Answer:
energy is the capacity or ability to do work
its si unit is joule
Which variable is represented by the following symbol? λ
a. Wavelength
b. Amplitude
c. Frequency
d. Velocity
Answer:
A
Explanation:
Wavelength is represented by lambda
what current flows between a voltage of 120v across a resistance of 30Ω?
Answer:
4 amp
Explanation:
From ohm's law,
V=IR
so,
I=V/R
I=120/30
I=4amp ans..
Loops spaced further apart create a stronger electromagnet. True or False
Answer:
False
Explanation:
Electromagnetic strength is inversely proportional to separation distance
please helpppp... thank u ❤️
Answer:
For Ryan:
[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]
For the football kicked:
[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]
Answer:
the highest point for the first question is 0 meters per second
the answer for question 2 is 45 degrees
A test car and its driver, with a combined mass of 600 kg, are moving along a straight,horizontal track when a malfunction causes the tires to stop rotating. The car skids to a halt with constant acceleration, leaving skid marks on the road during the whole time it skids. Which two of the following measurements, taken together, would allow engineers to find the total mechanical energy dissipated during the skid?
A. The length of the skid marks
B. The contact area of each tire with the track.
C. The coefficent of static frction between the tires and the track.
D. The coefficent of static frction between the tires and the track.
Answer:
The two of the following measurements, when taken together, would allow engineers to find the total mechanical energy dissipated during the skid
B. The contact area of each tire with the track.
C. The co-efficent of static friction between the tires and the track.
D. The co-efficent of static friction between the tires and the track.
Explanation:
Please solve it as soon as possible with steps
Answer:
In 1 round 62.857m
In 1.5 round 94.2855m
In 2 round 125.714m
In 2.5 round 157.1425
Q1. What is the mass of a ball that has a kinetic energy of16 J and it is traveling at 4 m/s?
Q2. What is the kinetic energy of a soccer ball which has a mass of 1 kg and is kicked with a velocity of 10 m/s?
Q3.exercise ball is on a table 2 m above the ground. What is the mass of the ball if it has a GPE of 40 ?
Q4.What is the gravitational potential energy (GPE) of a 2 kilogram book that is 20 meter above the ground?
Answer:
Explanation:
Kinetic Energy has a formula of
[tex]KE=\frac{1}{2}mv^2[/tex] and
Potential Energy has a formula of
PE = mgh. The first 2 problems use the KE formula and the next 2 use the PE formula.
Q1. KE = 16 and v = 4 m/s:
[tex]16=\frac{1}{2}m(4)^2[/tex] and
[tex]\frac{2(16)}{16}=m[/tex] so
m = 2 kg
Q2. mass = 1 kg and v = 10 m/s:
[tex]KE=\frac{1}{2}(1)(10)^2[/tex] so
KE = 50 J
Q3. PE = 40, h = 2, g = 9.8:
40 = m(9.8)(2) and
[tex]\frac{40}{(9.8)(2)}=m[/tex] so
m = 2.0 kg
Q4. mass = 2 kg, g = 9.8 m/s/s, h = 20:
PE = 2(9.8)(20) so
PE = 392 J
**I completely disregarded the rules for sig fig's because your numbers were very inexact**
Derive the relation between wavelength, frequency and speed of sound.
Explanation:
sorry I need some points foe this
A cubic box has a 0.8 meter side. Find the volume of air in the box in cubic meter?
Answer:
[tex]V=0.512\ m^3[/tex]
Explanation:
Given that,
The side of a cubic box, s = 0.8 m
We need to find the volume of air in the box.
We know that,
The volume of a cube is given by :
[tex]V=s^3[/tex]
So,
[tex]V=0.8^3\\\\V=0.8\times 0.8\times 0.8\\\\=0.512\ m^3[/tex]
So, the volume of air in the box is [tex]0.512\ m^3[/tex].
1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.
Answer:
a) Please find attached the required drawing of light passing through the lens
By the use of similar triangles;
The image distance from the lens = 26 cm
The height of the image = 14 cm
c) The image distance from the lens = 26 cm
The height of the image = 14 cm
Explanation:
Question;
a) Determine the image distance and the height of the image
b) Calculate the image position and height
The given parameters are;
The height of the object, h = 14 cm
The distance of the object from the mirror, u = 26 cm
The focal length of the mirror, f = 13 cm
The location of the object = 2 × The focal length
Therefore, given that the center of curvature ≈ 2 × The focal length, we have;
The location of the object ≈ The center of curvature of the lens
The diagram of the object, lens and image created with MS Visio is attached
From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m
The height of the image = The height of the object - 14 cm
b) The lens equation is used for finding the image distance from the lens as follows;
[tex]\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}[/tex]
Where;
v = The image distance from the lens
We get;
[tex]v = \dfrac{u \times f}{u - f}[/tex]
Therefore;
[tex]v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26[/tex]
The distance of the image from the lens, v = 26 cm
The magnification, M =v/u
∴ M = 26/26 = 1, therefore, the object and the image are the same size
Therefore;
The height of the image = The height of the object = 14 cm.
