What is the smallest prime number that is also a multiple of 20?

Answer:

base = 3x - 1

height = x

area of triangle = (1/2)bh

22 = (1/2)(3x-1)(x)

44 = (3x-1)(x)

44 = 3x^2-x

0 = 3x^2-x-44

0 = 3x^2-12x+11x-44

0 = (3x^2-12x)+(11x-44)

0 = 3x(x-4)+11(x-4)

0 = (x-4)(3x+11)

x = {-11/3, 4}

throw out the negative solution (extraneous) leaving

x = 4 m (height)

.

Base:

3x - 1 = 3(4) - 1 = 12 - 1 = 11 

Step-by-step explanation:

I hope it will help you

Solution :

For the bigger rectangle

Width of bigger rectangle = W

Length of bigger rectangle, L = 2W

For the smaller rectangle

Width , w = W+4

Length, l = L = 2W

Area, a =120 [tex]m^2[/tex]

Now we know,

Area = length x width

[tex]$a=l \times w$[/tex]

[tex]$120=(2W) \times (W+4)$[/tex]

[tex]$120=2W^2 + 8W$[/tex]

[tex]$2W^2+8W-120=0$[/tex]

[tex]$W^2+4W-60=0$[/tex]

[tex]$(W+10)(W-6) = 0$[/tex]

We get, either [tex]W=-10[/tex]   (rejecting)

                or     [tex]W=6[/tex]

∴ length of the bigger rectangle, [tex]$L=2W $[/tex]

                                                          = 2(6)

                                                           = 12 m

 Length of the smaller rectangle, [tex]$L=2W$[/tex]

                                                            = 2(6)

                                                           = 12 m

Hence, the length of the two gardens is 12 m.                                                            

Step-by-step explanation:

[tex]15)2n \\ 16)1 \times {10}^{7} \\ 17) {m}^{5} \\ 18)xy \\ 19)5 {n}^{2} - 6 \\ = - 6 \\ 20)9 {a}^{ 3} + 1 \\ = \frac{d}{da} (9a {}^{ 3} + 1) \\ 21) {x}^{3} . {y}^{3} \\ = (x.y) {}^{3} \\ = {x}^{3} {y}^{3} \\ 22)c {}^{4} .d {}^{6} \\ = {c}^{4} {d}^{6} \\ 23)3e + {e}^{2} \\ = e(e + 3) \\ \\ \\ hope \: it \: is \: help \: to \: you[/tex]

15 2 times n

16 10 race to the power 7

17 m race to the power 5

18 x times y

19 6 subtracted from 5 times n race to the power 2

20 1 added to 9 times a race to the power 3

21 x race to the power 3 times y race to the power 2

22 c race to the power 4 times d race to the power 6

23 3 times e added to 2 times e race to the power 2

Must click thanks and mark brainliest

Answer:

20

Step-by-step explanation:

C(6,3) = 6!/[3!(6-3)!]

= 20

A sample space is the space of all the possible outcomes in this event.

Let's define each outcome as:

(first marble, second marble)

Where the first marble can be green or red.

The second marble can be blue or yellow.

Then the possible outcomes are:

(green, yellow)

(green, blue)

(red, yellow)

(red, blue)

So we have four different outcomes, which means that the sample space has 4 elements.

Notice that the number of marbles of each color does not affect this, these numbers only affect the probability of each one of these possible outcomes.

If you want to learn more, you can read:

https://brainly.com/question/24329720

Answer:

2 1/2 miles = 1/6 hours 2 1/2 miles * 6 = 1/6 hours * 6 12 1/2 miles = 6/6 hours 12 1/2 miles = 1 hour 12 1/2 miles/hr

Answer:

[tex]\frac{\frac{5}{2} * 6 }{\frac{1}{6} * 6}[/tex] = [tex]\frac{\frac{30}{2} }{\frac{6}{6} }[/tex]

Step-by-step explanation:

Answer:

I don't know ask to your teacher

For the given question,

Total number of outcomes

= 6 (i.e. 1, 2, 3, 4, 5 and 6)

Number of favourable outcomes

= 4 (i.e. 3, 4, 5, 6)

So,

[tex]P = \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: outcomes} \\ = > P= \frac{4}{6} \\ = > P = \frac{2}{3} \\ = > P = 0.6666......[/tex]

K = 5n/m

F=KE

K= F/E

= 10/5

K = 5n/m

Answer:

Step-by-step explanation:

In order to undo that e, you need to take the natural log of both sides:

[tex]ln(e^x)=ln(7.1)[/tex] the ln and the e cancel each other out, leaving us with

x = ln(7.1) so

x = 1.96

Answer:

C. 12 for $6.00

Step-by-step explanation:

Answer:

C. 12 for $6.00

Step-by-step explanation:

better than $13.00 for 24. as that'd be $6.50 for 12..

The most common denominator for them is the LCM which is 21

Now

2/7 = 2/7×3/3

= 6/21

Therefore 6/21 and 10/21

Must click thanks and mark brainliest

Answer:

Place compass at P and, with compass set to segment AB, draw an arc that intersects line PA  2nd answer.

Step-by-step explanation:

Answer:

sin C= 5/13

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin C= 5/13

Answer: A) 4

Explanation:

For any 30-60-90 triangle, the short leg is half as long as the hypotenuse.

The short leg is opposite the smallest angle (30 degrees), so we see that

x = 8/2 = 4.

Answer: Choice A. 338 meters

Step-by-step explanation:

tan(31°)=203/x

Answer: 338 m

Step-by-step explanation:

Tan 59 = x/203

(1.66)(203)=338m

Complete question is;

Alejandra correctly wrote the equation y – 3 = (1/5) (x – 10) to represent a line that her teacher sketched. The teacher then changed the line so it had a slope of 2, but still went through the same point. Which equation should Alejandra write to represent the new line?

