HELPP AGAIN PLEASE!! 2/5 (10c -35) (the 35 is negative)
Answer:
4c - 14
Step-by-step explanation:
2/5 (10c -35)
Distribute
2/5 * 10c - 2/5 * 35
4c - 14
Answer:
See below.
Step-by-step explanation:
[tex]\frac{2}{5} (10c-35)\\\text{Distribute}\\=\frac{2}{5}(10c)+\frac{2}{5}(-35) \\=\frac{20}{5} c-\frac{70}{5}\\ =4c-14[/tex]
Simplify the expression in simplest form (3x - 5)x4 +2
Answer:
12x-8
Step-by-step explanation:
We can use PEMDAS to solve this expression.
P: Parenthesis
E: Exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction
The first step to do is use the distribute property to simplify the parenthesis.
The second step will be to simplify the exponent, but there aren't any so we can skip that step.
The third is to multiply but we can skip that and division while we are at it because there isn't any we can do to simplify.
The fourth step will be to add -20 with 2. We then get -18.
And finally, we have our answer
(3x - 5)x4 +2
12x-20+2
12x-18
A point on an ellipse is 11 unites from one focus and 7 units from another. What is the length of the major axis? Show your work
Answer:
77
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
x + y = major axis
11 + 7 = 18
Find the value of x.
76
A 4-pack of greeting cards costs $7.40. What is the unit price?pls answer fast
Answer:
The unit price of the problem is that one pack of greeting cards costs $1.85
Step-by-step explanation:
In order to find the unit rate, you have to divide the price by the quantity of the product. So, we will divide 7.40 by 4 so we can see the price of one pack.
7.40 ÷ 4 = 1.85
So, one pack of greeting cards costs $1.85 which is also our unit price.
Answer:
1.85
Step-by-step explanation:
First, divided the money ( $7.40 ) by the whole number ( 4 )
Then, you will receive your answer
if the morning temperature started at -7 celsius but warmed during the day to 24 celsius . What is the temperature change
Answer:
31° change
Step-by-step explanation:
If we want to find the change between two numbers, we need to imagine it like a number line.
<-------------0------------->
Let's plot -7 and 24 on this number line.
<----------[tex]-7[/tex]--0------------24>
If we want to get from -7 to 0, we increase by 7. To get from 0 to 24, we increase by 24.
So the total change is [tex]7 + 24 = 31[/tex].
Hope this helped!
Can u guys answer my question 13 and 14 pls
Answer:
√2=1.414
then :√8 +2√32 +3√128+4√50
√8=√2³ =2√2
2√32=√2^5 = 4*2√2 = 8√2
3√128 = 3√2^6*2=8*3√2 =24√2
4√50 =4√5²*2= 20√2
add results : 2√2+8√2 +24√2+20√2=54√2
54√2=54×1.414=76.356 ( it is not in the options)x=7-4√3
√x+ 1/√x
√(7-4√3) +1/√(7-4√3) =
(8-4√3)/√(7-4√3)
(8-6.93)/√(7-6.93) = 4 ( after rounded to the nearest whole number)
4 is your answer
Drag each label to the correct location on the table. Each label can be used more than once. A cross country coach records the number of miles his athletes on the Junior Varsity and Varsity teams ran today and displays the data in the provided dot plots. Given the shape of each distribution, determine which measures of center and spread are appropriate for him to use to summarize the data from each team. mean mean interquartile range interquartile range standard deviation standard deviation median median
Answer:
a.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed.
For the Junior Varsity Team, the mean would be the appropriate measure of the center since the data is symmetric or well-proportioned .
What is median?Median represents the middle value of the given data when arranged in a particular order.
Since the data for the Junior Varsity Team is symmetric or well-proportioned, the mean would be the best way to determine the center, and standard deviation, which also measures the center and how far the values deviate from the mean, should be used to determine the spread.
The median could be utilized for the Varsity Team since the data is not evenly distributed and skewed to the left, and it does not take into account outliers.
We can use the interquartile range (IQR) to quantify the spread of the data because IQR does not take into account the skewed data.
Therefore, the varsity squad competes in intercollegiate or international competitions on behalf of the high school or institution while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
Learn more about the Varsity team here
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what is the square root of 450
Answer:
[tex]15\sqrt{2}[/tex] or 21.2132
Step-by-step explanation:
[tex]\sqrt{450}[/tex]
[tex]\sqrt{15^{2} }[/tex] (root of a product is equal to the product of the roots of each factor)
[tex]\sqrt{15^{2} } \sqrt{2}[/tex] (simplify)
[tex]15\sqrt{2}[/tex] or ≈ 21.2132
Answer:
[tex]15\sqrt{2}[/tex] or 21.213
Step-by-step explanation:
For radical form: think of multiples of 450. Think of a pair that contains one perfect square, particularly the higher, the better . These 2 numbers are 25 and 18. 25 is the perfect square number since the two numbers that multiply to be 25 is 5 and 5.
