What is constant of a spring if there is 150 j when stretched 0.25 m?

Answers

Answer 1
0.45 This is the wrong answer

Related Questions

An air-filled capacitor stores a potential energy of 6.00 mJ due to its charge. It is accidentally filled with water in such a way as not to discharge its plates. How much energy does it continue to store after it is filled

Answers

This question is incomplete, the complete question is;

An air-filled capacitor stores a potential energy of 6.00 mJ due to its charge. It is accidentally filled with water in such a way as not to discharge its plates. How much energy does it continue to store after it is filled?

(The dielectric constant for water is 78 and for air it is 1.0006.)

Answer: it continue to store 0.07692 mJ after it was filled

Explanation:

Given that;

stored potential energy = 6.00 mJ = 0.006 J

dielectric constant for water K = 78

Energy stored  U = Q² / 2C = 0.006 J

C = ∈₀A/d { Air}

C = K∈₀A/d  { Water, k = 78 }

so

U = 0.006 / 78

U = 7.6723 × 10⁻⁵J

U = 0.07692 mJ

Therefore it continue to store 0.07692 mJ after it was filled

A Nov-Dec power bill shows that a home uses 1355 kwh over a 30-day period. Find the energy used (in kJ) for the 30-day period.

Answers

Answer:

The energy used for the 30-day period is 4878000 kilojoules.

Explanation:

According to the power bill, 1355 kilowatt-hours was used over a 30-day period. A kilowatt-hour is equal to 3600 kilojoules. Then, we calculate the energy used, measured in kilojoules, is determined by simple rule of three:

[tex]E = 1355\,kWh\times \frac{3600\,kJ}{1\,kWh}[/tex]

[tex]E = 4878000\,kJ[/tex]

The energy used for the 30-day period is 4878000 kilojoules.

What is the relationship between force and momentum?

A. A force will always increase momentum
B. A force acting for a certain time results in a change in momentum
C. There is no relationship
D. It depends on the kind of force​

Answers

Answer:

Explanation:

B

Choose all the answers that apply. Force has _____.
efficiency
direction
time
magnitude

Answers

Magnitude and Direction

3. Missy Diwater, the former platform diver for the Ringling Brother's Circus, had a kinetic energy of 12,000 ) just prior to hitting the bucket of water. If Missy's mass is 40 kg, then what is her speed?​

Answers

Answer:

v = 24.49[m/s]    

Explanation:

We must remember that kinetic energy can be calculated by means of a mathematical expression, which relates kinetic energy to mass and velocity

[tex]E_{kin}=\frac{1}{2}*m*v^{2} \\[/tex]

where:

Ekin = kinetic energy = 12000 [J]

m = mass = 40 [kg]

v = velocity [m/s]

[tex]12000=\frac{1}{2} *40*v^{2}\\24000=40*v^{2}\\600=v^{2}\\v=\sqrt{600}\\v=24.49[m/s][/tex]

If you want to delay a pulse of light in a laser experiment, you can send the light through a long coil of fiber optic cable. Light travels somewhat slower in the glass core of a fiber than it does in vacuum. We will approximate the speed of light in the fiber as 2.04 x 108 m/s. What length of fiber (in meters) should you use if you want to delay the arrival of light by 557 ns

Answers

Answer:

d = 113.6 m

Explanation:

For this exercise, the first thing we must notice is that the speed of the laser beam in the fiber is constant, so we can use the uniform motion relationships to find the necessary distance

          v = d / t

let's reduce to SI units

         t = 557 ns = 557 10⁻⁹ s

         d = v t

         d = 2.04 10⁸ 557 10⁻⁹

         d = 1.136 102 m

         d = 113.6 m

This is the distance of the fiber for the laser to arrive with the desired delay

True or False: Jumping off a diving board and into a pool is an example of a contact force.

