What is 32 divided by the opposite of 4

Answers

Answer 1

Answer: -8

Since we are dividing the OPPOSITE of 4 then we are dividing 32÷-4

When multiplying or dividing a POSITIVE to a NEGATIVE you get a NEGATIVE

P/N=N

N/N=P

P*P=P

P=Positive

N=Negative

Divide

32/-4=-8

So your answer is -8

Answer 2

When 32 is divided by opposite of 4 the obtained result is - 8.

What is additive inverse ?

Additive inverse of a number is such a number when the original number and it's additive inverse is added we get zero.

4 + ( - 4 ) = 0.So the additive inverse of 4 is - 4.

According to the given question we have to obtain the result when 32 is divided by opposite of 4.

Here opposite of 4 means additive inverse of 4 which is -4.

∴ 32/-4

= - 8.

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Related Questions

The double number line shows how many meters a dragonfly can fly in 1 second.

Answers

Answer: It's B

Step-by-step explanation:

The table that represents the double number line is (b)

How to determine the table of the number line?

On the double number line, we have the following points

x: 0    1

y: 0    25

This means that as x increases by 1, y increases by 25.

So, we have:

x: 0  1    2    3   4

y: 0 25  50 75 100

The above is represented by the second table

Hence, the table that represents the double number line is (b)

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Enter an expression that is equivalent to (6x2−1)+(x2+3)−2(x2−5)−15x2, combining all like terms. Use the on-screen keyboard to type the correct polynomial in the box below.

Answers

Answer:

Its 10x^2+12

Step-by-step explanation:

Answer:

-10X^2+12

Step-by-step explanation:

Identify the slope and y-intercept of the function y = –2x+1.

Answers

Answer:

Below

Step-by-step explanation:

The function is y= -2x +1

● the slope is -2

● the y-intercept is 1

Candice spent 5 1/4 hours doing her homework. Her brother, Ronald, spent 1/2 that number of hours doing his homework. How many hours did Ronald spend on his homework?

Answers

Answer:

Step-by-step explanation:

½ of 5¼

½×(21/4)

=21/8

=2⅝ hours

Answer:

2 5/8

Step-by-step explanation:

you would divide 5 1/4 by 2 :

5 divided by 2 =2 1/2

1/4 divided by 2=1/8

then make the numbers have the same denomanator

1/2, 2/4, 4/8

1/8,

then you add

2 4/8+1/8=2 5/8

What is the distance between the two endpoints in the graph below? If necessary, round your answer to two decimal places.



A.
16.45 units

B.
13 units

C.
15.81 units

D.
22 units

Answers

Answer:

C. [tex] d = 15.81 units [/tex]

Step-by-step explanation:

Given:

2 end points on a graph => (5, 6) and (-4, -7)

Required:

Distance between them

SOLUTION:

Distance between two points in a graph can be calculated using [tex] distance (d) = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Where,

[tex] (-4, -7) = (x_1, y_1) [/tex]

[tex] (5, 6) = (x_2, y_2) [/tex]

Plug in the values into the formula and solve

[tex] d = \sqrt{(5 - (-4))^2 + (6 - (-7))^2} [/tex]

[tex] d = \sqrt{(5 + 4))^2 + (6 + 7))^2} [/tex]

[tex] d = \sqrt{(9)^2 + (13)^2} [/tex]

[tex] d = \sqrt{81 + 169} [/tex]

[tex] d = \sqrt{250} [/tex]

[tex] d = 15.81 units [/tex]

Answer:

15.81

Step-by-step explanation:

A piece of buttered toast falls to the floor 17 times. The toast landed buttered side up 6 times. What is the probability that the toast lands buttered side down?

Answers

Step-by-step explanation:

Given that,

A piece of buttered toast falls to the floor 17 times. The toast landed buttered side up 6 times.

