ) =?

Wₖ = mₖ × gₖ

308 = 54.5 × gₖ

Divide both side by 54.5

gₖ = 308 / 54.5

gₖ = 5.65 m/s²

Thus, the acceleration due to gravity on planet Koja is 5.65 m/s²

Answer:

No work is done since no distance is given

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

Answer:

I’m. Nog sure

Explanation: