What is the value of the mean from the following set of data: 12,10, 11, 8, 6, 5, 3, 7, 9. Round to the nearest hundredth.

Answer:

2000

Step-by-step explanation:

20,000 is 2000 times the number 10.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given numbers are 20000 and 10. The number 20000 is how many times the number 10 will be calculated by dividing the number 20000 by 10.

E = 20000 / 10 = 2000

Therefore, the number 20,000 is 2000 times the number 10.

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Answer:

-35 and 37

Step-by-step explanation:

If you start with negative 35 and count up (including zero), you’ll cancel out when you get to positive 35 and have 71 numbers.  Then you continue on with 36 and 37 which equals 73, and you have 73 consecutive integers.

Answer:

The percentage is  k  =  2.3%

Step-by-step explanation:

From the question we are told that

  The  population mean is  [tex]\mu = 47[/tex]

    The  standard deviation is  [tex]\sigma = 14[/tex]

Given that the sales are normally distributed and that students at a certain school who sell at least 75 magazine subscriptions win a prize then the  percent of the fourth grade students receive a prize is mathematically represented as

     [tex]P(X > 75) = P(\frac{X - \mu }{\sigma } > \frac{75 - \mu }{\sigma })[/tex]

Generally

     [tex]\frac{X - \mu }{\sigma } = Z (The \ standardized \ value \ of \ X )[/tex]

So

   [tex]P(X > 75) = P(Z > \frac{75 - 47 }{14 })[/tex]

   [tex]P(X > 75) = P(Z > 2)[/tex]

From the standardized normal distribution table  

      [tex]P(Z > 2) =0.023[/tex]

=>   [tex]P(X > 75) = 0.023[/tex]

The  percentage of the fourth grade students receive a prize is  

  k =  0.023 * 100

   k  =  2.3%

[tex]x^2-3x+2=0\\x^2-x-2x+2=0\\x(x-1)-2(x-1)=0\\(x-2)(x-1)=0\\x=2 \vee x=1\\\\x^2=4 \vee x^2=1[/tex]

Answer:

Step-by-step explanation:

First we try to factor x²-3x+2.

We have to look for two numbers that multiply to 2 and add -3.

The two numbers are -1 and -2.

(x-1)(x-2) = 0

x-1 = 0 -> x = 1

x-2 = -> x = 2

Now we find x^2.

(1)^2 = 1

(2)^2 =4

Answer:

Step-by-step explanation:

Given that:

Let sample size of women be [tex]n_1[/tex]  = 1000

Let the proportion of the women be [tex]p_1[/tex] = 0.65

Let the sample size of the men be [tex]n_2[/tex] = 1000

Let the proportion of the mem be [tex]p_2[/tex]  = 0.60

The null and the alternative hypothesis can be computed as follows:

[tex]H_0: p_1 = p_2[/tex]

[tex]H_0a: p_1 \neq p_2[/tex]

Thus from the alternative hypothesis we can realize that this is a two tailed test.

However, the pooled sample proportion p = [tex]\dfrac{p_1n_1+p_2n_2 } {n_1 +n_2}[/tex]

p =[tex]\dfrac{0.65 * 1000+0.60*1000 } {1000 +1000}[/tex]

p = [tex]\dfrac{650+600 } {2000}[/tex]

p = 0.625

The standard error of the test can be computed as follows:

[tex]SE = \sqrt{p(1-p) ( \dfrac{1} {n_1}+ \dfrac{1}{n_2} )}[/tex]

[tex]SE = \sqrt{0.625(1-0.625) ( \dfrac{1} {1000}+ \dfrac{1}{1000} )}[/tex]

[tex]SE = \sqrt{0.625(0.375) ( 0.001+0.001 )}[/tex]

[tex]SE = \sqrt{0.234375 (0.002)}[/tex]

[tex]SE = \sqrt{4.6875 * 10^{-4}}[/tex]

[tex]SE = 0.02165[/tex]

The test statistics is :

