What is the inverse of the function f(x) = x +3?
O h(x) = 5x + 3
O h(x) =
1x-3
Oh(x) = x-3
Oh(x) = x + 3

Answer:

a

Step-by-step explanation:

because is a ok yo12222122221112w

Answer:

Option C is correct

Step-by-step explanation:

[tex]3 + 11 + 13 = 27[/tex]

[tex]5 + 11 + 13 = 29[/tex]

[tex]2 + 7 + 19 = 28[/tex]

[tex] 2 + 5 + 13 = 20[/tex]

Answer:

1452628383763637£838

Answer:

B

Step-by-step explanation:

Answer:

[tex]f(n) = \frac{32}{3}(\frac{3}{2})^n[/tex]

Step-by-step explanation:

Given

[tex]r = \frac{3}{2}[/tex]

[tex]f(5) = 81[/tex]

Required

The geometric sequence

A geometric sequence is represented as:

[tex]f(n) = ar^{n-1}[/tex]

Replace n with 5

[tex]f(5) = ar^{5-1}[/tex]

[tex]f(5) = ar^4[/tex]

Substitute values for f(5) and r

[tex]81 = a* (\frac{3}{2})^4[/tex]

Open bracket

[tex]81 = a* \frac{81}{16}[/tex]

Make a the subject

[tex]a = \frac{81 * 16}{81}[/tex]

[tex]a = 16[/tex]

So, the explicit function is:

[tex]f(n) = ar^{n-1}[/tex]

[tex]f(n) = 16 * (\frac{3}{2})^{n-1}[/tex]

Split

[tex]f(n) = 16 * (\frac{3}{2})^n \div (\frac{3}{2})[/tex]

Convert to multiplication

[tex]f(n) = 16 * (\frac{3}{2})^n * \frac{2}{3}[/tex]

[tex]f(n) = \frac{32}{3}(\frac{3}{2})^n[/tex]

Answer:

f(x) = 16*(3/2)^(x-1)

Step-by-step explanation:

right on edge

Answer:

3x-2

---------

x-1

Step-by-step explanation:

simplify 18x/6x = 3x/1x

simplify 108/54 = 2/1

Answer:

x² + 2² =(√15)²

x²+ 4. =15

x² =15-4

x² =11

x. =√11 mi

so the answer is 4th option

Answer:

The answer is

[tex] \frac{3}{x} = \frac{11}{10} - \frac{4}{5} \\ \frac{3}{x} = \frac{55 - 40}{50} \\ \frac{3}{x} = \frac{15}{50} \\ \frac{3}{x} = \frac{3}{10} \\ x = 10[/tex]

Answer:

Point A

Step-by-step explanation:

The question is asking for a drop in 3 degrees. That means whatever point we start on, we subtract 3 from it. We start on 0, so 0-3=-3. That is point A.

Answer:

A

Step-by-step explanation:

Hermes is incorrect. The opposite of 9 is -9 if Hermes says that the opposite of 9 is 9 since each number is 9 units from zero on the number line.

It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.

To find the same distance away from zero in the opposite direction to determine the opposite number.

The distance from zero in this situation is 9. nine times in the opposite direction from zero.

Thus, Hermes is incorrect. The opposite of 9 is -9 if Hermes says that the opposite of 9 is 9 since each number is 9 units from zero on the number line.

Learn more about the number line here:

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Answer:

I believe that the answer is B as well

Step-by-step explanation:

This might be for Ap3x but not 100% sure

Answer:

72

Step-by-step explanation:

6*6 = 36

3*12 = 36

36 + 36 = 72

Answer:

D

Step-by-step explanation:

Look for the intersection point of the two graphs

Another way:

You can just substitute each pair in both equations and u will find that d is the correct answer

Answer:

x = (4,0)

y = (0,-4)

Step-by-step explanation:

x - y = 4

(0) - y = 4

-(-y) = -(4)

y = -4

x - (0) = 4

x = 4

x = (4,0)

y = (0,-4)

