What is the relationship between the diameter d and circumference c of a circle

Hello,

a) photo attached

b) When y = 1, x ≈ 0.5

Verification through calculation :

We have :

y = 4x - 1

⇔ 1 = 4x - 1

⇔ 4x = 2

⇔ x = 2/4 = 0.5

This is just !

:-)

Answer:

500000 cm2

Step-by-step explanation:

Answer:

Option B

Step-by-step explanation:

By applying the converse theorem of corresponding angles,

"If corresponding angles formed between two parallel lines and the transversal line are equal then both the lines will be parallel"

Angle between line B and Y = 90°

Angle between line B and Z = 90°

Therefore, corresponding angles are equal.

By applying converse theorem, line Y and line Z will be parallel.

Option B will be the answer.

Answer:

4 and 5

Step-by-step explanation:

Let the numbers be x and y

If their sum is 9, hence;

x + y = 9 ....1

When reversed

10y+x = 2(10x+y)

10y+x = 20x + 2y

10y - 2y = 20x - x

8y = 19x

y = 10x/8 ...2

Substitute equation 2 into 1;

From 1;

x+y = 9

x +(10x/8) = 9

18x/8 = 9

18x = 72

x = 72/18

x = 4

Since x+y =9

y = 9-x

y =9-4

y = 5

Hence the numbers are 4 and 5

Answer:

Associative property

Step-by-step explanation:

The associative property is a math rule that says that the way in which factors are grouped in a multiplication problem does not change the product.

Hope this helps

Answer:

The data represents data right-skewed because it's numerical data are in the right place and showing the percentage of an event/object.

#LearnwithBrainly

Answer/Step-by-step explanation:

The diagram of the circular track is missing, and so also its dimensions.

However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.

Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.

Circumference = πd

d = 20 m (we are assuming the diameter is 20 meters)

π = 3.14

Circumference of circular track = 3.14 × 20 = 62.8 m.

This means that 1 lap = 62.8 m that she would have to run.

Therefore,

6 laps would be = 6 × 62.8 = 376.8 m

Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.

Answer:

The surface charge density is [tex]7.8\times10^{-8} C/m^2[/tex].

Step-by-step explanation:

separation, d = 85 mm

Work, W = 6 x 10^-3 J

charge , Q = 8µC

The potential difference is given by

W = q V

[tex]V=\frac{6\times 10^{-3}}{8\times 10^{-6}}=750 V[/tex]

Let the charge on he capacitor is q.

[tex]q = CV\\\\q = \frac{\varepsilon oA}{d}\times V\\\\\frac{q}{A} = \frac{8.85\times 10^{-12}\times750}{0.085} =7.8\times10^{-8} C/m^2[/tex]

Answer:

Each term is 4 less than the previous term.

Step-by-step explanation:

If this helps you mark as brainlist!

Answer:

B and D are your answers for that whole page

Step-by-step explanation:

Identify the rule that correctly describes each sequence.

12, 8, 4, 0, –4, …

Each term is 4 more than the previous term.

This Is the right one: Each term is 4 less than the previous term.

Each term is 1/2 the previous term.

Each term is 2/3 the previous term.

6, 12, 24, 48, 96, …

Each term is 6 more than the previous term.

Each term is 12 more than the previous term.

Each term is 1/2 the previous term.

This is the right one: Each term is 2 times the previous term.

Answer:

Try to glue it back together

Step-by-step explanation:

I heard gorilla glue works, but be careful and don't get the glue on your body. If that happens it can cause irritation and call posion control immediately.

Answer:

y = ( x-4)(x+7)

Step-by-step explanation:

When we know the zeros of the equation, we can write the equation in the form

y= a(x-z1) (x-z2)   where a is a constant and z1 and z2 are the zeros (solutions)

y = a( x-4)(x--7)

y =a( x-4)(x+7)

Since its says write an equation, we can pick a and I will let a=1

y = ( x-4)(x+7)

Given:

A cube has square sides with area [tex]x^2+24x+144[/tex].

To find:

The expression that represents the surface area of the cube.

