What is the direction of the magnetic field due to the positive charge at the location of the negative charge

Answers

Answer 1

Answer:

A positively charged object moving due west in a region where the Earth's magnetic field is due north experiences a force that is straight down as shown.

A negative charge moving in the same direction would feel a force straight up.

Related Questions

Answer the question plz

Answers

Answer:

b and d

Explanation:

Si la rapidez del sonido en el agua es de 1450 m/s. ¿Cuánto tiempo tardará en recorrer 500 m en el fondo del lago?

Answers

Answer:

2.9

Explanation:

es 2 minutos con 9 segundos seria algo así (1450)÷(500)

A ball of mass 0.175 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.805 m. What impulse was given to the ball by the floor

Answers

Answer:

The impulse received by the ball is - 1.561 kg.m/s

Explanation:

Given;

mass of the ball, m = 0.175 kg

initial displacement of the ball, h₁ = 1.25 m

final displacement of the ball, h₂ = 0.805 m

Assumptions:

let the downward direction of the ball be positive

let the upward direction of the ball be negative

The following equation of motion will be used to determine the final velocity of the ball at each displacement.

v² = u² ± 2gh

The final velocity of the ball when it is dropped downwards to 1.25 m;

v² = u² + 2gh

v² = 0 + 2gh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 1.25)

v = 4.95 m/s

The final velocity of the ball when it rebounds from the floor to 0.805 m;

vf² = u² - 2gh

vf² = 0² - 2gh

vf² = -2gh

vf = -√2gh

vf = - √(2 x 9.8 x 0.805)

vf = -3.97 m/s

The impulse received by the ball is calculated as;

J = ΔP = mΔv = m(vf - v)

= 0.175(-3.97 - 4.95)

= - 1.561 kg.m/s

The negative sign indicates upward direction of the impulse.

Atoms contain both positive nuclei and a negative electron cloud. Which of the following would cause an attraction between two atoms?

A. The nucleus of one atom and the electron cloud another atom

B.The nucleus of one atom and the nucleus of another atom

C. The electron cloud of one atom and the electron cloud of another atom

D.None of these would cause an attraction between atoms

Answers

Answer:

Option (D)

Explanation:

A. The nucleus of one atom and the electron cloud of the another atom will not the cause of attraction.

B. The nucleus of one atom and the other atom will not cause the attraction.

C. The electron cloud of one atom and the electron cloud of the another will not cause attraction.

D. So, this option is correct.

A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with same KE, E 0 . The energy of explosion will be Aa

Answers

Answer:

6Eo

Explanation:

If you connected 10 of these 12V (10 W) lamps in parallel, to the 12V source, how much current would the source have to supply

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Answer:

[tex]T=8.33A[/tex]

Explanation:

From the question we are told that:

Number of battery [tex]n=10[/tex]

Voltage source[tex]E=12V[/tex]

Lamp Power[tex]P=10W[/tex]

Generally the equation for Resistance is mathematically given by

[tex]R=\frac{V^2}{P}[/tex]

[tex]R=\frac{12^2}{10}[/tex]

[tex]R=14.4ohms[/tex]

Therefore

[tex]R_{eq}=\frac{14.4}{10}[/tex]

[tex]R_{eq}=1.44[/tex]

Generally the equation for Current is mathematically given by

[tex]T=\ffrac{V}{Req}[/tex]

[tex]T=\frac{12}{1.44}[/tex]

[tex]T=8.33A[/tex]

Name the physical quantity and write its SI unit which gives the slope Of I-V graph?

Answers

Slope of I-V graph is Resistance.

Its S.I. unit is Ohm.

The symbol of ohm is Ω.

The electric motor in the car is powered by a battery.

To charge the battery, the car is plugged into the mains supply at 230 V

The power used to charge the battery is 6.9 kW

Calculate the current used to charge the battery.

Answers

Answer:

I = 30 A.

