What is principle of liver??

Answer:

Aesthetic sports

Explanation:

Aesthetic sports are the one's that need well-developed physical qualities such as strength, agility, stamina, flexibility, and technical knowledge and artistry, in addition to technical ability and artistry. Elite athletes in these sports generally have a low abdominal fat , and the ranking is subjective.

In aesthetic sports like gymnastics, swimming, and figure skaters, dynamic and proactive flexibility is required.

Answer:

The maximum force is 1.8 N.

Explanation:

A pendulum is a vertically hanging spring with a stiffness of 30 N/m and a mass of 320 g. The excitable excitation oscillates vertically around the equilibrium position with an amplitude of 6 cm. Take g = 10m/s. The magnitude of the maximum pulling force of the distance from the suspension point during the oscillation of the weight is

stiffness, K = 30 n/m

mass, m = 320 g

amplitude, A = 6 cm = 0.06 m

g = 10 m/s^2

Let the maximum acceleration is a.

[tex]a = w^2 A\\\\a = \frac{K}{m}A\\\\Force, F = m a \\\\F = K A\\\\F = 30 \times 0.06 \\\\F = 1.8 N[/tex]

Answer:

A

Explanation:

low credit score means its more risky to lend someone money

Answer:

(i) The particle has a period of 0.3 seconds.

(ii) The angular velocity of the particle is a20.944 radians per second.

(iii) The linear velocity of the particle is 1.047 meters per second.

(iv) The linear acceleration of the particle is 21.933 meters per square second.

Explanation:

Statement is incomplete and have mistakes, complete and correct form is presented below:

A particle makes 800 revolutions in 4 minutes of a circle with a radius of 5 centimeters. Find (i) its period, (ii) its angular velocity, (iii) its linear velocity and (iv) its acceleration.

(i) The period of the particle ([tex]T[/tex]), in seconds, is the time taken to make a complete revolution:

[tex]T = \frac{4\,min \times \frac{60\,s}{1\,min} }{800\,rev}[/tex]

[tex]T = 0.3\,s[/tex]

The particle has a period of 0.3 seconds.

(ii) The angular velocity ([tex]\omega[/tex]), in radians per second, is determined by the following formula:

[tex]\omega = \frac{2\pi}{T}[/tex] (1)

[tex]\omega = \frac{2\pi}{0.3\,s}[/tex]

[tex]\omega \approx 20.944\,\frac{rad}{s}[/tex]

The angular velocity of the particle is a20.944 radians per second.

(iii) The linear velocity ([tex]v[/tex]), in meters per second, is calculated by the following formula:

[tex]v = R\cdot \omega[/tex] (2)

Where [tex]R[/tex] is the radius of the circle, in meters.

If we know that [tex]R = 0.05\,m[/tex] and [tex]\omega \approx 20.944\,\frac{rad}{s}[/tex], then the linear velocity of the particle is:

[tex]v = (0.05\,m)\cdot \left(20.944\,\frac{rad}{s} \right)[/tex]

[tex]v = 1.047\,\frac{m}{s}[/tex]

The linear velocity of the particle is 1.047 meters per second.

(iv) Since angular velocity is constant, linear acceleration of the particle ([tex]a[/tex]), in meters per square second, is entirely radial. Acceleration can be found by means of this expression:

[tex]a = \omega^{2}\cdot R[/tex] (3)

If we know that [tex]R = 0.05\,m[/tex] and [tex]\omega \approx 20.944\,\frac{rad}{s}[/tex], then the linear acceleration of the particle is:

[tex]a = \left(20.944\,\frac{rad}{s} \right)^{2}\cdot (0.05\,m)[/tex]

[tex]a = 21.933\,\frac{m}{s^{2}}[/tex]

The linear acceleration of the particle is 21.933 meters per square second.

Answer:

time.

Explanation:

Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.

Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, position, displacement, etc.

A graph can be defined as the graphical representation of data (informations) on horizontal and vertical lines i.e x-axis and y-axis respectively.

A position-time (x-t) graph is a graph of the position of an object against (versus) time.