It means that the total number of outcomes are 17

We need to find the probability that the toast lands buttered side down. Favourable oucome is 17-6 = 11

So, probability is given by :

[tex]P(E)=\dfrac{\text{favourable outcomes}}{\text{total no of outcomes}}[/tex]

[tex]P(E)=\dfrac{11}{17}[/tex]

So, the  probability that the toast lands buttered side down is 11/17.

the rainfall R(t) (inmm) over the course of a year in bali, indonesia as a function of time t(in days) can be modeled by a sinusoidal expression of the form a*sin(b*t)+d. At t=0, in mid april, the expected daily rainfall is 2.3mm, which is the daily average value throughout the year. 1 quarter of the year leter, at t=91.25, when the rainfall is at its minimum, the expected daily value is 1.4mm. find R(t).

Answers

[tex]\bold{\text{Answer:}\quad R(t)=-0.96\sin\bigg(\dfrac{\pi}{182.5}t}\bigg)+2.3}[/tex]

Step-by-step explanation:

The equation of a sin function is: y = A sin (Bx - C) + D     where

Amplitude (A) is the distance from the midline to the max (or min)Period (P) = 2π/B   -->   B = 2π/PC/B is the phase shift (not used for this problem)D is the vertical shift (aka midline)

D = 2.3

It is given that t = 0 is located at 2.30.  The sin graph usually starts at 0 so the graph has shifted up 2.3 units.  --> D = 2.3

A = -0.96

The amplitude is the difference between the maximum (or minimum) and the centerline.  A = 2.30 - 1.44 = 0.96

The minimum is given as the next point. Since the graph usually has the next point as its maximum, this is a reflection so the equation will start with a negative. A = -0.96

B = π/182.5

It is given that [tex]\frac{1}{4}[/tex] Period = 91.25  --> P = 365

B = 2π/P

  = 2π/365

  = π/182.5

C = 0

No phase shift is given so C = 0

Input A, B, C, & D into the equation of a sin function:

[tex]R(t)=-0.96\sin\bigg(\dfrac{\pi}{182.5}t-0}\bigg)+2.3[/tex]

Take your time! :) Not important, but I would like to know, I'm writing flashcards so I can remember when I start back in school. Can you explain how to get the LCM of two numbers,GCF of two numbers, and what's the difference?

Answers

Answer:

The LCM of two numbers is the least common multiple. You want to find the least possible number that is divisible by the two numbers. So, you can list the factors of the two numbers. If there are factors that are repeated, put the repeated factors to the side. With the remaining factors, multiply the factors by each other and the repeated factors.

For example, let's try to find the least common multiple between 10 and 15.

Factors of 10: 2 * 5

Factors of 15: 3 * 5

The repeated factor is 5.

2 and 3 are left over. 2 * 3 = 6. 6 * 5 = 30. So, that is the least common multiple.

The GCF of two numbers is the greatest common factor. You want to find the greatest factor that is included in both numbers. So, again, you can list the factors of the two numbers and find the greatest factor that is repeated between the two numbers.

For example, let's try to find the greatest common factor between 30 and 45.

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 45: 1, 3, 5, 9, 15, 45

Between the two numbers, shared factors are 1, 3, 5, and 15. So, the greatest common factor is 15.

Hope this helps!

What is the minimum sample size required to estimate a population mean with 90% confidence when the desired margin of error is 1.25

Answers

Complete Question

What is the minimum sample size required to estimate a population mean with 90% confidence when the desired margin of error is 1.25? The standard deviation in a pre-selected sample is  7.5

Answer:

The minimum sample size is  [tex]n =97[/tex]

Step-by-step explanation:

From the question  we are told that

 The margin of error is  [tex]E = 1.25[/tex]

   The  standard deviation is  [tex]s = 7.5[/tex]

Given that the confidence level is  90% then the level of significance is mathematically represented as

             [tex]\alpha = 100 - 90[/tex]  

             [tex]\alpha =10\%[/tex]  

             [tex]\alpha =0.10[/tex]

Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table  

    The value is  [tex]Z_{\frac{ \alpha }{2} } = 1.645[/tex]

   The  minimum sample size is mathematically evaluated as

         [tex]n = \frac{Z_{\frac{\alpha }{2} * s^2 }}{E^2 }[/tex]

=>        [tex]n = \frac{1.645^2 * 7.5^2 }{1.25^2 }[/tex]

=>        [tex]n =97[/tex]

