Which two moon phases can occur while the
relative positions of the sun, Earth, and moon
form a straight line?
Answer:
its the lunar and solar eclipse
Explanation:
the solar eclipse happens when the moon is in between the sun and earth
Please answer all of the examples below!
Answer:
The first one is balanced. The second one is not.
Explanation:
The first one is balanced because there are the same amount of elements on the reactant side as there are on the product side. The second one is not balanced because there are not the same amount of elements on the reactant side as there are on the product side. Therefore, it is not balanced
More Detailed: first example
Reactant side (left of arrow)
H: 2
C: 1
O: 3
Product side (right of arrow)
H: 2
C: 1
O: 3
More detailed: second example
Reactant side:
Na: 1
O: 1
H: 1
C: 1
Product side:
Na: 2
O: 4
H: 2
C: 1
the variables needed to balance this equation is 2,1, 1, 1.
If 4.04g of h2 gas react with oxygen gas to create 36.36g of water, how many grams of oxygen reacted?
Answer:
gO₂ = 32.32 g
Explanation:
In this case, let's write the general equation:
2H₂ + O₂ -------> 2H₂O
In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.
According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:
gO₂ = 36.36 - 4.04
gO₂ = 32.32 gHope this helps
Consider the following balanced equation:
3 H2 + N2 --> 2 NH3
What volume of hydrogen gas will react in a perfect ratio
with 3 liters of nitrogen gas?
Answer:
[tex]from \: avogadros \: hypothesis \\ 1 \: mole \: of \: nitrogen \: reacts \: with \: 3 \: moles \: of \: hydrogen \\ 3 \: litres \: of \: nitrogen \: react \: with \: ( \frac{3 \times 3}{1} ) \\ 9 \: litres \: of \: hydrogen[/tex]
What three temperature measurements Inust you make to calculate the specific heat of a sample using a calorimeter?
Answer:
Explanation:
Heat and temperature are two different but closely related concepts. Note that they have different units: temperature typically has units of degrees Celsius ( ∘ C ^\circ\text C ∘Cdegrees, start text, C, end text) or Kelvin ( Kstart text, K, end text), and heat has units of energy, Joules ( Jstart text, J, end text).
How much water should be added to 5.00 g of KCl to prepare a 0.500 m
solution? *
Molality = moles of solute
Kg of solvent
100 g
38g
500 g
134 g
Other
Answer:133.4
c
m
3
Explanation: Explanation:
Molarity is number of moles of solute divided by number of litres of solution.
M
=
n
V
Rearrange for V to give
V
=
n
M
Number of moles of KCl is the mass divided by the molar mass of KCl which is 75.5 g/mol, so (5/75.5) = 0.0667 moles.
Now plug in the numbers:
V
=
n
m
=
0.0667
0.5
=
0.1334
litres
So you need to add 0.1334 litres of 133.4
c
m
3
of water.
(NB: symbol for molarity is upper case M. m is metres).
Si la masa de una muestra de un compuesto Y es de 196 gramos y contiene 2 mol, la masa molar de Y es
Answer:
98 g/mol
Explanation:
La masa molar de un compuesto es la cantidad de materia (medida como masa) que hay en 1 mol de dicho compuesto. Por lo tanto, puede calcularse como sigue:
masa molar = masa/número moles
Tenemos los siguientes datos del compuesto Y:
masa Y = 196 g
número de moles de Y = 2 mol
Entonces, podemos calcular la masa molar de Y de la siguiente manera:
masa molar Y = (masa Y)/(número de moles de Y) = 196 g/2 mol = 98 g/mol
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con 1 g de H2O.
Answer:
0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.
Explanation:
¡Hola!
En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:
[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]
Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:
[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]
De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.
¡Saludos!
i hate chemistry but someone help please, no links or you’ll be reported
Answer:
A, D, E
Explanation:
Ca(NO3)2 wht is the mass
Answer:
164.088 g/mol
Explanation: hope this helps
Answer:
Calcium nitrate
Explanation:
164.088 g/mol
give me the brainliest plss
What is a precipitation
reaction?
Answer:
A precipitation reaction is one in which substances in solution are mixed and an insoluble product is made. The insoluble product is called a precipitate and can be seen as a solid forming in the reaction mixture.
Sample A has a mass of 40g and a volume of 10cm^3. Sample B has a volume of 15cm^3 and a mass of 45g. Which sample has a greater density? Show your work.
The Answer Is Sample A
Density -
[tex]density = \frac{mass}{volume} [/tex]
Input The Formula For Both Equations To Find Density.
Sample A -
[tex]d = \frac{40}{10} [/tex]
[tex]d = 4[/tex]
Sample B -
[tex]d = \frac{45}{15} [/tex]
[tex]d = 3[/tex]
A greater force is required to move an object with a larger mass than one with a smaller
mass.
Answer:
Explanation:
what do u need to know
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O How many moles of oxygen gas (O2) are needed to create EXACTLY 6 moles of Carbon dioxide(CO2)?.
*
14. An AREA which drains into a common river system.
watershed
tributary
drainage divide
riparian zone