A piece of iron has a mass of 30 g and its volume is 6.2 cm3. What is its density?
Answer:
Density = 4.84 g/cm³
Explanation:
Given the following data;
Mass = 30 g
Volume = 6.2 cm³
To find the density of the piece of iron;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
Substituting into the equation, we have;
[tex]Density = \frac{30}{6.2}[/tex]
Density = 4.84 g/cm³
Calculate the electric potential at point A, the middle of the rectangle, and at point B, the middle of the right-hand side of the rectangle. How would you find the electric potential?
Answer:
With the help of formula.
Explanation:
We can calculate the electric potential of any point through the formula of electric potential which is given below.
Electric potential = Coulomb constant x charge/ distance of separation.
Symbolically it can be written as, V = k q/ r where
V = electric potential
k = Coulomb constant
q = charge
r = distance of separation
If we have all these data, we can simply put the data in the formula and we will get the value of electric potential.
A 75kg hockey player is skating across the ice at a speed of 6.0m/s. What is the magnitude of the average force required to stop the player in 0.65s?
Answer:
692.31 N
Explanation:
Applying,
F = ma............... Equation 1
Where F = Average force required to stop the player, m = mass of the player, a = acceleration of the player
But,
a = (v-u)/t............ Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............ Equation 3
From the question,
Given: m = 75 kg, u = 6.0 m/s, v = 0 m/s (to stop), t = 0.65 s
Substitute these values into equation 3
F = 75(0-6)/0.65
F = -692.31 N
Hence the average force required to stop the player is 692.31 N
A positively charged rod is brought close to a neutral metal sphere. Explain what
happens to the charges in the neutral sphere as the rod comes close, touches the
sphere, and then moves away. Is the metal sphere still neutral at the end of this
encounter?
Answer:
No, the metal sphere becomes positively charged because electrons are transferred from the sphere to the rod.
What is the three-body problem? Explain at a level so an 8th grader could understand
Answer:
In physics and classical mechanics, the three-body problem is the problem of taking the initial positions and velocities (or momenta) of three point masses and solving for their subsequent motion according to Newton's laws of motion and Newton's law of universal gravitation.[1] The three-body problem is a special case of the n-body problem. Unlike two-body problems, no general closed-form solution exists,[1] as the resulting dynamical system is chaotic for most initial conditions, and numerical methods are generally required.
Hope this answer is right!
Amelia is doing an experiment in which she is
going to burn various solid chemicals to see the
colors of flames they produce. For this laboratory
experiment, what types of safety precautions
should she take?
tie hair back
leave open flame unattended to get a drink
only burn the amount of chemicals as
directed by the lab procedure
put out the flame with water from the eyewash
station
Answer:
tie hair back
only burn the amount of chemicals as
directed by the lab procedure
Explanation:
The correct safety precautions for Amelia to take from the options would be to tie her hair back and to only burn the amount of chemicals recommended by the lab procedure.
With her hair left flowing freely, Amelia runs the risk of the hair catching flame while trying to burn the chemicals according to the procedure. Hence, tying her hair up into one neat bunch will limit the risk of it catching fire while working in the lab.
Also, burning less or more than the amount of chemicals recommended by the procedure may be dangerous or hinder Amelia from getting the right result.
Answer:
1,3
Explanation:
just did it
What is the sum of a systems potential and kinetic energy is equal to?
a. Total Energy
b. Mechanical Energy
c. Thermal Energy
d. Hyper Energy
Answer:
Explanation:
TE = KE + PE which is total energy available to a system is equal to its potential energy plus its kinetic energy, and that total energy will remain throughout the entire "trip", whatever it might be. So a is your answer.
HELP ME ILL MARK U THE BRAINLIEST
Another box of weight 1500 N is raised vertically by 3.0 m
calculate the work done on the box
Answer:
[tex]workdone = force \times distance \\ = 1500 \times 3 \\ = 4500 \: joules[/tex]
Answer:
4,500J
Explanation:
Work done = force × distance
1500N × 3m = 4,500 Joules
In Einstein’s analysis, a photon striking the surface of a conductor is absorbed by an electron. Which statement describes the set of energy transfers that could occur?
A. the electron receives either all or none of the photon's energy
B. The electron may receive any fraction of the photon's energy, including all or none of it
C. The electron may receive only certain quantized amounts of the photon's energy, including all or none of it
Answer:
the correct answer is A
Explanation:
In an Einstein-type analysis, the photon is absorbed, it loses all its energy, therefore the electron must receive all or none of the energy of the incident photon. In a type of inelastic shock.
Let's analyze the different answers
A) true. In photon it is completely absorbed or passes without interaction
B) False. The photon must change energy, but in this case there is no absorption of the photon
C) False. In the insistent analyzes, the quantization of the electron in discrete states is not mentioned.
