What is the slope of (-0,-1) and (3,1)

Find the negative reciprocal of the slope of the orginal line. Undefined

Answer:

800

Step-by-step explanation:

100%-0%=100%

100% is also equal to the number 1.

We now have 1x=800

Simplify that and get 800

Answer:

Addition equation = -4-0) + [(-13)-(-4)]

Answer =  -13

Step-by-step explanation:

For the small arrow in the diagram, the expression is (-4 - 0)

For the bog arrow, the expression will be -13 - (-4)

Adding both expressions

Addition = (-4-0) + [(-13)-(-4)]

Addition = (-4) + (-13+4)

Addition = -4 + (-9)

Addition = -4-9

Addition = -13

Answer:

1. x + 4 = 9

Hint: the word 'sum' generally refers to addition.

2. 10a = 70

3. [tex]\frac{3}{4} t[/tex] = 15

4. [tex]\frac{1}{4} x[/tex] - 4 = 4

Answer:

In any quantitative science, the terms relative change and relative difference are used to compare two quantities while taking into account the "sizes" of the things being compared. The comparison is expressed as a ratio and is a unitless number.

Step-by-step explanation:

I hope it helps

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Answer:

The average value of the cost function over the interval  is of $23,500.

Step-by-step explanation:

Average value of a function:

The average value of a function, over an inteval [a,b], is given by:

[tex]A = \frac{1}{b-a} \int_{a}^{b} f(x) dx[/tex]

In this case:

Function [tex]C(x) = 20000 - 10x[/tex], interval with [tex]a = 0,b = 700[/tex]

So

[tex]A = \frac{1}{700} \int_{0}^{700} 20000+10x dx[/tex]

[tex]A = \frac{1}{700} (20000x+5x^2)|_{0}^{700}[/tex]

So

[tex]A = \frac{20000(700)+5(700)^2}{700} = 23500[/tex]

The average value of the cost function over the interval  is of $23,500.

Answer:

a=1, b=9, c=-2, d=4

Step-by-step explanation:

Answer:

hey there hope this answer helps you out

Step-by-step explanation:

we have two functions f(x) and g(x) such that

[tex]f(x) = \frac{1}{x} [/tex]

and

[tex]g(x) = {x}^{2} + 6x[/tex]

solving for f ° g, we'll substitute the x in f(x) by the value of g(x)

[tex]fog = \frac{1}{g(x)} [/tex]

[tex]fog \: = \frac{1}{ {x}^{2} + 6x } [/tex]

taking x common in denominator

[tex]fog = \frac{1}{x(x + 6)} [/tex]

for a function to exist it should not have 0 in its denominator

checking the values of x for which the denominator of f ° g becomes 0 :-

so the function doesn't exist at values x = 0, -6

Answer:

c ≈ 21

Step-by-step explanation:

By applying cosine rule in the given triangle ABC,

c² = a² + b² - 2abcos(C)

c² = (17)² + (10)² - 2(17)(10)cos(98.8°)

c² = 289 + 100 - 340(-0.1530)

c² = 441.015

c = 21

c ≈ 21

Answer:

please write in english i cannot understand

Step-by-step explanation:

Answer:

The first graph

Step-by-step explanation:

Answer:

2 feet

Step-by-step explanation:

Displacement at 0 seconds is 0 feet.

Displacement at 2 seconds is 2 feet because it took them 2 seconds to walk 2 feet.

Answer:

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Answer:

yes

Step-by-step explanation:

if you change it to standard form, it would be

y=1/2x

because it's in the format of y=ax then it is direct variation

Answer:

f(6)=-42

f(0)=0

f(-1)=7

Step-by-step explanation:

since f(x) =-7x

it implies that f(6),f(0) and f(-1) are all equal to f(x)

which is equal to -7x .

so wherever you find x you out it in the

function

Answer:

Lucy must walk up 80 steps to reach the 6th floor.

Step-by-step explanation:

Since Michael was 1.0 meters tall, and could only reach up to the 1st floor lift button, and from the 1st floor, he had to walk up 100 steps to reach the 6th floor; while Vinh was 1.4 meters tall, and could reach the 5th floor button, and he had to walk up 20 steps to reach the 6th floor; If Lucy was 1.1 meters tall, to determine how many steps did she have to walk up to reach the 6th floor, the following calculation must be performed:

1 = 100

1.4 = 20

1.4 - 1 = 100 - 20

0.4 = 80

0.1 = X

0.1 x 80 / 0.4 = X

20 = X

100 - 20 = 80

Therefore, Lucy must walk up 80 steps to reach the 6th floor.

