What is the equation of the line graphed below?
5
- 5
5
(3,-1)
1
-5
O A. y=-3x
1
O B. y = -
O c. y =
C. 5
-X
What is the equation of the line graphed below

Answer:

there are two solutions:

x=0

and

x=14

Step-by-step explanation:

lts suppose the numbers are x and x+2, so:

[tex]x(x+2)=8(x+(x+2))-16\\x(x+2)=8(2x+2)-16=16x+16-16=16x\\x^2+2x=16x\\x^2-14x=0\\x(x-14)=0\\x=0,~x=14[/tex]

Answer:

No mode

Step-by-step explanation:

Mode = number that appears the most

No number appears more than 1 time

Hence there is no mode

Answer:Should be no mode tell me if i'I'm wrong

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

79.5, 110.5, 141.5, 172.5, 203.5, 234.5

Step-by-step explanation:

Given

The attached distribution

Required

The lower class limits

To do this, we simply subtract 0.5 from the lower interval

From the attached distribution, the lower intervals are:

80.0, 111.0, 142.0, 173,0 .......

So, the lower class limits are:

[tex]80.0-0.5 = 79.5[/tex]

[tex]111.0-0.5 = 110.5[/tex]

[tex]142.0-0.5 = 141.5[/tex]

[tex]173.0-0.5 = 172.5[/tex]

[tex]204.0-0.5 = 203.5[/tex]

[tex]235.0-0.5 = 234.5[/tex]

Find the values of the sine, cosine, and tangent for ∠A

a. sin A = [tex]\frac{\sqrt{13} }{2}[/tex],  cos A = [tex]\frac{\sqrt{13} }{3}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

b. sin A = [tex]3\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]2\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{3}{2}[/tex]

c. sin A = [tex]\frac{\sqrt{13} }{3}[/tex],  cos A = [tex]\frac{\sqrt{13} }{2}[/tex],  tan A = [tex]\frac{3}{2}[/tex]

d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]3\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

d. sin A = [tex]2\frac{\sqrt{13} }{13}[/tex],  cos A = [tex]3\frac{\sqrt{13} }{13}[/tex],  tan A = [tex]\frac{2 }{3}[/tex]

The triangle for the question has been attached to this response.

As shown in the triangle;

AC = 36ft

BC = 24ft

ACB = 90°

To calculate the values of the sine, cosine, and tangent of ∠A;

i. First calculate the value of the missing side AB.

Using Pythagoras' theorem;

⇒ (AB)² = (AC)² + (BC)²

Substitute the values of AC and BC

⇒ (AB)² = (36)² + (24)²

Solve for AB

⇒ (AB)² = 1296 + 576

⇒ (AB)² = 1872

⇒ AB = [tex]\sqrt{1872}[/tex]

⇒ AB = [tex]12\sqrt{13}[/tex] ft

From the values of the sides, it can be noted that the side AB is the hypotenuse of the triangle since that is the longest side with a value of [tex]12\sqrt{13}[/tex] ft (43.27ft).

ii. Calculate the sine of ∠A (i.e sin A)

The sine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the hypotenuse side of the triangle. i.e

sin Ф = [tex]\frac{opposite}{hypotenuse}[/tex]             -------------(i)

In this case,

Ф = A

opposite = 24ft (This is the opposite side to angle A)

hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)

Substitute these values into equation (i) as follows;

sin A = [tex]\frac{24}{12\sqrt{13} }[/tex]

sin A = [tex]\frac{2}{\sqrt{13}}[/tex]

Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]

sin A = [tex]\frac{2}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]

sin A = [tex]\frac{2\sqrt{13} }{13}[/tex]

iii. Calculate the cosine of ∠A (i.e cos A)

The cosine of an angle (Ф) in a triangle is given by the ratio of the adjacent side to that angle to the hypotenuse side of the triangle. i.e

cos Ф = [tex]\frac{adjacent}{hypotenuse}[/tex]             -------------(ii)

In this case,

Ф = A

adjacent = 36ft (This is the adjecent side to angle A)

hypotenuse = [tex]12\sqrt{13}[/tex] ft (This is the longest side of the triangle)

Substitute these values into equation (ii) as follows;

cos A = [tex]\frac{36}{12\sqrt{13} }[/tex]

cos A = [tex]\frac{3}{\sqrt{13}}[/tex]

