Nucleus is present at the centre of atom. It contains protons and neutrons. It is very small as compared to the atom.
Answer:
It is a part of a cell which controls all the activities in the cells and contains the genetic information of the cell that is to be passed down to the next cell when it reproduces.
Explanation:
It is a part of a cell which controls all the activities in the cells and contains the genetic information of the cell that is to be passed down to the next cell when it reproduces.
A current of 5.29 A is passed through a Sn(NO3)2 solution for 1.30 h . How much tin is plated out of the solution?
Answer:
15.26 g of tin
Explanation:
Given that the equation of the process is;
Sn^2+(aq) + 2e ------> Sn(s)
Since 1e = 1F= 96500 C
but q =It
t is in hours so it must be converted to seconds, the SI unit of time
Hence;
119g of tin is deposited by 2 * 96500 C
xg of tin is deposited by 5.29 * 1.30 * 60 * 60
x = 119 * 5.29 * 1.30 * 60 * 60/ 2 * 96500
x = 2946106.8/193000
x= 15.26 g of tin
A current of 5.29 A is passed through a Sn(NO₃)₂ solution for 1.30 hour, the amount of tin plated is 15.26 grams.
How do we calculate mass?Mass of any deposited susbatnce that is obtained by the passing of current will be calculated by using the Faraday's Law as:
W = ECT/F, where
W = required mass of deposited tin
C = current = 5.29 A
T = time period = 1.30hr = 4,680sec
F = faradays constant = 96500C
E = equivalent mass
Equivalent mass will be calculated as:
E = molar mass/charge on atom = 119/2 = 59.5 g/equ
On putting all these values in the above equation, we get
W = (59.5)(5.29)(4680) / 96500
W = 15.26 g
Hence mass of tin is 15.26 g.
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A 25 cm sample of dilute sulfuric acid contains 0.025 moles of the acid.
What is the hydrogen ion concentration in the solution?
A. 0.2 mol/dm3
B. 0.05 mol/dm3
C. 1.00 mol/dm3
D. 2.00 mol/dm3
Answer:B. 0.05 mol/dm3
Explanation:
The hydrogen ion concentration in the solution is 2 mol/dm³
The correct answer to the question is Option D. 2 mol/dm³
We'll begin by calculating the molarity of the solution.
Volume = 25 cm³ = 25 / 1000 = 0.025 dm3
Mole of H₂SO₄ = 0.025 mol
Molarity of H₂SO₄ =?Molarity = mole / Volume
Molarity of H₂SO₄ = 0.025 / 0.025
Molarity of H₂SO₄ = 1 mol/dm³Finally, we shall determine the concentration of Hydrogen ion in the solution.H₂SO₄(aq) —> 2H⁺(aq) + SO₄²¯(aq)
From the balanced equation above,
1 mole of H₂SO₄ contains 2 moles of H⁺.
Therefore,
1 mol/dm³ H₂SO₄ will also contain 2 mol/dm³ H⁺.
Thus, the concentration of Hydrogen ion in the solution is 2 mol/dm³
The correct answer to the question is Option D. 2 mol/dm³
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