What is the area of the obtuse triangle given below? ​

Answer:

d

Step-by-step explanation:

Answer:

the person above me is correct

Step-by-step explanation:

cus I know

Within similar triangles, the angles are the same. So, we need to look at the side lengths then.

72 to 12

66 to 11

42 to 7

In each pair of corresponding side lengths, the original side length from triangle ABC is divided by 6 (or multiplied by 1/6) to get the smaller side length on triangle DEF.

The scale factor from ABC to DEF is 1/6.

Hope this helps!

Answer:

x = 3

Step-by-step explanation:

Step-by-step explanation:

3(8x-8)/2=64

3(8x-8)=64×2

24x-24=128

24x=128+24

24x=152

24x/24=152/24

x=6.3

Answer:

the center is -1,1 and the radius is 4 i think

Step-by-step explanation:

Answer:

=x^2 +4x+11

Step-by-step explanation:

f(x) = x^2 + 7,

Replace x with x+2

f(x+2) = (x+2)^2 + 7

         = (x+2)(x+2) +7

     FOIL

     = x^2 +2x+2x+4 +7

Combine like terms

    =x^2 +4x+11

Answer:

[tex]f(x+2)=x^2+4x+11[/tex]

Step-by-step explanation:

In [tex]f(x)=x^2+7[/tex], for all values of [tex]x[/tex], we substitute [tex]x[/tex] (what is in the parentheses) into [tex]x^2+7[/tex] to output a [tex]y[/tex] value.

In [tex]f(x+2)[/tex], the term [tex](x+2)[/tex] is in the parentheses. Therefore, substitute [tex](x+2)[/tex] for [tex]x[/tex] in [tex]x^2+7[/tex] to find [tex]f(x+2)[/tex]:

[tex]f(x+2)=(x+2)^2+7[/tex]

Expand using [tex](a+b)^2=a^2+2ab+b^2[/tex],

[tex]f(x+2)=x^2+4x+4+7[/tex]

Combine like terms:

[tex]\boxed{f(x+2)=x^2+4x+11}[/tex]

Answer:

Step-by-step explanation:

Answer:

cuadradas 777,2 unidades

Step-by-step explanation:

Answer:

67.7

Step-by-step explanation:

i just took the quiz

Answer:

Q.5

Step-by-step explanation:

(2x)^3+3×(2x)^2×3y+3×2x×(3y)^2+(3y)^3

8x^3+3×4x^2 × 3y + 3×2x×9y^2 + 27y^3

8x^3 + 36x^2 × y + 54xy^2 + 27y^3

Answer:

Traversable because it has exactly two odd nodes

Step-by-step explanation:

There is a rule that says it is traversable if it has exactly 2 odd nodes. The are other rule where it can be traversable is if has no odd nodes.

Also if we let the starting point be D and the ending point be B we can travel the network in such way that each edge is only traveled once which is the definition that the network is traversable.

So I will do this by starting at D, then travel to A using the outside edge, then travel to back to D using inside edge, then travel to C, then travel to B, then travel to A using outside edge, and then back to B from A using inside edge.

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3

Answer:

Step-by-step explanation:

If the product of 2 integers is -12, then that equation looks like this:

xy = -12

If the sum of those same 2 integers in 1, then that equation looks like this:

x + y = 1

Let's solve the second equation for x and plug it into the first equation. Solving the second equation for x gives us

x = 1 - y and plug that into the first equation in place of x to get:

(1 - y)y = -12 and

[tex]y-y^2=-12[/tex] Now move everything over to one side and factor to find y:

[tex]-y^2+y+12=0[/tex] and the 2 values for y are

y = -3 and y = 4. Let's see what happens when we solve for x.

If xy = -12 and y is -3:

x(-3) = -12 so

x = 4

If xy = -12 and y is4:

x(4) = -12 so

x = -3

So it looks like the 2 integers are -3 and 4

Answer:

B: Jorge could count how far each pre-image point is from the line of reflection along the perpendicular from the point to the line of reflection.

D: Jorge will not move any point that lies on the line of reflection.

E: Jorge could check his work by seeing if each segment joining a pre-image point with its image has the midpoint on the line of reflection.