Now take the perfect square of 25 and put it outside of the radical. The 18 remains inside: [tex]5\sqrt{18}[/tex]
Now, since 18 is a high number that needs to get reduced, do the same for 18 as we did for 450--find two numbers, one of which is a perfect square. These two numbers are 9 and 2.
Now take the perfect square of 9. This is 3. Take it out of the radical so that only the two remains inside. The 3 will now multiply with the 5: [tex]5*3\sqrt{2}[/tex]
Multiply 5 and 3 to get 15. The 15 stays outside the radical. Your answer is:
[tex]15\sqrt{2}[/tex]
[tex]\sqrt{\frac{4e}{3f} }[/tex]
Answer:
2√e√3√f / 3f
Step-by-step explanation:
√4√e / √3√f
2√e / √3√f * (√3√f / √3√f)
2√e√3√f / 3f
ochieng had sh 250 as pocket money at the begining of the term.in the middle of the term he was left with 2 over five of this amount .how much did she spend
Answer:
625
Step-by-step explanation:
250 × X = 2
X = 5
250 × 5 = 2
1250 = 2 after this step u divided it by 2
1250 ÷ 2
= 625
How would you write The product of 2 and the difference of a number and 9
Answer:
[tex]\large \boxed{2(x-9)}[/tex]
Step-by-step explanation:
Let the number be x.
The product of 2 and the difference of x and 9.
“product” is multiplication.
“difference” is subtraction.
[tex]2 \times (x-9)[/tex]
The mathematical expression is 2(n - 9) if the product of 2 and the difference of a number and 9.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
It is given that:
The product of 2 and the difference of a number and 9.
Let the number is n; n is the real number.
The difference of a number and 9 = n - 9
The linear expression can be defined as the relation between two variables, if we plot the graph of the linear expression we will get a straight line.
If in the linear expression, one variable is present, then the expression is known as the linear expression in one variable.
The product of 2 and (n - 9)
= 2(n - 9)
Thus, the mathematical expression is 2(n - 9) if the product of 2 and the difference of a number and 9.
Learn more about the expression here:
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which inequality is graphed on the coordinate plane?
Answer:
a
Step-by-step explanation:
1:cancel out any answers with equal to since the line is dotted
2:pick any two points of your choice and work out the gradient
3:use the gradient a point on the line and an anonymous point (x,y) to get equation of a line
4:then choose a point (0,0) and substitute x with 0 in the equation to get y (in this case it's -1) which is less than 0 hope it helps
The inequality that is graphed on the coordinate plane is y ≤ [tex]x^{2}[/tex].
The graph of this inequality is a parabola that is facing downwards. The parabola opens downwards because the inequality symbol is less than or equal to (≤). The vertex of the parabola is at the point (0, 0).
The parabola intersects the x-axis at the points (-1, 1) and (1, 1). This means that the values of x that satisfy the inequality are all the values that are less than or equal to 1.
The parabola does not touch the x-axis at any other points, so the values of x that do not satisfy the inequality are all the values that are greater than 1.
Here is a graph of the inequality y ≤ [tex]x^{2}[/tex]:
parabola that is facing downwards and intersects the x-axis at (-1, 1) and (1, 1)Opens in a new window
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parabola that is facing downwards and intersects the x-axis at (-1, 1) and (1, 1)
The other inequalities that are shown in the answer choices are not graphed correctly. The inequality y ≥ [tex]x^{2}[/tex] is graphed as a parabola that is facing upwards. The inequality y = [tex]x^{2}[/tex] is graphed as a line that is not a parabola. The inequality y > [tex]x^{2}[/tex] is not graphed at all.
Therefore, the only inequality that is graphed correctly is y ≤ [tex]x^{2}[/tex].
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ux=x+y/k, solve for x
Answer:
x = y/( ku-1)
Step-by-step explanation:
Here in this question, we are asked to solve for x.
we have;
Ux = x+ u/ k
cross multiply;
k * Ux = x + y
kUx = x + y
kUx- x = y
x(KU-1) = y
x = y/( ku-1)
Flight time from Houston to Orlando is 2 hours to 20 minutes. I arrived at Orlando at 4:15 pm. What time did I set of ?
Answer:
1:55 pm
Step-by-step explanation:
So, you arrive at 4: 15 pm in Orlando after a 2 hr and 20 minute flight from Houston. So, lets start with the easy part: let's subtract the 2 hrs part.
2 hrs earlier from 4:15 pm is 2:15 pm.
Then, you have to subtract the 20 minutes. Well, it's quite obvious that if you left at 2:00 pm, that would be a total of 2 hrs and 15 minutes. Just subtract the 15 minutes from the 2:15 pm. However, it's 20 minutes, not 15, so you have to still subtract that last five minutes.