[tex]z =\dfrac{p_1-p_2}{S.E}[/tex]

[tex]z =\dfrac{0.65-0.60}{0.02165}[/tex]

[tex]z =\dfrac{0.05}{0.02165}[/tex]

[tex]z =2.31[/tex]

At level of significance of 0.05  the critical value for the z test will  be in the region between - 1.96 and 1.96

Rejection region: To reject the null hypothesis if z < -1.96 or z > 1.96

Conclusion: Since the value of z is greater than 1.96, it lies in the region region. Therefore we reject the null hypothesis and we conclude that  the percentage of men and women favoring a higher legal drinking age is different.

Answer:

-2A = (-6, -8, 0, 8, 2, -8)

B - 2A = (2, -7, -4, 3, 4, -12)

AC is undefined.

CD = (3, 2, 12, 5)

Step-by-step explanation:

Given the matrices:

A = (3 4 0 -4 -1 4)

B = (8 1 -4 -5 2 -4)

C = (1 -1 3 1)

D = (3 -2 4 5)

We are required to compute the following

-2A, B - 2A, AC, CD

For -2A:

-2(3 4 0 -4 -1 4)

= (-6, -8, 0, 8, 2, -8)

For B - 2A:

Because B - 2A = B + (-2A), we have:

(8 1 -4 -5 2 -4) + (-6, -8, 0, 8, 2, -8)

(2, -7, -4, 3, 4, -12)

For AC:

(3 4 0 -4 -1 4)(1 -1 3 1)

This is undefined.

For CD:

(1 -1 3 1)(3 -2 4 5)

= (3, 2, 12, 5)

Answer:

3 years

Step-by-step explanation:

Use the formula I = prt, where I is the interest money made, p is the starting amount of money, r is the interest rate as a decimal, and t is the time the money was borrowed.

Plug in the values and solve for t:

108 = (1200)(0.03)(t)

108 = 36t

3 = t

= 3 years

Answer:

72

Step-by-step explanation:

The formula for surface area is SA = 2lw + 2wh + 2lh

W = width

L= length

H = height

A = 2(wl + hl + hw)

2·(6·3+2·3+2·6)

Simplify that down to get the answer 72

Answer:

720 different ways.

Step-by-step explanation:

Permutation has to do with arrangement. For example, in order to arrange 'n' objects in any order, this can only be done in n! ways since there is no condition or restriction on how to arrange the objects.

n! = n(n-1)(n-2)... (n-r)!

If there are 3 statistics books, 2 math books, and 1 computer science book on your bookshelf, the total number of books altogether is 3 + 2 + 1 = 6 books.

The number of ways that 6 books can be arranged in any order is 6!.

6! = 6(6-1)(6-2)(6-3)(6-4)(6-5)

6! = 6*5*4*3*2*1

6! = 120*6

6!= 720 different ways.

Hence, the books on your shelf can be arranged in 720 different ways.

Answer:

3x^2

Step-by-step explanation:

3 x times the fraction 1 over x to the power of negative 4 => 3x * 1/x^-4

= 3x *x^4 = 3x^5

times x to the power of negative 3 => x^-3

3x^5 * x^-3 = 3x^2

Answer:

3x^2

Step-by-step explanation:

i got it right on the test on god!

Answer:

[tex]\boxed{\mathrm{view \: explanation}}[/tex]

Step-by-step explanation:

Apply rule : [tex]a^1 =a[/tex]

[tex]\displaystyle \frac{1}{g^1 } =\frac{1}{g}[/tex]

[tex]\displaystyle \frac{1}{g^{-1}}[/tex]

Apply rule : [tex]\displaystyle a^{-b}=\frac{1}{a^b}[/tex]

[tex]\displaystyle \frac{1}{\frac{1}{g^1 } }[/tex]

Apply rule : [tex]\displaystyle \frac{1}{\frac{1}{a} } =a[/tex]

[tex]\displaystyle \frac{1}{\frac{1}{g^1 } }=g[/tex]

Answer:

[tex]\frac{1}{g^1}[/tex]

= [tex]\frac{1}{g}[/tex]

[tex]\frac{1}{g - 1}[/tex]

= [tex]\frac{g^1}{1}[/tex]

= [tex]\frac{g}{1}[/tex]

= g

Hope this helps!

