Answers
Answer:
[tex]y = \boxed0[/tex]
Step-by-step explanation:
we are given a sin function
[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) [/tex]
we want to figure out the midline of the function graphically The midline of a sinusoidal function is the horizontal line that passes exactly in the midline of its extreme value however since we a function recall that,
[tex] \displaystyle f(x) = a \sin(bx -c) + d[/tex]
where the midline is
[tex]y = d[/tex]to figure out the midline rewrite the function
[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) + 0[/tex]
therefore the midline is
[tex]y = \boxed0[/tex]
Related Questions
Select the correct answer from each drop-down menu.
A company makes cylindrical vases. The capacity, in cubic centimeters, of a cylindrical vase the company produces is given by the
function C() = 6.2873 + 28.26x2, where x is the radius, in centimeters. The area of the circular base of a vase, in square
centimeters, is given by the function A () = 3.14.2
To find the height of the vase, divide
represents the height of the vase.
the expressions modeling functions C(x) and A(z). The expression
Answers
Answer:
divide, 2x+9
Step-by-step explanation:
got it right
help lol i forgot everything of the summer time
fill in the table using this function rule
Answers
Answer:
hope it help you
Step-by-step explanation:
mark me brailiest answer
1. Y=-4(-1)+3
Y=4+3
Y=7
2. Y=-4(0)+3
Y=0+3
Y=3
3. Y=-4(1)+3
Y=-4+3
Y=-1
4. Y=-4(2)+3
Y=-8+3
Y=-5
Hope this helps!! :)
4. a) x2 + xy2 + y 4
Answers
Answer:
x2 + xy2 + y 4=（x+y^2)^2-xy^2
Step-by-step explanation:
The chance of solving a problem by A and B is and 1/3 and 2/5 respectively. What is the probability the problem will be solved?
a)2/15
b)1
c)9/15
d)11/15
Books shows "c" as the answer.. I am confused..
Answers
We want to compute the probability P(A or B) because we could either solve it following path A, path B, or doing both paths.
P(A) = 1/3
P(B) = 2/5
P(A and B) = P(A)*P(B) assuming A,B are independent
P(A and B) = (1/3)*(2/5)
P(A and B) = 2/15
--------
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B) = 1/3 + 2/5 - 2/15
P(A or B) = 5/15 + 6/15 - 2/15
P(A or B) = (5 + 6 - 2)/15
P(A or B) = 9/15
We could reduce this to 3/5, but it appears your teacher has chosen not to.
PLS HELP ME ON THIS QUESTION I WILL MRK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Which of the following measures is a measure of spread?
A. median
B. range
C. mode
D. mean
Answers
Answer:
range
Step-by-step explanation:
Answer:
B. range.
Step-by-step explanation:
others are:
» Standard variation.
» Interquatile range.
» Quatiles, deciles and percentiles.
» variance.
[tex]{ \underline{ \blue{ \sf{christ \: † \: alone}}}}[/tex]
What is the smallest 3-digit palindrome that is divisible by both 3 and 4?
Answers
Answer:
252
Step-by-step explanation:
To be divisible by 3, it's digits have to add to a number that is a multiple of 3.
To be divisible by 4 its last 2 digits have to be divisible by 3.
So let's start with 1x1 which won't work because 1x1 is odd. so let's go to 2x2 and see what happens.
212 that's divisible by 4 but not 3
222 divisible by 3 but not 4
232 divisible by 4 but not 3
242 not divisible by either one.
252 I think this might be your answer
The digits add up to 9 which is a multiple of 3 and the last 2 digits are divisible by 4
find the missing side. Round it the nearest tenth.
Answers
Answer: x= 11√3= 19.0525 = 19.1
Step-by-step explanation:
Let the reference angle be 30
so
cos 30 = b/h
√3/2 = x/22
or, 22√3 = 2x
or. x = (22√3)/2
so, x = 11√3
Answer:
x = 19.1 cm
Step-by-step explanation:
→ Find the name of the side you are not given
Opposite
→ Find a formula without opposite in it
Cos = Adjacent ÷ Hypotenuse
→ Rearrange to make adjacent the subject
Adjacent = Cos × Hypotenuse
→ Substitute in the values
Adjacent = Cos ( 30 ) × 22
→ Simplify
Adjacent = 19.1
Amy, a nature photographer, randomly sampled photographs she took within the last year. She wanted to find out how many of her photographs contained flowers. The proportion of photographs that had flowers was 0.61, with a margin of error of 0.04. Construct a confidence interval for the proportion of her photographs taken within the last year contained flowers.
