Answer:
0.25 g
Explanation:
We'll begin by writing the number of mole of CO₂. This can be obtained as follow:
Volume (V) = 0.125 L
Temperature (T) = 273 K
Pressure (P) = 760 torr = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) =?
PV = nRT
1 × 0.125 = n × 0.0821 × 273
0.125 = n × 22.4133
Divide both side by 22.4133
n = 0.125 / 22.4133
n = 0.0056 mole
Finally, we shall determine the mass of 0.0056 mole of CO₂. This can be obtained as follow:
Number of mole of CO₂ = 0.0056 mole
Molar mass of CO₂ = 12 + (2×6)
= 12 + 32
= 44 g/mol
Mass of CO₂ =?
Mass = mole × molar mass
Mass of CO₂ = 0.0056 × 44
Mass of CO₂ = 0.25 g
Thus, the mass of CO₂ is 0.25 g
A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this bubble?
Answer:
1.5x10²² particulates
Explanation:
Assuming ideal behaviour, we can solve this problem by using the PV=nRT formula, where:
P = 2.4 atmV = 250 mL ⇒ 250 / 1000 = 0.250 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 15 °C ⇒ 15 + 273 = 288 KWe input the given data:
2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 KAnd solve for n:
n = 0.025 molFinally we calculate how many particulates are there in 0.025 moles, using Avogadro's number:
0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulatesLee y analiza a detalle el Anexo #1 de este plan de trabajo el cual habla sobre las fuentes alternativas de energía. Posteriormente con la información elabora un cartel o un cuadro sinóptico en tu cuaderno donde organices la información para darla a conocer a los miembros de tu comunidad.
Answer: el texto no es tan claro
An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.
How many milliliters of this suspension should be given to an infant weighing 13 lb.
Answer:
0.8853 mL
Explanation:
First we convert 13 lb to kg, keeping in mind that 1 lb = 0.454 kg:
13 lb * [tex]\frac{0.454kg}{1lb}[/tex] = 5.902 kgThen we calculate how many mg of acetaminophen should be given, using the recommended dose and infant mass:
15 mg/kg * 5.902 kg = 88.53 mgFinally we calculate the required mL of suspension, using its concentration:
88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mLla. A man was traveling by sie is allowed a maximum of 20kg luggage. The man
weighing 3.5kg, 15kg.2kg and 15kg
Find the excess weight of his luggage.
Express the excess weight as a percentage of the maximum weight allowed
Answer: The excess weight of the luggage is 15.5 kg and its percentage is 77.5%
Explanation:
Given values:
Maximum amount of luggage allowed = 20 kg
Amount of luggage man is carrying = [3.5 + 15 + 2 + 15] kg = 35.5 kg
Excessive weight of the luggage carried = Amount of luggage carrying - Maximum amount of luggage allowed
Excessive weight of the luggage carried = [35.5 - 20] = 15.5 kg
To calculate the percentage of excess weight, we use the equation:
[tex]\% \text{excess weight}=\frac{\text{Excess weight carried}}{\text{Maximum allowed}}\times 100[/tex]
Putting values in above equation, we get:
[tex]\% \text{excess weight}=\frac{15.5kg}{20kg}\times 100\\\\\% \text{excess weight}=77.5%[/tex]
Hence, the excess weight of the luggage is 15.5 kg and its percentage is 77.5%
Gizmo Warm-up Just like students sharing markers, atoms sometimes share or swap electrons. By doing this, atoms form bonds. The Ionic Bonds Gizmo allows you to explore how ionic bonds form. To begin, check that Sodium (Na) and Chlorine (Cl) are selected from the menus at right. Click Play ( ) to see electrons orbiting the nucleus of each atom. (Note: These atom models are simplified and not meant to be realistic.) 1. Each atom consists of a central nucleus and several shells that contain electrons. The outermost electrons are called valence electrons. How many valence electrons does each atom have
Answer: Sodium element has 1 valence electron and chlorine element has 7 valence electrons.