Answer:

A and b Are in quadrant 2. F and D are in quadrant 1. F is in quadrant 3 and C is in quadrant 4

Step-by-step explanation:

each quadrant is in the boxes and the question is asking what is each  coordinate is in what quadrant

Step-by-step explanation:

here is the answer. Feel free to ask for more.

Answer:

x= - 1

Step-by-step explanation:

Answer:

[tex]m = \frac{1}{12}[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (36,6)[/tex]

[tex]f(x) = \sqrt x[/tex] ----- the equation of the curve

Required

The slope of f(x)

The slope (m) is calculated using:

[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]

[tex](x,y) = (36,6)[/tex] implies that:

[tex]a = 36; f(a) = 6[/tex]

So, we have:

[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]

[tex]m = \lim_{h \to 0} \frac{f(36 + h) - 6}{h}[/tex]

If [tex]f(x) = \sqrt x[/tex]; then:

[tex]f(36 + h) = \sqrt{36 + h}[/tex]

So, we have:

[tex]m = \lim_{h \to 0} \frac{\sqrt{36 + h} - 6}{h}[/tex]

Multiply by: [tex]\sqrt{36 + h} + 6[/tex]

[tex]m = \lim_{h \to 0} \frac{(\sqrt{36 + h} - 6)(\sqrt{36 + h} + 6)}{h(\sqrt{36 + h} + 6)}[/tex]

Expand the numerator

[tex]m = \lim_{h \to 0} \frac{36 + h - 36}{h(\sqrt{36 + h} + 6)}[/tex]

Collect like terms

[tex]m = \lim_{h \to 0} \frac{36 - 36+ h }{h(\sqrt{36 + h} + 6)}[/tex]

[tex]m = \lim_{h \to 0} \frac{h }{h(\sqrt{36 + h} + 6)}[/tex]

Cancel out h

[tex]m = \lim_{h \to 0} \frac{1}{\sqrt{36 + h} + 6}[/tex]

[tex]h \to 0[/tex] implies that we substitute 0 for h;

So, we have:

[tex]m = \frac{1}{\sqrt{36 + 0} + 6}[/tex]

[tex]m = \frac{1}{\sqrt{36} + 6}[/tex]

[tex]m = \frac{1}{6 + 6}[/tex]

[tex]m = \frac{1}{12}[/tex]

Hence, the slope is 1/12

Answer:

283 flowers

Step-by-step explanation:

c=2pi*r

c = 1130.973 =1131

1131/4

282.75 = 283

Answer:

108 square metres

Step-by-step explanation:

A=√d square - l square

here

A = area

d= diagonal

l= length

Answer:

SAA

Step-by-step explanation:

HOPE IT HELPS YOU IN YOUR LEARNING PROCESS.

Answer:

129469.3194

342000

212530.6806

Step-by-step explanation:

Going to assume that the 8% is a nominal, montly rate

which means the effective monthly rate is .08/12= .006667

using the annuity immediate formula...

a.)

[tex]950(\frac{1-(1+.006667)^{-30*12}}{.006667})=129469.3194[/tex]

b.) we would pay 950*30*12= 342000

c.) the amount in interest would be 342000-129469.3194=212530.6806

a) The loan one can afford is $1,29,460.2

b) The total amount of money paid to the loan company over the life of the loan is $342,000.

c)  $212539.8 of the total amount paid is interest.

To determine the answers to these questions, we'll need to use the formula for calculating a fixed monthly mortgage payment:

[tex]M = \frac{P \times r \times (1 + r)^n}{((1 + r)^n - 1)}[/tex]

where:

M is the monthly payment,

P is the principal loan amount,

r is the monthly interest rate (annual interest rate divided by 12),

and n is the total number of payments (number of years multiplied by 12).

Given:

Monthly payment (M) = $950

Loan term = 30 years

Interest rate = 8% per year

a) How big of a loan can you afford?

Let's calculate the principal loan amount (P):

First, we need to convert the annual interest rate to a monthly interest rate:

r = 0.08 / 12

= 0.00667

n = 30 years × 12 months

n= 360

Using the formula and plugging in the values we have:

[tex]950 = \frac{P \times 0.00667 \times (1 + 0.00667)^{360}}{((1 + 0.00667)^{360} - 1)}[/tex]

[tex]950 = \frac{P \times 0.00667 \times 10.948}{10.948 - 1}[/tex]

[tex]950=\frac{P \times 0.07302316}{9.948}[/tex]

[tex]950\times9.948 = 0.0730P[/tex]

Divide by 0.073:

Now we can solve for P:

[tex]P=\frac{9450.6}{0.0730}[/tex]

[tex]P = 1,29,460.2[/tex]

Therefore, you can afford a loan amount of $1,29,460.2

b) The total amount paid to the loan company can be calculated by multiplying the monthly payment by the total number of payments:

Total amount = Monthly payment × Total number of payments

Total amount =[tex]$950 \times 360[/tex]

Total amount = [tex]342,000[/tex]

Therefore, the total amount of money paid to the loan company over the life of the loan is $342,000.

c) To find out how much of the total amount paid is interest, we can subtract the principal loan amount from the total amount:

Interest = Total amount - Principal loan amount

Interest = [tex]342,000 - 129460.2[/tex]

=$212539.8

Therefore, $212539.8 of the total amount paid is interest.