Answer:

1.)  [tex]\frac{1}{9^4}*9^3[/tex]

2.) [tex]\frac{1}{w^7}[/tex]

3.)

Step-by-step explanation:

When you have a negative exponent, rewrite:

[tex]x^{-a}=\frac{1}{x^a}[/tex]

Rewrite using this to change all negative exponents.

Answer:

Multiple Answers

Step-by-step explanation:

Note: When multiplying numbers with exponents, you add the exponents. When dividing numbers with exponents, you subtract exponents.When you have a negative exponent, flip the fraction and write it as a positive exponent.

1) -4 + 3= -1  

So we have  (9^-4) + (9^3)= (1/(9^1)

2) (1/w)^7

3) cannot read problem, but just apply the rules I wrote under "Note"

4) 14/y

5) cannot read problem,but just apply the rules I wrote under "Note"

6) 20d^4 n^? --Cannot read n exponents--.

7) cannot read problem

8) Cannot read problem

9) 90/z^4---only if exponents are 5,-3,and-6

10) 1/(9^5)

11) 54b^4

12) Cannot read problem

13) 16d^8c^8 ---if exponents are 5,3,6,2--

14) s^8

Hope this helps! Plz give brainly, I kinda need it.

The can be divided into two rectangles, one having length [tex]8.3[/tex] and width $3.8$

Another with, dimensions $7.4-3.8=3.6$ and $3.9$

Area of first rectangle=$3.8\times8.3=31.54$

Area of second rectangle =$3.6\times3.9=14.04$

Total area $=31.54+14.04=45.58$ ft²

Answer:

45.58 ft^2

Step-by-step explanation:

We can split the figure into two pieces

We have a tall rectangle that is 3.8 by 8.3

A = 3.8 * 8.3 =31.54 ft^2

We also have a small rectangle on the right

The dimensions are ( 7.4 - 3.8) by 3.9

A = 3.6*3.9 =14.04 ft^2

Add the areas together

31.54+14.04

45.58 ft^2

Answer:

f(-5) = 22

Step-by-step explanation:

f(x) =-3x+7

Let x = -5

f(-5) =-3*-5+7

      = 15 +7

       =22

Answer:

Length = 21.3333333333;   Width: 12.6666666667

Step-by-step explanation:

Perimeter = 68

Perimeter of a rectangle:

2 (L +W)

Length (L) = 2W - 4

Width = W

2 ( 2W -4 +W) = 68

=> 2 (3W - 4) = 68

=> 6w -8 = 68

=> 6w = 76

=> w = 12.6666666667

Length = (12.6666666667 X 2) - 4

=> 21.3333333333

Answer:

D)  0.49

Step-by-step explanation:

0.85 * 0.58 = 0.49

The probability is:

D  0.49

Answer:

Midpoint formula.

The midpoint formula is (x_1+x_2)/2 , (y_1+y_2)/2

Step-by-step explanation:

This is one method. A list wasn't provided.

Answer:

the probability that out of these 75 people, 14 or more drink coffee is 0.6133

Step-by-step explanation:

Given that:

sample size n = 75

proportion of high school students that drink coffee p = 20% = 0.20

The proportion of the students that did not drink coffee = 1 - p

Let X be the random variable that follows a normal distribution

X [tex]\sim[/tex] N (n, p)

X  [tex]\sim[/tex] N (75, 0.20)

[tex]\mu = np[/tex] = 75 × 0.20

[tex]\mu =[/tex] 15

[tex]\sigma = \sqrt{p (1-p) n}[/tex]

[tex]\sigma = \sqrt{0.20(1-0.20) 75}[/tex]

[tex]\sigma = \sqrt{0.20*0.80* 75}[/tex]

