Answer:
zero(0)
Step-by-step explanation:
The additive identity of a set of number is a number such that the its sum with any of the numbers in the set would give a result that is equal to the number in that set.
In other words, say for example the set of numbers is rational, the additive identity of rational numbers is 0. This is because, given any rational number say x, adding zero to the number x gives the same number x. i.e
x + 0 = x
If x is say 2, then we have;
2 + 0 = 2
Since adding zero to rational numbers gives has no effect on the numbers, then zero (0) is the additive identity of rational numbers.
WILL GIVE BRAINLIEST PLS HELP
Answer:
Hello
Step-by-step explanation:
[tex]y=2x^2-12x+19\\=2(x^2-6x)+19\\=2(x^2-2*3*x+9)+19-18\\=2(x-3)^2+1\\\\Vertex\ is\ (3,1)\\\\Axis\ of\ symmetry\ is\ x=3\\\\y-intercept\ is \\\\y=2(0-3)^2+1=19\\[/tex]
Which expressions are equivalent to
3(6+b) + 2b+1?
Select 2 answers.
Step 1 - Use the distributive property and pick your first
answer
Step 2 - Combine like terms and pick your second
answer
Step-by-step explanation:
3(6+b)+2b+1
18+3b+2b+1
5b+19
In January Mr.Tan's students read 20 books. In February, they read 15 books. What is the percent increase or decrease in the number of books the read?
Answer:
there is a 25% decrease in books being read
what is the difference of the fractions?
-2 1/2 - (-1 3/4)
Answer:
-3/4
Step-by-step explanation:
First, let's convert the mixed numbers into improper fractions in an effort to make this problem easier to solve.
-2 1/2 as a mixed number is -5/2 and -1 3/4 as a mixed number is -7/4.
Our problem is now -5/2 - (-7/4).
We still can't solve this because the two fractions do not share a common denominator. 4 can serve as one, so -5/2 with a denominator of 4 would be -10/4.
The problem is now -10/4 - (-7/4).
Two negatives make a positive so the problem can be rewritten as -10/4 + 7/4. The final answer is -3/4.
In a right angle triangle ABC angle B=90⁰ and AB+BC= 31cm AB-BC=17 cm the find sinA,cosA,sinC,cosC.
Answer:
see explanation
Step-by-step explanation:
Given
AB + BC = 31
AB - BC = 17
Add the 2 equations
2AB = 48 ( divide both sides by 2 )
AB = 24
Substitute AB = 24 into the first equation
24 + BC = 31 ( subtract 24 from both sides )
BC = 7
Using Pythagoras' identity to find the hypotenuse AC
AC² = AB² + BC² = 24² + 7² = 576 + 49 = 625 ( take square root of both sides )
AC = [tex]\sqrt{625}[/tex] = 25
Then
sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{7}{25}[/tex]
cosA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{24}{25}[/tex]
sinC = [tex]\frac{AB}{AC}[/tex] = [tex]\frac{24}{25}[/tex]
cosC = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{7}{25}[/tex]
What is his weekly allowance if he ended with $15?
56 = h/9
k/5 - 10 = 3
3t + 5 =2
Answer:
h = 504, k = 65, t = -1
Step-by-step explanation:
56 = h/9
h = 56 x 9
h = 504
k/5 - 10 = 3
k/5 = 3 + 10
k/5 = 13
k = 13 x 5
k = 65
3t + 5 = 2
3t = 2 - 5
3t = -3
t = -3/3
t = -1
Help me with these questions plz
Answer:
Step-by-step explanation:
2) Cost Price = CP = $ 35
Tax = $ 3.29
Tax percent = [tex]\frac{tax}{CP}*100[/tex]
[tex]= \frac{3.29}{35}*100\\\\[/tex]
= 9.4 %
Total amount paid by Ian = CP + tax = 35 + 3.29
= $ 38.29
3) Price of the order = $ 56.50
Shipping cost % = 3 % = 0.03
Shipping cost = price of the order * shipping cost %
= 56.5 * 0.03
= 1.695
= $ 1.70
Total cost = Price of the order + Shipping cost
= 56.5 + 1.70
= $ 58.20
4) Bill amount = $ 26
Tip % = 18%
Tip amount = Tip % * bill amount
[tex]= \frac{18}{100}*26\\[/tex]
= $ 4.68
5) commission% = 3.5 %
Commission amount = commission% * Sales
[tex]= \frac{3.5}{100}*50000[/tex]
= $ 1750
Base salary for a week = $400
Base salary for two weeks = 400 * 2 = $ 800
Emmett's earning for this two weeks period = Base salary for two weeks + commission
= 800 + 1750
= $ 2550
6) Tax % = 10.25 %
Purchase amount = $ 310.50
Tax = Tax% * Purchase amount
[tex]= \frac{10.25}{100}*310.50[/tex]
= $ 31.83
Total = Purchase amount + Tax
= 310.50+ 31.83
= $ 342.33
which one is the right answers
Answer:
B
Step-by-step explanation:
n is the number of litres.