Answer:

x = 4 . 0

y = 0 . -4)

Step-by-step explanation:

Answer:

(32;29) first thing is to find the gradient of that line and form some extra equation ( bodzatu ili

Answer:

- [tex]\frac{2\sqrt{3} }{3}[/tex]

Step-by-step explanation:

Using the identity and the exact value

csc x = [tex]\frac{1}{sinx}[/tex]  and sin60° = [tex]\frac{\sqrt{3} }{2}[/tex]

- 120° is in the third quadrant where sin < 0 , then

csc - 120° = - sin60° , then

csc - 120°

= [tex]\frac{1}{-sin60}[/tex]

= - [tex]\frac{1}{\frac{\sqrt{3} }{2} }[/tex]

= - [tex]\frac{2}{\sqrt{3} }[/tex] ( rationalise the denominator )

= - [tex]\frac{2}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex]

= - [tex]\frac{2\sqrt{3} }{3}[/tex]

The equivalent value of the trigonometric relation cosec ( -120 )° = 2√3/3

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

We know that the cosecant function is defined as the reciprocal of the sine function:

cosec (θ) = 1 / sin(θ)

Therefore, to evaluate cosec(-120°), we first need to find sin(-120°).

We know that sine is an odd function, which means that sin(-θ) = -sin(θ). Therefore,

sin(-120°) = -sin(120°)

We can now use the fact that the sine function has a period of 360 degrees, which means that sin(120°) is the same as sin(120° - 360°) = sin(-240°).

Using the same logic as before, we get:

sin(-240°) = -sin(240°)

Now , from the trigonometric relations , we get

Now, we can use the fact that sin(240°) = sin(240° - 360°) = sin(-120°), which means that:

sin(-240°) = -sin(-120°)

Therefore, we have:

sin(-120°) = -sin(120°) = -sin(-240°) = sin(240°)

Now, we can use the unit circle or trigonometric identities to find sin(240°). One way to do this is to draw a 30-60-90 degree triangle in the third quadrant of the unit circle, with the angle of 240° as the reference angle:

In this triangle, the opposite side (O) has a length of √3, the adjacent side (A) has a length of -1, and the hypotenuse (H) has a length of 2.

Therefore, sin(240°) = O/H = (√3)/2.

Finally, we can use the definition of the cosecant function to find cosec(-120°):

cosec(-120°) = 1/sin(-120°) = 1/sin(240°) = 1/((√3)/2) = 2/√3 = (2√3)/3.

Hence , cosec(-120°) is equal to (2√3)/3.

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[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]f(x) = \frac{2x + 3}{4x + 5} \\[/tex]

For [tex]f(-9)[/tex], put "[tex]-9[/tex]" for every value of "[tex]x[/tex]".

[tex]↬f( - 9) = \frac{2( - 9) + 3}{4( - 9) + 5}\\ [/tex]

[tex]↬ f(-9) = \frac{ - 18 + 3}{ - 36 + 5} \\[/tex]

[tex]↬ f(-9) = \frac{ - 15}{ - 31}\\ [/tex]

[tex]↬ f(-9)= \frac{15}{31}\\ [/tex]

[tex] ↬f(-9)= 0.48\\ [/tex]

[tex]\bold{ \green{ \star{ \red{Mystique35}}}}⋆[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{f(x) = \dfrac{2x + 3}{4x + 5}}[/tex]

[tex]\mathsf{y = \dfrac{ 2x + 3}{4x + 5}}[/tex]

[tex]\mathsf{y = \dfrac{2(-9) + 3}{4(-9) + 5}}[/tex]

[tex]\mathsf{2(-9)}[/tex]

[tex]\mathsf{\bf = -18}[/tex]

[tex]\mathsf{y = \dfrac{-18 + 3} {4(-9) + 5}}[/tex]

