What is the value of f ^-1 (0)? ( photo given )

PLEASE HELP ME, I would greatly appreciate it !!! ​

Answer:

18

Step-by-step explanation:

The interior and exterior angle of a polygon is supplementary

let interior be I

let exterior be E

I + E = 180

Since the interior angle is 8 times that of an exterior angle,

8E + E = 180          [replacing I with 8E]  

9E = 180                

E = 20                      

The exterior angle is 20 degrees

I + E = 180          

I + 20 = 180      

I = 160              

The interior angle is 160 degrees.

The equation to find the interior angle of a polygon with 'n' number of sides is:

I = ( (n − 2) × 180 ) ⁄ n

We know the interior angle, so plug it in and solve for n:

160 = ( (n − 2) × 180 ) ⁄ n      

160n = (n − 2) × 180            

160n = 180n − 360                  

-20n = -360                            

n = 18                                  

Answer:

V = 24.28 in ^3

Step-by-step explanation:

The area of the base is

A =5/2 × s × a  where s is the side length and a is the apothem

A = 5/2 ( 2.13) * .87

A = 4.63275

The volume is

V = Bh  where B is the area of the base and h is the height

V = 4.63275 ( 5.24)

V =24.27561 in^3

Rounding to the  hundredth

V = 24.28 in ^3

Answer:

hope this helps you

have a great day

Answer:

The slope is -3/4 and a point on the line is (-5,4)

Step-by-step explanation:

This equation is in point slope form

y -y1 = m(x-x1)

where m is the slope and (x1,y1) is a point on the line

Y-4=-3/4(x+5)

Y-4=-3/4(x -  -5)

The slope is -3/4 and a point on the line is (-5,4)

Answer:  2 distinct complex solutions (ie non real solutions).

Work Shown:

The given equation is in the form ax^2+bx+c = 0, so

a = 1, b = 3, c = 8

Plug those into the formula below to find the discriminant

D = b^2 - 4ac

D = 3^2 - 4(1)(8)

D = -23

The discriminant is negative, so we get two nonreal solutions. The two solutions are complex numbers in the form a+bi, where a & b are real numbers and [tex]i = \sqrt{-1}[/tex]. The two solutions are different from one another.

Answer:

Discriminant: -23

Number of real roots: 0

Step-by-step explanation:

For a quadratic in standard form [tex]ax^2+bx+c[/tex], the discriminant is given by [tex]b^2-4ac[/tex].

In [tex]x^2+3x+8[/tex], assign:

The discriminant is therefore:

[tex]3^2-4(1)(8)=9-32=\boxed{-23}[/tex]

For any quadratic:

Since the quadratic in the question has a discriminant less than 0, there are no real solutions to this quadratic.

Answer:

the first one...

the cost of renting the ally for 14 hours

Step-by-step explanation:

Answer:

the first one

the number of dollars it costs to rent the bowling lane for14 hours

Answer:

B) 9

Step-by-step explanation:

Because there's a square between the 2 angles, that means these angles are complementary (angles that add up to 90°). So:

5x - 9 + 6x = 90

11x - 9 = 90

11x = 90 + 9

11x = 99

x = 9

Answer:

B.9

Step-by-step explanation:

The way to solve this is by noticing that these angles are complementary(they add up to 90 degrees). So you add the equations together and equal them to 90. 5x-9+6x=90.Then you solve to find that x=9.

Answer:

4x -12

Step-by-step explanation:

8 - 4(-x + 5)

Distribute

8 -4(-x) -4(5)

8 +4x -20

4x -12

answer 4( - 3 + x)

answer

[tex]4( - 3 + x)[/tex]

[tex]8 - 4( - x + 5)[/tex]

answer

[tex] - 12 + 4x[/tex]

Answer:

⊥

Step-by-step explanation:

d and b meet at a 90 degree angle ( as shown by the box)

The lines are perpendicular (⊥)

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

Concepts:

Area of Square = s²

Area of Triangle = bh/2

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

Question # 16

Step One: Find the total area of two squares

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

Step Two: Find the area of the blank triangle

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

Step Three: Subtract the area of the blank triangle from the total area

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

Step One: Find the length of PT

Given:

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

Step Two: Find the length of S to PT perpendicularly

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Three: Find the area of ΔPST

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Four: Find the length of Q to PT perpendicularly

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Five: Find the area of ΔPQT

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Six: Combine area of two triangles to find the total area

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

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Explanation:

It helps to add point labels. Let's place point A at the very top point of the triangle. Then point B will be at the 90 degree angle. Point C is the far left point. Lastly, point D is on segment BC such that DC = 3.