In the nation of Gondor, the EPA requires that half the new cars sold will meet a certain particulate emission standard a year later. A sample of 64 one-year-old cars revealed that only 24 met the particulate emission standard. The test statistic to see whether the proportion is below the requirement is

Answers

Complete Question

In the nation of Gondor, the EPA requires that half the new cars sold will meet a certain particulate emission standard a year later. A sample of 64 one-year-old cars revealed that only 24 met the particulate emission standard. The test statistic to see whether the proportion is below the requirement is:

A -1.645

B -2.066

C -2.000

D-1.960

Answer:

The  correct option is C

Step-by-step explanation:

From the question we are told that

   The  population mean is  [tex]p = 0.50[/tex]

    The sample size is  [tex]n = 64[/tex]

     The  number that met the standard is  [tex]k = 24[/tex]

       

Generally the sample proportion is mathematically evaluated   as

             [tex]\r p = \frac{24}{64}[/tex]

             [tex]\r p =0.375[/tex]

Generally the standard error is mathematically evaluated as  

       [tex]SE = \sqrt{ \frac{p(1- p )}{n} }[/tex]

=>    [tex]SE = \sqrt{ \frac{0.5 (1- 0.5 )}{64} }[/tex]

=>   [tex]SE = 0.06525[/tex]

The  test statistics is evaluated as

        [tex]t = \frac{ \r p - p }{SE}[/tex]

        [tex]t = \frac{ 0.375 - 0.5 }{0.0625}[/tex]

        [tex]t = -2[/tex]

There are four blue marbles, an unknown number of red (r) marbles, and six yellow marbles in a bag. Which expression represents the probability of randomly selecting a blue marble, replacing it, and then randomly selecting a red marble? StartFraction 4 over 10 EndFraction (StartFraction r over 10 EndFraction) StartFraction 4 over 10 r EndFraction (StartFraction 4 over 10 r EndFraction) StartFraction 4 over 10 + r EndFraction (StartFraction r over 10 + r EndFraction) StartFraction 4 over 10 r EndFraction (StartFraction r over 10 r EndFraction)

Answers

Answer:

4/ (10+r) * r/ (10+r)

Step-by-step explanation:

four blue marbles, an unknown number of red (r) marbles, and six yellow marbles in a bag = 4+r+6 = 10+r marbles

P( blue) = blue marbles / total marbles

             = 4/ (10+r)

Then replace

P( r) = red marbles / total marbles

             = r/ (10+r)

P( blue replace ,red) =P ( blue ) * P(red)

                                    =  4/ (10+r) * r/ (10+r)

                                    = 4r / ( 10+r) ^2

Answer:

C. 4/10+r (r/10+r)

Step-by-step explanation:

EDG20

Please answer this correctly without making mistakes

Answers

Answer:

5/12

Step-by-step explanation:

3/4-1/3=

9/12-4/12=

5/12

determine the results of the following operations​

Answers

Answer:

[tex]\sqrt[3]{4}\times (\sqrt[3]{16}-10 )[/tex]

Step-by-step explanation:

Let be [tex]\sqrt[3]{64}-\sqrt[3]{32} \times \sqrt[3]{125}[/tex], this expression is simplified as follows:

1) [tex]\sqrt[3]{64}-\sqrt[3]{32} \times \sqrt[3]{125}[/tex] Given

2) [tex]\sqrt[3]{4^{3}}-\sqrt[3]{2^{5}}\times \sqrt[3]{5^{3}}[/tex] Definition of power

3) [tex](4^{3})^{1/3}-(2^{2}\cdot 2^{3})^{1/3}\times (5^{3})^{1/3}[/tex] Definition of n-th root/[tex]a^{b+c}= a^{b}\cdot a^{c}[/tex]/[tex](a^{b})^{c} = a^{b\cdot c}[/tex]

4) [tex]4 - (2^{2})^{1/3}\times 2\times 5[/tex] [tex]a^{b+c}= a^{b}\cdot a^{c}[/tex]/[tex](a\cdot b)^{c} = a^{c}\cdot b^{c}[/tex]

5) [tex]4 - 10\times 4^{1/3}[/tex] Multiplication/Definition of power

6) [tex]4^{1/3}\cdot (4^{2/3}-10)[/tex] Distributive property/[tex]a^{b+c}= a^{b}\cdot a^{c}[/tex]

7) [tex]\sqrt[3]{4}\times [(4^{2})^{1/3}-10][/tex] [tex](a^{b})^{c} = a^{b\cdot c}[/tex]/Definition of n-th root

8) [tex]\sqrt[3]{4}\times (\sqrt[3]{16}-10 )[/tex] Definition of power/Result

I
Ifm DGF = 72, what equation can you use to find mZEGF?

