What is the slope of the line shown below?

Answer:

6

Step-by-step explanation:

The solution for this problem is in this picture.

Answer:

12

Step-by-step explanation:

Answer:

He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots.

Step-by-step explanation:

He made the following mistake, he assumed that polynomial [tex](x^{2}+1) = (x^{2}-1)[/tex], having for granted that [tex]x^{2}+1[/tex] has two real roots, instead of two complex roots. The true factorized form of the fourth grade polynomial is:

[tex]r(x) = (x^{2}+1)\cdot (x^{2}-9)[/tex]

[tex]r(x) = (x- i)\cdot (x+i)\cdot (x+3)\cdot (x-3)[/tex]

Answer:

16+5w/4

Step-by-step explanation:

Answer:

Part A

The volume of the triangular prism is 500 cm³

Part B

The total surface area of the prism is approximately 441.42 cm²

Step-by-step explanation:

The given details are;

The dimensions of the side length of the cube, s = 10 cm

The shape the cube was cut across to obtain = A prism

Part A

Whereby the prism obtained is a triangular prism, we have;

The cube can be cut in half to form a triangular prism

The volume of each triangular prism obtained = (1/2) × The volume of the cube

∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³

Part B

The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism

The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50

The square cross sectional area, A₂  = 10 × 10 = 100

The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2

The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃

∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42

The total surface area of the prism, A ≈ 441.42 cm²

Answer:

The bearing of A from B is 122°

Answer:

C

Step-by-step explanation:

In a right triangle, the side opposite the right angle is the largest side as the right angle represents the largest angle in the triangle. Therefore, as 17.5 is opposite the right angle, we can say that AB²+10²=17.5², and √(17.5²-10²)=AB = 14.4

Using sohcahtoa, we can establish that

sin(∠C) = opposite/hypotenuse = 14.4/17.5, and

arcsin(14.4/17.5) = ∠C = 55°

Because the angles in a right triangle add up to 180 degrees, we can say that ∠A+∠B+∠C = 180°, so ∠A + 90 + 55 = 180 and ∠A = 35°

Answer:

hlw its jess

your answer is here

Step-by-step explanation:

hope it may help you

Answer:

13[tex]\sqrt{22}[/tex] / 44

Step-by-step explanation:

cos A = 9/13

here adjacent = 9 and hypotenuse = 13  opposite = ?

using pythagoras theorem to find opposite

a^2 + b^2 = c^2

9^2 + b^2 = 13^2

81 + b^2 = 169

b^2 = 169 - 81

b^2 = 88

b = [tex]\sqrt{88}[/tex]

b =  [tex]2\sqrt{22}[/tex]

therefore opposite =  [tex]2\sqrt{22}[/tex]

cosec A = hypotenuse/opposite

= 13/[tex]2\sqrt{22}[/tex]

rationalizing the denominator

=13/ [tex]2\sqrt{22}[/tex]  *  [tex]2\sqrt{22}[/tex] /  [tex]2\sqrt{22}[/tex]

=13 *[tex]2\sqrt{22}[/tex] /( [tex]2\sqrt{22}[/tex] )^2

=26 [tex]\sqrt{22}[/tex] / 4*22

=26 [tex]\sqrt{22}[/tex] / 88

=13[tex]\sqrt{22}[/tex] / 44

Answer:

[tex]cosec A = \frac{13}{\sqrt{88}}[/tex]

   OR

[tex]cosec A = \frac{13 \sqrt{22}}{44}[/tex]

Step-by-step explanation:

Formulas used:

[tex]cos^2 A = 1 - sin^2 A\\\\cosec A = \frac{1}{sin A}[/tex]

Given :

  [tex]cos A = \frac{9}{13}[/tex]

Find cosec A

   [tex]sin ^2 A = 1 - cos^2 A[/tex]

              [tex]= 1 - (\frac{9}{13})^2\\\\= 1 - \frac{81}{169}\\\\=\frac{169 - 81}{169}\\\\=\frac{88}{169}[/tex]

 [tex]sin A = \sqrt{\frac{88}{169}} = \frac{\sqrt{88}}{13}[/tex]

Therefore,

         [tex]cosec A = \frac{1}{sin A} = \frac{1}{ \frac{\sqrt{88}}{13}} = \frac{13}{ \sqrt{88}}[/tex]

OR In a simplified form :

[tex]cosec A = \frac{13}{\sqrt{88}} \times \frac{\sqrt{88}}{\sqrt{88}} = \frac {13 \times \sqrt{4 \times 22}}{88} = \frac{13 \times 2 \sqrt{22}} {88} = \frac{13 \sqrt{22}}{44}[/tex]        

Answer:

C

Step-by-step explanation:

you have the angle, adjacent and you want to find the hypotenuse

therefore use CAH - (I drew the triangle on the bottom of the attachment )

length of A / cos(angle) = hypotenuse

7 / cos(39)=9.007

Answer:

C: 9 to the nearest tenth

Step-by-step explanation:

You  have three choices on your calculator to solve this problem. Only 1 of the three will work.