Since BC = 8 and CA = 17, we can use the pythagorean theorem to get...

(AB)^2 + (BC)^2 = (AC)^2

(AB)^2 + (8)^2 = (17)^2

(AB)^2 + 64 = 289

(AB)^2 = 289-64

(AB)^2 = 225

AB = sqrt(225)

AB = 15

Now focus on triangle ABD and apply the pythagorean theorem again to find side AD

(AB)^2 + (BD)^2 = (AD)^2

AD = sqrt(  (AB)^2 + (BD)^2  )

AD = sqrt(  (AB)^2 + (BC-CD)^2  )

AD = sqrt( (15)^2 + (8-3)^2 )

AD = sqrt(250)

AD = sqrt(25*10)

AD = sqrt(25)*sqrt(10)

AD = 5*sqrt(10) .... answer is choice B

Answer:

O-2(x+5)=2x-10

Explanation

O-2(x+5)=2x-10

SOLUTION

-2x(x)= -2x

-2x+5 = -10

Answer:

9

Step-by-step explanation:

Using the rules of logarithms

log[tex]x^{n}[/tex] = nlogx

[tex]log_{b}[/tex] b = 1

Then

[tex]log_{x}[/tex] [tex]x^{9}[/tex]

= 9[tex]log_{x}[/tex] x

= 9

Answer:

B

Step-by-step explanation:

A x - 36 <42 is wrong because its saying how many can be added

B x +36 < 42 this one is most likely correct because its displays x as how many can be added

C x - 36 > 42 this is wrong because the bus has less than 42 seats

D x + 36 >57 like i said cant be over 42

The inequality representing the possible number of passengers that can be added to the bus is Option(B) x + 36 < 42.

An inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. Inequality is used most often to compare two numbers on the number line by their size. There is always a definite equation to represent it.

Let x be the number of passengers that can be added to the bus.

It is given that the bus has less than 42 seats and 36 seats are already occupied.

The sum of the remaining seats which are to be filled by the passenger and the 36 seats which are filled, must be less than the total seats that is 42.

Therefore the inequality equation becomes,

x + 36 < 42.

Thus, the inequality representing the possible number of passengers that can be added to the bus is Option(B) x + 36 < 42.

To learn more about inequality equation, refer -

https://brainly.com/question/17448505

#SPJ2

Answer:

Yes, the function is symmetric about y-axis.

Step-by-step explanation:

To check whether the function is symmetric with respect to y-axis, replace each x as -x and simplify.

If h(x) = h(-x) then it is symmetric about y-axis.

Let's find h(-x) now.

h(-x)= [tex](-x)^4} -5(-x)^{2} +3[/tex]

Let's simplify it

h(-x)=[tex]x^{4}-5x^{2} +3[/tex]

Here, h(x) = h(-x). The function is symmetric about y-axis.

Answer:

v =  14 km/h

Step-by-step explanation:

d = 0.0067[tex]v^{2}[/tex] + 0.15v

differentiate the function with respect to v to have;

d = 0.0134v - 0.15

given that the distance without skidding = 37 m (0.037 km) , then;

0.037 = 0.0134v - 0.15

0.0134v = 0.037 + 0.15

             = 0.187

v = [tex]\frac{0.187}{0.0134}[/tex]

  = 13.9552

v =  14 km/h

The speed of the car travelling would be 14 km/h to be able to stop within 37m.