[tex]\sigma = \sqrt{12}[/tex]

[tex]\sigma = 3.464[/tex]

Now ; if 14 or more people drank coffee ; then

[tex]P(X \geq 14) = P(\dfrac{X-\mu }{\sigma} \leq \dfrac{X-\mu}{\sigma})[/tex]

[tex]P(X \geq 14) =P(\dfrac{14-\mu }{\sigma} \leq \dfrac{14-15}{3.464})[/tex]

[tex]P(X \geq 14) = P(Z \leq \dfrac{-1}{3.464})[/tex]

[tex]P(X \geq 14) = P(Z \leq -0.28868)[/tex]

From the standard normal z tables; (-0.288)

[tex]P(X \geq 14) = P(Z \leq 0.38667)[/tex]

[tex]P(X \geq 14) = 1 - 0.38667[/tex]

[tex]P(X \geq 14) = 0.61333[/tex]

the probability that out of these 75 people, 14 or more drink coffee is 0.6133

Answer:

210.33 cm^2

Step-by-step explanation:

We know that 6 equilateral triangles makes one hexagon.

Also, an equilateral triangle has all its sides equal.

If the tile of each side of the triangular tile measure 9 cm, then the height of the triangular tiles can be gotten using Pythagoras's Theorem.

The triangle formed by each tile can be split along its height, into two right angle triangles with base (adjacent) 4.5 cm and slant side (hypotenuse) of 9 cm. The height  (opposite) is calculated as,

From Pythagoras's theorem,

[tex]hyp^{2} = adj^{2} + opp^{2}[/tex]

substituting, we have

[tex]9^{2} = 4.5^{2} + opp^{2}[/tex]

81 = 20.25 + [tex]opp^{2}[/tex]

[tex]opp^{2}[/tex] = 81 - 20.25 = 60.75

opp = [tex]\sqrt{60.75}[/tex] = 7.79 cm  this is the height of the right angle triangle, and also the height of the equilateral triangular tiles.

The area of a triangle = [tex]\frac{1}{2} bh[/tex]

where b is the base = 9 cm

h is the height = 7.79 cm

substituting, we have

area = [tex]\frac{1}{2}[/tex] x 9 x 7.79 = 35.055 cm^2

Area of the hexagon that will be formed = 6 x area of the triangular tiles

==> 6 x 35.055 cm^2 = 210.33 cm^2

Answer:

The range of the function f(x)= (x-4)(x-2) is all real numbers greater than or equal to -1

Step-by-step explanation:

Answer:

  2.5

Step-by-step explanation:

Put the values in place of the corresponding variables and do the arithmetic:

  ab - 0.5b = (1)(5) -0.5(5) = 5 - 2.5 = 2.5

Answer: 200 ways

Step-by-step explanation:

From the given information:

Total number of roads leading from Bluffton to​ Hardeeville = 4

Total number of roads leading from Hardeeville to​ Savannah = 10

Total number of roads leading from Savannah to Macon = 5

We need to find the total number of ways to get from Bluffton to​ Macon.

Total number of ways to get from Bluffton to​ Macon = 4 * 10 * 5

= 200

Therefore, there are 200 required number of ways to get from Bluffton to​ Macon.

Answer: p-value of the test  = 0.167

Step-by-step explanation:

Given that,

sample size n = 400

sample success X = 80

confidence = 95%

significance level = 1 - (95/100) = 0.05

This is the left tailed test .

The null and alternative hypothesis is

H₀ : p = 0.22

Hₐ : p < 0.22

P = x/n = 80/400 = 0.2

Standard deviation of proportion α = √{  (p ( 1 - p ) / n }

α = √ { ( 0.22 ( 1 - 0.22 ) / 400 }

α = √ { 0.1716 / 400 }

α = √0.000429

α = 0.0207

Test statistic

z = (p - p₀) / α

z = ( 0.2 - 0.22 ) / 0.0207

z = - 0.02 / 0.0207

z = - 0.9661

fail to reject null hypothesis.

