What is 1/8 * 1/8 in fraction? PLEASE HELP

Answer:

Exact Form:

x = 2 √ 2 − 1 3 , − 2 √ 2 − 1 3

Decimal Form:

x = 2.49509379 , − 3.16176045

Step-by-step explanation:

Simplify the decimals as needed

Answer:

3408

Step-by-step explanation:

Answer:

Greg is 28.

Step-by-step explanation:

Greg's age is y.

y - 5 = 23

y - 5 + 5 = 23 + 5

y = 28

9514 1404 393

Answer:

  ΔWZT ~ ΔWXY

Step-by-step explanation:

Angle XWY and angle ZWT are vertical angles, so congruent.

The sides on either side of those angles are proportional:

  WZ/WX = WT/WY

  11/22 = 10/20 = 1/2

so, we can claim similarity by the SAS Theorem.

  ΔWZT ~ ΔWXY

Answer:

Suppose you have a fair coin: this means it has a 50% chance of landing heads up and a 50% chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.

Answer:

B. 56° and 38°

Step-by-step explanation:

The sum of each of the two angles sums up to 90° ;

A.) 13° and 77°

Sum of A ; (13 + 77)° = 90°

B.) 56° + 38°

Sum = 56° + 38° = 94°

C) 37° and 53°

Sum = 37° + 53° = 90°

D.) 42° and 48°

Sum = 42° + 48° = 90°

Hence, the pair of degree measure which does not belong is B. 56° and 38°

Answer:

Step-by-step explanation:

Answer:

[tex]Shaded = 212.5cm^2[/tex]

Step-by-step explanation:

Given

See attachment

Required

The shaded region

First, calculate the area of the complete rectangle

[tex]Area =Length * Width[/tex]

[tex]Area = 14cm * 25cm[/tex]

[tex]Area = 350cm^2[/tex]

Next, calculate the area of the triangle

[tex]Area = \frac{1}{2} * Base * Height[/tex]

[tex]Area = \frac{1}{2} *25cm * 11cm[/tex]

[tex]Area = 137.5cm^2[/tex]

Subtract the area to calculate the shaded region area

[tex]Shaded = 350cm^2 - 137.5cm^2[/tex]

[tex]Shaded = 212.5cm^2[/tex]

9514 1404 393

Answer:

  (b)  (x – 4)^2 + (y – 6)^2 = 16

Step-by-step explanation:

The equation for a circle with center (h, k) and radius r is ...

  (x -h)^2 +(y -k)^2 = r^2

You want the equation for a circle with center (4, 6) and radius 4. That equation is ...

  (x -4)^2 +(y -6)^2 = 16

Answer:

B; (x – 4)2 + (y – 6)2 = 16

Step-by-step explanation:

correct on edge

Given:

ABC is an isosceles triangle in which AC =BC.

D and E are points on BC and AC such that CE=CD.

To prove:

Triangle ACD and BCE are congruent​.

Solution:

In triangle ACD and BCE,

[tex]AC=BC[/tex]                  (Given)

[tex]AC\cong BC[/tex]

[tex]\angle C\cong m\angle C[/tex]                  (Common angle)

[tex]CD=CE[/tex]                  (Given)

[tex]CD\cong CE[/tex]

In triangles ACD and BCE two corresponding sides and one included angle are congruent. So, the triangles are congruent by SAS congruence postulate.

[tex]\Delta ACD\cong \Delta BCE[/tex]           (SAS congruence postulate)

Hence proved.

Answer:

Given ABC is an isosceles triangle with AB=AC .D and E are the point on BC such that BE=CD

∴∠ABD=∠ACE (opposite angle of sides of a triangle ) ....(1)

Then BE−DE=CD−DE

ORBC=CE......................................(2)

In ΔABD and ΔACE

∠ABD=∠ACE ( From 1)

BC=CE (from 2)

AB=AC ( GIven)

∴ΔABD≅ΔACE

So AD=AE [henceproved]

Answer:

The volume increases at 35.71cm^3/min

Step-by-step explanation:

Given

[tex]PV^{1.4} = C[/tex]

[tex]V = 400cm^3[/tex]

[tex]P =80kPa[/tex]

[tex]\frac{dP}{dt} =-10kPa/min[/tex]

