What is the sum of the polynomials? (6x+7+x^2)+(2x^2-3)
a.-x^2+6x+4
b.3x^2+6x+4
c.9x + 4
d.9x^2+4

Answer:

(x-3)^2+y^2=8

Step-by-step explanation:

I'm going to go ahead and assume the center is (3,0). The radius can be found by computing the distance from the center, (3,0), to a point on the circle, (5,-2).

The distance between two points is calculated by doing sqrt((distance between x's)^2+(distance between y's)^2).

The distance between our x's is 2.

The distance between our y's is 2.

The square of each then is 4 and 4 respectively.

So we have the distance is sqrt(4+4)=sqrt(8).

The radius is sqrt(8).

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is center and r is radius.

If r=sqrt(8), then r^2=8.

(h,k)=(3,0)

(x-h)^2+(y-k)^2=r^2

(x-3)^2+(y-0)^2=8

(x-3)^2+y^2=8

Answer:

Hello,

3.85

Step-by-step explanation:

[tex]Number\ of\ customers=3+0+5+3+7+2=20\\\\mean=\dfrac{1*3+2*0+3*5+4*3+5*7+6*2}{20} =\dfrac{77}{20} =3.75[/tex]

Step-by-step explanation:

here's the answer to your question

Answer:

392.7 cubic centimeters. Hope that helps :)

Step-by-step explanation:

Answer:

No solutions

Step-by-step explanation:

Convert both equations into y = mx + b form, where m is the slope and b is the y intercept.

8x + 4y = 12

4y = -8x + 12

y = -2x + 3

Rearrange the other equation:

3y = -6x - 15

y = -2x - 5

So, both equations have a slope of -2. But, one has a y intercept of 3 and the other has a y intercept of -5.

Because the lines have the same slope but different y intercepts, the lines are parallel.

Parallel lines have no solutions, because they will never intersect.

So, the system has no solutions.

Answer:

B.

Step-by-step explanation:

Other equations don't have any value of x.

Answer:

Because if you see.. The component of x will get canceled in each of the other 3 options.. ( 2x - 2x) which means no solution.. In option B.. 2x + 2x will give 4x..= 31-31 = 0..

-------------------------

Hope it helps...

Have a great day!!

Hi there!

[tex]\large\boxed{0, 3}[/tex]

Find the y-intercept by substituting in 0 for x:

f(0) = 0² + 2(0) + 3

Simplify:

f(0) = 3

Answer:

0,3

hope this helped !!!

Step-by-step explanation:

Answer:

63.4

Step-by-step explanation:

Area of arc is (pi*(11)^2*(60/360))=63.4

Answer:

28.26

Step-by-step explanation:

A = (3.14)(3)^2

A = 3.14 * 9

A = 28.26

Answer:

28.26

Step-by-step explanation:

The area of a circle is

A = pi r^2  where r is the radius

A = 3.14 ( 3)^2

A = 3.14 *9

28.26

Answer:

2/15

Step-by-step explanation:

I think not 100% on this but not so sure-

Subtract 5 1/10 from 5 3/4

5 3/4 - 5 1/10

• Subtract the whole numbers (5 and 5)

5 - 5 = 0

• LCM of the denominators (4 and 10)

= 13/20

She put an extra 13/20

Answer:

y = x

Step-by-step explanation:

So what we're going to want to do here is use the slope formula and the general equation y = mx + b.

Let's start.

The slope formula is y2-y1/x2-x1. So, put our points in here. 4-0/4-0. Slope: 1.

Okay, we have that. Now, a line that passes through the origin (0,0) is not going to have a y-intercept because it hits the y-axis at 0. So, that cancels out the b.

With our slope 1, the answer is just y = x. Very simple equation.

Hope this helped!

