what is -4 as a fraction

Answer:

240 inches cubed

Step-by-step explanation:

Volume equals length times width times height. Imagine the net is folded into its shape. The product of the base, 6 x 10 = 60, and the height, 4, equals 240. Remember that each square accounts for two inches. Hope this helps.

Answer:

Width: 4

Length: 6

Step-by-step explanation:

We can create a systems of equations for this problem, assuming W is width and L is length.

W = 3L-14

WL = 24

We can substitute W into the equation.

(3L-14)L = 24

3L²-14L = 24

3L² - 14L - 24 = 0

(3L+4)(L-6)=0

L = 6

Now we can find W by substituting L into the equation.

[tex]6\cdotw=24\\w = 4[/tex]

Hope this helped!

Answer:

140°

Step-by-step explanation:

The circle has a central angle of 80. This means that the arc it intercepts is also 80°. Therefore, the rest of the circle not intercepted by the arc is 360-80=280°

Remember that inscribed angles have one-half of the arc-length it intercepts. We can see that Angle C intercepts the entire circle except for the arc intercepted by Angle O. Therefore, the arc intercepted by Angle C is 280°. This means that Angle C is the half of 280, or 140°.

Answer:

The correct option is;

Left object volume = right object volume

Step-by-step explanation:

The shapes given in the question are two circular cones that have equal base radius and equal height

The formula for the volume, V of a circular cone = 1/3 × Base area × Height

The base area of the two shapes are for the left A = π·r², for the right A = π·r²

The heights are the same, therefore, the volume are;

For the left

[tex]V_{left}[/tex] = 1/3×π·r²×h

For the right

[tex]V_{right}[/tex] = 1/3×π·r²×h

Which shows that

1/3×π·r²×h  = 1/3×π·r²×h and [tex]V_{left}[/tex]  = [tex]V_{right}[/tex], therefore, the volumes are equal and the correct option is left object volume = right object volume.

Answer:

h(x + 1) = (x+3)(x-1)

Step-by-step explanation:

Simply plug the value of x+1 into the equation for x.

h(x) = x^2 - 4

h(x + 1) = (x + 1)^2 - 4

h(x + 1) = x^2 + 2x + 1 - 4

h(x + 1) = x^2 + 2x - 3

h(x + 1) = (x+3)(x-1)

Cheers.

Answer:

h(t)= t² - 2t -3

Step-by-step explanation:

h(x+1)= x²-4 is the given function

We can write it x²-4 as:

Substituting x+1  with  t. Then function is:

or

Answer: The two choices with the square root of 2 will have irrational answers

Step-by-step explanation: By definition:

As long As you have normal fractions, you have rational numbers.

Square roots of "perfect squares" 4, 9, 16, 25, etc. can be rational numbers. The square roots of anything else and pi will be irrational.

Answer:

y > 9

Step-by-step explanation:

The range of a function is the interval of all possible y-values that make the function true.

Here, one way to figure this out is to look at a graph of the function (see attachment).

From the graph, we can see that y-values approach very closely the value 9 and then the line rises beyond 9 forever. Thus, we can conclude that the range for f(x) is y > 9.

~ an aesthetics lover

Answer:

69

Step-by-step explanation:

On a graph, points are grouped closely together to form a line and decrease.

====================================

Explanation:

Negative association is where the points decrease as you move from left to right. In other words, you move downhill as you move from left to right. There could be random upward bumps here and there, but overall the general trend is down.

Linear association is when the points are close to the same straight line, known as the regression line.

When points have strong negative linear association, we combine the two ideas mentioned above. The points are close to the same straight line and this line has a negative slope. The correlation coefficient r is close to r = -1.

Choice C is a close answer, but choice D is the better answer due to the "to form a line". If all points are on the same straight line, then r = -1 exactly and we have the strongest possible negative correlation.

The strongest negative linear association is depicted by the graph where points are grouped closely together to form a line and decrease.

Therefore, a graph with closely grouped points which forms a line and decreases infers a strong negative linear association.

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Answer:

[tex]\huge\boxed{Perimeter = 34\ units}[/tex]

Step-by-step explanation:

DE = 10 units

GF = 10 units

DG = 7 units

EF = 7 units

Perimeter of rectangle = Sum of all sides

P = DE + GF + DG + EF

P = 10 + 10 + 7 + 7

Perimeter = 34 units

Answer:

D) 34 units

Step-by-step explanation:

Coordinates:

D: (-5,4)

E: (5,4)

F: (5, -3)

G: (-5,-3)

Distance between points D and E = Distance between points F and G = 10

Distance between points E and F = Distance between points G and D = 7

Formula for perimeter of your rectangle:

2(x) + 2(y) =

2(10) + 2(7) =

20 + 14 = 34 units

That's your answer!

Hope that helps and maybe earns a brainliest!