Explanation:

Given that,

The voltage of the battery, V = 230 V

Power used to charge the battery, P = 6.9 kW

We need to find the current used to charge the battery. The formula for the power is given by :

P = VI

Where

I is current

So,

So, the required current is 30 A.

scientists are seen very busy in designing the solar power equipments, why?

Answers

Answer:

it is because solar energy is the perpetual source of energy and by using it non renewable sources of energy can be conserved for the future

Connected to a battery that offers a d.d.p. of 3.0Volts, we have the four lamps, all identical with resistances equal to 2.0 Ohms. The association appears in the figure. Note that the switch is open, so it doesn't pass current in the circuit (it's like an off switch). When the key closes, the lamps come on. Determining the Req of the association and the total current flowing through the circuit, we will find:

Answers

Answer:

Option D. 5Ω e 0.6 A

Explanation:

1. Determination of the equivalent resistance.

We'll begin by calculating the equivalent resistance of resistor B and resistor C. This can be obtained as follow:

Resistor B (R₆) = 2 Ω

Resistor C (R꜀) = 2 Ω

Equivalent Resistance (R₆꜀) =?

R₆꜀ = R₆ × R꜀ / R₆ + R꜀ (parallel connection)

R₆꜀ = 2 × 2 / 2 + 2

R₆꜀ = 4 / 4

R₆꜀ = 1 Ω

Finally, we shall determine the equivalent resistance of the circuit. This can be obtained as follow:

Resistor A (Rₐ) = 2 Ω

Equivalent resistance of resistor B and C (R₆꜀) = 1 Ω

Resistor D (Rₔ) = 2 Ω

Equivalent Resistance (R) =?

R = Rₐ + R₆꜀ + Rₔ (series connection)

R = 2 + 1 + 2

R = 5 Ω

Thus, the equivalent resistance of the circuit is 5 Ω

2. Determination of the total current in the circuit.

Potential difference (V) = 3 V

Equivalent resistance (R) = 5 Ω

Total current (I) =?

V = IR

3 = I × 5

Divide both side by 5

I = 3 / 5

I = 0.6 A

Thus, the total current in the circuit is 0.6 A

Summary:

Equivalent resistance = 5 Ω

Current = 0.6 A

Option D gives the current answer to the question.

What happen to the frequency of transverse vibration of a stretched string if its tension is halved and the area of cross section of the string is doubled?

Answers

Answer:

The fundamental frequency of the stretched string is:

[tex]f=[/tex] [tex]\frac{1}{2} \sqrt{\frac{T}{L} }[/tex] [ T = Tension and μ = mass per unit length]

Here,

μ = [tex]\frac{m}{L} = \frac{Vp}{L} = Ap[/tex]

[tex]f= \frac{1}{2} \sqrt{\frac{T}{Ap} }[/tex]

If T is halved and A is doubled,

[tex]f= \frac{1}{2} \sqrt{\frac{T'}{A'p} } = \sqrt{\frac{1}{2* 2* A* p} } = \frac{1}{2} (\frac{1}{2} \sqrt{\frac{T}{Ap} } = \frac{1}{2} f[/tex]

Thus, the frequency is reduced to half if its tension is halved and the area of cross-section of the string is doubled.

When the tension is halved and the area of cross section is doubled, the frequency increases by a factor of 1.414.

The frequency of transverse vibration of a stretched string is calculated as follows;

[tex]f = \frac{1}{2l} \sqrt{\frac{T}{\mu} }[/tex]

where;

T is the tension on the stringμ is the mass per unit length

[tex]f = \frac{1}{2l} \sqrt{\frac{T}{\mu} }\\\\f = \frac{1}{2l} \sqrt{\frac{Tl}{m} } \\\\f = \frac{l^2}{2l} \sqrt{\frac{T}{m} } \\\\f = \frac{A}{2l} \sqrt{\frac{T}{m}}[/tex]

when the tension is halved and the area of cross section is doubled, the frequency is calculated as;