To make a position-time graph, you should plot the values of the position of an object or body with respect to the starting point on the y-axis against the corresponding time on the x-axis.

Generally, the slope of the line of a position-time (x-t) graph is typically used to determine or calculate the velocity of an object.

An instantaneous velocity can be defined as the rate of change in position of an object in motion for a short-specified interval of time. Thus, an instantaneous velocity is a quantity that can be found by measuring the slope of a line that is tangent to a point on the graph.

In conclusion, the x - t graph also referred to as the position-time graph is used for determining the instantaneous velocity from the slope.

Answer:

The force acting is given by 1N.

Explanation:

mass, m = 500 g = 0.5 kg

acceleration, a = 2 m/s^2

According to the Newton's second law, the force acting on an object is given by the product of mass and the acceleration of the object.

F = m a

F = 0.5 x 2 = 1 N

Answer:

The boiling point of liquids always increases when pressure is applied on a liquid. This is because the molecules of a liquid will need more energy to turn into a gaseous state when pressure is applied on that substance.

Answer:

v=4m/s

wavelength=6m

f=v/∧

f=0.67Hz

now, v= 1.7 m/s

f=0.67Hz

∧=v/f

∧=1.7/0.67

∧=2.54m

Explanation:

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2.54m is the wavelength in the shallower region.

Wavelength exists the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in the area or along a wire. In wireless systems, this length exists usually specified in meters (m), centimeters (cm), or millimeters (mm).

Wavelength can be represented as the distance between two successive crests or troughs of a wave. It exists calculated in the direction of the wave.

v=4m/s

wavelength=6m

f=v/λ

f=0.67Hz

now, v= 1.7 m/s

f=0.67Hz

λ=v/f

λ=1.7/0.67

λ=2.54m.

Hence, 2.54m is the wavelength in the shallower region.

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Answer:

The goal of physics is to understand how things work from first principles. ... Courses in physics reveal the mathematical beauty of the universe at scales ranging from subatomic to cosmological. Studying physics strengthens quantitative reasoning and problem solving skills that are valuable in areas beyond physics.

Answer:

The distance of car form the mirror is 330 cm.

Explanation:

height of object, h = 140 cm

height of image, h' = 14 cm

radius of curvature, R = 60 cm

focal length, f = R/2 = + 30 cm

Let the distance of image is v and the distance of object is u.

[tex]\frac{h'}{h}\frac{v}{u}\\\\\frac{14}{140} =\frac{v}{u}\\\\v =\frac{u}{10}[/tex]

Use the formula of focal length

[tex]\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\\\frac{1}{30}=\frac{10}{u}+\frac{1}{u}\\\\\frac{1}{30}=\frac{11}{u}\\\\u = 330 cm[/tex]

Answer:

(I)W=18×10³ J

(ii) P=720W

Explanation:

30 Bricks = 1brick weight× 30 Bricks

30 Bricks= 12×30

=360N

Distance=50m

Time= 25s

1. Work done= Force× Distance

=360×50

= 18×10³ J

2. Power= Work done/ Time

18×10³/25

Power= 720W.

Answer:

t = 2.7 seconds

Explanation:

Given that,

Initial speed, u = 3.8 m/s

Final speed, v = 4.2 m/s

Acceleration of Michael, a = 0.15 m/s²

(a) Let t is the time taken by him to catch Robert. It can be calculated as follows :

[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{4.2-3.8}{0.15}\\\\t=2.7\ s[/tex]

So, the time taken is 2.7 seconds.

Complete Question:

The density of aluminium is 2.70g/cm³. The thickness of a rectangular sheet of aluminium foil varies, but is much less than 1 mm.

