what is the area of the trapezoid?

Answer:

It will be 31.4 cm rounded off for circumference

It will be 78.53 cm2 rounded off for area

Step-by-step explanation:

Diameter = 10 cm

Radius = 10/2 cm = 5 cm

Circumference = 2×pi×radius

= 2pi×5

= 31.4 cm

Area = pi × r square

= 25 pi

= 78.53cm2

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Answer:

  1 -√2

Step-by-step explanation:

  [tex]\tan(x/2)=\dfrac{1-\cos(x)}{\sin(x)}\\\\\tan\left(\dfrac{1}{2}\cdot\dfrac{7\pi}{4}\right)=\dfrac{1-\cos\dfrac{7\pi}{4}}{\sin\dfrac{7\pi}{4}}=\dfrac{1-\dfrac{1}{\sqrt{2}}}{-\dfrac{1}{\sqrt{2}}}=\boxed{1-\sqrt{2}}[/tex]

tan(7π/8) = 1 -√2

Answer:

The correct label of the line is CD

Answer:

D

Step-by-step explanation:

everything seems to be correctly filled.

if you wanted confidence by confirmation: here, take some

It is an exponentially decaying function.

An exponential function is where the independent variable is in the exponent. Generally the the independent variable is in the power of a constant term e.

Exponential functions are of two types one is exponentially growing function and exponentially decaying function.

when the we have a positive exponent the function is exponentially growing and when we have a negative exponent the function is exponentially decaying.

In the given question f(x) = 8e⁻ˣ

when, x = 0 f(x) = 8

f(x) = 8e⁻ˣ

f(0) = 8e⁰

f(0) = 8

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Answer:

y=-2x+1

Step-by-step explanation:

The slope of the line is - 2. The y intercept is 1. Hence the equation is y=-2x+1

Answer:

f(x) = 3ex - e

Step-by-step explanation:

In this equation we have basically the times e by 3x and -1

so first let's do e times 3x

here...

e X 3x = 3ex

so let's rewrite the equation

3ex - 1

now we times e by 1. (Note - Negative sign stays)

3ex - 1e

we don't have to write 1e cause 1e = e, they are the same.

Therefore the answer is 3ex - 1e

Following are the calculation of inverse:

Given:  

[tex]\to f(x)=e^{3x-1}[/tex]

To find:

inverse function=?

Solution:

A function g is the inverse of function F if for [tex]y=f(x), x=g(y)[/tex]

[tex]\to y=e^{3x-1}[/tex]

Replacing the value of x with y  

[tex]\to x=e^{3y-1}[/tex]

Solve for [tex]y, x=e^{3y-1}[/tex]

Therefore, the answer is [tex]\frac{\log(x)+1}{3}[/tex].

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Answer: multiply 631.6 by 0.8​ = 505.28

Answer:

Option c, Scheme C

Step-by-step explanation:

scheme A: 45000/6 = 7500 per month

scheme B: 46800/9 = 5200 per month

scheme C: 48000/12 = 4000 per month

Answer:

Terry misappropriately represented the ratio on the left-hand side. Instead of 16/4, he wrote 4/16.

4+z/y = 36/18

Step-by-step explanation:

a) Since both triangles are similar triangles, then the ratio of their similar sides is equal to a constant k. Therefore:

16/4 = 18/y

Note that the arrangement depends on which of the triangles sides cones first.

Terry misappropriately represented the ratio on the left-hand side. Instead of 16/4, he wrote 4/16.

b) Same rule in (a) applies to the sum as well. Hence;

4+z/y = 16+20/18

4+z/y = 36/18

Answer:

x = 8ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Answer:

x=4

Step-by-step explanation:

2x-2+x+2x-2+x=3+7+3+7

6x-4=20

6x=24

x=4

The value of g across from angle G is 5feet

According to sine rule

[tex]\frac{e}{sinE}=\frac{f}{sinF}=\frac{g}{sinG}[/tex]

Given the following

∠G = 45°

∠F = 82°

f = 7feet

Required

side g

Substitute the given values into the formula

[tex]\frac{f}{sinF}=\frac{g}{sinG}\\ \frac{7}{sin82}=\frac{g}{sin45}\\\frac{7}{0.9903}=\frac{g}{0.7071}\\7.0686=\frac{g}{0.7071}\\g=7.0686*0.7071\\g=4.998\\g\approx5ft[/tex]

Hence the value of g across from angle G is 5feet

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The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

Let be [tex]EFG[/tex] a Triangle, whose expression derived from the Law of Sines is described below:

[tex]\frac{e}{\sin E} = \frac{f}{\sin F} = \frac{g}{\sin G}[/tex] (1)

Where:

[tex]e[/tex] - Measure of the line segment FG, in feet.

[tex]f[/tex] - Measure of the line segment EG, in feet.

[tex]g[/tex] - Measure of the line segment EF, in feet.

[tex]E[/tex] - Angle at vertex E, in sexagesimal degrees.

[tex]F[/tex] - Angle at vertex F, in sexagesimal degrees.

[tex]G[/tex] - Angle at vertex G, in sexagesimal degrees.

