What is the direction and magnitude of the net dipole of CCl2F2

There will be no oxygen in the product. Some of the oxygen will evaporate into the air.

Answer:

1. Milk comes in a range of sizes and forms, and is packaged in a range of materials. Glass bottles, plastic coated paper board, blow mold nonreturnable polyethylene containers, plastic pouches, and returnable rigid polycarbonate containers are among the commercial containers available.

Dont know the answer to the second one sorry :(

Answer:

151 g/mol

Explanation:

In order to solve this problem we need to keep in mind the formula for the boiling point elevation:

Where:

Input the data and calculate m:

We now can calculate the number of moles of the substance, using the definition of molarity:

In this case kg of solvent = 90.0 g / 1000 = 0.090 kg

Finally we calculate the molar mass, using the number of moles and the mass:

Answer:

Kr- Dispersion Forces

H2O- Hydrogen Bonding

CHCI3- Dipole-Dipole Forces

HF- Hydrogen Bonding

C2H6- Dispersion Forces

HBr- Hydrogen Bonding Forces

Explanation:

Dispersion forces occurs in all substances. They are the dominant intermolecular interaction in all non polar substances such as C2H6 and Kr.

Hydrogen bonding occurs when hydrogen is bonded to a highly electronegative atom such as Cl, Br, O etc. It is the dominant intermolecular interaction in HF, HBr and H2O.

Dipole-Dipole interactions occur when a permanent dipole exists in a molecule such as in CHCI3

Answer:

[tex]V_{Na_2S}=368mL[/tex]

[tex]m_{Al_2S_3}=67.3gAl_2S_3[/tex]

Explanation:

Hello there!

In this case, according to the given information, it is possible to realize that the only way for us to calculate the required volume of sodium sulfide, is by calculating the moles of this substance consumed 163 mL of 2.75 mol/L aluminum sulfate by using the definition of molar concentration and the 1:3 mole ratio between these two:

[tex]n_{Na_2S}=0.163L*2.75\frac{molAl_2(SO_4)_3}{L}*\frac{3molNa_2S}{1molAl_2(SO_4)_3} =1.34molNa_2S[/tex]

Now, we divide these moles by the molar concentration of sodium sulfide to obtain the required volume:

[tex]V_{Na_2S}=\frac{1.34molNa_2S}{3.65mol/L} =0.368L=368mL[/tex]

For the last part, we now use the 1:1 mole ratio of aluminum sulfate to aluminum sulfide and the molar mass of the latter (150.158 g/mol) in order to calculate the required mass:

[tex]m_{Al_2S_3}=0.163L*2.75\frac{molAl_2(SO_4)_3}{L}*\frac{1molAl_2S_3}{1molAl_2(SO_4)_3} *\frac{150.158gAl_2S_3}{1molAl_2S_3} \\\\m_{Al_2S_3}=67.3gAl_2S_3[/tex]

Regards!

Answer:

a

Explanation:because i did the test

Answer:

I dont no ma men

Explanation:

Sorry cause a dont no

The more finely divided the solid is, the faster the reaction happens. A powdered solid will normally produce faster reaction than if the same mass is present as a single lump. The powdered solid has a greater surface than the single lump

Explanation:

Mark as brainlist

Answer:

the name for NO is nitrogen monoxide

Answer:

Those two horizontal lines.

Explanation:

Hello there!

In this case, when focusing on these heating curves, it is important to say they tend to have two constant-temperature sections and three variable-temperature sections. Thus, from lower to higher temperature, the first constant-temperature section corresponds to melting and the second one vaporization, whereas the three variable-temperature sections correspond to the heating of the solid until melting, the liquid until vaporization and the gas until the critical point.

In such a way, we infer that the boxes referred to constant temperature are referred to a gain in potential energy, that is, the two horizontal lines.

Regards!

Answer: My sacrifica has been made.

Explanation:

Answer:

H

Explanation:

try not to put your hands on him

Answer:

A wave character exhibited by all particles

Explanation:

The central idea in quantum mechanics is the paradox of wave-particle duality. In quantum mechanics, all particles are believed to also exhibit wavelike characters.

The electron is assumed to behave as a wave hence its position can not be precisely determined according the Heisenberg's uncertainty principle.

These are the underlying postulates that informed Erwin Schrödinger's wave mechanical model of the atom.

Hence, the basic postulate of quantum mechanics is that a wave character is exhibited by all particles.

Answer:

jhhhhhhhhh

Explanation:

dffffffffffffg

Answer:

s = 4.41 g/L.

Explanation:

¡Hola!