P-value Approach

P-value = 0.167

As P-value >= 0.05, fail to reject null hypothesis.

Since test is left tailed so p-value of the test is 0.167. Since p-value is greater than 0.05 so we fail to reject the null hypothesis.

(a) Expand the given expression as

[tex]\dfrac{3s-10}{s^2+25}=3\cdot\dfrac s{s^2+25}-2\cdot\dfrac5{s^2+25}[/tex]

You should recognize the Laplace transform of sine and cosine:

[tex]L[\cos(at)]=\dfrac s{s^2+a^2}[/tex]

[tex]L[\sin(at)]=\dfrac a{s^2+a^2}[/tex]

So we have

[tex]L^{-1}\left[\dfrac{3s-10}{s^2+25}\right]=3\cos(5t)-2\sin(5t)[/tex]

(b) Take the Laplace transform of both sides:

[tex]y'(t)+3y(t)=e^{6t}\implies (sY(s)-y(0))+3Y(s)=\dfrac1{s-6}[/tex]

Solve for [tex]Y(s)[/tex]:

[tex](s+3)Y(s)-2=\dfrac1{s-6}\implies Y(s)=\dfrac{2s-11}{(s-6)(s+3)}[/tex]

Decompose the right side into partial fractions:

[tex]\dfrac{2s-11}{(s-6)(s+3)}=\dfrac{\theta_1}{s-6}+\dfrac{\theta_2}{s+3}[/tex]

[tex]2s-11=\theta_1(s+3)+\theta_2(s-6)[/tex]

[tex]2s-11=(\theta_1+\theta_2)s+(3\theta_1-6\theta_2)[/tex]

[tex]\begin{cases}\theta_1+\theta_2=2\\3\theta_1-6\theta_2=-11\end{cases}\implies\theta_1=\dfrac19,\theta_2=\dfrac{17}9[/tex]

So we have

[tex]Y(s)=\dfrac19\cdot\dfrac1{s-6}+\dfrac{17}9\cdot\dfrac1{s+3}[/tex]

and taking the inverse transforms of both sides gives

[tex]y(t)=\dfrac19e^{6t}+\dfrac{17}9e^{-3t}[/tex]

Greetings from Brasil...

In this problem we have 2 translations: 4 units horizontal to the left and 3 units vertical to the bottom.

The translations are established as follows:

→ Horizontal

F(X + k) ⇒ k units to the left

F(X - k) ⇒ k units to the right

→ Vertical

F(X) + k ⇒ k units up

F(X) - k ⇒ k units down

In our problem, the function shifted 4 units horizontal to the left and 3 units vertical to the bottom.

F(X) = X³

4 units horizontal to the left: F(X + 4)

3 units vertical to the bottom: F(X + 4) - 3

So,

F(X) = X³

The transformed function is f ( x ) = ( x + 4 )³ - 3 and the graph is plotted

Every modification may be a part of a function's transformation.

Typically, they can be stretched (by multiplying outputs or inputs) or moved horizontally (by converting inputs) or vertically (by altering output).

If the horizontal axis is the input axis and the vertical is for outputs, if the initial function is y = f(x), then:

Vertical shift, often known as phase shift:

Y=f(x+c) with a left shift of c units (same output, but c units earlier)

Y=f(x-c) with a right shift of c units (same output, but c units late)

Vertical movement:

Y = f(x) + d units higher, up

Y = f(x) - d units lower, d

Stretching:

Stretching vertically by a factor of k: y = k f (x)

Stretching horizontally by a factor of k: y = f(x/k)

Given data ,

Let the function be represented as g ( x )

Now , the value of g ( x ) = x³

And , the transformed function has coordinates as A ( -4 , -3 )

So , when function is shifted 4 units to the left , we get

g' ( x ) = ( x + 4 )³

And , when the function is shifted vertically by 3 units down , we get

f ( x ) = ( x + 4 )³ - 3

Hence , the transformed function is f ( x ) = ( x + 4 )³ - 3

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Answer:

Probabilty of both Black

= 1/6

Step-by-step explanation:

A bag contains five white balls and four black balls.