We can determine a missing length, by knowing the length of a neighboring side and two consecutive angles. If we know that [tex]f = 7\,ft[/tex], [tex]G = 45^{\circ}[/tex] and [tex]F = 82^{\circ}[/tex], then the measure of the line segment EF is:

[tex]g = f\cdot \left(\frac{\sin G}{\sin F} \right)[/tex] (2)

[tex]g = (7\,ft)\cdot \left(\frac{\sin 45^{\circ}}{\sin 82^{\circ}} \right)[/tex]

[tex]g\approx 4.998\,ft[/tex]

[tex]g \approx 5\,ft[/tex]

The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

Answer:

B) C and G

Step-by-step explanation:

The radius is equal to 1/2 the diameter

r = 1/2 d

G has a diameter of 45

1/2 (45) = 22.5

C and G are the same

Answer:

c and g!

Step-by-step explanation:

Answer:

Ture

Step-by-step explanation:

The rates of the same participatant are paired.

Answer:

Step-by-step explanation:

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Answer:

  y = -1

Step-by-step explanation:

We assume you want the line with a slope of zero. That is a horizontal line, so y is a constant. In order to make the line go through the point with y=-1, the equation of the line is ...

  y = -1

Answer:

15,300 units

Step-by-step explanation:

First, find how many units of Product B were sold:

34,000(0.3)

= 10,200

Find how many units of Product A were sold:

10,200(1.5)

= 15,300

So, 15,300 units of Product A were sold.

Product A  sold 15,300 units that is 1.5 times more than product B

Given :

Product A sells 1.5 times more than Product B. Product B sells 70% less than Product C.

Product C sold 34,000 units this month

Product C sold = 34000

Product B is 70% less than product C

So, product B is 100-70% =30% of product C

[tex]Product B=\frac{30}{100} \cdot 34000\\Product B \; sold = 10200[/tex]

Lets find out product A sold

Product A sold = 1.5 times more than product B

[tex]Product A= 1.5 \cdot product B\\Product A=1.5 \cdot 10200=15300[/tex]

15,300 units of product A were sold.

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Step-by-step explanation:

here's the answer to your question

C.

Observe that the roots of polynomial are [tex]-3,2,5[/tex]

We have a polynomial in a factored form,

[tex](x+3)(x-2)(x-5)[/tex]

If you substitute x for any of [tex]-3,2,5[/tex] the product will always equal to zero that is these numbers are roots of polynomial.

Hope this helps :)

Answer:

Step-by-step explanation:

Is the function f(x) = 3x+1, f(x) = 3ˣ⁺¹, or f(x) = 3ˣ+1 ?

f(x) = 3x+1 is not an exponential function. It is a straight line.

f(x) = 3ˣ⁺¹ Is an exponential function. The base is 3.

f(x) = 3ˣ+1 is an exponential function. The base is 3.

Answer:

2(w+3)

Step-by-step explanation:

2(w+3) or 2w+6

Let

We know

[tex]\boxed{\sf Area =Length\times Width}[/tex]

[tex]\\ \sf\longmapsto x(8x-38)=4050[/tex]

[tex]\\ \sf\longmapsto 8x^2-38x=4050[/tex]

[tex]\\ \sf\longmapsto 8x^2-38x-4050=0[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{81}{4}\:or\:x=25[/tex]

[tex]\\ \sf\longmapsto Length=8x-38=8(25)-38=200-38=162m[/tex]

log₉(x - 7) + log₉(x - 7) = 1

2 log₉(x - 7) = 1

log₉(x - 7) = 1/2

Take the base-9 antilogarithm of both sides; in other words, make both sides powers of 9:

[tex]9^{\log_9(x-7)} = 9^{1/2}[/tex]

[tex]9^{1/2}[/tex] can also be written as √9 = 3, and [tex]b^{\log_b(a)}=a[/tex], so the equation reduces to

x - 7 = 3

Solve for x :

x = 10

Answer:

Both are true.

Step-by-step explanation:

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Answer:

  x, y ∈ all real numbers

Step-by-step explanation:

For your function ...

  f(x, y) = 2x^3·y -xy

there appear to be no values of x or y for which the function is undefined. The domain for both x and y is "all real numbers."

Answer:

Step-by-step explanation:

No that is true. I can't make anything more out of it.

Step-by-step explanation:

Consuelo Butler

08/07

Homework: Practice

Exam 3

Question 1, 12.1.13

HW Score: 10%, 3 of 30 points

Score: 1 of 1

A professor had students keep track of their social interactions for a week. The

number of social interactions over the week is shown in the following grouped

frequency distribution. How many students had at least 60 social interactions for

the week?

12

Number of Social

Interactions

30-34

35-39

40-44

45-49

50-54

55-59

60-64

65-69

70-74

75-79

Frequency

9

14

11

15

16

8

7

By calculating the greater than cumulative frequency using the given frequency table, 12 students had at least 60 social interactions for the week.

The greater than cumulative frequency is also known as the more than type cumulative frequency. Here, the greater than cumulative frequency distribution is obtained by determining the cumulative total frequencies starting from the highest class to the lowest class.

Class interval     Frequency     Cumulative frequency

30-34                9                   85

35-39                14                   76

40-44                11                   62

45-49                15                   51

50-54                16                   36

55-59                 8                   20

60-64                 7                   12

65-69                 3                    5

70-74                  1                    2

75-79                  1                     1

[We read the cumulative frequencies with respect to the corresponding lower class limits. For example, 85 students had 'more than 30' social interactions, 76 students had 'more than 35 social interactions and so on.]

By reading the greater than cumulative frequency, we find that 12 students had at least 60 social interactions for the week.

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