Answers

Answer:

see explanation

Step-by-step explanation:

∠ DGE + ∠ EGF = ∠ DGF , that is

∠ EGF = ∠ DGF - ∠ DGE

∠ EGF = 72° - ∠ DGE

A box is 90 cm long. Which of these is closest to the length of this box in feet?{1 inch= 2.54cm} (1 point)

Answers

Answer:

2.952755906 ft

Step-by-step explanation:

We need to convert 90 cm to inches

90 cm * 1 inch / 2.54 cm =35.43307087 inches

Now convert inches to ft

12 inches = 1ft

35.43307087 inches * 1 ft/ 12 inches =2.952755906 ft

Simplify 6.92 to the exponent of 1000

Answers

Answer:

Whatever is raised to the power of 0 is 1

SO the answer is 1

Algebraic Expressions
Evaluate
The weight of a bag of oranges is 1.3 pounds. There are 9 bags of oranges. What is the total weight?
Help please :)​

Answers

Answer:

11.7 pounds

Step-by-step explanation:

Multiply the weight of one bag of oranges by 9 bags.

On a map, two locations are 0.75 centimeter apart. Their actual distance is 15 kilometers apart. What scale could be
shown on the map? Select three options.

Answers

Answer:

20

Step-by-step explanation:

It is 20 because 0.75 is on the map and its actualy distance is 15 so 15/0.75 is 20

Prove that if a and b are integers, then for any integer k one has (a,b) = (a + kb,b). (Hint: Show that they are mutually divisible.)

Answers

Answer:

The operation:

(a,b) is equal to the rest of the division of a by b.

Now, if we have:

(a + kb,b) = (a,b) + (k*b,b)

But if we have that k and b are integers, then:

(k*b)/b = k

So b divides k*b into a whole number, this means that (k*b,b) = 0

then:

(a + kb,b) = (a,b) + (k*b,b) = (a,b) + 0 = (a,b)

What is the solution (x, y) to this system of linear equations? 2x – 3y = –6 x + 2y = 11

Answers

Answer:

x = 3, y = 4

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

2x +6x = 3y + 2y = 11
8x = 5y= 11

8x= 11
X= 11/8 or 1.375

5y= 11
Y= 11/5 or 2.2


Maybe ^ haven’t done these in a while.

The MCAT is the admission exam that medical schools use as one of the criteria for accepting students. The exam is based on a scale of 0-45. The following data shows the MCAT scores for nine students.

32 36 29 31 30 35 34 26 30

The 35th percentile of this data set is:________

a. 31
b. 32
c. 31.5
d. 30

Answers

Answer:

d. 30

Step-by-step explanation:

The computation of the 35th percentile of this data set is shown below:

Before that first we have to series the number in ascending number

S. No          Numbers

1                       26

2                      29

3                      30

4                      30

5                      31

6                      32

7                      34

8                      35

9                       36

Now use the formula

Here n = 9

Percentile = 100

[tex]= \frac{35(9 + 1)}{100} \\\\[/tex]

= 3.5th

= 3th + 0.5 (4th - 3th)

= 3th + 0.5 (30 - 30)

= 3th + 0

= 30

Prove that for all integers m and n, m - n is even if, and only if, both m and n are even or both m and n are odd.

Answers

Answer:

Below

Step-by-step explanation:

Suppose that m and n are both even numbers.

So we can express them as the product of 2 and another number.

● n = 2×a

● m = 2×b

● m-n = 2b-2a

● m-n = 2(b-a)

m-n is an even number since it is divisible by 2.