Rationalize the result by multiplying both the numerator and denominator by [tex]\sqrt{13}[/tex]

cos A = [tex]\frac{3}{\sqrt{13}} * \frac{\sqrt{13} }{\sqrt{13} }[/tex]

cos A = [tex]\frac{3\sqrt{13} }{13}[/tex]

iii. Calculate the tangent of ∠A (i.e tan A)

The cosine of an angle (Ф) in a triangle is given by the ratio of the opposite side to that angle to the adjacent side of the triangle. i.e

tan Ф = [tex]\frac{opposite}{adjacent}[/tex]             -------------(iii)

In this case,

Ф = A

opposite = 24 ft (This is the opposite side to angle A)

adjacent = 36 ft (This is the adjacent side to angle A)

Substitute these values into equation (iii) as follows;

tan A = [tex]\frac{24}{36}[/tex]

tan A = [tex]\frac{2}{3}[/tex]

Answer:

[tex]\displaystyle f(3x) = \frac{6x + 5}{3x + 4}[/tex]

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f(x) = \frac{2x + 5}{x + 4}[/tex]

Step 2: Find

Answer:

58°

Step-by-step explanation:

Given that,

The measure of two interior angles are 68° and 54º.

We need to find the measurement of the third interior angle.

We know that, the sum of angles of a triangle is equal to 180°. Let the angle is x. So,

x+68+54 = 180

x+122 = 180

x = 180-122

x = 58°

So, the measure of the third interior angle is equal to 58°.

Answer:

The center of the circle is found at h,k

These values represent the important values for graphing and analyzing a circle.

Center: 0,0

And also,

Algebra Graph x^2+y^2=25 x2 + y2 = 25 x 2 + y 2 = 25 This is the form of a circle.

And also,

Simple and best practice solution for X2+y2=25 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework. If it's not what You are looking for type in the equation solver your own equation and let us solve it.

And also,

Match the values in this circle to those of the standard form. The variable r r represents the radius of the circle, h h represents the x-offset from the origin, and k k represents the y-offset from origin. The center of the circle is found at (h,k) ( h, k).

And also,

Ox (0) 6°x= 1) 6x ** + y = 25 SOLUTION (a) Since f(x) = 25 - x2 0, we can interpret this integral as the area under the curve y = 25 - x2 from 0 to 5 . But since y2 = 25 - x2 , we get x2 + y2 = 25, which shows that the graph of fis a quarter-circle with radius 5 in the top figuer

And also,

(3x2y2)3 Final result : 32x2y2 Reformatting the input : Changes made to your input should not affect the solution: (1): "y2" was replaced by "y^2".

And thats all!

Solution graph is image 2.

We first graph [tex]x^2+y^2=25[/tex]. This is a circle with center = (0,0) and radius = [tex]\sqrt{25} =5[/tex].

For [tex]x^2+y^2<25[/tex], we'll shade inside the circle.

[tex]y^2=6x[/tex] is a parabola.

we make a table for it.

x   -1   0   1

y   -6  0   6

For [tex]y^2<6x[/tex] we'll shade inside the parabola.

So the graph will be image 1.

So the solution region is image 2.

Learn more: https://brainly.com/question/15816805

Answer:

Step-by-step explanation:

secθ = 1/cosθ

cosθ = 0 for π/2, 3π/2

secθ is undefined for θ = π/2, 3π/2

An equation can be defined as a mathematical statement in which two expressions are set equal to each other. In simple words, equations mean equality i.e. the equal sign. Since equations are all about “equating one quantity with another”,they are simply known as equation

Answer:

In algebra, an equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value. ... For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

Answer:....... no clue ut pls mark me brainiest

Step-by-step explanation:

Answer:

(2,3) (4,2) (5,2) (1,4) (0,2)

Step-by-step explanation:

because all these points have something common to each other. Now pay attention in your class and stop cheating!!

Answer:

Step-by-step explanation:

eq. of circle is (x-2)²+(y-3)²=10²

now substitute the values of x and y

which satisfies the above eq.that point lies on the circle.

(Q.1)

[tex]y = \dfrac{C - e^x}{2x} \implies y' = \dfrac{-2xe^x-2C+2e^x}{4x^2} = \dfrac{-xe^x-C+e^x}{2x^2}[/tex]

Then substituting into the DE gives

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{2\left(\dfrac{C-e^x}{2x}\right) + e^x}{2x}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = -\dfrac{C-e^x + xe^x}{2x^2}[/tex]

[tex]\dfrac{-xe^x-C+e^x}{2x^2} = \dfrac{-C+e^x - xe^x}{2x^2}[/tex]

and both sides match, so y is indeed a valid solution.