Answers

Answer:

False

Explanation:

A contact force is any force that requires contact to occur. Contact forces are ubiquitous and are responsible for most visible interactions between macroscopic collections of matter. Pushing a car up a hill or kicking a ball across a room are some of the everyday examples where contact forces are at work. 

Answer:

false

Explanation:


Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3

Answers

Answer:

Ro = 8.65 [g/cm³]

Explanation:

We must remember that density is defined as the ratio of mass to volume.

[tex]Ro=m/V[/tex]

where:

m = mass = 0.450 [kg] = 450 [g]

V = volumen = 52 [cm³]

Ro = density [g/cm³]

Now replacing:

[tex]Ro = 450/52\\Ro = 8.65 [g/cm^{3} ][/tex]

A car with a mass of 2,000 kg travels at 20 m/s. Which one has the greatest impulse?

Answers

Answer:2000kg

Explanation:

Convert it

A 2kg object is tied to the end of a cord and whirled in a horizontal circle of radius 2 m. If the body makes three complete revolutions every second,

what is its linear speed?

And what is its centripetal acceleration?

Answers

Answer:

a) 37.70 m/s

b)710.6 m/s²

Explanation:

Given that ;

Mass of object = 2 kg

Radius of the motion = 2m

Frequency of motion = 3 rev/s

The formula to apply is;

v= 2πrf   where v is linear speed

v = 2×π×2×3 =12π = 37.70 m/s

Centripetal acceleration is given as;

a= 4×π²×r×f²  

a= 4×π²×2×3²

a=710.6 m/s²

As an object’s speed decreases, its kinetic energy (KE) ________.

As an object’s height increases, its gravitational potential energy (PEg) ________.

Answers

1. Decreases
2. Increases

Calculate the heat energy needed to change the temperature of 2 kg of copper from 10°C to 110°C.

If you could show your process and equations used, that would be very helpful! Thanks!

Answers

Answer:

77000 J

Explanation:

Formula for the heat energy is;

Q = m•c•Δt

We are given;

mass; m = 2 kg

Change in temperature; Δt = 110 - 10 = 100 °C

From online values, specific heat capacity of copper is; c = 385 J/kg.°C

Thus;

Q = 2 × 100 × 385

Q = 77000 J

Answer:

heat = 20 Kcal

Explanation:

Hydrogen bonds create unusual properties in water. What are they?

Answers

Answer:Liquid water is denser than Ice.

Ice float on top of liquid water.

Explanation:

Just trust me

A 420 g soccer ball is kicked into the air with an initial velocity of 30 m/s. How much kinetic energy does the soccer ball have?

Answers

Answer:189000J

Explanation:KE=1/2mv^2

1/2(420g)(30m/s)^2

=189000J

a ballon is filled with air. what forces are acting on the ballon and the air?

Answers

Answer: Three forces act significantly on a freely floating helium-

filled balloon: gravity, air resistance (or drag force), and a

buoyant force.

Explanation:

The air pressure on the bottom of the balloon is slightly higher than the air pressure on the top of the balloon (because of the altitude difference). This difference gives rise to the bouyant force. This force competes with gravity as the two main forces acting on the balloon. Every time your feet hit the ground when you are running, the ground hits your feet with an equal and opposite force. Newton’s third law explains how balloons and rocket engines work. When the neck of an inflated balloon is released, the stretched rubber material pushes against the air in the balloon. The air rushes out of the neck of the balloon.

Q3) Salman walks to the mosque with speed 2.4 m/s. If it takes him 3 min to
reach the mosque. Find the distance.​

Answers

Answer: 432m

Explanation:

Convert 3 min to seconds

1 min = 60 sec

3 min = 180 sec

Multiply the speed times time to get distance.

2.4 x 180 = 432m

please hellp!!!!!!!!!!!!!!!!!!!!?