■■■■■■■■■■■■■■■■■■■■■■■■■■

Suppose that both n and m are odd numbers.

● n = 2a+1

● m = 2b+1

● m-n = 2b+1-(2a+1)

● m-n = 2b+1-2a-1

● m-n = 2b-2a

● m-n = 2(b-a)

So m-n is even since it is divisible by 2.

■■■■■■■■■■■■■■■■■■■■■■■■■■

Suppose that m is odd and n is even ir vice versa

● n = 2a or n= 2a+1

● m = 2b+1 or m = 2b

● m-n = 2b+1-2a or m-n = 2b-2a-1

● m-n = 2(b-a) +1 or m-n = 2(b-a)-1

In both cases m-n isn't even.

■■■■■■■■■■■■■■■■■■■■■■■■■■

So m-n is even if and only if m and n are odd or m and are even

Answer:

Case 1

both m and n are even

Therefore m/2 and n/2 are integers

Then,

m-n

=2(m/2 - n/2)

Since m/2 and n/2 are integers

Then m/2 - n/2 will be an integer

Therefore,

m-n = 2(Z)

Where Z is an integer

Since 2 is a factor of m-n

Therefore m -n is even

Case 2

Both m and n are odd

m-n

= 2(½m - ½n)

When an odd number is divided by 2 it gives an integer and a remainder of 1

Therefore

½m = Y + ½

And

½n = Z + ½

Where Y and Z are integers

Then

m-n = 2(Y+½-Z-½)

= 2(Y-Z)

Y-Z will also be an integer

m-n= 2A

Therefore m-n is even

Case 3

One is odd and the other even

m-n = 2(m/2 - n/2)

Assume m is even and n is odd

From the discussions above

m-n = 2(Y - Z - ½)

m-n = 2(A - ½)

Hence m-n is not even because when is divided by two it doesn't give an integer.

Therefore for all integers m and n, m - n is even if, and only if, both m and n are even or both m and n are odd.

Find the solution of the inequality 5 > r - 3.
A) r<2
B) r = 2
C) r=8
(D) r < 8​

Answers

Answer:

[tex]\huge\boxed{r<8}[/tex]

Step-by-step explanation:

[tex]5 > r - 3[/tex]

Adding 3 to both sides

[tex]5 + 3 > r[/tex]

[tex]8 > r\\OR \\r < 8[/tex]

Answer: D. r<8

Step-by-step explanation:

[tex]5>r-3[/tex]

add 3 to both sides

[tex]r-3+3<5+3[/tex]

[tex]5+3=8[/tex]

simplify

[tex]r<8[/tex]

The formula for the area of a square is s2, where s is the side length of the square. What is the area of a square with a side length of 6 centimeters? Do not include units in your answer.

Answers

Answer:

36

step by step

given length=6

so area of square is given by s2 i.e 6^2

=6×6

=36 (Ans)

(a) Five friends are in a netball squad. In each game during the 21-round season, at least 3 of them are picked in the team. Prove that there will be at least 3 matches in which the same three friends are selected to play.
(b) How does the answer change if there are six friends instead of 5?
PLS ANSWER FAST!!!!

Answers

Answer:

  (a) there are 10 sets of 3 friends, so in 21 games, at least one set must show 3 times

  (b) there are 20 sets of 3 friends, so  in 21 games, at least one set must show 2 times.

Step-by-step explanation:

(a) The number of combinations of 5 things taken 3 at a time is ...

  5C3 = 5!/(3!·2!) = 5·4/2 = 10

There can be 10 games in which the same 3 friends do not show up. There can be 10 more games such that the same 3 friends show up exactly twice. In the 21st game, some set of 3 friends must show up 3 times.

__

(b) The number of combinations of 6 things taken 3 at a time is ...

  6C3 = 6!/(3!·3!) = 6·5·4/(3·2) = 20

Hence, there can be 20 games in which the same 3 friends do not show up. In the 21st game, some set of 3 friends will show up a second time.

Write 11 numbers in a row so that the sum of any 3 consecutive numbers is negative, while the sum of all the numbers is positive.

