What is the dependent variable in this
experiment?
DONE
Biologists designed an experiment to test
the effect of compost on the development
of root crops. They tested several different
crops, including carrots, potatoes, beets,
and onions. They grew most of the plants
in the greenhouse, but due to space issues,
they had to grow some outdoors. They gave
all the plants the same amount of compost.
They obtained the compost from a local
farmer and from the local hardware store.
They ran out of the farmer's compost, so
some of the plants received that compost
when the seeds were planted and other
plants got hardware store compost after
the plants had already started growing.
What is the independent variable in this
experiment?
DONE

the order of vector addition doesn't affect the resultant vector and grouping or order of pair doesn't effect the sum.

Answer:

Both have equal impulse.

Explanation:

Let the mass of cars be m.

Then the Force acting on each of them for taking them to state of rest:

(Using Newton's second law of motion)

[tex]F_A=\frac{m\times (0-30)}{\Delta t_A}[/tex]

[tex]F_A=-30\frac{m}{\Delta t_A}[/tex] ...................................(1) (negative sign is associated with direction, here we are concerned about the magnitude only)

[tex]F_B=\frac{m\times (0-30)}{\Delta t_B}[/tex]

[tex]F_B=-30\frac{m}{\Delta t_B}[/tex] ...................................(2)

[tex]\because \Delta t_A<\Delta t_B[/tex]

[tex]\therefore F_A>F_B[/tex]

We know that impulse is given as:

[tex]J=F\times \Delta t[/tex] ........................................(3)

So, from eq. (1), (2) & (3)

[tex]J_A=F_A\times \Delta t_A[/tex]

[tex]J_A=-30m[/tex]

&

[tex]J_B=F_B\times\Delta t_A[/tex]

[tex]J_B=-30m[/tex]

Hence both have equal impulse.

Answer:

[tex]V.E=498.02m/s^2[/tex]

Explanation:

From the question we are told that:

Radius [tex]r=301Km[/tex]

Gravitational acceleration [tex]g=0.412 m/s^2[/tex]

Generally the equation for Escape velocity is mathematically given by

 [tex]V.E^2=2gr[/tex]

 [tex]V.E^2=2*0.412m/s^2*301000[/tex]

 [tex]V.E^2=248024[/tex]

 [tex]V.E=\sqrt{248024}[/tex]

 [tex]V.E=498.02m/s^2[/tex]

Answer:

Yes it would be different on Earth and the moon

Answer:

yes

Explanation:

Answer:

F = 0.414 N

Explanation:

Given that,

Magnetic flux density,[tex]B=3.6\times 10^{-2}\ T[/tex]

The length of the wire, l = 24 m

Current, I = 0.48 A

We need to find the force acting on the wire. The formula for the force is given by:

[tex]F=ILB[/tex]

Put all the values,

[tex]F=0.48\times 24\times 3.6\times 10^{-2}\\\\F=0.414\ N[/tex]

So, the force acting on the copper wire is equal to 0.414 N.

The magnetic force of the copper wire is  41.472 N.

The magnetic force of the copper wire is calculated by applying the following equation.

F = BIL x sinθ

Where;

F = (3.6 x 10⁻²) x (48) x 24 x sin(90)

F = 41.472 N

Thus, the magnetic force of the copper wire is  41.472 N.

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Answer:

The measurement of first cylinder is more accurate.(A)

Explanation:

The least possible error higher will be accuracy.

Answer:

The experimental scientist

Answer:

[tex]N_B-W_B = 0[/tex]

Explanation:

There are two forces acting on object B. If we consider the law of equilibrium, then the two forces must be equal in magnitude, for the object to remain in equilibrium position:

[tex]N_B = W_B\\\\N_B-W_B = 0[/tex]

Therefore, the correct answer of the given question, from the given choices, is:

[tex]N_B-W_B = 0[/tex]

Answer:

below

Explanation:

that is the procedure above

Answer:

Explanation:

Assuming the squirrel is jumping off the ground, here's what we know but don't really know...

v₀ = 4.0 at 50.0°

So that's not really the velocity we are looking for. We are dealing with a max height problem, which is a y-dimension thing. Therefore, we need the squirrel's upward velocity, which is NOT 4.0 m/s. We find it in the following way:

[tex]v_{0y}=4.0sin(50.0)[/tex] which gives us that the upward velocity is

v₀ = 3.1 m/s

Moving on here's what we also know:

a = -9.8 m/s/s and

v = 0

Remember that at the very top of the parabolic path, the final velocity is 0. In order to find the max height of the squirrel, we need to know how long it took him to get there. We are using 2 of our 3 one-dimensional equations in this problem. To find time:

v = v₀ + at and filling in:

0 = 3.1 - 9.8t and

-3.1 = -9.8t so

t = .32 seconds.