Have a terrific day! >   <

                                   U

Answer:

x = a + 8

Step-by-step explanation:

x = The number that is 40% more than five more than a number a.

x = 40% more than 5 (plus a)

5 * 0.6 = 3

5+3 = 8

x = a + 8

Answer:  see proof below

Step-by-step explanation:

You will need the following identities to prove this:

[tex]\tan\ (\alpha-\beta)=\dfrac{\tan \alpha-\tan \beta}{1+\tan \alpha\cdot \tan \beta}[/tex]

[tex]\cos\ 2\alpha=\cos^2 \alpha-\sin^2\alpha[/tex]

LHS → RHS

[tex]\dfrac{2\tan\ (45^o-A)}{1+\tan^2\ (45^o-A)}\\\\\\=\dfrac{2\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)}{1+\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)}{1+\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{1+\bigg(\dfrac{1-2\tan\A+\tan^2 A}{1+2\tan A+\tan^2A}\bigg)}\\[/tex]

[tex]=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{(1+2\tan A+\tan^2A)+(1-2\tan A+\tan^2 A)}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{2+2\tan^2A}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{2\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}\\\\\\=\dfrac{\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}[/tex]

[tex]=\dfrac{1-\tan A}{1+\tan A}}\times \dfrac{(1+\tan A)^2}{1+\tan^2A}\\\\\\=\dfrac{1-\tan^2 A}{1+\tan^2 A}\\\\\\=\dfrac{1-\dfrac{\sin^2 A}{\cos^2 A}}{1+\dfrac{\sin^2 A}{\cos^2 A}}\\\\\\=\dfrac{\bigg(\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A}\bigg)}{\bigg(\dfrac{\cos^2 A+\sin^2 A}{\cos^2 A}\bigg)}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A+\sin^2 A}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{1}\\\\\\=\cos^2 A-\sin^2 A\\\\\\=\cos 2A[/tex]

cos 2A = cos 2A   [tex]\checkmark[/tex]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  [tex]\sqrt{x+7}-\sqrt{x^2+2x-15}[/tex]  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

Answer:

14 yards²

Step-by-step explanation:

To find the area of this complex shape, we can break it down into two parts.

I've broken it down into the left shape (with side lengths of 2, 2, 4 and 4) and the right shape (with side lengths of 2, 2, 2 and 3).

Looking at the shape on the left, the width is 4 yards and the length is 2 yards. Multiplying these numbers will get the area for that shape.

[tex]2\cdot4=8[/tex] yards².

Now in the right shape, the length is 3 and the width is 2, so:

[tex]3\cdot2=6[/tex] yards².

Now we can add both of these to get the total area of the figure.

[tex]6+8=14[/tex] yards².

Hope this helped!

Answer:

14 yds^2

Step-by-step explanation:

We can split this into two rectangles

There is a vertical rectangle on the left, 4 yds by 2 yds

The area is 4*2 = 8 yd^2

There is a horizontal rectangle on the right  3 yds by 2 yds

The area is 3*2 = 6 yd ^2

Add the areas together

8+6 = 14

The exponent 7 tells us how many copies of "8" are being multiplied together.

The expression 8*8*8 is equal to 8^3, while 8*8*8*8 = 8^4

Multiplying 8^3 and 8^4 will have us add the exponents to get 8^7. The base stays at 8 the entire time.

The rule is a^b*a^c = a^(b+c) where the base is 'a' the entire time.

Answer:

8^ 7

Step-by-step explanation:

(8*8*8) * (8*8*8*8)

There are 3 8's times 4 8's

8^3 * 8^4

We know that a^b * a^c = a^ (b+c)

8 ^ ( 3+4)

8^ 7

Answer:

[tex]\huge\boxed{B) x = 20}[/tex]

Step-by-step explanation:

50 * 5x = 5000

Dividing both sides by 50

=> 5x = 5000/50

=> 5x = 100

Dividing both sides by 5

=> x = 20

Answer:

the answer is B

Step-by-step explanation:

X: (x)50=20

Answer: The solution for the system is (2, -7)

Step-by-step explanation:

Ok, here we have linear relationships.

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

In this case, we have two lines:

ya, that passes through:

(-8, -5) and (-3, -6)

Then the slope is:

a = (-6 - (-5))/(-3 - (-8)) = (-6 + 5)/(-3 + 8) = -1/5

now, knowing one of the points like (-3, - 6) we can find the value of b.

y(x) = (-1/5)*x + b

y(-3) = -6 = (-1/5)*-3 + b

-6 = 3/5 + b

b = -6 - 3/5 = -33/5

then the first line is:

ya =  (-1/5)*x  -33/5

For the second line, we know that it passes through the points:

(-8, -15) and (-3, -11)

Then the slope is:

a = (-11 - (-15))/(-3 -(-8)) = (-11 + 15)/(-3 + 8) = 4/5

The our line is:

y(x) = (4/5)*x + b

and for b, we do the same as above, using one of the points, for example (-3, -11)

y(-3) = -11 = (4/5)*-3 + b

b = -11 + 12/5 = -(55 + 12)/5 = -43/5

then:

yb = (4/5)*x - 43/5.