Explanation:
Valence electrons are defined as the electrons that are present in the outermost shell.
An ionic compound is formed when the complete transfer of electrons takes place from one element (usually metals) to another element (usually non-metals).
To know this, we need to write the electronic configuration of each element.
Sodium is the 11th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^1[/tex]
It has 1 valence electron
Chlorine is the 17th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^23p^5[/tex]
It has 7 valence electrons
Hence, sodium element has 1 valence electron and chlorine element has 7 valence electrons.
You are an intermediate product of an industrial process which intends to separate iron from its ore. A well known iron ore is hematite. Which of these ores does not contain iron?
Goethite
Malachite
Siderite
Limonite
Answer:
Malachite
Explanation:
Malachite is a copper carbonate hydroxide mineral, with the equation Cu2CO3(OH)2. This dark, green-joined mineral solidifies in the monoclinic precious stone framework, and frequently shapes botryoidal, sinewy, or stalagmitic masses, in cracks and profound, underground spaces, where the water table and aqueous liquids give the way to synthetic precipitation. So, the answer is malachite. Best of Luck!
Wat are representative elements
Answer:
the representative elements are elements where the the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3-11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.
Explanation:
=)
Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct number of significant figures.
a. [9.8(±0.3)−2.31(±0.01)]8.5(±0.6)= __________
b. absolute uncertainty: __________
c. absolute uncertainty: _________
d. percent relative uncertainty: ___________
Answer:
Explanation:
Given the equation:
[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}[/tex]
The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.
The first step is to determine the algebraic value on the numerator.
Algebraic value = 9.8 - 231
= 7.49
The absolute uncertainty = [tex]\sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}[/tex]
absolute uncertainty = [tex]\sqrt{(0.3)^3 + (0.01)^2}[/tex]
= [tex]\sqrt{0.09 + 0.0001}[/tex]
= 0.300167
∴
[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)
The division process now is:
[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}[/tex]
Relative uncertainty = [tex]\dfrac{(\pm 0.300167)}{7.49}\times 100 \ , \ \dfrac{(\pm 0.6) }{8.5} \times 100[/tex]
Relative uncertainty = ±4.007565% , ±7.058824%
[tex]\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}[/tex]
[tex]\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}[/tex]
[tex]\text{Relative uncertainty} = \sqrt{65.88757349}[/tex]
[tex]\text{Relative uncertainty} = 8.117116[/tex]
≅ 8%
The algebraic value = [tex]\dfrac{7.49}{8.5}[/tex]
= 0.881176
≅ 0.88
The percentage of the relative uncertainty =[tex]\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100[/tex]
By cross multiplying:
[tex]\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}[/tex]
[tex]\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}[/tex]
[tex]\text{Absolute uncertainty} (\%) = 0.0715260[/tex]
[tex]\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}[/tex]
Finally:
[tex]\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}[/tex]
1. Determine the volume of SO2 (at STP) formed from the reaction of 96.7 mol FeS2 and 55.0 L of O2 at 358 K and 1.20 atm.
4 FeS2(s) + 11O2(g) 2Fe2O3(s) + 8SO2(g)
Answer:
40.0L of SO2 are produced
Explanation:
To solve this question we need to find the moles of O2 using PV = nRT in order to find the moles. Thus, we can find the limiting reactant and the moles (And volume) of SO2 produced as follows:
Moles O2:
n = PV/RT
n = 1.20atm*55.0L / 0.082atmL/molK*358K
n = 2.25 moles of O2.
Clearly, limiting reactant is O2.
The moles of SO2 produced are:
2.25 moles of O2 * (8mol SO2 / 11mol O2) = 1.6351 moles SO2
Volume SO2:
V = nRT/P
V = 1.6351 moles SO2*0.082atmL/molK*358K / 1.20atm
V = 40.0L of SO2 are produced
For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase in GPS of the system, decrease S, or leave S unchanged. If you don’t have enough information to decide, check the “not enough information“ button in the last column. Note for advanced students: you may assume ideal gas and ideal solution behavior.