Now that we know how long it took him to get to the max height, we use that in our next one-dimensional equation:

Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] and filling in:

Δx = [tex]3.1(.32)+\frac{1}{2}(-9.8)(.32)^2[/tex] and using the rules for adding and subtracting sig fig's correctly, we can begin to simplify this:

Δx = .99 - .50 so

Δx = .49 meters

Explanation:

soln,

weight=600N

mass=?

gravity=9.8 m/s²

now,

hope it helps.

Answer:

m = 61.22 kg

Explanation:

F = 600 N

g = 9.8 m/s²

m = ?

F = mg

600 = m(9.8)

---> m = 61.22 kg

Answer:

In coin card experiment smooth card is used so that the card can slide easily from glass

Answer:

Explanation:

mass and distance

Answer:

a. 0.8 cm

Explanation:

The distance of the object from the lens, u = 1 cm

The magnification of the lens, m = 5

The focus of a lens formula is given as follows;

[tex]f = \dfrac{1}{\dfrac{1}{v} + \dfrac{1}{v} }[/tex]

The magnification of the lens, m = -v/u

Where;

v = The distance of the image from the lens

Therefore, we have;

v = m × u

∴ v = 5 × 1 cm = 5 cm (on the other side of the lens)

From which we get;

[tex]f = \dfrac{1}{\dfrac{1}{1} + \dfrac{1}{5} } = \dfrac{5}{6} \approx 0.8[/tex]

The focal length ≈ 0.8 cm

Answer:

Explanation:

First I need to tell you that I used .20 s for the period of rotation instead of just .2, and I used 30.0 kg for the mass instead of just 30. The reason being that both those numbers as stated in the problem only have 1 significant digit and that's not generally enough to get the accuracy you're looking for. Adding a 0 to the ends of each of those numbers doesn't change the value of the numbers, only the number of sig fig's in each. Beginning with a:

a. [tex]f=\frac{1}{T}[/tex] so [tex]f=\frac{1}{.2}[/tex] and f = 5.0 Hz

b. The circumference is the distance around the outside of the washer's drum. We need to find that, but before we do, I'm going to state the radius in meters instead of cm. 35 cm = .35 m. Therefore,

C = 2(3.1415)(.35) so

C = d = 2.2 m

c. The speed of the washer is found in d = rt, where r is the rate and our velocity and d is the distance around the outside of the drum (circumference). Therefore,

2.2 = v(.20) so

v = 11 m/s

d. The centripetal acceleration has an equation

[tex]a_c=\frac{v^2}{r}[/tex] so

[tex]a_c=\frac{(11)^2}{.35}[/tex] and

[tex]a_c=\frac{121}{.35}[/tex] so

[tex]a_c=350\frac{m}{s^2}[/tex]

e. The centripetal force has an equation

[tex]F_c=\frac{mv^2}{r}[/tex] and

[tex]F_c=\frac{(30.0)(11)^2}{.35}[/tex] and

[tex]F_c=[/tex] 1.0 × 10⁴ N

f. The equation for Power is

[tex]P=\frac{W}{t}[/tex] where W is work and W = FΔx (force times displacement). Therefore,

[tex]P=\frac{(1.0*10^4)(2.2)}{.20}[/tex] so

P = 1.1 × 10⁵ Watts

Answer:

Time = 16.667 seconds

Explanation:

Given the following data;

Distance = 50 meters

Velocity = 3 m/s

To find the time it will take;

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

Velocity = distance/time

Making time the subject of formula, we have;

Time = distance/velocity

Time = 50/3

Time = 16.667 seconds

Answer:

This question is incomplete but the completed question is below

As a girl pushes an object across a wood floor, she suddenly comes to an area where the floor has been waxed recently, making it slippery. What becomes true of the coefficient of kinetic friction? A. The coefficient of kinetic friction increases. B. The coefficient of kinetic friction decreases. C. The coefficient of kinetic friction becomes zero. D. The coefficient of kinetic friction becomes negative.

The correct option is B

Explanation:

Coefficient of kinetic friction can be defined as the frictional force resisted by the motion of an object. From the question, it might take the girl to apply a force equivalent to just half that of the weight of the object to overcome friction to keep the object moving on a wood floor. Once she gets to the waxed area, the frictional force reduces, thereby also reducing the coefficient of kinetic friction further. Thus, she will be able to use less than half of the force (equivalent to less than half of the weight of the object) to push the object.

Thus, the correct option is B.

Answer:

Option (a) is correct.

Explanation:

The electric charge is the inherent property of matter which appears due to the deficiency of charge or the excess number of electrons.