if you substitute 1 for 'n' then you will get :
C = 8 + 1.5(1)
C = $9.5
$9.50 for every litre
Answer:
C is correct
Step-by-step explanation:
The $8 charge is only once regardless of how many liters are ordered, so only answer C works.
Find the area of the circle.
Use 3.14 for it. Do not round your answer.
Hint: A = Tira
14 inches
Area = [?] inches?
Enter the number that
belongs in the green box.
Use the formula given. R is half the diameter
R = 14/2 = 7 inches.
Area = 3.14 x 7^2
Area = 153.86 inches^2
Answer:
Does the answer help you?
PLEASE HELP QWQ AsAp with these 4 questions
Answer:
Step-by-step explanation:
I can't believe I'm doing this for 5 points, but ok!
For the first 3, we are going to multiply to find the value of that 3 x 3 matrix by picking up the first 2 columns and plopping them down at the end and then multiplying through using the rules for multiplying matrices:
[tex]\left[\begin{array}{ccccc}7&4&6&7&4\\-4&8&9&-4&8\\1&8&7&1&8\end{array}\right][/tex] and from there find the sum of the products of the main axes minus the sum of the products of the minor axes, as follows (I'm not going to state the process in the next 2 problems, so make sure you follow it here. This is called the determinate. The determinate is what you get when you evaluate or find the value of a matrix. Just so you know):
[tex](7*8*7)+(4*9*1)+(6*-4*8)-[(1*8*6)+(8*9*7)+(7*-4*4)][/tex] which gives us:
392 + 36 - 192 - [48 + 504 - 112] which simplifies to
236 - 440 which is -204
On to the second one:
[tex]\left[\begin{array}{ccccc}-8&-4&-1&-8&-4\\1&7&-3&1&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us
[tex](-8*7*9)+(-4*-3*8)+(-1*1*9)-[(8*7*-1)+(9*-3*-8)+(9*1*-4)][/tex] which gives us:
-504 + 96 - 9 - [-56 + 216 - 36] which simplifies to
-417 - 124 which is -541, choice c.
Now for the third one:
[tex]\left[\begin{array}{ccccc}-2&-2&-5&-2&-2\\2&7&-3&2&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us
[tex](-2*7*9)+(-2*-3*8)+(-5*2*9)-[(8*7*-5)+(9*-3*-2)+(9*2*-2)][/tex] which gives us:
[tex]-126+48-90-[-280+54-36][/tex] which simplifies to
-168 - (-262) which is 94, choice c again.
Now for the last one. I'll show you the set up for the matrix equation; I solved it using the inverse matrix. So I'll also show you the inverse and how I found it.
[tex]\left[\begin{array}{cc}-4&-5&\\-6&-8\\\end{array}\right][/tex] [tex]\left[\begin{array}{c}x\\y\\\end{array}\right][/tex] = [tex]\left[\begin{array}{c}-5\\-2\\\end{array}\right][/tex] and I found the inverse of the 2 x 2 matrix on the left.
Find the inverse by:
* finding the determinate
* putting the determinate under a 1
* multiply that by the "mixed up matrix (you'll see...)