Answers
The Constructed confidence interval for the proportion of her photographs taken within the last year contained flowers is
[tex]CI\ E(0.57,0.65)[/tex]
From the question we are told that:
The proportion of photographs that had flowers P= 0.61
Margin of error of M.E= 0.04
Generally, the equation for Confidence interval for proportion is mathematically given by
[tex]CI=0.61 \pm 0.04[/tex]P \pm M.E
Therefore Confidence interval is
[tex]CI=0.61 \pm 0.04[/tex]
And can also be written as
[tex]CI\ E((0.61+0.04),0.61-0.04))[/tex]
[tex]CI\ E(0.57,0.65)[/tex]
In conclusion the Confidence interval is
[tex]CI\ E(0.57,0.65)[/tex]
For more information on this visit
https://brainly.com/question/24131141?referrer=searchResults
If a line has a midpoint at (2,5), and the endpoints are (0,0) and (4,y), what is the value of y? Please explain each step for a better understanding:)
Answers
Answer:
y = 10
Step-by-step explanation:
To find the y coordinate of the midpoint, take the y coordinates of the endpoints and average
(0+y)/2 = 5
Multiply each die by 2
0+y = 10
y = 10
100 POINTS AND BRAINLIEST FOR THIS WHOLE SEGMENT
a) Find zw, Write your answer in both polar form with ∈ [0, 2pi] and in complex form.
b) Find z^10. Write your answer in both polar form with ∈ [0, 2pi] and in complex form.
c) Find z/w. Write your answer in both polar form with ∈ [0, 2pi] and in complex form.
d) Find the three cube roots of z in complex form. Give answers correct to 4 decimal
places.
Answers
Answer:
See Below (Boxed Solutions).
Step-by-step explanation:
We are given the two complex numbers:
[tex]\displaystyle z = \sqrt{3} - i\text{ and } w = 6\left(\cos \frac{5\pi}{12} + i\sin \frac{5\pi}{12}\right)[/tex]
First, convert z to polar form. Recall that polar form of a complex number is:
[tex]z=r\left(\cos \theta + i\sin\theta\right)[/tex]
We will first find its modulus r, which is given by:
[tex]\displaystyle r = |z| = \sqrt{a^2+b^2}[/tex]
In this case, a = √3 and b = -1. Thus, the modulus is:
[tex]r = \sqrt{(\sqrt{3})^2 + (-1)^2} = 2[/tex]
Next, find the argument θ in [0, 2π). Recall that:
[tex]\displaystyle \tan \theta = \frac{b}{a}[/tex]
Therefore:
[tex]\displaystyle \theta = \arctan\frac{(-1)}{\sqrt{3}}[/tex]
Evaluate:
[tex]\displaystyle \theta = -\frac{\pi}{6}[/tex]
Since z must be in QIV, using reference angles, the argument will be:
[tex]\displaystyle \theta = \frac{11\pi}{6}[/tex]
Therefore, z in polar form is:
[tex]\displaystyle z=2\left(\cos \frac{11\pi}{6} + i \sin \frac{11\pi}{6}\right)[/tex]
Part A)
Recall that when multiplying two complex numbers z and w:
[tex]zw=r_1\cdot r_2 \left(\cos (\theta _1 + \theta _2) + i\sin(\theta_1 + \theta_2)\right)[/tex]
Therefore:
[tex]\displaystyle zw = (2)(6)\left(\cos\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right) + i\sin\left(\frac{11\pi}{6} + \frac{5\pi}{12}\right)\right)[/tex]
Simplify. Hence, our polar form is:
[tex]\displaystyle\boxed{zw = 12\left(\cos\frac{9\pi}{4} + i\sin \frac{9\pi}{4}\right)}[/tex]
To find the complex form, evaluate:
[tex]\displaystyle zw = 12\cos \frac{9\pi}{4} + i\left(12\sin \frac{9\pi}{4}\right) =\boxed{ 6\sqrt{2} + 6i\sqrt{2}}[/tex]
Part B)
Recall that when raising a complex number to an exponent n:
[tex]\displaystyle z^n = r^n\left(\cos (n\cdot \theta) + i\sin (n\cdot \theta)\right)[/tex]
Therefore:
[tex]\displaystyle z^{10} = r^{10} \left(\cos (10\theta) + i\sin (10\theta)\right)[/tex]
Substitute:
[tex]\displaystyle z^{10} = (2)^{10} \left(\cos \left(10\left(\frac{11\pi}{6}\right)\right) + i\sin \left(10\left(\frac{11\pi}{6}\right)\right)\right)[/tex]