There are two types of charges, positive and negative.

When an object has deficiency of charge it becomes positive charge and when it gains some electrons, it becomes negative charge.

When the charge is in motion, it is called electric current and when the charge is at rest, it is called static current.

A charge at rest contributes the electric field only while the charge is in motion contributes the electric and magnetic field both.

Answer:

the correct answer is B

Explanation:

To solve the system they must have the same amount of unknowns as equations,

a) If the system does not have friction, we must write the x-axis equation for each body, therefore we need to write N equations

b) if the system has friction, two equations are needed for each particle

therefore the correct answer is B

Answer:

40 kW

Explanation:

A railcar has a continuous 1000 N decelerating force any time it is in motion. If no braking occurs, how much power would be required to keep the railcar moving at 40 m/s

Solution:

Power in Physics is the rate of doing work and the work can be mechanical, electrical, etc. The S.I unit of power is the watts (W).

The power required to keep the car moving must match the work done by the friction force (decelerating force) that tends to slow down the railcar.

Work done = Force * displacement

Power = Work done / time = (Force * displacement) / time

Power = Force * (displacement / time)

Power = force * velocity = 1000 N * 40 m/s = 40000 W

Power = 40 kW

Answer:

The number of electrons flowing per second is [tex]4.375\times 10^{18}[/tex].

Explanation:

How many electrons per second pass through a section of wire that carries a current of 0.70 A.?

Current, I = 0.7 A

time, t = 1 s

According to the definition of current, let the charge is q.

q = I t

q = 0.7 x 1 = 0.7 C

Let the number of electrons is n.

[tex]n =\frac{q}{e}\\\\n = \frac{0.7}{1.6\times 10^{-19}}\\\\n = 4.375\times 10^{18}[/tex]

Answer:

The gravitational potential energy (gpe) possessed by an object or body is directly proportional to the height of the object or body.

Explanation:

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

G.P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Generally, the gravitational potential energy (gpe) of an object or body is directly proportional to the height of the object or body. Thus, the gravitational potential energy of a body increases as the height of the body increases.

In conclusion, an object with a higher height would have a higher gravitational potential energy.

The Torque is only produced when the force is applied perpendicular to the moment arm.

The equal and opposite force acting at a point from the axis of rotation is called the moment.

M = F x r

Moment of force is also called as Torque.

Moment arm is the distance of the point of application of force from the axis of rotation of the body.

Thus, the perpendicular component only, produces the torque.

Learn more about moment of force.

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Answer:

[tex]d=58m[/tex]

Explanation:

From the question we are told that:

Initial Speed [tex]U=12m/s[/tex]

Time [tex]T=5.6s[/tex]

Angle [tex]\theta=30[/tex]

Generally the  Newton's equation for motion is mathematically given by

[tex]d=d'+ut+\frac{at^2}{2}[/tex]

[tex]d=12cos30*5.6[/tex]

[tex]d=58m[/tex]

Answer:

The linear speed of the car, v, is 24.26 m/s

Explanation:

Given;

radius of the car's tire, r = 0.330 m

angular speed of the car, ω = 11.7 revolutions/s

The angular speed of the car in radian per second:

[tex]\omega = 11.7 \ \frac{rev}{s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 73.523 \ rad/s[/tex]

The linear speed of the car, v, is calculated as;

v = ωr

v = 73.523 rad/s  x  0.33 m

v = 24.26 m/s

Therefore, the linear speed of the car, v, is 24.26 m/s

Answer:

the answer is 4 acceleration is 0

Explanation:

this is because when parallel line is drawn through x axis the velocity will bw uniform

plz brainliest

Answer:

A

Explanation:

The first thing you have to do is go back and list the resistances correctly. R1 = 20 R2 = 30 and R3 = 10.

Leave the units off if you can't make an omega.

The resistance of a series circuit (that's what this is) is r1 + r2 + r3 = 10 + 20 + 30 = 60 ohms

Now use ohms law.

R = 60 ohms

V = 110 volts.

I = V / R

I = 110/60

I = 1.833 to the nearest 1/10 = 1.8

Answer:

The assertion is true and reason is false.

Explanation:

Assertion: I P+ Q I = I P- QI, then P must be perpendicular to Q.

Reason : The relation will hold even when Q is a null vector.

Now

[tex]\left | P + Q \right |=\left | P - Q \right |\\\\P^2 + Q^2 + 2 P Q cos \theta =P^2 + Q^2 - 2 P Q cos \theta\\\\4 P Q cos \theta = 0 \\\\cos \theta = 0 \\\\\theta = 90 degree[/tex]

So, P and Q are perpendicular to each other.

So, the assertion is true.

Reason is false.