(Q.2)

[tex]\ln\left(y^x\right)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

This DE is separable, since you can write [tex]\ln\left(y^x\right)=x\ln(y)[/tex]. So you have

[tex]x\ln(y)\dfrac{\mathrm dy}{\mathrm dx} = 3x^2y[/tex]

[tex]\dfrac{\ln(y)}y\,\mathrm dy = 3x\,\mathrm dx[/tex]

Integrate both sides (on the left, the numerator suggests a substitution):

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 + C[/tex]

Given y (2) = e ³, we find

[tex]\dfrac12 \ln^2(e^3) = 6 + C[/tex]

[tex]C = \dfrac12 \times3^2 - 6 = -\dfrac32[/tex]

so that the particular solution is

[tex]\dfrac12 \ln^2(y) = \dfrac32 x^2 - \dfrac32[/tex]

[tex]\ln(y) = \pm\sqrt{3x^2 - 3}[/tex]

[tex]\boxed{y = e^{\pm\sqrt{3x^2-3}}}[/tex]

(Q.3) I believe I've already covered in another question you posted.

Answer:

C. 468 mm²

Step-by-step explanation:

Surface area of the composite solid = 2(LW + LH + WH)

Length (L) = 12 mm

Width (W) = 6 mm

Height (H) = 2 + 7 = 9 mm

Plug in the values into the formula

Surface area = 2(12*6 + 12*9 + 6*9)

Surface area = 2(72 + 108 + 54)

Surface area = 2(234)

= 468 mm²

Answer:

3

Step-by-step explanation:

x 1，2，3，4

y-3，-5，-7，-9

[tex]y = - 3 - (x - 1) \times 2[/tex]

The linear function is given by y = 7x - 4

A linear function is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the y intercept

From the table, using the points (1, 3) and (4, 24):

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-3=\frac{24-3}{4-1}(x-1)\\\\ y=7x-4[/tex]

The linear function is given by y = 7x - 4.

Find out more on linear function at: https://brainly.com/question/4025726

Answer:

1. Tyler

2. 8.33

3. 8.5

4. Tyler

Step-by-step explanation:

this is just playing with the numbers. no complex math concepts.

Tyler's graph shows she reached 1 mile after 8 1/3 minutes (8 minutes and 20 seconds). that is 25/3 minutes.

according to Elena's equation she reached 1 mile (x=1) after 8.5 minutes. that is 8 1/2 minutes or 8 minutes and 30 seconds.

so, we see that Elena took more time (10 seconds longer) to run 1 mile, so Tyler was faster.

to generally compare the 2 we can write also Tyler's graph as function (like for Elena) :

8 1/3 = 8.333333....

y = 8.33x

but that is just FYI (not asked for here).

since Tyler was faster (and her graph also showed a straight line of time and distance up to 10 minutes and beyond, so, she did not slow down after the first mile), she also ran further after 10 minutes. that is the definition of "being faster" - to go further in the same amount of time.

Tyler needed 8.33 minutes per mile.

Elena needed 8.5 minutes per mile.

and so, Tyler was faster.

points 1 and 4 are directly coupled. they both express the same thing.

9514 1404 393

Answer:

  517 minutes

Step-by-step explanation:

There are 60 minutes in an hour, so 8×60 = 480 minutes in 8 hours.

In 8 hours 37 minutes, there are ...

  480 min + 37 min = 517 minutes

Answer:

C. 17 units

Step-by-step explanation:

Surface area of rectangular prism is given as:

A = 2lw + 2lh + 2wh

A = 930 square units

l = 12 units

h = 9 units

w = ? (We're to find the width)

Plug in the value into the formula

930 = 2*12*w + 2*12*9 + 2*w*9

930 = 24w + 216 + 18w

Add like terms

930 - 216 = 42w

714 = 42w

Divide both sides by 42

714/42 = 42w/42

17 = w

w = 17 units

Answer with Step-by-step explanation:

We are given that

[tex]a+ib=\sqrt{\frac{1+i}{1-i}}[/tex]

We have to prove that

[tex]a^2+b^2=1[/tex]

[tex]a+ib=\sqrt{\frac{(1+i)(1+i)}{(1-i)(1+i)}}[/tex]

Using rationalization property

[tex]a+ib=\sqrt{\frac{(1+i)^2}{(1^2-i^2)}}[/tex]