Answer:

33/4

Step-by-step explanation:

Let n = number

2/3 * n = 11

Multiply each side by 3/2

3/2 * 2/3 n = 11 * 3/2

n = 33/2

We want to find 1/2 of n

1/2 * 33/2 = 33/4

Answer:

A, B, E

Step-by-step explanation:

Exterior angles are angles that are outside the shape. In this case, angle 4, 3 and 2 are exterior angles.

Answer:

180m cubed

Step-by-step explanation:

Multiply the length, width, and height together: 6×6×5=180

Answer:

Formula of a rectangular prism:

L x W x H

Now we place in the numbers and solve:

5 x 6 x 6 = 180 m3

Answer:

Just want the points

Step-by-step explanation:

Answer:

Another example of a number who's square root is greater than the number is  [tex]\sqrt{0.49}[/tex] which is 0.7

Step-by-step explanation:

This square root is larger than the number because it is a decimal. When you multiply a decimal by a decimal, the decimal point becomes greater. For example: 0.7 multiplied by 0.7 equals 0.49 which has 2 decimal places, while 0.7 only has one.

Answer:

B (x+7, y-6)

Step-by-step explanation:

It goes right 7 and down 6

Answer:

(x,y) --> (x+7, y-6)

Step-by-step explanation:

Good luck with your exam! :DD

Answer:

Yes, she will be able to retrieve the item

Step-by-step explanation:

The information with regards to the research historian interest in finding a sunken treasure are;

The depth from which the equipment can recover items = 5,000 m

The speed of sound through water, v = 1,530 m/s

The time it takes the echo from the item to return to the sonar detector, t = 6.2 s

Let d, represent the depth at which the item is located

Given that an echo travels from the sonar detector to the item and back to the sonar detector, the distance traveled by the sound wave which is received as an echo by the sonar detector = 2 × d

Velocity, v = Distance/time

∴ Distance = Velocity × Time

The distance traveled by the echo = 2 × d = v × t

2 × d = v × t

∴ 2 × d = 1,530 m/s × 6.2 s

d = (1,530 m/s × 6.2 s)/2 = 4,743 m

The depth at which the item is located, d = 4,743 m is less than the maximum depth the equipment can recover items, therefore, she will be able to retrieve the item.

Answer:

Step-by-step explanation:

1) ML // JK , MK is transversal,

∠LMK = ∠MKJ   {Alternate interior angles are congruent}

∠LMK = 30°

In ΔMKO,

30 + 115 + ∠ JLM = 180  {Angle sum property of triangle}

        145 +∠ JLM  = 180

∠ JLM  = 180 - 145

∠ JLM = 35°

2) AB // CD , AC is transversal

∠DCA = ∠BAC     {Alternate interior angles are congruent}

∠DCA = 23

∠BCD = ∠DCA + ∠BCA

          = 23 + 37

          = 60

3) EF // HG ; FH  is transversal

∠FHG = ∠HFE   {Alternate interior angles are congruent}

 ∠FHG = 77

4) ZY // WX ;  WY is transversal

∠ZYW = ∠XWY         {Alternate interior angles are congruent}

            = 65

ZY // WX ;  WY is transversal

∠ZWY = ∠WYX   {Alternate interior angles are congruent}

           = 36

In  ΔWZY

36 +  65 + ∠z = 180

        101 +∠Z = 180

∠Z = 180 - 101

∠Z = 79

Answer:

8/10

Step-by-step explanation:

Answer:

D. Closed circle on 8, shading to the right.

Answer:

.5987

Step-by-step explanation:

Use a ztable and find .25 (pic below)

Answer:

i am not sure about this answer but i got r^2+10r+25

Answer:

common difference = 4

Step-by-step explanation:

common difference is the difference between the successive term and its preceding term.

let's take the successive term of -20 that is - 16

common difference (d) = successive term - preceeding term

= -16 -(-20)

= -16 + 20

= 4

if we take the successive term of -16 that is -12

we'll get the same common difference.

d = -12 -(-16)

d = -12 + 16

d = 4

this means that the common difference for an AP remains constant.