Answer:
For each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don?t have enough information to decide, check the not enough information button in the last column
What is the price coke difference between a strong and weak acid?
Explanation:
Strong acids are those that are completely ionized in body fluids, and weak acids are those that are incompletely ionized in body fluids. Hydrochloric acid (HCl) is considered a strong acid because it is present only in a completely ionized form in the body, whereas carbonic acid (H2 CO3) is a weak acid because it is ionized incompletely, and, at equilibrium, all three reactants are present in body fluids. See the reactions below.
H2 CO3 (acid)↔H+ + HCO3- (base)
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what is most likely to happen during a precipitation reaction
A substance will react with oxygen to form water and carbon. ... dioxide.
Answer:
it will rain and there the other defined for precipitation snow and sleet and hail
Look at this picture.
Which process in the water cycle is shown in the picture?
evaporation
transpiration
condensation
precipitation
Answer:
condensation
Explanation:
the water has condensed from the gaseous form into rain drops
Answer:
precipitation
Explanation:
Write the structural formula for a primary, a secondary, and a tertiary constitutionally isomeric alcohol of the molecular formula C5H12O.
Answer:
The structures of all isomeric alcohols of molecular formula C5H12O along with their IUPAC names are as shown.
Their classification of primary, secondary, and tertiary alcohols are -
1-pentanol -
2-pentanol -
3-pentanol
2-methylbutan-1-ol
2-methylbutan-2-ol
3-methylbutan-2-ol
3-methylbutan-1-ol
2,2-dimethylpropanol
Identify the alkene obtained on dehydration of each of the following alcohols:
a. 3-Ethyl-3-pentanol
b. 1-Propanol
c. 2-Propanol
d. 2,3,3-Trimethyl-2-butanol
Answer:
Explanation:
The information below explains how dehydration of alcohol occurs to produce alkene.
Under the influence of a catalyst, alcohol dehydrates to produce an alkene and water. To produce alkene and water, the reaction eliminates the OH group from alcohol containing the carbon atom and the hydrogen atom from a neighboring carbon atom via the same molecule.
The –OH group in alcohol contribute two(2) electrons to H+ out from the acid reagent, resulting in the formation of an alkyloxonium ion. This ion serves as an excellent leaving group, allowing a carbocation to form. The nucleophile which acts as the deprotonated acid subsequently attacks and creates a double bond with the hydrogen next to the carbocation.
Gaseous methane CH4 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.963 g of methane is mixed with 1.2 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 2 significant digits.
Answer:
[tex]m_{H_2O}=0.676gH_2O[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the maximum mass of water by firstly setting up the undergoing chemical reaction as follows:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
Thus, we are able to firstly calculate the moles of water produced by both methane and oxygen in order to identify the limiting reactant, which is related to maximum of water:
[tex]0.963 gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{2molH_2O}{1molCH_4} =0.120molH_2O\\\\1.2gO_2*\frac{1molO_2}{32gO_2}*\frac{2molH_2O}{2molO_2} =0.0375molH_2O[/tex]
Thus, we infer the limiting reactant is O2 and therefore we can obtain up to 0.0375 moles of water, which are related to the following mass:
[tex]m_{H_2O}=0.0375molH_2O\frac{18.02gH_2O}{1molH_2O}=0.676gH_2O[/tex]
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A can contains 375mL of soda. Using the appropriate number of significant figures, how much soda is left in the can after 308mL is poured into a glass
Answer:
[tex]V_l=67mL[/tex]
Explanation:
From the question we are told that:
Initial Volume [tex]V_1=375mL[/tex]
Final Volume [tex]V_2=308mL[/tex]
Generally the equation for Left-Over is mathematically given by
[tex]V_l=V_1-V_2[/tex]
[tex]V_l=375-308[/tex]
[tex]V_l=67mL[/tex]
Which of the following mixtures is best separated by the use of a separating funnel?
methane and water
ethyl ethanoate and water
ethanol and water
ethanoic acid and water
Answer:
ethyl ethanoate and water
Explanation:
At the point when one fluid doesn't blend in with another yet glides on top of it, an isolating pipe can be utilized to isolate the two fluids. Oil glides on water. This combination can be isolated utilizing an isolating channel as demonstrated on the following page.