Sin(39)

Tan(39)

Cos(39)

You want the hypotenuse (x) and you are given the adjacent side. The adjacent side is the other side that makes up the reference angle other than the hypotenuse.

Cos(theta) = adjacent side / hypotenuse.    The is the function you use.

Adjacent side = 7

Cos(39) = 7 / x               Multiply both sides by x

x * Cos(39) = 7               Divide by Cos(39)

x = 7 / Cos(39)

x = 9                               Isn't that neat? It is actually 9.0073. but C is the answer.

Answer:

See Explanation

Step-by-step explanation:

You posted an incomplete question with little and unclear details.

I will answer this question with a more complete version (see attachment)

Given that:

[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]

Required

The fraction that passed the test

Rearrange the score in ascending order:

[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

The total number of students is:

[tex]n =20[/tex]

Extract the students that passed (scored 70 and above)

[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

Their numbers are:

[tex]Passed: 14[/tex]

So, the fraction of those that passed is:

[tex]Fraction = \frac{Passed}{n}[/tex]

[tex]Fraction = \frac{14}{20}[/tex]

Reduce fraction

[tex]Fraction = \frac{7}{10}[/tex]

Answer:

A: 42

Step-by-step explanation: 10.5x4=42

Answer:

your answer is A 42

Step-by-step explanation:

make me brainliest

The lower the frequency the least common the average.

There are two frequencies that are 1, which would be the least common.

The answer is C. 0.320-0.329 and 0.360 -0.369

Answer:

option C

Step-by-step explanation:

option c is contains the two batting averages which have a frequency of 1, this means that they both only occurred once which is the least amount of times any of the batting averages has occurred.

Answer:

1248 cm^2

Step-by-step explanation:

Volume = Length · Width · Height

Volume = 24 · 6 · 5

Volume = 720 cm^2

Volume = Length · Width · Height

Volume = 8 · 6 · 11

Volume = 528 cm^2

528 + 720 = 1248

Answer:

1248 cm³

Step-by-step explanation:

V = lwh

V = 24 cm × 6 cm × 5 cm

V = 720 cm³

V = lwh

V = 8 cm × 6 cm × 11 cm

V = 528 cm³

720 cm³ + 528 cm³

1248 cm³

Answer:

D.

Step-by-step explanation:

If you look on both triangles, PQ and ST are both and the same spots. (P is in the same spot as S and Q is in the same spot as T.

Answer:

3.75

Step-by-step explanation:

Answer: 52x+4

Step-by-step explanation: Do 16(2x-1)+4(5x+5) and get 52x+4.

Answer:

450 mL

Step-by-step explanation:

Given that :

Amount in mL of medicine taken at a time = 10mL

Number of times taken per day = 3 times

Amount in mL taken per day = 3 * 10mL = 30mL

Total amount in mL of medicine taken in 15 days :

Amount in mL taken per day * 15 days

= 30mL * 15

= 450mL

Answer:

1

Step-by-step explanation:

that's a very vague question

Answer:

3  7/15

Step-by-step explanation:

1 4/5 + 2 2/3 - 16/15

9/5 + 8/3 - 16/15

27/15 + 40/15 - 16/15

52/15 = 3  7/15

Answer:

3 2/5

Step-by-step explanation:

STEP 1: Convert all fractions into improper fractions

9/5 + 8/3 - 16/15

Step 2: pass denominators

(9x3 + 8x5 - 16) / 15

=51/15

Step it into proper mixed number

3 2/5

Answer:

v = 27,000 mm³

Step-by-step explanation:

v = s³

v = 30³

v = 27,000 mm³

Answer:

Diagonals of a square bisect each other

Step-by-step explanation:

The diagonals of a square are equal and bisect each other at right angles and making the bisected parts equal.

Answer:

to do this lets first solve this so

5*5*5*5=625

5^-3=0.008

0.008^2=0.000064

0.000064*625=0.4

so all equations that are equal to 0.4 are right which is C

Answer:

B.

Step-by-step explanation:

you know that (a+b+c)/d is the same as a/d + b/d + c/d.

and (a×b)/(c×d) is the same as (a/c)×(b/d).

and the powers of variables subtract when the variables are divided, and the powers add when the variables are multiplied.