Therefore the correct answer is A
The specific heat capacity of sea water is 4100 J/Kg°C and the boiling point of 100.6 °C. (i) Calculate the energy required to raise the temperature of 0.900 kg of this sea water from 10 °C up to its boiling point. Also mention the equation to be used. *
Answer:
334.314 (kJ)
Explanation:
1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.
2) according to the formula above:
Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).
A car has a kinetic energy of 103kJ.
The speed of the car is 13.1 m/s.
Calculate the mass of the car.
Give your answer to 2 significant figures.
Answer: 1200kg
Explanation:
KE = (1/2)mv^2
103kJ = 103000J
103000J = (1/2) * m * (13.1m/s)^2
Solve for m
A car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
A car has a kinetic energy of 103 kJ. The speed of the car is 13.1 m/s,
The kinetic energy of the car = 1/2 × mass × velocity
103000 =0.5 × mass × (13.1) ²
The mass of the car = 1200 Kilogram
Thus, if a car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.
To learn more about mechanical energy, refer to the link;
https://brainly.com/question/2409175
#SPJ5
Which variable is represented by the following symbol? ∑F
a. Normal Force
b. Applied Force
c. Weight
d. Net Force
Answer:
d.Net force
Explanation:
The net force is the force which is the sum of all the forces acting on an object simultaneously.
A motor has an internal resistance of 12.1 Ω. The motor is in a circuit with a current of
4.0 Amps
What is the voltage?
Answer:
Explanation:
V = I * R
V = 4 * 12.1 = 48.4 v
PLEASE HELP WITH THIS QUESTION
What of Newton's 3 laws is represented in this picture?
Answer:
The first law states that an object at rest will stay at rest, and an object in motion will stay in motion unless acted on by a net external force. Mathematically, this is equivalent to saying that if The second law states that the rate of change of momentum of a body over time is directly proportional to the force applied, and occurs in the same direction as the applied force. the net force on an object is zero, then the velocity of the object is constant. The third law states that all forces between two objects exist in equal magnitude and opposite direction: if one object A exerts a force FA on a second object B, then B simultaneously exerts a force FB on A, and the two forces are equal in magnitude and opposite in direction
Explanation:
What nuclear reaction is shown in the equation below
Answer:
nuclear fission
Explanation:
nuclear fission
Answer: Nuclear fission
Explanation:
A 50.0 kg object is moving east at an unknown velocity when it collides with a 60.0 kg stationary object. After collision, the 50.0 kg object is traveling at a velocity of 6.0 m/s 50.0degree N of E and the 60.0 kg object is traveling at a velocity of 6.3 m/s 38degree S of E.
What was the velocity of the 50.0 kg object before collision?
p=m•v is the formula.
The principle of conservation of momentum states that:
momentum before collision = momentum after collisionMomentum = mass * velocityMomentum before collision:
Velocity of 50.0 kg object = v m/s
Momentum of 50.0 kg object = 50 * v
Momentum after collision:
Velocity of the 50.0 kg object = 6.0 m/s 50.0degree N of E
Velocity of the 60.0 kg object = 6.3 m/s 38degree S of E.
Momentum of 50.0 kg object = 50 * 6 = 300 kgm/s
Momentum of 50.0 kg object = 60 * 6.3 = 378 kgm/s
Total momentum after collision = 678 kgm/s
From the principle of conservation of momentum:
50 kg * v = 678 kgm/s
v = 678 kgm/s / 50 kg
velocity, v = 13.56 m/s
Therefore, the velocity of the 50.0 kg object before collision was 13.56 m/s.
Learn more about conservation of momentum at: https://brainly.com/question/7538238
Let's say you cut open a log of wood with an axe, what type of simple machine are you using? Does it matter how sharp it is?
yes it matters because if it's not sharp it would take all day
Answer:
an axe is a type of machine called a wedge. it does matter how sharp your axe is. if your axe is not sharp then you will have a harder time cutting wood.
Explanation:
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Answer:
I'm pretty sure the answer is broken
Explanation:
if a car is taken from the garage driven for 100km before returning to the garage after 2 hours what is it average speed?
Answer:
50km/h
Explanation:
Average Speed = Distance/Time
100km/2h = 50km/h
how can you account for the differences in the entropies of combination of methyl propane (-1465J/mol K) and butane (1465J/mol K)
Explanation:
The change in entropy is a measure of temperature. When the temperature of a compound or a system increases, there will be more randomness in the system.
The boiling point is directly related to the number of carbon atoms but is indirectly proportional to the branching in a hydrocarbon.
Butane and methyl propane, both have 4 carbon atoms.
But, butane has 4 carbon atoms in a straight chain while methyl propane has 3 carbon atoms in a straight chain and 1 methyl substituent which makes it a branched hydrocarbon.
Thus, the boiling point of methyl propane will be less than the butane. Likewise, the pattern in entropies will be seen.