Answers

Answer:

the second to last by the north pole

Explanation:

second to last
sorry if that’s wrong
but have a good day!!:)

1| Page
01. (a) (i) What is Polarization of a matter
(ii) draw in atomic view before and after​

Answers

Answer:

Polarization occurs when an electric field distorts the negative cloud of electrons around positive atomic nuclei in a direction opposite the field. Polarization P in its quantitative meaning is the amount of dipole moment p per unit volume V of a polarized material, P = p/V.

Explanation:

Answer:

Polarization occurs when an electric field distorts the negative cloud of electrons around positive atomic nuclei in a direction opposite the field. Polarization( P) in its quantitative meaning is the amount of dipole moment (p) per unit volume V of a polarized material, where P = p/V.

How can a body have centripetal acceleration even if the speed is constant?

Please help me understand this it’ll be greatly appreciated!

Answers

Answer:

motion of an object—even if the object is maintaining a constant speed—still count as acceleration

Explanation:

The weight of a 0.5 kg object on the surface of Planet X is 20 N. If the radius of the planet is 4 X 106 m, what is its mass?

Answers

Answer:

The mass of the Planet X is 9.595 x 10²⁴ kg.

Explanation:

mass of the object, m = 0.5 kg

radius of the Planet X, r = 4 x 10⁶ m

weight of the object, W = F = 20 N

let the mass of the Planet  X = mₓ

Apply Newton's gravitational law;

[tex]F = \frac{Gmm_x}{r^2} \\\\m_x = \frac{Fr^2}{Gm} \\\\m_x = \frac{(20)(4\times 10^6)^2}{6.67 \times 10^{-11} \ \times \ 0.5} \\\\m_x = 9.595 \times 10^{24} \ kg[/tex]

Therefore, the mass of the Planet X is 9.595 x 10²⁴ kg.

Trolley A, of mass 180 g, is moving at a velocity of 4 m/s towards trolley B
which is stationary and has a mass of 120 g. Trolley A then collides with
trolley B.
Calculate the speed of trolley B if:
i the collision is elastic (trolley A stops and trolley B moves off)

Answers

Answer:

To solve typical questions like this we can use law of conversation of linear momentum...which is

T.I.L.M.=T.F.L.M.

(Total initial linear momentum = total final linear momentum.)

Momentum = mass × velocity

T.I.L.M = T.F.L.M

180×4 + 120×0 = 180×0 + 120×V

(180 ×4)/120 = V

6Ms^-1 = v

A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v. The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance

Answers

The satellite is moved to a new circular orbit that is 2R from the center of the moon, then the gravitational field strength of the moon at this new distance would be one-fourth of the initial gravitational field.

What is gravity?

It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.

As given in the problem A satellite of mass m orbits a moon of mass M in a uniform circular motion with a constant tangential speed of v. The gravitational field strength at a distance R from the center of the moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon.

The gravitational field strength is inversely proportional to the square of the distance from the center of the planet.

Thus, the gravitational field strength of the moon at this new distance would be one-fourth of the initial gravitational field.

To learn more about gravity here, refer to the link given below ;

brainly.com/question/4014727

#SPJ1

What are the units for measuring specific heat?

a. degrees Celsius per gram
b. joules per degrees Celsius
c. joules per gram degree Celsius
d. degrees Celsius per joule gram

Answers

You answer should be C sorry if I’m wrong

Answer:

c. joules per gram degree Celsius

Explanation:

edg 2021

The wavelength of a particular color of violet light is 417 nm. The energy of this wavelength of light is

Answers

Answer:

E = 4.7 x [tex]10^{-19}[/tex] Joules

Explanation:

Solution:

The wavelength of a particular color of violet light = 417 nm

What is the energy = ?

In order to calculate energy, we will use the following formula:

E = hf

where, f = frequency = 1/wavelength = c/λ

where c = speed of light = 299 792 458 m / s or 3 x [tex]10^{8}[/tex] m/s

where h = Plank's constant = 6.62x [tex]10^{-34}[/tex] [tex]m^{2}[/tex] kg / s

So,

λ = 417 nm

1 nm = [tex]10^{-9}[/tex] m

so,

λ = 417 x [tex]10^{-9}[/tex] m

Now, just plug in the values to calculate the energy of this wavelength of light.