14a⁸y³ / 7a⁴y

14/7 = 2

a⁸/a⁴ = a⁴

y³/y = y²

=> 2a⁴y² is the first part. that eliminates already all other answer options. only B can be right.

but let's practice and look at the second part :

-7a⁴y⁵ / 7a⁴y

-7/7 = -1

a⁴/a⁴ = 1

y⁵/y = y⁴

=> -y⁴ is the second part. B is still confirmed.

the third part :

28a¹²y² / 7a⁴y

28/7 = 4

a¹²/a⁴ = a⁸

y²/y = y

=> + 4a⁸y is the third part. B confirmed.

There are two pints per quart

3 q * 2 p/qt = 6 pints needed

6 pint /1.5 pint/container = 4 containers

Answer:

8 - 42x - 56y - 12xy

Step-by-step explanation:

Length = 4 - 7(3x + 4y)

= 4 - 21x - 28y

Width = 3x(-2y)

= -6xy

Perimeter of the rectangle = 2(length + width)

= 2{(4 - 21x - 28y) + ( -6xy)}

= 2(4 - 21x - 28y - 6xy)

= 8 - 42x - 56y - 12xy

Perimeter of the rectangle = 8 - 42x - 56y - 12xy

[tex]f(x) = \log_b(x)[/tex] is a decreasing function when [tex]0 < b < 1[/tex]

This is because we can use the change of base formula to say

[tex]\log_b(x) = \frac{\log(x)}{\log(b)}[/tex]

If b is between 0 and 1, not including either endpoint, notice how the log(b) term is negative.

For example, if b = 0.5, then log(b) = log(0.5) = -0.301 approximately. I'm using log base 10 to get log(0.5) = -0.301

So for b = 0.5, we have,

[tex]\log_{0.5}(x) = \frac{\log(x)}{\log(0.5)} \approx \frac{\log(x)}{-0.301} \approx -3.322\log(x)[/tex]

The log(x) part on its own is always increasing. The negative coefficient out front flips it to always decreasing.

By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex]decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D) #SPJ5

Logarithms are trascendent functions whose form is defined by the following expression:

[tex]\log _{b} x[/tex] such that [tex]x = b^{a}[/tex], where b > 0.

Where b is the base of the power.

Whose rules are described below:

By applying the behavior rules we notice that the expression [tex]F(x) = \log_{b} x[/tex] is a decreasing function if the base of the logarithm is 0 < b < 1. (Correct choice: D)

The statement is poorly formatted and reports several mistakes. Correct form is shown below:

For what values of b will [tex]F(x) = \log_{b} x[/tex] be a decreasing function?

A. b > 0

B. 0

C. b < 0

D. 0 < b < 1

To learn more on logarithms, we kindly invite to check this: https://brainly.com/question/20785664 #SPJ5

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{2.3(x - 2) = 15}[/tex]

[tex]\mathsf{2.3(x) + 2.3(-2) = 15}[/tex]

[tex]\mathsf{2.3x - 4.6 = 15}[/tex]

[tex]\large\textsf{ADD 4.6 to BOTH SIDES}[/tex]

[tex]\mathsf{2.3x - 4.6 + 4.6 = 15 + 4.6}[/tex]

[tex]\large\textsf{CANCEL out: -4.6 + 4.6 because it gives the number 0}[/tex]

[tex]\large\textsf{KEEP: 15 + 4.6 because that helps solve find the x-value}[/tex]

[tex]\mathsf{15 + 4.6 = \boxed{\bf 19.6}}[/tex]

[tex]\large\textsf{NEW EQUATION: 2.3x = 19.6}[/tex]

[tex]\large\textsf{DIVIDE 2.3 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{2.3x}{2.3}=\dfrac{19.6}{2.3}}[/tex]

[tex]\large\textsf{CANCEL out: }\mathsf{\dfrac{2.3}{2.3}}\large\textsf{ because that gives you 1}[/tex]

[tex]\large\textsf{KEEP: }\mathsf{\dfrac{19.6}{2.3}}\large\textsf{ because that gives you the value of x}[/tex]

[tex]\mathsf{\dfrac{19.6}{2.3}= \boxed{\bf x}}[/tex]

[tex]\mathsf{\boxed{\bf x}=\dfrac{19.6}{2.3}}[/tex]

[tex]\boxed{\bf {x = 8.521739}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf x = 8.521739}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:) }[/tex]

Answer:

The answer is below

Step-by-step explanation:

The area of the wall is 84 ft².

The width of the wallpaper is 18 in.

1 ft. = 12 in

Hence; 18 in = 18 in * 1 ft. per 12 in = 1.5 ft

The length of the wallpaper is 33 ft.

Therefore, the area of the wallpaper = length * width = 1.5 ft. * 33 ft. = 49.5 ft². This means that each roll of wallpaper has an area of 49.5 ft²

Therefore, the minimum amount of rolls of wallpaper needed = area of wall / area of wallpaper

Amount of wallpaper = 84 ft² / 49.5 ft² = 1.7 rolls