Simplify:
[tex]\displaystyle z^{10} = 1024\left(\cos\frac{55\pi}{3}+i\sin \frac{55\pi}{3}\right)[/tex]Simplify using coterminal angles. Thus, the polar form is:
[tex]\displaystyle \boxed{z^{10} = 1024\left(\cos \frac{\pi}{3} + i\sin \frac{\pi}{3}\right)}[/tex]
And the complex form is:
[tex]\displaystyle z^{10} = 1024\cos \frac{\pi}{3} + i\left(1024\sin \frac{\pi}{3}\right) = \boxed{512+512i\sqrt{3}}[/tex]
Part C)
Recall that:
[tex]\displaystyle \frac{z}{w} = \frac{r_1}{r_2} \left(\cos (\theta_1-\theta_2)+i\sin(\theta_1-\theta_2)\right)[/tex]
Therefore:
[tex]\displaystyle \frac{z}{w} = \frac{(2)}{(6)}\left(\cos \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right) + i \sin \left(\frac{11\pi}{6} - \frac{5\pi}{12}\right)\right)[/tex]
Simplify. Hence, our polar form is:
[tex]\displaystyle\boxed{ \frac{z}{w} = \frac{1}{3} \left(\cos \frac{17\pi}{12} + i \sin \frac{17\pi}{12}\right)}[/tex]
And the complex form is:
[tex]\displaystyle \begin{aligned} \frac{z}{w} &= \frac{1}{3} \cos\frac{5\pi}{12} + i \left(\frac{1}{3} \sin \frac{5\pi}{12}\right)\right)\\ \\ &=\frac{1}{3}\left(\frac{\sqrt{2}-\sqrt{6}}{4}\right) + i\left(\frac{1}{3}\left(- \frac{\sqrt{6} + \sqrt{2}}{4}\right)\right) \\ \\ &= \boxed{\frac{\sqrt{2} - \sqrt{6}}{12} -\frac{\sqrt{6}+\sqrt{2}}{12}i}\end{aligned}[/tex]
Part D)
Let a be a cube root of z. Then by definition:
[tex]\displaystyle a^3 = z = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]
From the property in Part B, we know that:
[tex]\displaystyle a^3 = r^3\left(\cos (3\theta) + i\sin(3\theta)\right)[/tex]
Therefore:
[tex]\displaystyle r^3\left(\cos (3\theta) + i\sin (3\theta)\right) = 2\left(\cos \frac{11\pi}{6} + i\sin \frac{11\pi}{6}\right)[/tex]
If two complex numbers are equal, their modulus and arguments must be equivalent. Thus:
[tex]\displaystyle r^3 = 2\text{ and } 3\theta = \frac{11\pi}{6}[/tex]
The first equation can be easily solved:
[tex]r=\sqrt[3]{2}[/tex]
For the second equation, 3θ must equal 11π/6 and any other rotation. In other words:
[tex]\displaystyle 3\theta = \frac{11\pi}{6} + 2\pi n\text{ where } n\in \mathbb{Z}[/tex]
Solve for the argument:
[tex]\displaystyle \theta = \frac{11\pi}{18} + \frac{2n\pi}{3} \text{ where } n \in \mathbb{Z}[/tex]
There are three distinct solutions within [0, 2π):
[tex]\displaystyle \theta = \frac{11\pi}{18} , \frac{23\pi}{18}\text{ and } \frac{35\pi}{18}[/tex]
Hence, the three roots are:
[tex]\displaystyle a_1 = \sqrt[3]{2} \left(\cos\frac{11\pi}{18}+ \sin \frac{11\pi}{18}\right) \\ \\ \\ a_2 = \sqrt[3]{2} \left(\cos \frac{23\pi}{18} + i\sin\frac{23\pi}{18}\right) \\ \\ \\ a_3 = \sqrt[3]{2} \left(\cos \frac{35\pi}{18} + i\sin \frac{35\pi}{18}\right)[/tex]
Or, approximately:
[tex]\displaystyle\boxed{ a _ 1\approx -0.4309 + 1.1839i,} \\ \\ \boxed{a_2 \approx -0.8099-0.9652i,} \\ \\ \boxed{a_3\approx 1.2408-0.2188i}[/tex]
Here is a list of fractions 18/45 14/30 10/25 8/20 16/40 one of these fractions are not equivalent to 2/5 write down this fractions
Answers
Answer:
14/30Step-by-step explanation:
How to simplify: • divide both numerator and denominator by their GCF.18/45= 18 ÷ 9 / 45 ÷ 9= 2/514/30= 14 ÷ 2 / 30 ÷ 2= 7/1510/25= 10 ÷ 5 / 25 ÷ 5= 2/58/20= 8 ÷ 4 / 20 ÷ 4= 2/516/40= 16 ÷ 8 / 40 ÷ 8= 2/5[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
[tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex] in the list of fractions [tex]\frac{18}{45}, \frac{14}{30} , \frac{x}{y} \frac{10}{25}, \frac{8}{20}, \frac{16}{40}[/tex].