Answer:

y – 3 = 2(x – 10)

Step-by-step explanation:

Since the original line is;

y – 3 = (1/5) (x – 10)

This means the slope is 1/5 and the x and y coordinates are (10, 3) respectively.

Now, if she changes the slope to 2 and it still passed through the same point, then it means it's x and y points are still (10, 3). Thus, the equation will now be;

y – 3 = 2(x – 10)

Answer:

28.284

Step-by-step explanation:

Answer:

Convert fraction (ratio) 8 / 16 Answer: 50%

Step-by-step explanation:

Answer:

(4, -1)

Step-by-step explanation:

xB = -2+(-2-(-8)) = -2 +6 = 4

yB = 1+(1-3)=1+(-2) = -1

so, the coordinates of point B => (4, -1)

Answer:

Diagonals of a rhombus intersect at right angles

Therefore, [tex]\angle AOD=90[/tex]

[tex]Now,in\: \bigtriangleup AOD[/tex]

[tex]\angle OAD+\angle AOD+\angle ADO=180[/tex]

[tex]x+90+3x+12=180[/tex] [tex]\leftarrow [combing \: like\: terms][/tex]

[tex]4x+102=180\\-102 \: -102[/tex] [tex]\leftarrow [subtracting \:102 ][/tex]

[tex]\frac{4x}{4} =\frac{78}{4} \leftarrow [dividing \: by\: 4][/tex]

[tex]x=19.5[/tex] [tex]\Longleftarrow[/tex]

OAmalOHopeO

Answer:

B

Step-by-step explanation:

The secant- tangent angle b is half the difference of the measures of the intercepted arcs , then

b = [tex]\frac{1}{2}[/tex] ( 180 - 35) = [tex]\frac{1}{2}[/tex] × 145° = 72.5° → B

Answer:

g: -7/10 or -0.7

Step-by-step explanation:

[tex]6g+5=-2\left(1+2g\right)[/tex]

Apply the distributive law:-

[tex]-2\left(1+2g\right)[/tex]

[tex]=-2-4g[/tex]

[tex]6g+5=-2-4g[/tex]

Now, we´ll Subtract 5 from both sides :-

[tex]6g+5-5=-2-4g-5[/tex]

[tex]6g=-4g-7[/tex]

Add 4g to both sides :-

[tex]6g+4g=-4g-7+4g[/tex]

[tex]10g=-7[/tex]

Now, divide both sides by 10:-

[tex]\frac{10g}{10}=\frac{-7}{10}[/tex]

[tex]g=-\frac{7}{10}[/tex]

OAmalOHopeO

Answer:

x = 19

Step-by-step explanation:

The angles sum are complementary so they will sum to 180

(6x+9) +(4x-19) = 180

Combine like terms

10x - 10 = 180

Add 10 to each side

10x-10+10 =180+10

10x =190

Divide by 10

10x/10 = 190/10

x = 19

Answer:

1 Solar day = 86,400 seconds (SI Base Unit)

1 day = 1,440 minutes

Step-by-step explanation:

If need anymore help just ask I'm not really good at explaining but I'll try just comment haha ☺️

Answer:

(0.5,3.5)

Step-by-step explanation:

First, we can draw the image, as shown. The diagonals in the rectangle are the following lines:

from (-2,9) to (3,-2)

from (-5, 6) to (6,1)

To find where they intersect, we can start by making an equation for the lines. For an equation y=mx+b, m represents the slope and b represents the y intercept, or when x=0

For the first line, from (-2,9) to (3,-2), we can calculate the slope by calculating the change in y/change in x = (y₂-y₁)/(x₂-x₁). If (3,-2) is (x₂,y₂) and (-2,9) is (x₁,y₁), our slope is

(-2-9)/(3-(-2)) = -11/5

Therefore, our equation is

y= (-11/5)x + b

To solve for b, we can plug a point in, like (3,-2). Therefore,

-2=(-11/5)*3+b

-2=-33/5+b

-10/5=-33/5+b

add 33/5 to both sides to isolate b

23/5=b

Our equation for one diagonal is therefore y=(-11/5)x+23/5

For the second line, from (-5, 6) to (6,1), if (6,1) is (x₁,y₁) and (-5,6) is (x₂,y₂), the slope is (1-6)/(6-(-5)) = -5/11 . Plugging (6,1) into the equation y=(-5/11)x+b, we have

1=(-5/11)*6+b

11/11 = -30/11 + b

add 30/11 to both sides to isolate b

41/11 = b

our equation is

y = (-5/11) x + 41/11

Our two equations are thus

y = (-5/11) x + 41/11

y=(-11/5)x+23/5

To find where they intersect, we can set them equal to each other

(-11/5)x+23/5 = y = (-5/11) x + 41/11

(-11/5)x + 23/5 = (-5/11)x + 41/11

subtract 23/5 from both sides as well as add 5/11 to both sides to make one side have only x values and their coefficients

(-11/5)x + (5/11)x = 41/11-23/5

11*5 = 55, so 55 is one value we can use to make the denominators equal.

(-11*11/5*11)x+(5*5/11*5)x=(41*5/11*5)-(23*11/5*11)

(-121/55)x+(25/55)x = (205/55) - (253/55)

(-96/55)x = (-48/55)

multiply both sides by 55 to remove the denominators

-96x=-48

divide both sides by -96 to isolate x

x=-48/-96=0.5

plug x=0.5 into a diagonal to see the y value of the intersection

(-11/5)x + 23/5 = y = (-11/5)* 0.5 + 23/5 = 3.5