What is the tissue that allows for flexibility of bones?

Answer: In the case of water, we know that the O-H covalent bond is polar, due to the different electronegativities of hydrogen and oxygen. Since there are two O-H bonds in water, their bond dipoles will interact and may result in a molecular dipole which can be measured.

Explanation:

Answer:

bottom right corner with arrows going up

Answer:

i think the answer is c

Explanation:

collission

Answer:

35.453 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A (Cl–35):

Abundance (A%) = 75.77%

Mass of A = 34.969 amu

Isotope B (Cl–37):

Abundance (B%) = 24.23%

Mass of B = 36.966 amu

AVERAGE atomic mass of Cl =?

The average atomic mass of Cl can be obtained as follow:

Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

Average = [(34.969 × 75.77)/100] + [(36.966 × 24.23)/100]

Average = 26.496 + 8.957

Average atomic mass of Cl = 35.453 amu.

Answer:

the final temperature is 465.2k

Answer:

carbon mono oxide CO

Explanation:

as both are in 1:1 ratio so CO is formed

Hi there! :)

[tex]\large\boxed{x = 2.49 L}[/tex]

Use the proportion for Charles' Law where:

[tex]\frac{v_{1}}{t_{1}}= \frac{v_{2}}{t_{2}}[/tex]

v1 = initial volume

t1 = initial temperature

v2 = final volume

v2 = final temperature

Substitute in the given values into the proportion:

v1 = 4.39 L

t1 = 44° C

t2 = 25°C

v2 = x L

Set up the proportion:

[tex]\frac{4.39}{44} = \frac{x}{25}[/tex]

Cross multiply:

[tex]25 * 4.39 = 44x\\\\109.75 = 44x\\\\x = 2.49 L[/tex]

Answer:

The new volume will be approximately 2.49 L.

Explanation:

We are given that a gas sample occupies 4.39 L at 44° C.

We are also given that we are going decrease the temperature to 25° C.

Charles' Law has a formula which shows the relationship between the volumes of a samples and the temperatures of the samples.

The proportion is shown as:

[tex]\displaystyle \bullet \ \ \ \frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex],

where V₁ and V₂ are the initial and final volume respectively and T₁ and T₂ are the initial and final temperature respectively.

This proportion can be used to determine what our unknown is. We need to know the final volume.

[tex]\displaystyle \frac{4.39 \ \text{L}}{44 \ \text{C}} = \frac{\text{x}}{25 \ \text{C}}\\\\\\\frac{4.39}{44} = \frac{x}{25}\\\\\\4.39 \times 25 = 44 \times x\\\\\\44x = 109.75\\\\\\\frac{44x}{44}=\frac{109.75}{44}\\\\\\x = 2.49432 \approx \boxed{2.49 \ \text{L}}[/tex]

Therefore, if we reduce the temperature to 25 °C, we will be reducing the volume of the substance to 2.49 L.

thermal contact

When heat flows from one object or substance to another it is in contact with, the objects or substances are said to be in thermal contact. The state where objects in thermal contact with each other reach the same temperature, no heat flows between them.

Answer:

The answer is c, Clouds fill with moisture and get too hravy

Answer:

PCl3 - trigonal pyramidal <109 degrees

SCl2 - bent<109 degrees

SiF4 - tetrahedral 109 degrees

Explanation:

The shape of all three molecules derive from a tetrahedral arrangement of electron pairs.

However, in PCl3 there is a lone pair of electrons on P and three bond pairs. This leads to the observance of a trigonal pyramidal geometry with bond angle <109 degrees.

In SCl2, there are four regions of electron density around S, two lone pairs and two bond pairs leading to a bent molecular geometry with bond angle <109 degrees.

In SiF4, there are four bond pairs and no lone pair. The molecular geometry is tetrahedral with a bond angle of 109 degrees.

Answer:

a.) 294.12 g/mol

Explanation:

1 equivalent of fatty acid reacts with 1 equivalent of NaOH.