E = hc/λ

E = ( 6.62x [tex]10^{-34}[/tex] ) (299 792 458) / (417 x [tex]10^{-9}[/tex] )

E = 0.047 x[tex]10^{-17}[/tex]

E = 4.7 x [tex]10^{-19}[/tex] Joules

A 0.53 kg arrow leaves a bowstring at a velocity of 63 m/s. If the arrow was initially at rest and then the string applied a force on it for 7 x 10-3 seconds, what was the approximate average force in Newtons that acted on the arrow during this time?

Answers

Answer:

4770 N

Explanation:

Momentum is the product of mass and velocity and force is the change in momentum divided by change in time.

Given from the question;

Mass of arrow= 0.53 kg

Velocity of arrow = 63 m/s

Initial velocity of arrow = 0 m/s

Change in time = 0.007 s

Finding momentum after the arrow is released as;

p=m*v

p= 0.53 * 63

p= 33.39 kg*m/s

Force is the change in momentum divided by change in time;

F= 33.39 / 0.007

F= 4770 N

A metallic ring of mass 1 kg has moment of inertia 1 kg m² when rotating about one of its diameters. It is molten and
remoulded into a thin uniform disc of the same radius. How much will its moment of inertia be, when rotated about its own
axis.​

Answers

Answer:

The moment of inertia of disc about own axis is 1 kg-m².

Explanation:

Given that,

Mass of ring m= 1 kg

Moment of inertia of ring at diameter [tex](I_{r})_{d}=1\ kg\ m^{2}[/tex]

The radius of metallic ring and uniform disc both are equal.

So, [tex]R_{r}=R_{d}[/tex]

We need to calculate the value of radius of ring and disc

Using theorem of perpendicular axes

[tex](I_{r})_{c}=2\times (I_{r})_{d}[/tex]

Put the value into the formula

[tex](I_{r})_{c}=2\times1[/tex]

[tex](I_{r})_{c}=2\ kg\ m^2[/tex]

Put the value of moment of inertia

[tex]MR_{r}^2=2[/tex]

[tex]R_{r}^2=\dfrac{2}{M}[/tex]

Put the value of M

[tex]R_{r}^2=\dfrac{2}{1}[/tex]

So, [tex]R_{r}^2=R_{d}^2=2\ m[/tex]

We need to calculate the moment of inertia of disc about own axis

Using formula of moment of inertia

[tex]I_{d}=\dfrac{1}{2}MR_{d}^2[/tex]

Put the value into the formula

[tex]I_{d}=\dfrac{1}{2}\times1\times2[/tex]

[tex]I_{d}=1\ kg\ m^2[/tex]

Hence, The moment of inertia of disc about own axis is 1 kg-m².

The area of the foundation of a square house is 840 ft. Find
the side length of the foundation of the house to nearest whole
number

Answers

Answer:

210 ft.

Explanation:

Since a square has 4 sides and all sides are equal, just do 210 divided by 4.

if a train has 1,450 kg of momentum and is traveling at 40 m/s ¿what is the mass of tren?
Help plis I have this wrong

Answers

Answer:

P=mv

1x450,200=m40

m= 36,255kg

A football player kicks a ball with a mass of 0.5 kg. The average acceleration of the football was 15 m/s/s. How much force did the kicker apply to the football?

Answers

Answer:

i think its 8.2

Explanation:

Calculate the volume of 1280 kilograms of aluminium if the density is 2700kg/m3

Answers

Answer:

0.47m3

Explanation:

Volume = Mass / Density

In this case:

Mass - 1280 kg

Density - 2700kg/m3

1280 / 2700 = 0.4740741m3

When this is rounded off ( 2 d.p ):

0.47 m3

HOPE THIS HELPED

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