[tex]\frac{f_1}{A_1 \sqrt{T_1} } = \frac{f_2}{A_2\sqrt{T_2} } \\\\f_2 = \frac{f_1 A_2\sqrt{T_2}}{A_1 \sqrt{T_1} }\\\\f_2 = \frac{f_1 \times 2A_1\sqrt{0.5T_1} }{\sqrt{T_1} }\\\\f_2 = \frac{f_1 \times 2A_1 \times 0.7071\sqrt{T_1} }{\sqrt{T_1} }\\\\f_2 = 1.414 f_1[/tex]

Thus, when the tension is halved and the area of cross section is doubled, the frequency increases by a factor of 1.414.

Learn more about tension in a string here: https://brainly.com/question/25743940

9. In a __________ collision, 100% of both vehicles' speed is directed towards the point of impact. A. head-on B. rear-end C. side-impact

Answers

Answer: A

Explanation:

What is the relation between acceleration due to gravity and radius of the earth?

Answers

Answer:

As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.

Formula: g = GM/r2

Dimensional Formula: M0L1T-2

Values of g in SI: 9.806 ms-2

Explanation:

Please Mark me brainliest

Answer:

♡

Explanation:

Find the sum. Express the answer in scientific notation. (1.54 x 10^6)+(6.15 x 10^6)

Answers

Answer:

[tex] { \tt{(1.54 \times {10}^{6}) + (6.15 \times {10}^{6}) }} \\ = { \tt{(1.54 + 6.15) \times {10}^{6} }} \\ = { \tt{7.69 \times {10}^{6} }}[/tex]

What factors could the skater change to apply the same amount of torque but increase the rate of his spin

Answers

Answer:

The moment of inertia should be decreased.

Explanation:

The torque is given by

Torque = Moment of inertia x angular velocity

To keep the torque constant, the spin rate be increased when the moment of inertia decreases.

The moment of inertia of the body are the efforts to put the object in rotation.

3.00 m^3 of water is at 20.0°C.
If you raise its temperature to
60.0°C, by how much will its
volume expand?
Water
ß = 207•10-6C-1
(Unit = m^3)

Answers

Answer:

9m^3

Explanation:

Given data

volume v1= 3m^3

volume v2= ???

Temperature T1= 20.0°C.

Temperature T2= 60.0°C.

Applying the relation for temperature and volume

V1/T1= V2/T2

substitute

3/20= V2/60

3*60= V2*20

180= 20*V2

180/20= V2

V2= 9m^3

Hence the final volume is 9m^3

[tex]what \: is \: reflection \: of \: light \: \: \: \: {?}[/tex]

Answers

Answer:

When a ray of light approaches a smooth polished surface and the light ray bounces back, it is called the reflection of light. The incident light ray which lands upon the surface is said to be reflected off the surface. The ray that bounces back is called the reflected ray.

A penny is dropped into a well. It takes 5 seconds to fall. Calculate the depth of the well in feet.

Answers

Answer:

d=1/2 (a)(t^2)

D = distance

A = acceleration

T = time

acceleration due to gravity is 32 ft/second

so, d=1/2 (32)(5^2)

d=16(25)

d=400

Explanation:

Answer:

400 ft.

Explanation:

D= 1/2 gt^2

=1/2(-32 ft/sec^2)(5 sec^2)

= -(1/2)(32)(25) ft

D= -400 ft, down

A 4 LBfweight is attached to a spring suspended from the ceiling. When the weight comes to rest at equilibrium, the spring has been stretched 3 inches. The damping constant for the system is 2 LBf−sec ft . If the weight is raised 9 inches above equilibrium and given an initial upward velocity of 2 ft/sec, determine the equation of motion of the weight and give its damping factor, quasiperiod and quasifrequency.