A student wishes to find the average thickness. She obtain the following measurements

Mass of sheet = 60.7g

Length of sheet = 50.0cm

Width of sheet = 30.0 cm

Calculate the student's values for

(i) the volume of the sheet

(ii) the average thickness of the sheet

Answer:

Thickness = 0.015 cm

Explanation:

Given the following data;

I. To find the volume of the sheet;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

[tex] Density = \frac {mass}{volume} [/tex]

Making volume the subject of formula, we have;

[tex] Volume = \frac {mass}{density} [/tex]

Substituting into the formula, we have;

[tex] Volume = \frac {60.7}{2.70} [/tex]

Volume = 22.48 cm³

II. Volume = length * width * height

But, height = thickness

Volume = length * width * thickness

22.48 = 50 * 30 * thickness

22.48 = 1500 * thickness

[tex] Thickness = \frac {22.48}{1500} [/tex]

Thickness = 0.015 cm

Conversion:

1 mm = 0.1 cm

X mm = 0.015 cm

X = 0.015/0.1 = 0.15 mm

Therefore, the thickness of the rectangular sheet of aluminium foil is less than 1 millimetre.

Answer:

Explanation:

-Cambio de temperatura

Al calentar un cuerpo la temperatura aumenta

Es el efecto más inmediato del calor, el aumento de la temperatura. Al calentar un cuerpo, es habitual, aunque no siempre, que el cuerpo aumente de temperatura. El aumento dependerá de la cantidad de calor que se suministra, del tipo de sustancia y de su cantidad.

-Dilatación

Cuando un objeto se calienta, su volumen aumenta. Este fenómeno se llama dilatación térmica. Por el contrario, cuando un objeto se enfría, su volumen disminuye, debido a la contracción térmica.

Cuando se calienta un cuerpo, además de cambiar de estado o variar su temperatura, también cambia su tamaño, se dilata.

Por ejemplo, los puentes no se construyen de una única pieza, sino que suelen presentar uno o varios cortes longitudinales, las llamadas juntas de dilatación. Si no existieran esas juntas, los cambios de longitud del puente entre el invierno y el verano o entre el día y la noche acabarían por romperlo.

La dilatación de un cuerpo dependerá del aumento de temperatura que experimente, de su tamaño y de la sustancia de que esté hecho. Cuanto más aumente la temperatura más aumentará su tamaño, lo mismo que cuanto mayor sea, mayor se hará.

Todos los cuerpos, ya sean sólidos, líquidos o gaseosos, varían su tamaño cuando intercambian calor con otro cuerpo.

-Cambios de estado:

Si una sustancia modifica el estado de sólido, líquido o gaseoso, se produce un cambio de estado. Un cambio de estado es una modificación en la forma en que se disponen las partículas que constituyen una sustancia.

El estado en que se encuentre un cuerpo depende de la presión a la que está sometido y de su temperatura. Para cambiar su estado se debe modificar alguna de estas variables, o ambas. Al elevar la temperatura de una sustancia sólida, aumenta la agitación de sus partículas.

Answer:

All forms of matter (solid, liquid and gas) undergo expansion on heating. When a solid is heated, the atoms gain energy and vibrate more vigorously. This results in the expansion of the solid. For a given change in temperature, the extent of expansion is smaller in solids than in liquids and gases. This is due to the rigid nature of solids.

Explanation:

Answer:

D. more mass is concentrated.

Explanation:

Gravity is considered to be a universal force of attraction which acts between all objects that has both mass, energy and occupy space. Therefore, it acts in such a way as to bring objects together.

Additionally, the gravity of earth makes it possible for all physical objects to possess weight.

Newton's law of universal gravitation states that the force of attraction (gravity) acting between the Earth and all physical objects is directly proportional to the Earth's mass, directly proportional to the physical object's mass and inversely proportional to the square of the distance separating the Earth's center and that physical object.

Center of gravity can be defined as the specific point where all of the weight of an object is concentrated.

Generally, all the objects found around the world all have a center of gravity.

Additionally, when an object is balanced so that a displacement lowers its center of gravity, the object is said to be in stable equilibrium.

The centre of gravity of a physical object is usually located where more mass is concentrated in the physical object or body.

However, the location of the centre of gravity is subject to change and as such doesn't always remain the same.

Answer:

Gamma rays

Gamma rays have the highest energies, the shortest wavelengths, and the highest frequencies.