Step-by

i just took the test lol

Answer:

BDE are the answeres

Step-by-step explanation:

took the quiz

Answer:

2x+5x^2=1

2x+5x*5x=1

2x+25x=1

27x=1

1/27=x

Hope This Helps!!!

Answer:

D. 24

Hope it helps!

Answer:

The length of tape to wrap = 5 cm

Step-by-step explanation:

Let the length of tape used to wrap 1 present be = x

Tape length            Number of presents

   15 cm                            3

      x                                 1

     [tex]\frac{15}{x} = \frac{3}{1} \\\\x \times 3 = 1 \times 15\\\\x = \frac{15}{3} = 5 \ cm[/tex]

Answer:

F

Step-by-step explanation:I just took the test

Answer:

x = 9

Step-by-step explanation:

The ratios of corresponding sides are equal, that is

[tex]\frac{BC}{MN}[/tex] = [tex]\frac{AB}{LM}[/tex] , substitute values

[tex]\frac{x}{15}[/tex] = [tex]\frac{6}{10}[/tex] ( cross- multiply )

10x = 90 ( divide both sides by 10 )

x = 9

Answer:

B.

Step-by-step explanation:

Answer:

If you are talking about inequalities, t < r.

Step-by-step explanation:

Since s is bigger than t and r is bigger than s,

r should be bigger than t obviously.

Answer:

The probability of a person getting their own hat is 1/5 or 20%.

Step-by-step explanation:

If each person has one hat the chances (the probability) of them getting their own hat would be 20%. The chances (the probability) of them getting a hat that belongs to one of the other four students would be 80%. Due to there being 5 hats each person owns 1 hat so there would be a 1 out of 5 chance of them getting their own hat.

Answer:

38

Step-by-step explanation:

6⅓÷⅙

change 6⅓ to improper fraction

19/3÷1/6

keep the first fraction, change the division sign to multiplication and reciprocate/flip the second fraction

19/3× 6/1

the denominator 3 and numerator 6 will simplify/cancel each other

the new fraction is now: 19/1 × 2/1

there is no need to multiply the denominators because it will still be equal to 1 so we just need to multiply the numerators by each other

19×2=38 OR 38/1 (both answers are the same)

Answer:

In picture

Step-by-step explanation:

Brainliest please~

[tex](0,3)[/tex] and [tex](1,-2)[/tex]

Equation: (refer the image below)

Slope:

[tex]m=\frac{3+2}{0-1}[/tex]

[tex]m=-5[/tex]

Equation:

[tex]y=5x-b[/tex]

[tex]3=b[/tex]

Substitute (0,3)

Point: [tex](1,-2)[/tex]

Answer:

y = -1/3x - 2/3

Step-by-step explanation:

y = -1/3x + b

-2 = -1/3(4) + b

-2 = -4/3 + b

-2/3 = b

Answer:

Collect like terms 5 p 2 − p 2

Step-by-step explanation:

#CarryOnLearning

Answer:

x + 5y -18=0

Step-by-step explanation:

Two points are given to us and we need to find the equation of the line. The given points are (6,3) and (-6,6) . Firstly let's find out the slope of the line .

Finding slope :-

[tex]\implies Slope = \frac{ y_2-y_1}{x_2-x_1} \\\\\implies Slope =\frac{ 3-6}{6+6} \\\\\sf\implies Slope =\frac{ -3}{12} \\\\\sf\implies Slope = \dfrac{-1}{4} [/tex]

Using point slope form :-

[tex]\implies y - y_1 = m( x - x_1 ) \\\\\sf\implies y - 3 = \dfrac{-1}{4}( x - 6)\\\\\sf\implies 4y - 12 = 6 - x \\\\\sf\implies x + 4y -12-6=0 \\\\\sf\implies\underline {\underline{ x + 5y -18=0}}[/tex]

Answer:

(5, -5)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

2x - 3y = 25

5x + 3y = 10

Step 2: Solve for x

Elimination

Step 3: Solve for y

Answer:

(5,-5)

Step-by-step explanation:

Hi there!

We are given this system of equations:

2x-3y=25

5x+3y=10

and the question asks to solve it by elimination

To solve by elimination, we will add the equations together to clear one variable, solve for the variable that wasn't cleared, then use the value of the variable that wasn't cleared to solve for the variable that was cleared earlier

Before we clear a variable, the coefficients  in front of the variable that we want to clear need to be opposites (ex. if we wanted to clear x, the coefficients of x in the systems have to be -2 and 2, as that would equal 0).