Required

Rate at which volume increases

[tex]PV^{1.4} = C[/tex]       [tex]V = 400cm^3[/tex]       [tex]P =80kPa[/tex]

Differentiate: [tex]PV^{1.4} = C[/tex]  

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = \frac{d}{dt}C[/tex]

By differentiating C, we have:

[tex]P*\frac{dV^{1.4}}{dt} +V^{1.4}*\frac{dP}{dt} = 0[/tex]

Rewrite as:

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} + V^{1.4}*\frac{dP}{dt} = 0[/tex]

Solve for [tex]\frac{dV}{dt}[/tex]

[tex]P*(1.4)*V^{0.4}* \frac{dV}{dt} =- V^{1.4}*\frac{dP}{dt}[/tex]

[tex]\frac{dV}{dt} =- \frac{V^{1.4}*\frac{dP}{dt} }{P*(1.4)*V^{0.4}}[/tex]

Substitute values

[tex]\frac{dV}{dt} =- \frac{400^{1.4}*-10 }{80*(1.4)*400^{0.4}}[/tex]

[tex]\frac{dV}{dt} =\frac{400*10 }{80*1.4}[/tex]

[tex]\frac{dV}{dt} =\frac{4000 }{112}[/tex]

[tex]\frac{dV}{dt} =35.71cm^3/min[/tex]

. ( m →(N v Q)) →((M→N) v (M→Q))

2.((T v U) → V) → (T → (U → V)) wut tyhe hell is this

Answer:

50/50

Step-by-step explanation:

It's random

9514 1404 393

Answer:

  5196 m

Step-by-step explanation:

The difference in elevation is found by subtracting one elevation from the other. Usually, we're interested in the positive difference, so we subtract the smaller number from the larger.

  5040 -(-156) = 5040 +156 = 5196

The difference in elevation is 5196 meters.

Answer:

"fair" srry im only in 8th so im d.u.m

Step-by-step explanation:

Answer:

ifeywifheb

Step-by-step explanation:

hkefewib

Answer:

13122

Step-by-step explanation:

a(n) = 6 * 3^(n -1)

a(8) = 6* 3^7

3^7 = 2187

a(8) =6 * 2187

a(8) = 13122

Answer:

1.043

Step-by-step explanation:

Decimal multiplier to increase by x% is computed as:-

100% + x%

The decimal multiplier to increase by 4.3% would be

100% +4.3% = 104.3%

To remove% we divide the number by 100, so the number will become

Hence, The decimal multiplier to increase by 4.3% = 1.043

Please Mark as Brainliest

Hope this Helps

Answer:

Base: 7

Height:10

BH divided by two so

7 times 10 = 70 divided by two 35

Base: 7 yd

Height: 10 yd

Area: 35 square yd

         ([tex]A=\frac{h_{b}b }{2}[/tex] = [tex]\frac{10*7}{2}[/tex] = 35)

hope this helps....

Answer:

parallel

Step-by-step explanation:

the slope of each line is 5/6 which means the lines are parallel

Answer:

the coordinates of pre - image point H is (3,2)

Answer:

c time for learning

Step-by-step explanation:

Answer:

Step-by-step explanation:

(0,2). y=mx+b or 2=-2 × 0+b, or solving for b: b=2-(-2)(0).

Answer:

the required equqtion is x-y=2

Answer:

4.605170185988091

Step-by-step explanation:

ln 100 = 4.605170185988091

e^4.605170185988091 = 100

Step-by-step explanation:

100=1 log 10(1)=0

I hope this is helpful for you

Answer:

Option c (Upper tailed) is the correct choice.

Step-by-step explanation:

Given that:

The average attendance is:

= 74,900

We will have to test:

⇒ [tex]H_0:\mu \leq \mu_0[/tex]

or,

   [tex]H_0: \mu \leq 74,900[/tex]

Verses,

⇒ [tex]H_1: \mu> \mu_0[/tex]

or,

    [tex]H_1: \mu >74,900[/tex]

The other given alternatives aren't connected to the given scenario. So the above is the correct one.

Answer:

10 square inches

Step-by-step explanation:

that is the procedure above

Answer:

Area=10.167=10.2

Step-by-step explanation:

Area=1/2ab sin c

area= 1/2(7)(9.4)sin18

area = 10.167=10.2

this is for delta math