Solution:

It is given that,

The area of each side of cube = [tex]x^2+24x+144[/tex]

Number of sides of a cube = 6

Total surface area of the cube is the product of number of sides of the cube and the area of each side. So, the total surface area of the cube is

[tex]SA=6(x^2+24x+144)[/tex]

[tex]SA=6(x^2)+6(24x)+6(144)[/tex]

[tex]SA=6x^2+144x+864[/tex]

Therefore, the expression that represents the surface area of the cube is [tex]6x^2+144x+864[/tex].

Answer:

The answer is D

Step-by-step explanation:

-x is n

Y=0

Answer:

D

Step-by-step explanation:

Basically....... graph shown in picture

Answer:

12 5/24 thats the answer

Step-by-step explanation:

use this website for mixed number calculator: https://www.calculatorsoup.com/calculators/math/mixednumbers.php

Answer:

3

Step-by-step explanation:

f(x) =2x+3

Let x=0

f(0) =2*0+3

Multiply

f(0) =0+3

Add

f(0) =3

Answer:

3

step-by-step explanation

f ( x ) = 2 x + 3

f ( 0 ) = 2 × 0 + 3 .. ( f ( x = 0 ) - given )

multiply

f ( 0 ) = 0 + 3

Add the numbers

f ( 0 ) = 3

Answer:

2 cups of Ice cream and 4 cups of dark choclate

Step-by-step explanation:

If 20 needs 1 cup cream 2 cups dark chocolate you want to find 40 you need to double all ingrediants so answer is 2 cups of Ice cream and 4 cups of dark choclate

Answer:

Option A = 1/15 cubic meters

Step-by-step explanation:

Formule to find volume of rectangular prism:

Volume = width × height × length

V = w×h×l

V = 1/3 × 1/4 × 4/5

V = 1/15 cubic meters

Answer:

[tex] \displaystyle - \frac{1}{2} [/tex]

Step-by-step explanation:

we would like to compute the following limit:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{1}{ \ln(x + \sqrt{ {x}^{2} + 1} ) } - \frac{1}{ \ln(x + 1) } \right) [/tex]

if we substitute 0 directly we would end up with:

[tex] \displaystyle\frac{1}{0} - \frac{1}{0} [/tex]

which is an indeterminate form! therefore we need an alternate way to compute the limit to do so simplify the expression and that yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

now notice that after simplifying we ended up with a rational expression in that case to compute the limit we can consider using L'hopital rule which states that

[tex] \rm \displaystyle \lim _{x \to c} \left( \frac{f(x)}{g(x)} \right) = \lim _{x \to c} \left( \frac{f'(x)}{g'(x)} \right) [/tex]

thus apply L'hopital rule which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \ln(x + 1) - \ln(x + \sqrt{ {x}^{2} + 1 } }{ \dfrac{d}{dx} \ln(x + \sqrt{ {x}^{2} + 1} ) \ln(x + 1) } \right) [/tex]

use difference and Product derivation rule to differentiate the numerator and the denominator respectively which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{1}{x + 1} - \frac{1}{ \sqrt{x + 1} } }{ \frac{ \ln(x + 1)}{ \sqrt{ {x}^{2} + 1 } } + \frac{ \ln(x + \sqrt{x ^{2} + 1 } }{x + 1} } \right) [/tex]

simplify which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \sqrt{ {x}^{2} + 1 } - x - 1 }{ (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

unfortunately! it's still an indeterminate form if we substitute 0 for x therefore apply L'hopital rule once again which yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \dfrac{d}{dx} \sqrt{ {x}^{2} + 1 } - x - 1 }{ \dfrac{d}{dx} (x + 1)\ln(x + 1 ) + \sqrt{ {x}^{2} + 1} \ln( x + \sqrt{ {x }^{2} + 1} ) } \right) [/tex]

use difference and sum derivation rule to differentiate the numerator and the denominator respectively and that is yields:

[tex] \displaystyle \lim _{x \to 0} \left( \frac{ \frac{x}{ \sqrt{ {x}^{2} + 1 } } - 1}{ \ln(x + 1) + 2 + \frac{x \ln(x + \sqrt{ {x}^{2} + 1 } ) }{ \sqrt{ {x}^{2} + 1 } } } \right) [/tex]

thank god! now it's not an indeterminate form if we substitute 0 for x thus do so which yields:

[tex] \displaystyle \frac{ \frac{0}{ \sqrt{ {0}^{2} + 1 } } - 1}{ \ln(0 + 1) + 2 + \frac{0 \ln(0 + \sqrt{ {0}^{2} + 1 } ) }{ \sqrt{ {0}^{2} + 1 } } } [/tex]

simplify which yields:

[tex] \displaystyle - \frac{1}{2} [/tex]

finally, we are done!