Equivalent FractionsEquivalent fractions represent the same value even though they look different.
How to determine the Equivalent fractions?We know we can find an equivalent fraction of a given fraction by or dividing both the numerator and denominator of the given fraction with the same number (maybe LCM or HCF of the numerator or denominator).
[tex]\frac{18}{45}=\frac{18/9}{45/9}=\frac{2}{5}[/tex] (since [tex]9[/tex] is HCF of [tex]18, 45[/tex])
[tex]\frac{14}{30}=\frac{14/2}{30/2}=\frac{7}{15}[/tex] (since [tex]2[/tex] is HCF of [tex]7, 15[/tex])
[tex]\frac{10}{25} =\frac{10/5}{25/5} =\frac{2}{5}[/tex] (since [tex]5[/tex] is HCF of [tex]10, 25[/tex])
[tex]\frac{8}{20} =\frac{8/4}{20/4} =\frac{2}{5}[/tex] (since [tex]4[/tex] is HCF of [tex]8, 20[/tex])
[tex]\frac{16}{40} =\frac{16/8}{40/8} =\frac{2}{5}[/tex] (since [tex]8[/tex] is HCF of [tex]16, 40[/tex])
Thus, [tex]\frac{14}{30}[/tex] is not equivalent to [tex]\frac{2}{5}[/tex].
Learn more about Equivalent fractions here- https://brainly.com/question/17912
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help help help help
Answers
Answer:
abc is a triangle so ,
a is ( 9,6 )
b is ( 9,3 )
and c is ( 3,3 )
Evaluate 4(3 - 1)^2..
Answers
Answer:
16
Step-by-step explanation:
4(3 - 1)^2
~Simplify using PEMDAS
4(2)^2
4(4)
16
Best of Luck!
Helpppp pleaseeee !!!!!!
Answers
Answer:
149 inches squared
Step-by-step explanation:
top rectangle: 25 * 7 = 175
second rectangle: 8 * (25 - 17) = 8^2 = 64
triangle in bottom right: 1/2 * (13 - 8) * (15 - 11) = 10
175 + 64 + 10 = 149 sq in
hopefully got this right!
If LM = 9x + 27 and RS = 135, find x.
Answers
Answer:
x=12
Step-by-step explanation:
LM = RS
9x+27 = 135
Subtract 27 from each side
9x+27-27 =135-27
9x=108
Divide each side by 9
9x/9 = 108/9
x = 12
the boxes are equivalent so the one with a single dash is equal to the other with a single dash.
the one with 2 dashes is equal to the other with 2 dashes so on and so forth
SR=LM
LM=9x+27
RS=135
9x+27=135
so I solve it in my own weird way but you can solve it differently. 135-27=108
108/9=12
so your answer is 12
ax^2-y^2-x-y factorize
Answers
Answer:
x(ax-1)-y(y+1)
Step-by-step explanation:
you have to group the like terms
ax^2-x-y^2-y
x(ax-1)-y(y+1)
I hope this helps
Lilian is building a swimming pool in the shape of a right rectangular prism. The area of the base of the swimming pool is 72 square meters. The depth of the swimming pool is 3 meters. What is the volume of the swimming pool?