First things first, the determinate:
|A| = (-4*-8) - (-6*-5) which simplifies to
|A| = 32 - 30 so
|A| = 2; now put that under a 1 and multiply it by the mixed up matrix. The mixed up matrix is shown in the next step:
[tex]\frac{1}{2}\left[\begin{array}{cc}-8&5\\6&-4\end{array}\right][/tex] (to get the mixed up matrix, swap the positions of the numbers on the main axis and then change the signs of the numbers on the minor axis). Now we multiply in the 1/2 to get the inverse:
[tex]\left[\begin{array}{cc}-4&\frac{5}{2}\\3&-2\\\end{array}\right][/tex] Multiply that inverse by both sides of the equation. This inverse "undoes" the matrix that's already there (like dividing the matrix that's already there by itself) which leaves us with just the matrix of x and y. Multiply the inverse matrix by the solution matrix:
[tex]\left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{cc}-4&\frac{5}{2} \\3&-2\end{array}\right] *\left[\begin{array}{c}-5&-2\\\end{array}\right][/tex] and that right side multiplies out to
x = 20 - 5 which is
x = 15 and
y = -15 + 4 which is
y = -11
(It works, I checked it)
please help me Find DE.
Answer:
DE = 11
Step-by-step explanation:
DF = DF +EF
4x+2 = x+7 + 7
Combine like terms
4x+2 = x+14
Subtract x from each side
4x+2-x = x+14-x
3x+2 = 14
Subtract 2 from each side
3x+2-2 =14-2
3x=12
Divide by 3
3x/3 = 12/3
x = 4
DE = x+7 = 4+7 =11
Answer:
DE is 11
Step-by-step explanation:
[tex]DE = DF - EF \\ DE = (4x + 2) - 7 \\DE = 4x - 5 [/tex]
But for x:
[tex]4x + 2 = (x + 7) + 7 \\ 4x + 2 = x + 14 \\ 3x = 12 \\ x = 4[/tex]
Therefore:
[tex]DE = (4 \times 4) - 5 \\ = 16 - 5 \\ = 11[/tex]
if possible help me in this. I need to find the two odd numbers...
Part (a)
Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer
For example, if x = 7, then x+2 = 9 is right after.
Answer: x+2========================================================
Part (b)
The consecutive odd integers we're dealing with are x and x+2.
Their squares are x^2 and (x+2)^2, and these squares add to 394.
Answer: x^2 + (x+2)^2 = 394========================================================
Part (c)
We'll solve the equation we just set up.
x^2 + (x+2)^2 = 394
x^2 + x^2 + 4x + 4 = 394
2x^2+4x+4-394 = 0
2x^2+4x-390 = 0
2(x^2 + 2x - 195) = 0
x^2 + 2x - 195 = 0
You could factor this, but the quadratic formula avoids trial and error.
Use a = 1, b = 2, c = -195 in the quadratic formula.
[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\[/tex]
If x = 13, then x+2 = 13+2 = 15
Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394
Or we could have x = -15 which leads to x+2 = -15+2 = -13
So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394
We get the same thing either way.
Answer: Either 13, 15 or -15, -13which is odd one out 4:10 12:25 20:50 8:20
Answer:
All of them except 12:25 simply to 2:5. So 12:25 is the odd one out.
Banners at the school’s store we’re on sale for $4 off the regular price. Mike brought 5 banners on sale and paid a total of $20. Write and solve an equation to find the regular price of one banner.
Answer:
$8Step-by-step explanation:
Let the regular price is x, then:
(x - 4)*5 = 20x - 4 = 20/5x - 4 = 4x = 4 + 4x = 8BRAINLIEST
HOW CAN POSTULATES AND THEOREMS RELATING TO SIMILAR AND CONGRUENT ANGLES BE USED TO WRITE A PROOF?
Answer:
How can postulates and theorems relating to similar and congruent triangles be used to write a proof? If the three sets of corresponding sides of two triangles are in proportion, the triangles are similar. ... If the three sets of corresponding sides of two triangles are in proportion, the triangles are similar.
Step-by-step explanation:
Hope this helps :D good luck!!
28. find the range…
please help!!!
Answer:
A
Step-by-step explanation:
lmao this problem is bullshit because the actual answer would be [2, 2] U (7, infty) but thats literally not there, so ig the closest one would be [2, infty) which is A
if it was asking for the domain on the other hand, then it would be B lmao
but I would go with A
The divisibility rule for 7 says 10a + b is a multiple of 7 if only and only if a - 2b is a multiple of 7
Explain.
Answer:
Step-by-step explanation:
Well I can show you by example. Try 28
a = 2
b = 8
2 - 2*8 = 2 - 16 = -14
- 14 is divisible by 7. You get - 2.
