Molarity= no. of moles of solute/ volume of solution(in L)
Molarity = 6.2 moles/ 2.5 L = 62/25 mol/L
= 2.48 mol/L
How many grams of water should be added to 4.00 g NaOH to create 2.00% by mass NaOH solution?
Answer:
196 grams
because ^^^ was wrong and person in comments said it was 196 and it was right
When NaOH of 4.00 g is being added with water, the mass of water required to create 2.00% of NaOH solution by mass is 196 g.
What is mass percent of solute?It means that the particular amount of solute in terms of percentage is present in the solute.
Given the mass of the solute, NaOH is 4.00g
Suppose the mass of water required to add is x in g.
The mass percent of the solute is
[tex]\dfrac{2}{100} =\dfrac{4.00}{4.00 +x }[/tex]
x =196 g
Therefore, mass of water required to create 2.00% of NaOH solution by mass is 196 g.
Learn more about Mass percent of solute.
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Consider the following reaction occurring in a 1.0 L container:
H2 (g) + I2 (g) → 2 HI (g)
State 2 requirements for a successful collision between H2 and I2.
Answer:
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