Ok, our system of equations is:

ya = (-1/5)*x  -33/5

yb = (4/5)*x - 43/5.

To solve this, we suppose ya = yb

then:

(-1/5)*x + -33/5 = (4/5)*x - 43/5.

-33/5 + 43/5 = (4/5)*x + (1/5)*x

10/5 = 2 = (4/5 + 1/5)*x = x

2 = x

now we evaluate x = 2 in one of the lines:

ya = (-1/5)*2 -33/5 = -2/5 - 33/5 = -35/5 = -7

Then the lines intersect at the point (2, - 7), which is the solution for the system.

Answer: x^2 + (x+2)(x-2)

Step-by-step explanation:

The caret ^ before the 2 indicates that the 2 is an exponent. It means "x squared"

If the keyboard doesn't allow exponents the caret is the thing to use.

The expression for the square of Lara’s age and the product of ages of Lara’s best friends is x² + (x-2)(x+2)

The first thing to do is to calculate the square of Lara's age and this will be:

= x × x = x²

The product of the ages of Lara’s best friends will be (x-2)(x+2).

Therefore, the expression that can be used to calculate the square of Lara’s age and the product of ages of Lara’s best friends is x² + (x-2)(x+2)

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Explanation : If 66 is a factor of this unknown value, then 22 must be as well considering that 22 is a factor off 66. Let's say that this large value is 330. It is a multiple of 66, as 66 [tex]*[/tex] 5 = 330. At the same time 22 [tex]*[/tex] 15 = 330, so 330 is a multiple of 22 as well - or vice versa, 12 is a factor of 330.

We can also tell that 15, 22 fit into 330 through another approach. 22 [tex]*[/tex] 3 = 66, and 66 [tex]*[/tex] 5 = 330, so 5 [tex]*[/tex] 3 = 15 - the same value. This proves that 22 will always be a factor of a value that is the factor of 66.

18 + 4 ÷ 2 − 8

Following PEDMAS, divide first:

18 + 2 -8

Now add and subtract to get the final answer:

18+2 = 20

20-8 = 12

The answer is 12

Answer:

12

Step-by-step explanation:

Answer:

x=4      or    x= - 16

Step-by-step explanation:

|x+6|

Now subtract 7 which equals to 3.

|x+6|-7=3

|x+6|=10

Now remove the mode by adding plus minus sign in the front of 10.

x+6=±10

x+6=10 or x+6=-10

x=4      or x=-16

Answer:

5

12

0

range

Step-by-step explanation:

i just did it, these are the right answers.

Answer:

5,12,0, and the last answer is range

Step-by-step explanation:

Did it on Edge2021. Hope this helps!

Answer:

In 7, seven kids checked out 7. [tex]7*7=49[/tex] (Correct answer because 49 is the biggest number here)

In 1, only two kids checked out 1. [tex]1 *2=2[/tex] (Wrong answer because 2 is lower than 49)

In 4, only eight kids checked out 4. [tex]4*8=32[/tex] (Wrong answer because 32 is lower than 49)

In 12, only two kids checked out 12. [tex]12*2=24[/tex] (Wrong answer because 24 is lower than 49)

So 7 is the correct answer because [tex]7*7=49[/tex] is the greatest equation here.

The 0 and 11 number book is the typical book one student checked out.

Given, the dot plot shows the no. of book  each student checked out from the library last month.

Since each dot represent a different student, so clearly from the dot plot the 8 number book is checked out by the most of the students because it has most of the dots.

Since the number 0 and 11 has only one dot it represent that only 1 student checked out these books last month.

Hence the 0 and 11 number book is the typical book one student checked out.

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Answer:

Isn’t it just 8/26

Step-by-step explanation:

Since 1 is 1/26 so 8 is just 8/26?

The part of a year is 8 fortnights is ( 8 / 26 ).

Multiplication is the process of determining the product of two or more numbers in mathematics.

It is given that a fortnight is 1/26 of a year. The part of the year for 8 fortnights is calculated as:-

⇒ 8 x ( 1 / 26 )

⇒( 8 / 26 )

Therefore, the part of a year is 8 fortnights is ( 8 / 26 ).

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Answer:

1. EF = 65m

2. DF = 73m

Step-by-step explanation:

1. EF = height of the building = h = 33 / tan 27 = 65m

2. DF = sqrt (65² + 33²) = 73m

The building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.