Ethyl liquor and water are two miscible fluids. Refining is a cycle that can be utilized to isolate an unadulterated fluid from a combination of fluids. An isolating channel can be utilized to isolate the parts of the combination of immiscible fluids.
The answer is ethyl ethanoate and water. Hope this helps you!
A community has a nearby forest that has some insect-damaged trees that are dying. They decide to cut the dying trees and sell the wood for
firewood.
How does science knowledge support this solution?
A. Cutting down the trees allows more animals to live in the forest.
B. Using the trees for firewood eliminates pollution caused by heating homes.
C. Selling the diseased trees as firewood allows the community to make money.
D. Removing the diseased trees allows the remaining trees to get more water and sunlight.
what is the pH value of water
Answer:
The pH of pure water (H20) is 7 at 25oC, but when exposed to the carbon dioxide in the atmosphere this equilibrium results in a pH of approximately 5.2. Because of the association of pH with atmospheric gasses and temperature, it is strongly recommended that the water be tested as soon as possible.
Calculate the molality of a 35.4 % (by mass) aqueous solution of phosphoric acid (H3PO4) (35.4 % means 35.4 g of H3PO4in 100 g of solution)
Answer:
3.6124 m/kg
Explanation:
Molality is calculated as moles of solute (mol) divided by kilogram of solvent (kg). Here, we can find these numbers by using the 35.4%, which gives us 35.4 g of H3PO4 and 100 g of solution to work with.
To go from grams to moles for the phosphoric acid, you need to find the molar mass of the compound or element and divide the grams of the compound or element by that molar mass.
Here, the molar mass for phosphoric acid is 97.9952 g/mol. The equation would look like this:
35.4 g x 1 mol / 97.9952 g = 0.3612422 mol
Next, the 100 g of solvent can easily be converted to 0.1 kg of solvent.
To find the molality, divide the moles of solute and kilograms of solution.
0.3612422 mol / 0.1 kg = 3.6124 m/kg
Emily spills concentrated sodium hydroxide solution on her lab bench. What she should do first?
Answer:
Explanation: hell noo
What is the role of a decomposer in a food chain?
A. to move food from producers to consumers
B. to move food from consumers to other consumers
C. to make food for the ecosystem
D. to return matter to the environment
Answer:D
Explanation:
Decomposers decompose food and return it to the environment through the soil
Determine the number of moles of C in each sample
2.0 mol CH4, 0.175 mol C2H6,
4.21 mol C4H10, 24.5 mol C8 H18
Explanation:
In [tex]CH_4[/tex]:Given moles = 2.0 moles
1 mole of methane contains 1 mole of carbon and 4 moles of hydrogen
Moles of carbon in [tex]CH_4=(2.0\times 1)=2.0 moles[/tex]
In [tex]C_2H_6[/tex]:Given moles = 0.175 moles
1 mole of ethane contains 2 moles of carbon and 6 moles of hydrogen
Moles of carbon in [tex]C_2H_6=(0.175\times 2)=0.35 moles[/tex]
In [tex]C_4H_{10}[/tex]:Given moles = 4.21 moles
1 mole of butane contains 4 moles of carbon and 10 moles of hydrogen
Moles of carbon in [tex]C_4H_{10}=(4.21\times 4)=16.84 moles[/tex]
In [tex]C_8H_{18}[/tex]:Given moles = 24.5 moles
1 mole of octane contains 8 moles of carbon and 18 moles of hydrogen
Moles of carbon in [tex]C_8H_{18}=(24.5\times 8)=196 moles[/tex]
What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid a 0° C?