Answers

Answer:

Step-by-step explanation:

Hello, if I take the following

2, 2, -5, 2, 2, -5, 2, 2, -5, 2, 2

The sum is 8*2-5*3=16-15=1 > 0

and

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

-5 + 2 + 2 < 0

2 + 2 -5 < 0

2 - 5 + 2 < 0

Hope this helps.

Do not hesitate if you need further explanation.

Thank you


An apartment building is infested with 6.2 X 10 ratsOn average, each of these rats
produces 5.5 X 10' offspring each year. Assuming no rats leave or die, how many additional
rats will live in this building one year from now? Write your answer in standard form.

Answers

Answer: 3.41x10^3

Step-by-step explanation:

At the beginning of the year, we have:

R = 6.2x10 rats.

And we know that, in one year, each rat produces:

O = 5.5x10 offsprins.

Then each one of the 6.2x10 initial rats will produce 5.5x10 offsprings in one year, then after one year we have a total of:

(6.2x10)*(5.5x10) = (6.2*5.5)x(10*10) = 34.1x10^2

and we can write:

34.1 = 3.41x10

then: 34.1x10^2 = 3.41x10^3

So after one year, the average number of rats is:  3.41x10^3

10/7p+13/8+15/2p=909/56 i NEED THiS solving multi step equations w fractions and #8 PLEASE

Answers

Answer:

P= 2

Step-by-step explanation:

10/7p+13/8+15/2p=-909/56

Combine like terms

10/7p+15/2p=-909/56-13/8

20p+105p/14=-909-13*7/56

125/14p=-909-91/56

125/14p= -1000/56

125/14p*14/125= -1000/56*14/125

simplify

P= 8/4=2

And for #8 n =1 I answered this question it

Search

Evaluate the integral using integration by parts with the indicated choices of u and dv. (Use C for the constant of integration.) ∫4x2 lnx dx ; u= lnx , dv=4x 2dx

Answers

Take

[tex]u=\ln x\implies\mathrm du=\dfrac{\mathrm dx}x[/tex]

[tex]\mathrm dv=4x^2\,\mathrm dx\implies v=\dfrac43x^3[/tex]

Then

[tex]\displaystyle\int4x^2\ln x\,\mathrm dx=\frac43x^3\ln x-\frac43\int x^2\,\mathrm dx=\frac43x^3\ln x-\frac49x^3+C[/tex]

[tex]=\boxed{\dfrac49x^3(3\ln x-1)+C}[/tex]

The required integration is,

∫4x² lnx dx = (lnx) [(4/3)x³ + C₁] - (4/9)x³ + C

The given integral is,

∫4x² lnx dx

Using integration by parts, choose u and dv.

In this case, we choose u = lnx and dv = 4x²dx.

Using the formula for integration by parts, we have:

∫ u dv = uv - ∫ v du

Substituting the values of u and dv, we get:

∫4x² lnx dx = (lnx) (∫ 4x² dx) - ∫ [(d/dx)lnx] (∫4x² dx) dx

Simplifying the first term using the power rule of integration, we get:

∫ 4x² dx = (4/3)x³ + C₁

For the second term, we need to evaluate (d/dx)lnx,

Which is simply 1/x. Substituting this value, we get:

∫ [(d/dx)lnx] (∫4x² dx) dx = ∫ [(1/x) ((4/3)x³ + C₁)] dx

Simplifying this expression, we get:

∫4x² lnx dx = (lnx) [(4/3)x³ + C₁] - ∫ [(4/3)x³/x] dx

Using the power rule of integration again, we get:

∫4x² lnx dx = (lnx) [(4/3)x³ + C₁] - (4/9)x³ + C

Where C is the constant of integration.

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simplify -3(2g - 6) +4g

Answers

-3-2g+6+4g

3+2g

hope it helps

Answer:

-2g + 18

Step-by-step explanation:

-3(2g - 6) + 4g

First we use distributive property.

-3 × 2g = -6g

-3 × -6 = 18

now we have

-6g + 18 + 4g

Now we combine the like terms

-6g + 4g = -2g

Finally we have

-2g + 18

and they are not like terms so we leave them and the equation is solved.

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