Explanation:

acceleration a = v-v0/ t = ∆V/∆t

first we must calculate F = M.A

The average strength of this force will be 7.5 N

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = ?

Mass,m = 5 kg

Initial velocity,u=5 m/sec

Final velocity,v==8 m/sec

Time period,t=2.0 sec

The average strength of this force will be;

F=m[(v-u)/t]

F= 5 kg × [(8 m/sec -5 m/sec)/2.0 sec]] m/s²

F= 7.5 N

Hence the average strength of this force will be 7.5 N

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Answer:

9.81 J

Explanation:

The 10 kg block shown in the figure is in contact with the spring that has a natural length of 25 cm. When the block is released, it compresses the spring, remaining static 15 cm from the floor. Calculate the change in elastic potential energy of the spring in Joules

The given parameters are;

The mass of the block in contact with the spring = 10 kg

The natural length of the spring = 25 cm

The final height of the block after being released = 15 cm

Therefore;

The potential energy of the block = m·g·h

The initial potential energy of the block = 10 kg × 9.81 m/s² × 0.25 m = 24.252 J

The final potential energy of the block = 10 kg × 9.81 m/s² × 0.15 m = 14.715 J

By energy conservation principle

The change in potential energy of the block = The change in elastic potential energy of the spring = (1/2)·k·x² = 24.252 J - 14.715 J = 9.81 J

Answer:

The work done is 12 MJ.

Explanation:

The engine of a car exerts a constant traction force of F=4000N . Assume that the car is moving at a constant speed of 36 km/hr. In five minutes, what is the work done by the engine's traction?

Force, F = 4000 N

speed, v = 36 km/h = 10 m/s

time , t = 5 minutes = 5 x 60 = 300  s

Work done is given by

W =  force x distance

W = 4000 x 10 x 300 J = 12 x 10^6 J = 12 MJ

Explanation:

the answer is B normal force is always perpendicular to the surface

Let h be the height of the water in the tube. Then the total volume of water is

(h m) (1 m²) = h m³

After dropping the ball into the water, the height of the water changes to

h m + 2.25 mm = (h + 0.0025) m

and so the contents of the tub take up (h + 0.0025) m³ of volume.

This means the ball displaces

(h + 0.0025) m³ - h m³ = 0.0025 m³

of water, which is to say that this is volume of the ball.

With a mass of 4 kg, you would find its density to be

(4 kg) / (0.0025 m³) = (4 kg) / (2.5 L) = 1.6 kg/L

Answer:

q = 2.65 10⁻⁶ C

Explanation:

For this exercise we use Coulomb's law

        F =[tex]k \frac{q_1q_2}{r^2}[/tex]

In this case they indicate that the load is of equal magnitude

       q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

       F = [tex]k \ \frac{q^2}{r^2}[/tex]

       q = [tex]\sqrt{\frac{F \ r^2}{k} }[/tex]

we calculate

        q = [tex]\sqrt{\frac{0.7 \ 0.3^2 }{9 \ 10^9} }[/tex]

        q = [tex]\sqrt{7 \ 10^{-12} }[/tex]Ra 7 10-12

        q = 2.65 10⁻⁶ C

Answer:

Explanation:

The dimension less constants are the constants having no dimensions and also have a constant value.

For example, 1, 2, 3... numbers, e (exponent), [tex]\pi[/tex], etc.

The dimension less variables are the variables having no dimensions.

For example, refractive index, angle, strain, etc.

Answer:

wrong answer because m=100

Explanation:

I think it is incorrect

Ah, I tried

Expla

pV/T=const goodluke

Answer:

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Answer:

90 degree

Explanation:

Electric field line is vertical to the electric field line.

The angle between the field line and the equipotential where an electric field line crosses an equipotential surface is 90°

This is a region of space around a charged particle, or between two voltages.

The angle between Electric field crosses an equi-potential surface is always 90 degrees. When the potential becomes constant,the negative potential gradient also becomes zero, hence necessitating the need for Electric field to be always normal with surface.

Therefore, the angle between electric field and equi-potential surface is 90 degrees.

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