So, 2:00 pm minus 5 minutes would equal 1:55 pm.
(b-2)x= 8
In the given equation, b is a constant. If the equation
has no solution, what is the value of b ? A) 2
B) 4
C) 6
D) 10
Answer:
2
Step-by-step explanation:
(2-2)x = 8
(0)x = 8
x = 8/0
no solution
The value of "b" that would result in the equation having no solution is A) 2.
To determine the value of "b" that would result in the given equation having no solution, we need to look at the coefficient of "x" in the equation (b - 2) and the constant term on the other side (8).
The equation is: (b - 2)x = 8
For the equation to have no solution, the coefficient of "x" (b - 2) must be 0. This is because when you multiply any number by 0, the result is always 0, meaning the left-hand side of the equation becomes 0x, which simplifies to 0. However, the right-hand side is 8, and 0 is never equal to 8.
Therefore, to make (b - 2) equal to 0, we can set:
b - 2 = 0
Adding 2 to both sides:
b = 2
So, the value of "b" that would result in the equation having no solution is A) 2.
To know more about equation"
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which pair of functions represents a decomposition of f(g(x)) = | 2(x + 1) ^2 + (x + 1) | ?
Answer:
|2x^2+5x+3|
Step-by-step explanation:
Answer: D
f(x) = | 2x2 + x | and g(x) = (x + 1)
Step-by-step explanation:
[tex] \frac{5 + n}{4} = - 1[/tex]
What is n?
Answer:
n= -9
Step-by-step explanation:
Answer:
-9
Step-by-step explanation:
5 + n
==== = -1
4
Multiply both sides by 4
5 + n = - 1 * 4
5 + n = - 4
Subtract 5 from both sides
5-5 + n = - 4 - 5
n = - 9
Congratulations on being able to use latex.
Point R is on line segment QS. Given RS=11 and QS=19, determine the length QR.
================================================
Explanation:
R is between Q and S and on segment QS, allowing us to say
QR + RS = QS
because of the segment addition postulate.
-------
Use substitution and solve for QR
QR + RS = QS
QR + 11 = 19
QR = 19 - 11 .... subtracting 11 from both sides
QR = 8
El Pirata Barba Plata ha llegado a la isla del Coral para buscar un tesoro. En el mapa pone que, desde la orilla, debe recorrer 37 hm a la pata coja hacia el centro de la isla, y después otros 85 dam dando volteretas en la misma dirección. ¿Cuántos metros recorrerá en total desde la orilla hasta el tesoro? Expresa el resultado también en kilómetros.
Answer:
4550m ; 4
Step-by-step explanation:
Recall
1 hectometre = 100m
1 decameter = 10m
Distance from shore to center of island = 37hm
Another 85 decameter toward stge se direction
Therefore total metres it will travel in other to get to the treasure :
37 hectometre + 85 decameter
(37 * 100)m + (85 * 10)m
3700m + 850m = 4550m
In kilometers :
1000 meters = 1 kilometers
4550 meters =
(4550 / 1000)meters
= 4.55km
Write in point-slope form an equation of the line that passes through the point (8, 9) with slope 7.
Answer:
y=7x-47Step-by-step explanation:
[tex](8,9)=(x1,y1) \\ m=7 \\ y−y1=m(x−x1) \\ y−9=7(x−8)
[/tex]
[tex]y - 9 = 7x - 56 \\ y = 7x - 56 + 9 \\ y = 7x - 47[/tex]
Which is the simplified form of r to the negative 7th power plus s to the negative twelve
Answer:
1/r^7 + 1/s^12
Step-by-step explanation:
Since there is a negative exponent, the term becomes a fraction. As we do not know the value of the term, it remains in its variable form with a positive exponent
I WILL GIVE BRAINLIEST TO THE BEST ANSWER!!!! I NEED HELP!!!!!
Answer:
D. Both functions are increasing but function g increases at a faster average rate
Step-by-step explanation:
Let's get the values of g(x) for each value of x
X= -2
g= -18(1/3)^-2 +2
g =-160
X= -1
g= -18(1/3)^-1 +2
g= -52
X= 0
g= -18(1/3)^0 +2
g= -16
X= 1
g= -18(1/3)^1 +2
g= -4
X= 2
g= -18(1/3)^2 +2
g= 0
Comparing the first and last values of both f and g we can see clearly that function g has a drastic change in it's rate.
Factor 4 out of 4x + 12.
Answer:
4(x + 3)
Step-by-step explanation:
So, to solve these questions is pretty simple.
4 times what equals 4x, and 4 times what equals 12?
Well,
4 times x = 4x, and 4 times 3 = 12.
soo.