Answer:

[tex]a =-3[/tex]    [tex]b =2[/tex]

Step-by-step explanation:

Given

[tex]y = ab^x[/tex]

[tex](x_1,y_1) = (0,-3)[/tex]

Required

Find a and b

Substitute [tex](x_1,y_1) = (0,-3)[/tex] for x and y in [tex]y = ab^x[/tex]

[tex]-3 = ab^0[/tex]

[tex]-3 = a * 1[/tex]

[tex]-3 = a[/tex]

Rewrite as:

[tex]a =-3[/tex]

The above implies that (a) is correct;

Hence:

[tex]a =-3[/tex]    [tex]b =2[/tex]

So, the equation is:

[tex]y = -3(2)^x[/tex]

Answer: a=-3 b=2

Step-by-step explanation:

Answer:

Please find attached sketch of the path of the ball, having plot area and plot points, created with MS Excel

Step-by-step explanation:

Question;

The equation representing the path of the ball obtained from a similar question posted online are;

h₁ = -4·(t + 1)·(t - 5), h₂ = -4·(t - 2)² + 36, h₃ = -4··t² + 16·t + 20

The above equations represent the same path

The equation, h₁ = -4·(t + 1)·(t - 5), gives the roots of the height function, h(t), used in determining the height of the ball after time t

At (t + 1) = 0 (t = -1) or at (t - 5) = 0 (t = 5), the ball is at ground level

The ball reaches the ground, is at ground level at t = 1, and at t = 5 seconds after being tossed, where h(t) = 0

The equation of the path of the ball in vertex form, y = a·(x - 2)² + k, is h₂ = -4·(t - 2)² + 36, where, by comparison, we have;

The vertex of the ball = The maximum height reached by the ball  = (h, k) = (2, 36)

The coefficient of the quadratic term, t², is negative, therefore, the shape of the parabola is upside down, ∩, shape

The sketch of the path of the ball created with MS Excel, used in plotting the vertex, the initial value and the root points of the parabola, through which the ball passes and joining of the points with a 'smooth' curve is attached

Answer:

Một trục số đi từ âm 6 đến dương 6. Các điểm ở âm 6, âm 2, 5.

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex](x - 1) \: and \: (x - 5)[/tex]

I hope that is useful for you :)

The factors of the quadratic function whose graph is given are (-x -1) and ( x-5).

Factor of a quadratic equation is any monomial or binomial which divides the quadratic equation without leaving any remainder.

Factoring a quadratic equation can be defined as the process of breaking the equation into the product of its factors.

The solutions of a quadratic equation represent the values of x that make the equation true. And the solutions to any equation are the x-intercepts of that equation.

According to the given question

We have a graph of a quadratic equation and x intercepts -1 and -5.

⇒ we have two points (-1,0) and (-5,0)

⇒ -1 and -5 will be the solution of the quadratic function.

⇒ x = -1  and x = -5

⇒ x+ 1= 0 and x + 5 = 0

or -x -1 = 0 and x+5 = 0

Therefore, the factors of the quadratic function whose graph is given are (-x -1) and ( x-5).

Learn more about the factors of a quadratic function here:

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b) ( 7, 21)

Step-by-step explanation:

5(7)=2(21)-7

35=42-7

35=35

Answer:

None of them

Step-by-step explanation:

a: 5*0=2*6-7 False

b: 5*21=2*7-7 False

c: 5*18=2*8-7 False

d: 5*4=2*-3-7 False

Answer:

D. 50°

Step-by-step explanation:

We know that there are 3 line segments that are forming the angles. Based on that, we can safely say that each line segment is 180°. Given that, we can find the other 2 interior angles of the triangle. We know that one of the exterior angles is 90° so that interior angle also has to be 90° because both angles have to sum to 180. The 2nd exterior angle that we know is 140, so 180-140 = 40°. Since we know the other 2 angles of the triangle now and we know that all the angles of a triangle must sum to 180°, we add 90 and 40 to get 130 and then subtract that from 180 to get 50°. That would look something like this: 180-(90+40) = 180 - 130 = 50°. Hope this helps!

Answer

The measure of p is 50 degrees.

Explanation

You can see that p is located in a triangle.

The interior angles of a triangle always add up to 180 degrees.

So, to solve this problem, you can find the other interior angles, then subtract those from 180 to find p.

The exterior angles are 140 and 90 degrees. To find the measure of the interior angles, you subtract them from 180, (because the exterior angles and interior angles add up to 180).

The measure of the interior angles are 40 and 90 degrees; 180-140=40 and 180-90=90.

Now you can subtract the measure of the two interior angles from 180 to find p; 180-40-90=50.

Given:

Diameter of the tennis ball = 14 inches.

Three tennis balls are fit in a cylindrical tennis ball cane.