As in the titration are required 0.0034 equivalents of NaOH, the equivalents of fatty acids = moles of fatty acids are:

0.0034 moles of fatty acids

Molar mass is defined as the ratio between mass of substance in a determined amount of moles. The mass of the fats was 1 gram, that means the molar mass is:

1g / 0.0034moles =

294.12g/mol

Right option is:

Answer:

118 mL

Explanation:

We can easily calculate the final volume of the solution (V₂) by applying the following mathematical expression:

V₁ x C₁ = V₂ x C₂

⇒ V₂ = V₁ x C₁/C₂

Given:

V₁ = 10 mL

C₁ = 0.65 M

C₂ = 0.055 M

We replace the data in the mathematical expression to calculate V₂:

V₂ = V₁ x C₁/C₂ = 10 ml x (0.65 M)/ (0.055 M) = 118.18 mL ≅ 118 mL

Answer:

1) magnesium chloride

2) b) The copper is getting oxidized from Cu+ to Cu2+ and turns blue.

Explanation:

The work published by David N. Frick, Sukalyani Banik, and Ryan S. Rypma in J Mol Biol. 2007 Jan 26; 365(4): 1017–1032 clearly shows that divalent metal ions of group 2 such as Mg^2+ play an important role in ATP hydrolysis. Addition of EDTA decreased the rate of hydrolysis of ATP (due to sequestration of the divalent ion of group 2) indicating an active participation of divalent ions in the process.

2) The copper I ion is colourless because it is a d^10 specie. However, when it is oxidized to Cu^2+, a blue colour appears in the solution.

Answer:

Explanation:

T

Answer:

for this one you would have to divide 19.9g by the kinetic energy 1.0 and you would get your answer.

Explanation:if you would give me brainiest that would help a lot :)

Answer:

Molarity = 0.3 M

Explanation:

Given data:

Moles of NaOH = 0.720 mol

Volume of water = 2.40 L

Molarity = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 0.720 mol / 2.40 L

Molarity = 0.3 mol/L

Molarity = 0.3 M

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

Answer:

C. are found in the nucleus of an atom

Explanation:

Protons and Neutrons are always located at the center of the atom also called as the nuclei of the atom and constitute nearly all the mass of the atom, while the electrons revolve around them in orbits called shells. Only protons have a positive charge and electrons have negative charges, due to which only protons and electrons attract each other, while neutrons lack charges or have 'Neutral Charges'.

Answer:

P4O10

Explanation:

Answer:

i do k12 too!

Explanation:

lol

The [H₃0⁺] of the solution : 1.778  x 10⁻¹² M

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.  

A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.  

pH of solution = 11.75

the [H₃0⁺] of the solution :

[tex]\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^{-11.75}=1.778\times 10^{-12}[/tex]

Answer:

After 3 half lives 10 g of radio active material left.

Explanation:

Given data:

Total amount of radio active material = 80 g

Amount left after 3 half lives = ?

Solution:

At time zero = 80 g

At first half life = 80 g/2 = 40 g

At 2nd half life = 40 g/2 = 20 g

At 3rd half life = 20 g/2 = 10 g

Thus, after 3 half lives 10 g of radio active material left.

Answer:

i not sure but i searched it up and it said Q=104525J

Explanation:

Answer:

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

The pH at equivalence point is = 7

Explanation:

The reaction of Ba(OH)₂ with HCl is:

Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

First, we need to find moles of HCl. With these moles and the chemical equation we can find the moles of Ba(OH)₂ and the volume required:

Moles HCl:

75.0mL = 0.075L * (0.845mol / 1L) = 0.063375moles HCl

Moles Ba(OH)₂:

0.06338moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.03169 moles Ba(OH)₂

Volume of the 0.125M Ba(OH)₂:

0.03169 moles Ba(OH)₂ * (1L / 0.125mol) = 0.2535L are required =

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

As the titration was of a strong acid, HCl, with a strong base, Ba(OH)₂, the pH at equivalence point is = 7

Answer:

the  molar mass of the compound is  34.0 g /mol

Explanation:

The computation of the molar mass of the compound is as follows:

As we know that

PV = nRT

n = mass ÷ MW

PV = mRT ÷ MW

It can be rearrange as

MW = mRT ÷ (PV)

MW = (0.941)(0.082)(150 + 273) ÷ (1 × 0.96)

= 33.99g/mol

= 34.0 g /mol

Hence, the  molar mass of the compound is  34.0 g /mol