Using the property

[tex](a+b)(a-b)=a^2-b^2[/tex]

[tex]a+ib=\sqrt{\frac{(1+i)^2}{(1-(-1))}}[/tex]

Using

[tex]i^2=-1[/tex]

[tex]a+ib=\frac{1+i}{\sqrt{2}}[/tex]

[tex]a+ib=\frac{1}{\sqrt{2}}+i\frac{1}{\sqrt{2}}[/tex]

By comparing we get

[tex]a=\frac{1}{\sqrt{2}}, b=\frac{1}{\sqrt{2}}[/tex]

[tex]a^2+b^2=(\frac{1}{\sqrt{2}})^2+(\frac{1}{\sqrt{2}})^2[/tex]

[tex]a^2+b^2=\frac{1}{2}+\frac{1}{2}[/tex]

[tex]a^2+b^2=\frac{1+1}{2}[/tex]

[tex]a^2+b^2=\frac{2}{2}[/tex]

[tex]a^2+b^2=1[/tex]

Hence, proved.

Answer with Step-by-step explanation:

We are given that

Side of cube, x=30 cm

Error in measurement of edge,[tex]\delta x=0.5[/tex] cm

(a)

Volume of cube, [tex]V=x^3[/tex]

Using differential

[tex]dV=3x^2dx[/tex]

Substitute the values

[tex]dV=3(30)^2(0.5)[/tex]

[tex]dV=1350 cm^3[/tex]

Hence,  the maximum possible error in computing the volume of the cube

=[tex]1350 cm^3[/tex]

Volume of cube, [tex]V=(30)^3=27000 cm^3[/tex]

Relative error=[tex]\frac{dV}{V}=\frac{1350}{2700}[/tex]

Relative error=0.05

Percentage  error=[tex]0.05\times 100=5[/tex]%

Hence, relative error in computing the volume of the cube=0.05  and

percentage error in computing the volume of the cube=5%

(b)

Surface area of cube,[tex]A=6x^2[/tex]

[tex]dA=12xdx[/tex]

[tex]dA=12(30)(0.5)[/tex]

[tex]dA=180cm^2[/tex]

The maximum possible error in computing the volume of the cube=[tex]180cm^2[/tex]

[tex]A=6(30)^2=5400cm^2[/tex]

Relative error=[tex]\frac{dA}{A}=\frac{180}{5400}[/tex]

Relative error  in computing the volume of the cube=0.033

The percentage error in computing the volume of the cube=[tex]0.033\times 100=3.3[/tex]%

Answer:

4 + 5i

Step-by-step explanation:

To calculate this you have to combine the like terms until they cannot be combined any further:

7 + 10i + 4 - 10i - (7 - 5i)

11 + 0i - 7 - 5i

7 & 4 are liked terms so add them together + subtract 10i and 10i

4 + 5i  <--- Final answer

Hope this helps!

Answer:

4 + 5i

Step-by-step explanation:

(7 + 10i) + (4 - 10i) - (7 - 5i)

7 + 10i + 4 - 10i - (7 - 5i)

11 - 7 + 5i

4 + 51

Answer:

[tex]-\frac{3(\sqrt{6}-\sqrt{2})}{2}\text{ or } \frac{-3\sqrt{6}+3\sqrt{2}}{2}}\text{ or }\frac{3(\sqrt{2}-\sqrt{6})}{2}[/tex]

Step-by-step explanation:

There are multiple ways to achieve and even express the exact answer to this problem. Because the exact value of [tex]6\cos(105^{\circ}})[/tex] is a non-terminating (never-ending) decimal, it does not have a finite number of digits. Therefore, you cannot express it as an exact value as a decimal, as you'd either have to round or truncate.

Solution 1 (Cosine Addition Identity):

Nonetheless, to find the exact value we must use trigonometry identities.

Identity used:

[tex]\cos(\alpha +\beta)=\cos \alpha \cos \beta-\sin \alpha \sin \beta[/tex]

Notice that [tex]45+60=105[/tex] and therefore we can easily solve this problem if we know values of [tex]\cos(45^{\circ})[/tex], [tex]\cos(60^{\circ})[/tex], [tex]\sin (45^{\circ})[/tex], and [tex]\sin(60^{\circ})[/tex], which is plausible as they are all key angles on the unit circle.