En este caso, considerando el escenario dado, se hace necesario para nosotros saber que la posible reacción de disociación la experimenta el cloruro de plomo (II) como se muestra a continuación:

[tex]PbCl_2(s)\rightleftharpoons 2Cl^-(aq)+Pb^{2+}(aq)[/tex]

Lo cual hace que la expresión de equilibrio se calcule como:

[tex]Ksp=[Pb^{2+}][Cl^-]^2[/tex]

Y que en términos de la solubilidad molar, s, se resuelve como:

[tex]1.6x10^{-5}=s(2s)^2\\\\1.6x10^{-5}=4s^3\\\\s=\sqrt[3]{\frac{1.6x10^{-5}}{4} } \\\\s=0.0159molPbCl_2/L[/tex]

Ahora, convertimos este valor a g/L al multiplicarlo por la masa molar del cloruro de plomo (II):

[tex]s=0.0159molPbCl_2/L*\frac{278.1gmolPbCl_2}{1molmolPbCl_2} \\\\s=4.41g/L[/tex]

¡Saludos!

Answer: The factor that lead to cyclopropane being less stable than the other cycloalkanes is the presence of a RING STRAIN.

Explanation:

In organic chemistry, the end carbon atoms of an open aliphatic chain can join together to form a closed system or ring to form cycloalkanes. Such compounds are known as cyclic compounds. Examples include cyclopropane, cyclobutane, cyclopentane and many among others.

Cyclopropane is less stable than other cycloalkanes mentioned above because of the presence of ring strain in its structural arrangement. The ring strain is the spatial orientation of atoms of the cycloalkane compounds which tend to give off a very high and non favourable energy. The release of heat energy which is stored in the bonds and molecules cause the ring to be UNSTABLE and REACTIVE.

The presence of the ring strain affects mainly the structures and the conformational function of the smaller cycloalkanes. cyclopropane, which is the smallest cycloalkane than the rest mentioned above, contains only 3 carbons with a small ring.

Answer:

A. Glucose

Explanation:

Glucose is a monomer and not a polymer. So, option (A) is not a polymer.

Glucose is not a polymer because it is a kind of molecule while Starch , cellulose and DNA are polymers.

The correct answer is option A. Glucose.

Answer:

The concentration of the acid, HCl is 0.013 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nₐ) = 2

The mole ratio of base, Ca(OH)₂ (n₆) = 1

Finally, we shall determine the molarity of the HCl. This can be obtained as follow:

Volume of acid, HCl (Vₐ) = 250 mL

Molarity of base, Ca(OH)₂ (M₆) = 0.118 M

Volume of base, Ca(OH)₂ (V₆) = 13.7 mL

Molarity of acid, HCl (Mₐ) =?

MₐVₐ / M₆V₆ = nₐ/n₆

Mₐ × 250 / 0.118 × 13.7 = 2/1

Mₐ × 250 / 1.6166 = 2

Cross multiply

Mₐ × 250 = 1.6166 × 2

Mₐ × 250 = 3.2332

Divide both side by side 250

Mₐ = 3.2332 / 250

Mₐ = 0.013 M

Thus, the concentration of the acid, HCl is 0.013 M

Answer:

5 and the rest are all set to the same date on your list as the other one to get you a list on for a your special first year week and with a special holiday party holiday

Explanation:

Sorry desperate for points

Answer:

For A: The average molecular speed of Ne gas is 553 m/s at the same temperature.

For B: The rate of effusion of [tex]SO_2[/tex] gas is [tex]1.006\times 10^{-3}mol/hr[/tex]

Explanation:

For A:

The average molecular speed of the gas is calculated by using the formula:

[tex]V_{gas}=\sqrt{\frac{8RT}{\pi M}}[/tex]

     OR

[tex]V_{gas}\propto \sqrt{\frac{1}{M}}[/tex]

where, M is the molar mass of gas

Forming an equation for the two gases:

[tex]\frac{V_{Ar}}{V_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Ar}}}[/tex]          .....(1)

Given values:

[tex]V_{Ar}=391m/s\\M_{Ar}=40g/mol\\M_{Ne}=20g/mol[/tex]

Plugging values in equation 1:

[tex]\frac{391m/s}{V_{Ne}}=\sqrt{\frac{20}{40}}\\\\V_{Ne}=391\times \sqrt{2}=553m/s[/tex]

Hence, the average molecular speed of Ne gas is 553 m/s at the same temperature.