To learn more on Simple Interest click:

https://brainly.com/question/30964674

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step by step explanation:

[tex]\mathfrak{x}^{2}+{y}^{2}+16=0[/tex]

=[x2+16=0x26]

=[2x{y}^2{16}~0]

=[4×{y}^0{16}]

=[32x{y}^x]

Answer:

nine 9 classes in the histogram

Answer:

The speed of the boat is 24 kilometers per hour, and the speed of the stream is 2 kilometers per hour.

Step-by-step explanation:

Given that a riverboat travels 52 km downstream in 2 hours, and it travels 66 km upstream in 3 hours, the following calculations must be performed to find the speed of the boat and the speed of the stream:

Downstream = 52/2 = 26

Upstream = 66/3 = 22

Stream = 4/2 = 2

Therefore, the speed of the boat is 24 kilometers per hour, and the speed of the stream is 2 kilometers per hour.

I think you are asked to find the value of the first derivative of f(x) at π/4. Given

[tex]f(x) = \dfrac{\sin(4x)-\cos(x)}{\tan(x)}[/tex]

use the quotient to differentiate and you get

[tex]f'(x) = \dfrac{\tan(x)(4\cos(4x)+\sin(x))-(\sin(4x)-\cos(x))\sec^2(x)}{\tan^2(x)}[/tex]

Then at x = π/4, you have

tan(π/4) = 1

cos(4•π/4) = cos(π) = -1

sin(π/4) = 1/√2

sin(4•π/4) = sin(π) = 0

cos(π/4) = 1/√2

sec(π/4) = √2

==>   f ' (π/4) = (1•(-4 + 1/√2) - (0 - 1/√2)•(√2)²) / 1² = -4 + 1/√2 + √2

(1) Recall that

sin(x - y) = sin(x) cos(y) - cos(x) sin(y)

sin²(x) + cos²(x) = 1

Given that α lies in the third quadrant, and β lies in the fourth quadrant, we expect to have

• sin(α) < 0 and cos(α) < 0

• sin(β) < 0 and cos(β) > 0

Solve for cos(α) and sin(β) :

cos(α) = -√(1 - sin²(α)) = -3/5

sin(β) = -√(1 - cos²(β)) = -5/13

Then

sin(α - β) = sin(α) cos(β) - cos(α) sin(β) =  (-4/5) (12/13) - (-3/5) (-5/13)

==>   sin(α - β) = -63/65

(2) In the second identity listed above, multiplying through both sides by 1/cos²(x) gives another identity,

sin²(x)/cos²(x) + cos²(x)/cos²(x) = 1/cos²(x)

==>   tan²(x) + 1 = sec²(x)

Rewrite the equation as

3 sec²(x) tan(x) = 4 tan(x)

3 (tan²(x) + 1) tan(x) = 4 tan(x)

3 tan³(x) + 3 tan(x) = 4 tan(x)

3 tan³(x) - tan(x) = 0

tan(x) (3 tan²(x) - 1) = 0

Solve for x :

tan(x) = 0   or   3 tan²(x) - 1 = 0

tan(x) = 0   or   tan²(x) = 1/3

tan(x) = 0   or   tan(x) = ±√(1/3)

x = arctan(0) + nπ   or   x = arctan(1/√3) + nπ   or   x = arctan(-1/√3) + nπ

x = nπ   or   x = π/6 + nπ   or   x = -π/6 + nπ

where n is any integer. In the interval [0, 2π), we get the solutions

x = 0, π/6, 5π/6, π, 7π/6, 11π/6

(3) You only need to rewrite the first term:

[tex]\dfrac{\sin(x)}{1-\cos(x)} \times \dfrac{1+\cos(x)}{1+\cos(x)} = \dfrac{\sin(x)(1+\cos(x))}{1-\cos^2(x)} = \dfrac{\sin(x)(1+\cos(x)}{\sin^2(x)} = \dfrac{1+\cos(x)}{\sin(x)}[/tex]

Then

[tex]\dfrac{\sin(x)}{1-\cos(x)}+\dfrac{1-\cos(x)}{\sin(x)} = \dfrac{1+\cos(x)+1-\cos(x)}{\sin(x)}=\dfrac2{\sin(x)}[/tex]