That means that 28 is also divisible by 8
We'll try one more. Try 56
a = 5
b = 6
5 - 2*6 = 5 - 12 = - 7
- 7 is divisible by 7 so 56 must be as well. What I'm wondering is if the rule in some form works for 735 and if it does how?
a = 73
b = 5
73 - 10 = 63
63 is divisible by 7 (giving 9)
so 10*73 + b is divisible by 7.
Try something a bit harder.
115444
a = 11544
b = 4
a - 2*4
11544 - 8
11536 / 7
1648 which works perfectly.
115444 is divisible by 28 which is a multiple of 7
Really amazing! Thanks for posting.
Solve the inequality.
q + 12 - 2(q - 22) > 0
a.)9 <-32
b.)9 < 56
c.)9> -32
d.)9 > 56
[tex]\\ \sf\longmapsto q+12-2(q-22)>0[/tex]
[tex]\\ \sf\longmapsto q+12-2q+44>0[/tex]
[tex]\\ \sf\longmapsto q-2q+12+44>0[/tex]
[tex]\\ \sf\longmapsto -q+56>0[/tex]
[tex]\\ \sf\longmapsto -q>-56[/tex]
[tex]\\ \sf\longmapsto q<56[/tex]
If 24n-¹ + 3 = 7 What is the value of n
Answer:n=6
Step-by-step explanation:
56 is less than the square of 10
Need helppppp asappppppp
Answer:
162
Step-by-step explanation:
because this is a parallelogram :
m<2 = m<4 so
4x - 22 = 3x - 12
4x - 3x = 22 - 12
x = 10 replace x with 10 in the equation for m<4
3x - 12 is 30 - 12 = 18
m<4 and m<1 are supplementary and their sum is equal to 180
m<4 + m<1 = 180
m<1 = 180 - 18
m<1 = 162
Given two consecutive integers whose sum is 92, find the larger of the two integers.
Write down a decimal that is more than 7/11 and less than 7/9
will award brainiest!!
Answer:
0.7
Step-by-step explanation:
7/11 = 0.63636363
7/9 = 0.777777778
so a decimal between them will be, 7/10 = 0.7
Find the equation of the line:
through (5, -1) and (2, 2).
Answer:
y = -x + 4
Step-by-step explanation:
(x₁,y₁)= (5, - 1) & (x₂,y₂)= (2 , 2)
Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]\frac{2-[-1]}{2-5}\\\\=\frac{2+1}{-3}\\\\=\frac{3}{-3}\\\\= -1[/tex]
m = -1
Equation of the line y - y₁ = m(x - x₁)
y - [-1] = (-1)*(x - 5)
y + 1 = -x + 5 {-1 is distributed}
y = -x + 5 - 1
y = -x + 4
f(x)=-4+7, what is f(2)
Answer:
3
Step-by-step explanation:
7-4
if √x-5 varies directly as y and x=30 when y= 2, find the value of x when y=8.
Answer:
let,
√x-5=ky
x=30 when y=2
√30-5=2k
or, k=(√30-5)/2
now, when y=8
√x-5=8×(√30-5)/2
or, √x-5=4√30-20
or, √x=4√30-15
or, x=(4√30-15)²
or, x=47.73..
Multiply the polynomial by distribution. Show your work and explain the steps you used to solve.
- 8x(x^2 – 8x + 3)
Answer:
-8x^3 + 64x^2 - 24x
Step-by-step explanation:
To distribute, we must multiple -8x to each term:
-8x(x^2) - 8x(-8x) - 8x(3)
-8x^3 + 64x^2 - 24x
Step-by-step explanation:
[tex] - 8x( {x}^{2} - 8x + 3) \\ = ( - 8x \times {x}^{2}) - ( - 8x \times 8x) + ( - 8x \times 3) \\ = - 8 {x}^{3} + 64 {x}^{2} - 24x[/tex]
distribute -8x to each term in the perenthesis i.e. multiply each term by -8x
Find the area of the rectangle with the length 2x-4 and height of -3
Answer:
-3(2x-4) or -6x+12
Step-by-step explanation:
Area is H*W
theres no value for x so that would be it, unless there is then all you do is plug that into the answer I put.
what is the bionomial expansion of (x-1y)^2
Answer:
[tex] {(x - y)}^{2} \\ = (x - y)(x - y)[/tex]
open the brackets:
[tex] = ( {x}^{2} - xy - xy + {y}^{2} ) \\ = {x}^{2} - 2xy + {y}^{2} [/tex]