Recall from either memory or the unit circle that:

Therefore, we have:

[tex]\cos(105^{\circ})=\cos(45^{\circ}+60^{\circ}}),\\\cos(45^{\circ}+60^{\circ}})=\cos 45^{\circ}\cos 60^{\circ}-\sin 45^{\circ}\sin 60^{\circ},\\\cos(45^{\circ}+60^{\circ}})=\frac{\sqrt{2}}{2}\cdot \frac{1}{2}-\frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2},\\\cos(105^{\circ})=\frac{\sqrt{2}}{4}-\frac{\sqrt{6}}{4},\\\cos(105^{\circ})={\frac{-\sqrt{6}+\sqrt{2}}{4}}[/tex]

Since we want the value of [tex]6\cos 105^{\circ}[/tex], simply multiply this by 6 to get your final answer:

[tex]6\cdot {\frac{-\sqrt{6}+\sqrt{2}}{4}}=\frac{-3\sqrt{6}+3\sqrt{2}}{2}}=\boxed{\frac{3(\sqrt{2}-\sqrt{6})}{2}}[/tex]

Solution 2 (Combination of trig. identities):

Although less plausible, you may have the following memorized:

[tex]\sin 15^{\circ}=\cos75^{\circ}=\frac{\sqrt{6}-\sqrt{2}}{4},\\\sin 75^{\circ}=\cos15^{\circ}=\frac{\sqrt{6}+\sqrt{2}}{4}[/tex]

If so, we can use the following trig. identity:

[tex]\cos(\theta)=\sin(90^{\circ}-\theta)[/tex] (the cosine of angle theta is equal to the sine of the supplement of angle theta - the converse is also true)

Therefore,

[tex]\cos (105^{\circ})=\sin (90^{\circ}-105^{\circ})=\sin(-15^{\circ})[/tex]

Recall another trig. identity:

[tex]\sin(-\theta)=-\sin (\theta)[/tex] and therefore:

[tex]\sin (-15^{\circ})=-\sin (15^{\circ})[/tex]

Multiply by 6 to get:

[tex]6\cos (105^{\circ})=-6\sin (15^{\circ})=-6\cdot \frac{\sqrt{6}-\sqrt{2}}{4}=\boxed{-\frac{3(\sqrt{6}-\sqrt{2})}{2}}[/tex] (alternative final answer).

Answer:

The answer is "47.5354".

Step-by-step explanation:

In the given graph it is a half-circle and a triangle.

So, the diameter of the circle is 6.2 so the radius is 3.1

[tex]\text{Area of a circle}= \pi r^2\\\\\text{Area of a triangle}= \frac{1}{2} b h\\\\[/tex]

Calculating the total area of the shape:

[tex]= \pi r^2+\frac{1}{2} \times b\times h\\\\ = 3.14 \times 3.1^2+\frac{1}{2} \times 6.2 \times 5.6\\\\ = 3.14 \times 3.1^2+\frac{1}{2} \times 6.2 \times 5.6\\\\=3.14 \times 9.61+\frac{1}{2} \times 34.72\\\\=3.14 \times 9.61+\frac{1}{2} \times 34.72\\\\= 30.1754+17.36\\\\=47.5354\\\\[/tex]

Answer:

W = 4.95

Step-by-step explanation:

You want to start by writing down what you know, and forming a system of equations.

L= length W= width

2L+2W=14.7    

L= 2.4

On the left side of the equation, you're adding all your side lengths, and on the right, is the total perimeter. (Also could be written L+L+W+W = 14.7)

You would then substitute L from the bottom equation into the top equation to get:

2(2.4) +2W=14.7

Solving:

4.8+2w=14.7

W= 4.95

To check your answer simply add all the sides together and make sure it equals your perimeter. You can also plug W and L back into the original equation.

Answer:

y = -x.

Step-by-step explanation:

The slope of the line (m) = -1.  ( because of the -x in y = -x - 5)

y - y1 = m (x - x1)    where (x1, y1) is a point on the line, so we get;

y - 2 = -1(x - (-2))

y - 2 = -x + -1 * +2

y - 2 = -x - 2

y = -x.

Answer:

B

Step-by-step explanation:

B is the correct equation

Answer:

main age = total age/total people

if Main age is = 27

[tex]27 = \frac{ \times }{5} [/tex]

and x = 135

Total age is = 135

then main age is 35

[tex][35 = \frac{y}{6} [/tex]

and y = 210

first main age - second main age = age of the person participating

210 - 135 = 75

HAVE A NİCE DAY

Step-by-step explanation:

GREETINGS FROM TURKEY