Total number of balls= 5+4

Total number of balls= 9

Probabilty of selecting a black ball first

= 4/9

Black ball remaining= 3

Total ball remaining= 8

Probabilty of selecting another black ball without replacement

= 3/8

Probabilty of both Black

=3/8 *4/9

Probabilty of both Black

= 12/72

Probabilty of both Black

= 1/6

Answer:

Option b. None is the correct option.

The Answer is 63%

Step-by-step explanation:

To solve for this question, we would be using the z score formula

The formula for calculating a z-score is given as:

z = (x-μ)/σ,

where

x is the raw score

μ is the population mean

σ is the population standard deviation.

We have boxes X and Y. So we will be combining both boxes

Mean of X = 100 lb

Mean of Y = 5 lb

Total mean = 100 + 5 = 105lb

Standard deviation for X = 1 lb

Standard deviation for Y = 0.5 lb

Remember Variance = Standard deviation ²

Variance for X = 1lb² = 1

Variance for Y = 0.5² = 0.25

Total variance = 1 + 0.25 = 1.25

Total standard deviation = √Total variance

= √1.25

Solving our question, we were asked to find the percent of filled boxes weighing between 104 lb and 106 lb are to be expected. Hence,

For 104lb

z = (x-μ)/σ,

z = 104 - 105 / √25

z = -0.89443

Using z score table ,

P( x = z)

P ( x = 104) = P( z = -0.89443) = 0.18555

For 1061b

z = (x-μ)/σ,

z = 106 - 105 / √25

z = 0.89443

Using z score table ,

P( x = z)

P ( x = 106) = P( z = 0.89443) = 0.81445

P(104 ≤ Z ≤ 106) = 0.81445 - 0.18555

= 0.6289

Converting to percentage, we have :

0.6289 × 100 = 62.89%

Approximately = 63 %

Therefore, the percent of filled boxes weighing between 104 lb and 106 lb that are to be expected is 63%

Since there is no 63% in the option, the correct answer is Option b. None.

The percent of filled boxes weighing between 104 lb and 106 lb is to be expected will be 63%.

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

A machine fills boxes weighing Y lb with X lb of salt, where X and Y are normal with a mean of 100 lb and 5 lb and standard deviation of 1 lb and 0.5 lb, respectively.

The percent of filled boxes weighing between 104 lb and 106 lb is to be expected will be

Then the Variance will be

[tex]Var = \sigma ^2[/tex]

Then for X, we have

[tex]Var (X) = 1^2 = 1[/tex]

Then for Y, we have

[tex]Var (Y) = 0.5^2 = 0.25[/tex]

Then the total variance will be

[tex]Total \ Var (X+Y) = 1 + 0.25 = 1.25[/tex]

The total standard deviation will be

[tex]\sigma _T = \sqrt{Var(X+Y)}\\\\\sigma _T = \sqrt{1.25}[/tex]

For 104 lb, then

[tex]z = \dfrac{104-105}{\sqrt{25}} = -0.89443\\\\P(x = 104) = 0.18555[/tex]

For 106 lb, then

[tex]z = \dfrac{106-105}{\sqrt{25}} = 0.89443\\\\P(x = 106) = 0.81445[/tex]

Then

[tex]P(104 \leq Z \leq 106) = 0.81445 - 0.18555 = 0.6289 \ or \ 62.89\%[/tex]

Approximately, 63%.

More about the normal distribution link is given below.

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Answer:

1, 165.500

Step-by-step explanation:

1, 165.492 rounded to the nearest hundredth is 1, 165.500 because the hundredth space in the decimal is 5 or above, so the whole decimal gets rounded to the nearest hundred, which in this case, would be .500.

165.492 is the correct answer

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

[tex]P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40[/tex]

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

[tex]P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36[/tex]

Thus, the probability that only white balls are drawn is 0.36.