[tex]\mathsf{-18 + 3}\\\mathsf{= \bf -15}[/tex]

[tex]\mathsf{y = \dfrac{ -15} {4(-9) + 5}}[/tex]

[tex]\mathsf{4(-9)}\\\mathsf{\bf = -36}[/tex]

[tex]\mathsf{y = \dfrac{-15}{-36 + 5}}[/tex]

[tex]\mathsf{-36 + 5}\\\mathsf{= \bf-31}[/tex]

[tex]\mathsf{y = \dfrac{-15}{ -31}\rightarrow\boxed{\bf \dfrac{15}{31}}}[/tex]

[tex]\boxed{\boxed{\huge\text{Answer: } \boxed{\bf f(-9) = \dfrac{15}{31}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

9

Step-by-step explanation:

x = 1

y = 4

x + 2y = 1 + 8 = 9

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

9

Step-by-step explanation:

x + 2y

subtitute:

1 + 2(4)

simplify:

1 + 8 = 9

Answer:

£840

Step-by-step explanation:

800 × 1.05 = 840

(1.05 Is the decimal multiplier = (100% + 5%)/100)

Answer:

C is the answer

Step-by-step explanation:

I'm sure it is

Answer:

Moving 4 to the right on the x axis

Answer:

y=X²-4x+5

Step-by-step explanation:

substitute all the left side values to get the outputs..

y=(5)²-4(5)+5 =10

Answer:

A

Step-by-step explanation:

In fact, if we try to substitute, we have:

10 = 5^2 -4(5) +5

10 = 25 - 20 + 5

10 = 10 (ok)

17 = -2^2 - 4(-2) + 5

17 = 4 + 8 + 5

17 = 17 (ok)

and so on

Answer:

Step-by-step explanation:

Average rate of change is the same thing as the slope. This is a quadratic so the slope is not something that is constant like it is in a line. Here you have the x coordinates of 1 and 5; each one of these x coordinates has a y coordinate that goes with it. If we draw a line from one of these coordinates to another,  that line will have a slope. That is the slope we are trying to find. Thus, we need the y coordinates that go with each of these x coordinates. To do that, plug x into the equation and do the math to find y:

Let's start with x = 1.

f(1) = [tex]17-(1)^2[/tex] so

f(1) = 16 and the coordinate is (1, 16).

f(5) = [tex]17-(5)^2[/tex] so

f(5) = -8 and the coordinate is (5, -8). Now we apply the slope formula:

[tex]m=\frac{-8-16}{5-1}=\frac{-24}{4}=-6[/tex] So the answer is -6.

Answer:

Third option:

Ax + By < 0

Step-by-step explanation:

The general form of an inequality is:

(something)  (symbol)  (another thing).

Where the symbols can be:

> = "larger than"

< = "smaller than"

≤ = "smaller than or equal to"

≥ = "larger than or equal to"

So, a given inequality can be:

K > M

This means that K is larger than M.

From the given options, the only one that has this general form is the third option:

Ax + By < 0

This can be read as:

"A times x, plus B times y, is smaller than zero"

Answer:

C

Step-by-step explanation:

The scale factor is the ratio of corresponding sides, image to original, so

scale factor = [tex]\frac{XY}{AB}[/tex] = [tex]\frac{9}{45}[/tex] = [tex]\frac{1}{5}[/tex] → C

The scale factor will be equal to 1 / 5. the correct option is C.

The scale factor is defined as the proportion of the new image's size to that of the previous image. Dilation is the process of increasing the size of an object while maintaining its shape. Depending on the scale factor, the object's size can be increased or decreased.

In the given image all the angles are the same and the sides are dilated so the scale factor will be calculated as below,

Scale factor = Original size / dilated size

Scale factor = XY / AB

Scale factor = 9 / 45

Scale factor = 1 / 5

Therefore, the scale factor will be equal to 1 / 5. the correct option is C.

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Answer:

the first one

Step-by-step explanation:

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]