To find:

The volume of air left between the balls and the cane​.

Solution:

Diameter of the tennis ball = 14 inches.

Radius of the tennis ball = 7 inches

Radius of tennis ball is equal to radius of cane. So,

Radius of the cane = 7 inches

Height of cane is:

[tex]3\times 14=42[/tex] inches

Volume of a ball is:

[tex]V_1=\dfrac{4}{3}\pi r^3[/tex]

Where, r is the radius of the ball.

So, the volume of 3 ball is:

[tex]V_2=3\times V_1[/tex]

[tex]V_2=3\times \dfrac{4}{3}\times \dfrac{22}{7}\times (7)^3[/tex]

[tex]V_2=4312[/tex]

Volume of the cane is:

[tex]V_3=\pi r^2h[/tex]

Where, r is the radius of the cane and h is the height of the cane.

[tex]V_3=\dfrac{22}{7}\times (7)^2\times 42[/tex]

[tex]V_3=6468[/tex]

Now, the volume of air left between the balls and the cane​ is:

[tex]V=V_3-V_2[/tex]

[tex]V=6468-4312[/tex]

[tex]V=2156[/tex]

Therefore, the volume of air left between the balls and the cane​ is 2156 cubic inches.

Answer

34 match sticks (C)

please mark me as brainliest and pls someone answer my question also

Answer:

Step-by-step explanation:

for first question your pattern is 3x+4 then 3(10)+4=34.. I mean your answer is part c

in second picture if your mean is 7 question, the answer is part 1. w=p/2_125 can not be the answer.

if your mean is 8 question, it's answer is point S. because x=5 &y=-25 then 5-(-25)=+30 it means point S.

but if your mean is the 6 question,it's answer is part 1..it means 3e+5c+2(1)

Answer:

3 is the missing value

Step-by-step explanation:

Given

[tex]24 + 12 = \_ * (8 + 4)[/tex]

Required

Complete the blank

The model is not given; but the question can still be solved.

We have:

[tex]24 + 12 = \_ * (8 + 4)[/tex]

Add 8 to 4

[tex]24 + 12 = \_ * 12[/tex]

Add 24 to 12

[tex]36= \_ * 12[/tex]

Divide both sides by 12

[tex]3= \_[/tex]

Rewrite as:

[tex]\_ = 3[/tex]

Hence, the blank will be completed with 3

Answer:

a

Step-by-step explanation:

edg 2021

Answer:

x=6

pqs=82

sqr=59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

23x + 3= 141

23x = 136

x = 136/23 = 6

~~~~~~~~~~~~~~~

pqs = 13x + 4  = 13(6) + 4 = 78+4 = 82

sqr =  10x - 1 = 10(6)-1 = 60 - 1 = 59

Answer:

x = 6

Angle PQS is 82

Angle SQR is 59

Step-by-step explanation:

13x + 4 + 10x - 1 = 141

Group like terms : 23x + 3 = 141

Subtract 3 from both sides to get 23x = 138

Divide both sides by 23 to get x = 6

Angle PQS: Plug 6 into x  for 13x + 4 = 13 (6) + 4 = 82

Angle SQR: Plug 6 into x for 10x - 1 = 10 (6) -1 = 59

Answer:

1)  [tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

2)  [tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

3)  [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

4)  [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

5)  [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

Step-by-step explanation:

The rationalization of the denominator of the surds are found as follows;

1) [tex]\dfrac{2}{\sqrt{5} }[/tex]

[tex]\dfrac{2}{\sqrt{5} } \times \dfrac{\sqrt{5} }{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

[tex]\dfrac{2}{\sqrt{5} } = \dfrac{2 \cdot \sqrt{5} }{5}[/tex]

2) [tex]-\dfrac{5}{\sqrt{3} }[/tex]

[tex]-\dfrac{5}{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

[tex]-\dfrac{5}{\sqrt{3} } = -\dfrac{5 \cdot \sqrt{3} }{3}[/tex]

3) [tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} }[/tex]

[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } \times \dfrac{ \sqrt{10} }{\sqrt{10} } = \dfrac{\sqrt{20} + \sqrt{50} }{10 } = \dfrac{2\cdot \sqrt{5} + 5 \cdot \sqrt{2} }{10} = \dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

[tex]\dfrac{\sqrt{2} + \sqrt{5} }{\sqrt{10} } =\dfrac{\sqrt{5} }{5} + \dfrac{ \sqrt{2} }{2}[/tex]

4) [tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} }[/tex]

[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \dfrac{3 \cdot \sqrt{3}+\sqrt{6} }{3 } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

[tex]\dfrac{3 + \sqrt{2} }{\sqrt{3} } \times \dfrac{\sqrt{3} }{\sqrt{3} } = \sqrt{3} + \dfrac{\sqrt{6} }{3}[/tex]

5) [tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }[/tex]

[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} } = \dfrac{\sqrt{5} - \sqrt{2} }{\sqrt{5} - \sqrt{2} } = \dfrac{\sqrt{15} -\sqrt{6} }{5 - 2} = \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

[tex]\dfrac{\sqrt{3} }{\sqrt{5} + \sqrt{2} }= \dfrac{\sqrt{15} - \sqrt{6} }{3}[/tex]

6) [tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} }[/tex]

[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} = \dfrac{\sqrt{21} + \sqrt{35}}{{3} + {5}} = \dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]

[tex]\dfrac{\sqrt{7} }{\sqrt{3} - \sqrt{5} } \times \dfrac{\sqrt{3} + \sqrt{5}}{\sqrt{3} + \sqrt{5}} =\dfrac{\sqrt{21} + \sqrt{35}}{8}[/tex]

Answer:

[tex]y = \boxed0[/tex]

Step-by-step explanation:

we are given a sin function

[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) [/tex]

we want to figure out the midline of the function graphically The midline of a sinusoidal function is the horizontal line that passes exactly in the midline of its extreme value however since we a function recall that,

[tex] \displaystyle f(x) = a \sin(bx -c) + d[/tex]

where the midline is

to figure out the midline rewrite the function

[tex] \displaystyle h(x) = - 4 \sin(x -\pi /4) + 0[/tex]

therefore the midline is

[tex]y = \boxed0[/tex]

Answer:

The distance is 7[tex]\sqrt{2}[/tex]

Step-by-step explanation:

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{The formula for \underline{distance between} is: }\mathsf{\sqrt{(x_2-x_1)^2 + (y_2 - y_1)^2}}[/tex]

[tex]\large\textsf{Whereas }\mathsf{x_2}\large\textsf{ is }\mathsf{2}\large\textsf{ and }\mathsf{x_1}\large\textsf{ is }\mathsf{ -5}\\\\\large\textsf{And also }\mathsf{y_2}\large\textsf{ is }\mathsf{ -2}\large\textsf{ and }\mathsf{ y_1}\large\textsf{ is }\mathsf{5}[/tex]

[tex]\mathsf{\sqrt{(2 - -5)^2+ (-2 + 5)^2}}\\\mathsf{2 - -5}\\\mathsf{= 2 + 5}\\\mathsf{= \bf 7}\\\\\mathsf{-2 + 5}\\\mathsf{= \bf -7}\\\\\mathsf{= \sqrt{(7)^2+ (-7)^2}}\\\\\mathsf{7^2}\\\mathsf{= 7\times7}\\\mathsf{= \bf 49}\\\\\mathsf{(-7)^2}\\\mathsf{= -7\times-7}\\\mathsf{= \bf 49}\\\\\mathsf{= \sqrt{49 +49}}\\\\\mathsf{49+49}\\\mathsf{=\bf 98}[/tex]

[tex]\mathsf{= \sqrt{98}}\\\mathsf{= 7\sqrt{2}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf 7\sqrt{2}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

19:1

Step-by-step explanation:

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights. The ratio is 9500:500 or 19:1

The ratio of defective headlights to non-defective headlights will be 19:1.

The Percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

In mathematics, ratios are used to determine the relationship between two numbers it indicates how many times is one number to another number.

There are 10000 headlights. If 5% are defective, then 500 are defective. Since we took that 500 out, we get 9500 good headlights.

The ratio will be calculated as below:-

Ratio = 9500:500

Ratio = 19:1

Therefore, the ratio of defective headlights to non-defective headlights will be 19:1.

To know more about percentages follow

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Answer:

true

Step-by-step explanation:

:)