In this case, the coefficients in front of y in the equations are -3 and 3 respectively. That equals 0, so y would be cleared if we added the equations together

so we don't have to multiply or divide by anything prior to clearing

Let's add the equations together. Remember that y will be cleared, as (-3y+3y=0)

2x-3y=25

+

5x+3y=10

______________

7x+0=35

subtract 0 from both sides

7x=35

divide both sides by 7

x=5

we found the value of x

now we need to find the value of y

substitute 5 as x into either one of the equations to solve for y

if we were to do it into 2x-3y=25 for instance,

2(5)-3y=25

multiply

10-3y=25

subtract 10 from both sides

-3y=15

divide both sides by -3

y=-5

So the answer is x=5, y=-5, or as point (5,-5)

Hope this helps! :)

Answer:

[tex] {y}^{2} = - 2x + 5[/tex]

Step-by-step explanation:

vertex = [tex]( \frac{5}{2} \: ,0)[/tex]

Answer:

The answer is A :)

Step-by-step explanation:

Answer:

A whole number is even if and only if it is evenly divisible by 2

Step-by-step explanation:

BRAINLY

JannetPalos

Ambitious

808 answers

526.6K people helped

Answer:

A whole number is even if and only if it is evenly divisible by 2

Step-by-step explanation:

1.  The first statement is false because product of two negative integers is positive.

Ex:

(- 2) × (- 3) = 6

2.  The second statement is false because there are whole numbers which are divisible by 2 but not divisible by 4.

Ex:

6 is divisible by 2 but not divisible by 4

3.  The fourth statement is false because if a whole number is divisible by 2, then, by definition, it must be an even number.

Ex:

6 is divisible by 2 and hence it is an even number

4.  The third statement is true because if a whole number is divisible by 2, then, by definition, it must be an even number.

Ex:

6 is divisible by 2 and hence it is an even number

Answer: (1, 8)

Step-by-step explanation:

Substitute y = 3x + 5 into the equation 2x + 3y = 26:

2x + 3(3x + 5) = 26

2x + 9x + 15 = 26

11x = 26 - 15

11x = 11

x = 1

Substitute the value of x into the equation y = 3x + 5:

y = 3(1) + 5 = 3 + 5 = 8

[tex]\sf \bf {\boxed {\mathbb {GIVEN:}}}[/tex]

Sum of three consecutive odd integers = [tex]27[/tex]

[tex]\sf \bf {\boxed {\mathbb {TO\:FIND:}}}[/tex]

The values of the three integers.

[tex]\sf \bf {\boxed {\mathbb {SOLUTION:}}}[/tex]

[tex]\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

Let us assume the three consecutive odd integers to be [tex]x[/tex], [tex](x+2)[/tex] and [tex](x+4)[/tex].

As per the condition, we have

[tex]Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27[/tex]

[tex]➺ \: x + (x + 2) + (x + 4) = 27[/tex]

[tex]➺ \: x + x + 2 + x + 4 = 27[/tex]

Now, collect the like terms.

[tex]➺ \: (x + x + x) + (2 + 4) = 27[/tex]

[tex]➺ \: 3x + 6 = 27[/tex]

[tex]➺ \: 3x = 27 - 6[/tex]

[tex]➺ \: 3x = 21[/tex]

[tex]➺ \: x = \frac{21}{3} \\[/tex]

[tex]➺ \: x = 7[/tex]

Therefore, the three consecutive odd integers whose sum is [tex]27[/tex] are [tex]\boxed{ 7 }[/tex], [tex]\boxed{ 9 }[/tex] and [tex]\boxed{ 11 }[/tex] respectively.

[tex]\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}[/tex]

[tex]⇢ 7 + 9 + 11 = 27[/tex]

[tex]⇢ 27 = 27[/tex]

⇢ L. H. S. = R. H. S.

[tex]\sf\blue{Hence\:verified.}[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]

Answer:

38.5

Step-by-step explanation:

b^2= 29^2+20^2-2×20×29× Cos 102

b^2=841+400-1160 (-0.2079)

=1241- 241.164

b^2=1482.164

b= square root of 1482.164

AC = 38.5