Answers
Answer:
216
Step-by-step explanation:
Volume of a rectangular prism = area of base * depth
Area of base: 72
Depth: 3
Volume = 72 * 3 = 216
help me pls??????? :)
Answers
Answer:4 in each bad 2 left over
Step-by-step explanation:
Answer:
4 in each bag and 2 left over
Step-by-step explanation:
divide 14 by 3
3 goes into 14, 4 times
14 - 12 = 2
4 in each bag and then 2 left over
What is the quotient?
(-3)
(-3)²
O-9
1
o
1
9
100
O 9
Answers
Answer:
(-3)
Step-by-step explanation:
follow me if you want
Determine the sum of the first 33 terms of the following series:
−52+(−46)+(−40)+...
Answers
Answer:
1320
Step-by-step explanation:
Use the formula for sum of series, s(a) = n/2(2a + (n-1)d)
The terms increase by 6, so d is 6
a is the first term, -56
n is the terms you want to find, 33
Plug in the numbers, 33/2 (2(-56)+(32)6)
Simplify into 33(80)/2 and you get 1320
Two observers are 300 ft apart on opposite sides of a flagpole. The angles of
elevation from the observers to the top of the pole are 20°
and 15°. Find the
height of the flagpole.
Answers
Help me! thank you so much
Answers
Answer:
Step-by-step explanation:
[tex]\frac{sinxcos^3x-cos xsin^3x}{cos^42x-sin^42x} \\=\frac{sin x cos x(cos^2x-sin ^2 x)}{(cis^2 2x+sin^2 2x)(cos^2 2x-sin ^22x)} \\=\frac{2sin x cos x cos 2x}{2(1)(cos 4x)} \\=\frac{sin 2x cos 2x}{2 cos 4x} \\=\frac{2 sin 2x cos 2x}{4 cos 4x} \\=\frac{sin 4x}{4 cos 4x} \\=\frac{1}{4} tan 4x[/tex]
What would it be tho 300 doesn’t show up in my options my options are
1/49 -1/49 -49 and 49
Answers
F is on the bisector of angle BCD. Find the length of FD (with lines over FD)
Answers
Answer:
8n-2 = 6n+9
2n-2 = 9
2n = 11
n = 5.5
So C is correct
Let me know if this helps!
Jay has a jar of beads. 6 purple beard, 8 blue beads, and 4 yellow beads. If he removes one bead at random, what is the probability that it will not be yellow?
Answers
You get a pie chart to do percentages just so you dont cheat you still can do work y'know
I NEEDDD HELPPP ITSSSSSS URGENTTTTT!!!
Answers
100 degrees
Step-by-step explanation:
measure of FHD = 65 + 35
measure of FHD = 100
Basically count/add up the total amount of degrees that are include in the angle <FHD.
-- (central angles)
So, 35 + 65 = 100 degrees
a piece of work can be done by 24 men in 15 days.in how many days can 18 men do the same work?
Answers
18 people is 25% less people so will take 25% longer
25% of 15 is 3.75
3.75+ 15 = 18.75 days ?
Find the length of x
Answers
Answer:
20
Step-by-step explanation:
Since the triangles are similar then the sides must be proportional
10/6 = x/12 cross multiply expressions
6x = 120 divide both sides by 6
x = 20
3a + 2 = 20
5(b+1) = 10
3 (2y - 3) - 2y = y-3
2+ (2+4p) =6p
Please answer these questions with steps please!
Answers
3a=18
a=6
2. b+1=2
b=2-1
b=1
3. 6y-9-2y=y-3
4y-9=y-3
4y-y=-3+9
3y=6
y=2
4. 2+2+4p=6p
4+4p=6p
4p-6p=-4
-2p=-4
p=2
SAT/ACT What is the solution of 1,200 – 5(3x + 30) = 600? A 30 B 50 C 150 D 200 E 250
Answers
The answer you are looking for is letter A, x=30.
Solution/Explanation:
First, write out the equation,
1200-5(3x+30)=600
Next, using the Distributive Property,
1200-15x-150=600
Simplify the left side of the equation just a little bit more,
1050-15x=600
Reverse order of terms on the left side, to make it a little bit easier to solve,
-15x+1050=600
Now, subtract 1050 from both sides,
-15x+1050-1050=600-1050
Now, simplify this part of the equation,
-15x=-450
Finally, divide both sides by -15,
So, therefore, the final answer is x=30.
I hope this helped you. Enjoy your day, and take care!