4(x + 3)
Answer:
4x+12 factor 4 out of the equation
4(x+3)19) : -7x=5.6⇒ x=-5.6/-7
x=5.6/7=0.8x/8- 5/2=5/2 common factor
(x-20)/8 =5/2
2(x-20)=40
2x-40=40
2x=80
x=80/2=40The weights of ice cream cartons are normally distributed with a mean weight of ounces and a standard deviation of ounce. (a) What is the probability that a randomly selected carton has a weight greater than ounces? (b) A sample of cartons is randomly selected. What is the probability that their mean weight is greater than ounces? (a) The probability is nothing. (Round to four decimal places as needed.) (b) The probability is nothing. (Round to four decimal places as needed.)
Answer:
The answer is below
Step-by-step explanation:
The weights of ice cream cartons produced by a manufacturer are normally distributed with a mean weight of 10 ounces and a standard deviation of 0.5 ounce. (a) What is the probability that a randomly selected carton has a weight greater than 10.21 ounces? (b) You randomly select 25 cartons. What is the probability that their mean weight is greater than 10.21 ounces
Answer:
Given that:
Mean (μ) = 10 ounces, standard deviation (σ) = 0.5 ounces.
The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score (z) is given by:
[tex]z=\frac{x-\mu}{\sigma} \\\\For\ a\ sample\ size(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }[/tex]
a) For x = 10.21:
[tex]z=\frac{x-\mu}{\sigma}\\\\z=\frac{10.21-10}{0.5}=0.42[/tex]
From the normal distribution table, probability that a randomly selected carton has a weight greater than 10.21 ounces = P(x > 10.21) = P(z > 0.42) = 1 - P(z < 0.42) = 1 - 0.6628 = 0.3372
b ) For x = 10.21 and n = 25
[tex]\sqrt{x} \sqrt{x} z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\z=\frac{10.21-10}{0.5/\sqrt{25 } }=2.1[/tex]
From the normal distribution table, probability that a randomly selected carton has a weight greater than 10.21 ounces = P(x > 10.21) = P(z > 2.1) = 1 - P(z < 2.1) = 1 - 0.9826 = 0.0174
Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distance (in meters). Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters. A. 15 m B. 130−−−√ m C. 178−−−√ m D. 13 m
Answer:
C. 178−−−√ m
Step-by-step explanation:
Given the following :
v = final velocity (in m/s)
u = initial velocity (in m/s)
a = acceleration (in m/s²)
s = distance (in meters).
Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters
Using the 3rd equation of motion :
v^2 = u^2 + 2as
v^2 = 8^2 + 2(3)(19)
v^2 = 64 + 114
v^2 = 178
Take the square root of both sides :
√v^2 = √178
v = √178
slope of (-2,2) and (3,4)
Answer:
2/5
Step-by-step explanation:
Good luck!
find the perimeter of a square of length of 5cm
Answer:
20cm
Step-by-step explanation:
If each side of the square = 5 cm, 5 cm times 4 sides = 20 cm.
Answer:
P=20cm
Step-by-step explanation:
To find the perimeter of a square, you just add all the four sides.
Because it says the sides are 5cm, and squares always have the same length, you just:
5+5+5+6=20cm
So, the perimeter of this square is 20cm.
Hope this helps, and have a nice day:)
the price of sugar increase from shs 1000 to shs 1200.In what percentage did the price increase
Answer:
20%
Step-by-step explanation:
1000×120%=1200
120-100=20
1. Find the greatest common divisor of the term 144x3y2and 81xy4
Answer:
[tex]1296x^3y^4[/tex]
Step-by-step explanation:
Given the terms:
[tex]144x^3y^2[/tex]
and [tex]81xy^4[/tex]
To find:
Greatest Common Divisor of the two terms or Least Common Multiple (LCM) of two numbers = ?
Solution:
First of all, let us find the HCF (Highest Common Factor) for both the terms.
i.e. the terms which are common to both.
Let us factorize them.
[tex]144x^3y^2 = \underline{3 \times 3} \times 16\times \underline x \times x^{2}\times \underline{y^{2} }[/tex]
[tex]81xy^4= \underline {3\times 3}\times 9 \times \underline{x} \times \underline{y^2}\times y^2[/tex]
Common terms are underlined.
So, HCF of the terms = [tex]9xy^2[/tex]
Now, we know the property that product of two numbers is equal to the product of the numbers themselves.
HCF [tex]\times[/tex] LCM = [tex]144x^3y^2[/tex] [tex]\times[/tex] [tex]81xy^4[/tex]
[tex]LCM = \dfrac{144x^3y^2 \times 81xy^4}{9xy^2}\\\Rightarrow LCM = 144x^3y^2 \times 9x^{1-1}y^{4-2}\\\Rightarrow LCM = 144x^3y^2 \times 9x^{0}y^{2}\\\Rightarrow LCM = \bold{1296x^3y^4 }[/tex]