The molecule β-carotene has λ 450 nm, and ɛ = 15,000 m2 mol-1. Calculate the absorption (A) expected for a solution in which 0.1 mg has been dissolved in 10 ml of water (given: the molecular weight of β-carotene, C40H56, as 536) with a path length of 1 cm. Group of answer choices
Answer: The absorbance for a solution is 0.0028
Explanation:
To calculate the absorption of a solution, the equation by Beer-Lambert law is used:
[tex]A=\varepsilon \times b\times C[/tex]
OR
[tex]A=\varepsilon \times b\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex]
where,
A = absorbance = ?
[tex]\varepsilon[/tex] = molar absorptivity = [/tex]15000m^2mol^{-1}L[/tex]
b = path length = 1 cm = 0.01 m (Conversion factor: 1 m = 100 cm)
Given mass of [tex]\beta-[/tex] carotene = 0.1 mg = 0.0001 g (Conversion factor: 1 g = 1000 mg)
Molar mass of [tex]\beta-[/tex] carotene = 536 g/mol
Volume of solution = 10 mL
Putting values in equation 1:
[tex]A=15000\times 0.01\times \frac{0.0001\times 1000}{536\times 10}\\\\A=0.0028[/tex]
Hence, the absorbance for a solution is 0.0028
What is its density in kilograms per cubic meter?
Copper has a density of 8950 kg/m3 = 8.95 kg/dm3 = 8.95 g/cm3. Water has a density of 1000 kg/m3 = 1000 g/L = 1 kg/dm3 = 1 kg/L = 1 g/cm3 = 1 g/mL.
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Draw the structure of the neutral organic product formed in the reaction. Do not draw counterions or byproducts.
Answer: Hello the reaction related to your question is missing attached below is the reaction
answer : attached below
Explanation:
The structure of the neutral organic product formed in the reaction is attached below.
The neutral organic product formed is ESTER
The reaction in the question is Anhydride on reaction with alcohol
What law allows calories to be determined by heat (energy) transfer from one substance to another, but it is never destroyed?
Answer:
matter i think
Explanation:
matter i am pretty sure
The law that allows calories to be determined by heat (energy) transfer from one substance to another, but it is never destroyed is first law of thermodynamics.
What is first law of thermodynamics?Energy cannot be generated or destroyed, only changed in form, according to the basic law of thermodynamics.
Energy transfer occurs when mass crosses the control boundary, external work is performed, or heat is transferred across the boundary in any system. These cause the stored energy in the control volume to shift.Hence first law of thermodynamics justify the given statement.
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When optically active (R)-2-methylcyclohexanone is treated with either aqueous base or acid, racemization occurs. Explain.
Answer:
See explanation
Explanation:
Racemization is said to occur when a 1:1 ratio of (+) and (-) enantiomers of a compound are produced in a reaction.
The reaction of optically active (R)-2-methylcyclohexanone with either aqueous base or acid leads to the formation of a planar enol species for reaction with acid and a planar enolate species for reaction with base.
Both reactions involves the formation of achiral species which reverts back to the chiral product with equal chances of the formation of both enantiomers of the product during the process. This leads to racemization of the product in both cases.
Racemization of the optically active (R)-2-methylcyclohexanone results from the production and subsequent interconversion of intermediates during the reaction with an aqueous base or acid. This is due to the inversion of stereochemistry at the chiral centre.
Racemization can happen when an optically active molecule is exposed to an aqueous base or acid because the compound's enantiomers are interconverted. The carbon-carbon bond next to the carbonyl group in (R)-2-methylcyclohexanone breaks as a result of the chemical reaction with the aqueous base or acid. The creation of the negatively charged intermediate known as the enolate ion occurs when a base, such as hydroxide ions, is present and attacking the carbonyl carbon. The carbonyl group can then be reformated by this enolate ion after it has undergone a nucleophilic attack on a proton.
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