For B:

Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation for this follows:

[tex]Rate\propto \frac{1}{\sqrt{M}}[/tex]

Where, M is the molar mass of the gas

Forming an equation for the two gases:

[tex]\frac{Rate_{SO_2}}{Rate_{Xe}}=\sqrt{\frac{M_{Xe}}{M_{SO_2}}}[/tex]          .....(2)

Given values:

[tex]Rate_{Xe}=7.03\times 10^{-4}mol/hr\\M_{Xe}=131g/mol\\M_{SO_2}=64g/mol[/tex]

Plugging values in equation 2:

[tex]\frac{Rate_{SO_2}}{7.03\times 10^{-4}}=\sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=7.03\times 10^{-4}\times \sqrt{\frac{131}{64}}\\\\Rate_{SO_2}=1.006\times 10^{-3}mol/hr[/tex]

Hence, the rate of effusion of [tex]SO_2[/tex] gas is [tex]1.006\times 10^{-3}mol/hr[/tex]

Answer:

d. none of the above

Explanation:

An electrochemical cell consists of two half-cells, with each cell containing an electrode.

The potential of a single electrode in a half-cell is called the Single electrode potential.

The emf of a cell that consists of two half-cells can be determined by connecting them to a voltmeter.

However, there is no way of measuring the emf of a single half-cell directly.

The only way to determine the emf of a single electrode is to combine it with a standard hydrogen electrode (SHE) and measure it with a voltmeter.

Therefore, the correct option is D "none of the above"

An electrochemical cell consists of two half-cells, with each cell containing an electrode.

An electrochemical cell is a device that can generate electrical energy from the chemical reactions occurring in it, or use the electrical energy supplied to it to facilitate chemical reactions in it.

The potential of a single electrode in a half-cell is called the Single electrode potential.The emf of a cell that consists of two half-cells can be determined by connecting them to a voltmeter.

The only way to determine the emf of a single electrode is to combine it with a standard hydrogen electrode (SHE) and measure it with a voltmeter.

Hence the correct option is D.

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Answer:

Using Newman projections, draw the most stable conformation for each of the following compounds.

(a) 3-methyl pentane, viewed along with the C2-C3 bond.

(b) 3,3-dimethyl hexane, viewed along with the C3-C4 bond.

Explanation:

(a) The structure of 3-methyl pentane is shown below:

In Newman projection, the most stable conformation is staggard conformation.

In staggard conformation, the torsional strain is very less compared to eclipsed conformation.

(b)3,3-dimethyl hexane, viewed along with the C3-C4 bond.

Answer: The instantaneous rate of formation of HBr at 50 s is [tex]1.4\times 10^{-2}M/s[/tex]

Explanation:

From the graph,

Initial rate of the [tex]Br_2[/tex] = 1.0 M

Time when the concentration of [tex]Br_2[/tex] is 0.5 M (half the concentration ) = 60 sec

For first order reaction:

Calculating rate constant for first order reaction using half life:

[tex]t_{1/2}=\frac{0.693}{k}[/tex] .....(1)

[tex]t_{1/2}[/tex] = half life period = 60 s

k = rate constant = ?

Putting values in equation 1:

[tex]k=\frac{0.693}{60s}\\\\k=0.01155s^{-1}[/tex]

For the given chemical reaction:

[tex]H_2(g)+Br_2(g)\rightarrow 2HBr(g)[/tex]

Rate of the reaction = [tex]-\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}[/tex]

Negative sign represents the disappearance of the reactants

From the above expression:

[tex]k[Br_2]=-\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}[/tex]

At 50 seconds, [tex][Br_2]=0.6 M[/tex]

Plugging values in above expression, we get:

[tex]\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}=0.01155\times 0.6\\\\\frac{\Delta [HBr]}{\Delta t}=2\times 0.01155\times 0.6=0.01386=1.4\times 10^{-2}M/s[/tex]

Hence, the instantaneous rate of formation of HBr at 50 s is [tex]1.4\times 10^{-2}M/s[/tex]

Answer:

This answer is "True"

Answer:

has 5, ans 3 decimals.

thats as simple as i can put it.

Answer:

Explanation:You can download the ly/3fcEdSxans[tex]^{}[/tex]wer here. Link below!

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According to molar concentration, there are 0.0406 moles of base used in the titration.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Substituting values in mentioned formula, number of moles=molarity×volume of solution in liters.

∴number of moles=0.125×0.3250=0.0406 moles

Thus, 0.0406 moles are used in the titration.

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Answer:

2.85 mol

Explanation:

Step 1: Given data

Mass of sulfur tetrafluoride (SF₄): 309 g

Step 2: Calculate the number of moles corresponding to 309 g of sulfur tetrafluoride

To convert mass to moles we need a conversion factor: the molar mass. The molar mass of SF₄ is 108.07 g/mol.

309 g × 1 mol/108.07 g = 2.85 mol

Answer:

pOH = - log[OH-]

[OH-] = 0.6M

[tex]pOH \: = - log(0.6) \\ = 0.2218487496 \\ pH \: + pOH \: = 14 \\ pH \: + 0.221848749 = 14 \\ pH = 14 - 0.221848749 \\ = 13.77815125 \\ 13.8[/tex]