From the triangle DEF, we find the value of EF by using tan function.

tan function is a ratio of opposite side and adjacent side.

tan(27)= 33/FE

0.5095 = 33/FE

Apply cross multiplication:

FE=33/0.5095

FE=64.76

Now DF is the hypotenuse, we find it by using pythagoras theorem.

DF²=DE²+EF²

DF²=33²+64.76²

DF²=1089+4193.85

DF²=5282.85

Take square root on both sides:

DF=72.68

In a triangle the the sum of three angles is 180 degrees.

∠D + 27 +90 =180

∠D + 117 =180

Subtract 117 from both sides:

∠D =63 degrees.

Hence, the building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.

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Answer:

the length of DB is 17 in

Step-by-step explanation:

Consider the sketch attached.

We will draw an imaginary line from point C to met line AB at point E.

A right-angled triangle will now be formed between points CBE.

The dimensions of the right-angled triangle will be:

CB = 10 in

CE= 8 in

EB = unknown

We will now proceed to find out the length of side EB using the Pythagoras' theorem.

[tex]EB =\sqrt{CB^2 -CE^2} \\EB =\sqrt{10^2 -8^2} \\EB = 6 in[/tex]

From the shape, we can find out that another right-angled triangle is made between points DAB.

The dimensions of the triangle are:

DA= 8in

AB = 9 in + 6 in = 15 in

DB = unknown.

We will now proceed to find out the length of side DB using the Pythagoras' theorem.

[tex]DB =\sqrt{AD^2 +AB^2} \\DB =\sqrt{8^2 +15^2} \\DB = 17 in[/tex]

Therefore, the length of DB is 17 in

Answer:

x = 180 - [(180 - 3x) + (180 - 2x)]

Step-by-step explanation:

Start off by finding the angles of the triangle

Angle F = 180 - 3x

The angle across from I (which I will call I) = 180 - 2x

Angle G = 180 - (F + I)

Now that we know what G is, we know what x is because the Alternate Exterior Angles Theorem states that if a pair of parallel lines are cut by a transversal, then the alternate exterior angles are congruent. So pretty much X = G

Therefore x =  180 - (F + I) or otherwise said as:

x = 180 - [(180 - 3x) + (180 - 2x)]

I hope this is helpful :)

Answer:

You cant get someone to do all of this try doing a few or getting help from someone older that's what I did

Explanation:

I asked help for one problem and the explanation and now I understand how they did it so the other problems I can do now

It's better to make an effort and try doing some of them instead of asking someone to do all of it

Because when the test comes it won't be that easy so next time just try putting a few so that way you can try understanding it and you can apply it to similar problems.

I hope you can find this some what help to you in the future. Also this is a suggestion from my experience so you don't have to do it I'm just trying to help out.

Answer: Tuesday, July 9 (correct me if I'm wrong)

Step-by-step explanation:

Jen goes every other day, so she goes every odd day.

Terry goes every third day, so Jen and Terry go together every six days.

Six days later is Sunday June 9, then Saturday June 15, then Friday Jun 21, then Thursday June 27, then Wednesday July 3.

Carlos only comes Mondays and Tuesday, so the next six days would be Tuesday July 9.

Answer:

d = √8

d ≈ 2.82843

Step-by-step explanation:

Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Simply plug in our coordinates into the distance formula:

[tex]d = \sqrt{(-3 + 5)^2+(-8 + 6)^2}[/tex]

[tex]d = \sqrt{(2)^2+(-2)^2}[/tex]

[tex]d = \sqrt{4+4}[/tex]

[tex]d = \sqrt{8}[/tex]

To find the decimal, simply evaluate the square root:

√8 = 2.82843

Answer:

Step-by-step explanation:

Let the points be A and B

A ( - 5 , - 6 ) ⇒ ( x₁ , y₁ )

B ( -3 , - 8 )⇒( x₂ , y₂ )

Now, let's find the distance between these two points:

AB = [tex] \mathsf{ \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }[/tex]

Plug the values

⇒[tex] \mathsf{ \sqrt{( - 3 - ( - 5) )^{2} + {( - 8 - ( - 6))}^{2} } }[/tex]

When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression

⇒[tex] \mathsf{ \sqrt{ {( - 3 + 5)}^{2} + {( - 8 + 6)}^{2} } }[/tex]

Calculate

⇒[tex] \mathsf{ \sqrt{ {(2)}^{2} + {( - 2)}^{2} } }[/tex]

Evaluate the power

⇒[tex] \mathsf{ \sqrt{4 + 4} }[/tex]

Add the numbers

⇒[tex] \mathsf{\sqrt{8} }[/tex]

Simplify the radical expression

⇒[tex] \mathsf{ \sqrt{2 \times 2 \times 2}} [/tex]

⇒[tex] \mathsf{2 \sqrt{2} }[/tex] units

Hope I helped!

Best regards!