9514 1404 393

Answer:

  -1/2

Step-by-step explanation:

Evaluating the expression directly at x=0 gives ...

  [tex]\dfrac{1}{\ln(\sqrt{1})}-\dfrac{1}{\ln(1)}=\dfrac{1}{0}-\dfrac{1}{0}\qquad\text{an indeterminate form}[/tex]

Using the linear approximations of the log and root functions, we can put this in a form that can be evaluated at x=0.

The approximations of interest are ...

  [tex]\ln(x+1)\approx x\quad\text{for x near 0}\\\\\sqrt{x+1}\approx \dfrac{x}{2}+1\quad\text{for x near 0}[/tex]

__

Then as x nears zero, the limit we seek is reasonably approximated by the limit ...

  [tex]\displaystyle\lim_{x\to0}\left(\dfrac{1}{x+\dfrac{x^2}{2}}-\dfrac{1}{x}\right)=\lim_{x\to0}\left(\dfrac{x-(x+\dfrac{x^2}{2})}{x(x+\dfrac{x^2}{2})}\right)\\\\=\lim_{x\to0}\dfrac{-\dfrac{x^2}{2}}{x^2(1+\dfrac{x}{2})}=\lim_{x\to0}\dfrac{-1}{2+x}=\boxed{-\dfrac{1}{2}}[/tex]

_____

I find a graphing calculator can often give a good clue as to the limit of a function.

Answer:

timely, timely,measurable

Step-by-step explanation:

Answer:

specific, timely, measurable

Step-by-step explanation:

i took the test on plato

[tex]\longrightarrow{\green{x\:=\:5}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

➝[tex]\: \frac{3x}{5} = \frac{x + 1}{2} [/tex]

➝[tex]\:2 \times 3x = 5(x + 1)[/tex]

➝[tex]\:6x = 5x + 5[/tex]

➝[tex]\:6x - 5x = 5[/tex]

➝[tex]\:x = 5[/tex]

✒[tex] \:\frac{3 \times 5}{5} = \frac{5 + 1}{2} [/tex]

✒[tex]\: \frac{15}{5} = \frac{6}{2} [/tex]

✒[tex]\:3 = 3[/tex]

✒[tex]\:L. H. S. =R. H. S. [/tex]

Hence verified.

[tex]\bold{ \green{ \star{ \orange{Mystique35☂}}}}⋆[/tex]

Answer: 280 km

Step-by-step explanation:

[tex]3\dfrac{1}{2} \: hours = 3.5 \: hours[/tex]

S = V × t

V = 80 km/h

t = 3.5 h

S = 80 × 3.5 = 280 km

Answer:

I think that a Cube Root Function

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

hypotenuse = 7.3

Step-by-step explanation:

the length two legs of the given triangle are 7 and 2 respectively.

using pythagoras theorem

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.3 = c

Answer:

100:350                   simplified: [tex]\frac{2}{7}[/tex]

Step-by-step explanation

A ratio of 2:3 means that for every item of A, we can expect of item B. Therefore, our total group is 2+3=5.

Calculate expected number of item A:

[tex]\frac{2x500}{5}[/tex]

Expected number of item A: [tex]\frac{1000}{5}[/tex]

This fraction can be reduced by 5 giving you:

Expected number of item A: 200

Calculate expected number of item B:

[tex]\frac{3x500}{5}[/tex]

Expected number of item B: [tex]\frac{1500}{5}[/tex]

This fraction can be reduced by 5 giving you:

Expected number of item B: 300

Step-by-step explanation:

is it a question ? please check.

Answer:

Step-by-step explanation:

D.

supplementary.

BC.

D.

Answer:

Step-by-step explanation:

The total number of students is 1800 + 1200 =  3000

The % of boys who did not pass is 100% - 32% = 68%

The number of boys who did not pass is 68/100 * 1800 =       1224

The % of the girls who did not pass is 100%  - 50% = 50%

The number of girls who did not pass was 50/100 * 1200 =    600

The total number who did not pass was                                  1824

The % who did not pass was 1824/3000 * 100 = 60.8%