Answers

Answer:

attached below

Explanation:

The initial conditions :

x(0) = - 9 inches = -3/4 ft

x'(0) = - 2 ft/sec

spring stretched 3 inches = 1/4 ft

mass = w / g = 4 Ib / 32 ft/sec^2 = 1/8 slug

the spring constant ( k ) = w / l = 4 / ( 1/4 ) = 16 Ib/ft

applying the second law of motion

m d^2x/dt^2 + b dx/dt + kx

= 1/8 d^2x/dt^2 + 2 dx/dt + 16 x

= d^2x/dt^2 + 16 dx/dt + 128 x ------- ( 1 )

we will resolve the above equation to obtain the required equation of motion x( t )

Attached below is the remaining part of the solution

Liquid to solid with explanation on the basis of kinetic model and freezing point.

Answers

Answer:

As a liquid is cooled its molecules lose kinetic energy and their motion slows. When they've slowed to where intermolecular attractive forces exceed the collisional forces from random motion, then a phase transition from liquid to solid state takes place and the material freezes.

hope this helps you..!!!!

Give reason:
Mass and volume are called physical quantities.
a.
b
Ionath is called

Answers

Mass and volume are called physical quantities because they can be measured by using physical devices i.e. mass is measured by using beam balance and volume is measured by using metre scale .

A body of mass 8000 moving with a velocity of 2.5m/s collides with a stationery twice the mass of the first body. After impact the mass moves to 1.0m/s Find the speed of the first body.

Answers

Answer:

the final speed of the first ball is 0.5 m/s

Explanation:

Given;

mass of the first body, m₁ = 8000 kg

mass of the second body, m₂ = 16,000 kg

initial velocity of the first body, u₁ = 2.5 m/s

initial velocity of the second body, u₂ = 0

final velocity of the stationary mass, v₂ = 1 m/s

let the final velocity of the first body = v₁

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

8000(2.5) + (16,000 x 0) = 8000v₁ + 16,000 (1)

20,000 + 0 = 8000v₁ + 16,000

8000v₁ = 4000

v₁ = 4000/8000

v₁ = 0.5 m/s

Therefore, the final speed of the first ball is 0.5 m/s

5- Clasifica los siguientes cambios de la materia, anotando delante de cada uno cambio físico (F) o cambio químico (Q): • Disolver azúcar en agua • Freir una chuleta • Arrugar un papel • El proceso de la digestión • Secar la ropa al sol • Congelar una paleta de agua • Hacer un avión de papel • Oxidación del cobre • Romper un lápiz • Prender fuegos artificiales • Excavar un hoyo • Quemar basura

Answers

Answer:

1) Disolver azúcar en agua - Cambio químico - Es un caso de una solución en donde el solvente es el azúcar y el soluto es el agua.

2) Freir una chuleta - Cambio físico - Es un proceso de cocinado por un transferencia de calor y transferencia de masa.

3) Arrugar un papel - Cambio físico - Se aplica fuerzas externas para deformar el papel.

4) El proceso de la digestión - Cambio químico - Reducción de los alimentos a desechos y la absorción de nutrientes por el contacto con jugos gástricos o ambientes intestinales.

5) Secar la ropa al sol - Cambio físico - El secado es un fenómeno de transferencia de masa.

6) Congelar una paleta de agua - Cambio físico - Cambio del estado líquido al estado sólido por transferencia de calor.

7) Hacer un avión de papel - Cambio físico - Aplicación de fuerzas externas para plegar y doblar la hoja de papel.

8) Oxidación del cobre - Cambio químico - Proceso de corrosión por contacto con iones que se transportan en el ambiente.

9) Romper un lápiz - Cambio físico - Proceso de ruptura por esfuerzo normal a causa de un momento como consecuencia de una fuerza externa aplicada sobre el lápiz.

10) Prender fuegos artificiales - Cambio químico - Reacción química de reducción-oxidación.

11) Excavar un hoyo - Cambio físico - Remoción de tierra por trabajo físico.

12) Quemar basura - Cambio químico - Reacción de combustión.

Explanation:

A continuación, veremos que representa cada caso: