what is the value of x to the nearest tenth

The temperature rose so you add the amount it rose to the starting temperature

68.7 + 9 = 77.7 degrees

It then dropped so mow you subtract t the amount it dropped:

77.7 - 12.3 = 65.4 degrees

The answer is 65.4 degrees

Answer:

Neither

Step-by-step explanation:

Answer:

let total be U and strawberry be S and.apple be A .

now

n[U]=200

n[S]=56% 0f 200=112

n[A]=44%of 200=88

n[A n S]=30%of 200=60

now

[tex] \bar {A U S}=?[/tex]

we have

n[U]=n[A] +n[B]-n[ A n B]+[tex] \bar{A U S}[/tex]

[tex] \bar{A U S}[/tex]=200-112-88+60=60

option C. 60 is a required answer.

Hope this help!!!

Have a nice day!!!

Answer:

The value of h(g(3)) is 17.

Step-by-step explanation:

We are given these following functions:

[tex]g(x) = x^2 - 5[/tex]

[tex]h(x) = 7x - 11[/tex]

h(g(3)) ?

[tex]h(g(x)) = h(x^2-5) = 7(x^2-5) - 11 = 7x^2 - 35 - 11 = 7x^2 - 46[/tex]

At x = 3

[tex]h(g(3)) = 7(3)^2 - 46 = 63 - 46 = 17[/tex].

The value of h(g(3)) is 17.

Answer:

E

Step-by-step explanation:

Beans: 2 possibilities

Meat: 3 possibilities

Vegetables: 4 posibilities

Toppings: 4 possibilities

Then mulltiply the numbers:

2 x 3 x 4 x 4 which equals 96

Answer:

x = 50 + 95 = 145

.........

Answer:

x = 145°

Step-by-step explanation:

Given,

Measure of the first angle = 50°

Measure of the second angle = 95°

We know,

Sum of 3 angles of a triangle is equals to 180°

∴ The third angle = 180° - (50+95)°

                             = 180° - 145°

                             = 35°

Again,

Straight angle = 180°

∴ x = 180° - 35°

      = 145°

∴x = 145°

Answer:

The profit for any purchased of bananas is R2.

Step-by-step explanation:

Cost of 1 kg banana = R 3

Banana purchased = 4 kg

So, the cost of 4 kg bananas = 4 x 3 = R 12

Amount paid = R 14

Profit = R 14 - R 12 = R 2

So, the profit on any purchased of bananas is R 2.

Answer:

[tex]A_1 = 12[/tex]

[tex]A_n = A_{n-1} + 3[/tex]

Step-by-step explanation:

Given

[tex]A_n =12+(n-1)3[/tex]

Required

Write as recursive

We have:

[tex]A_n =12+(n-1)3[/tex]

Open bracket

[tex]A_n =12+3n-3[/tex]

[tex]A_n =12-3+3n[/tex]

[tex]A_n =9+3n[/tex]

Calculate few terms

[tex]A_1 =9+3*1 = 9 + 3 = 12[/tex]

[tex]A_2 =9+3*2 = 9 + 6 = 15[/tex]

[tex]A_3 =9+3*3 = 9 + 9 = 18[/tex]

The above shows that the rule is to add 3.

So, we have:

[tex]A_1 = 12[/tex]

[tex]A_n = A_{n-1} + 3[/tex]

Answer:

a translation of 2 units to the left and 7 units up

Step-by-step explanation:

Translation of points (x,y)

At point x, the function can be translated to the left or to the right.

(x-a) is the translation of the point a units to the left, and (x+a) is the translation of the point a units to the right.

At point x, the function can be translated up or down. y+a represents a shift of a units up, and y-a represents a shift of a units down.

(x, y) = (x - 2, y + 7)

x - 2: 2 units to the left.

y + 7: 7 units up

So the fouth option is correct.

Answer:

I think B

Step-by-step explanation:

121.346° is more close to 121.3°, than 121.4°

if i'm wrong, the i'm sorry

Answer:

jane is correct

Step-by-step explanation:

10⁻⁴ can be written as [tex]\frac{1}{10000}[/tex] and as 0.0001

Answer:

0.872

Step-by-step explanation:

Given that :

P(cloudy) = P(C) = 0.94

P(cloudy and rainy) = P(C n R) = 0.82

Probability that a given day will be rainy if it is cloudy ; this is a conditional probability problem:

Recall ; P(A|B) = P(AnB) / P(B)

P(R|C) = P(C n R) / P(C) = 0.82 / 0.94 = 0.872

Answer:

C. b²< 40

Step-by-step explanation:

2x²+ bx + 5=0 has no real solutions

=> D< 0

b² < 4ac

b²< 4(2)(5)

b²< 40

Answer:

Step-by-step explanation:

( - ∞ , - 3 ) ∪ [ - 1 , ∞ )

Answer:

x = 6 , y = 7

Step-by-step explanation:

solving  by substitution method

x + y = 13

x = 13 - y                          equation (i)

2x - y = 5

substitute the value of x

2(13 - y) - y = 5

26 - 2y - y = 5

26 - 3y = 5

26 - 5 = 3y

21/3 = y

7 = y

substitute the value of y in equation (i)

x = 13 - y

x = 13 - 7

x = 6

Answer:

The 95% confidence interval for the true population mean textbook weight is between 66.24 and 71.76 ounces.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 1.96\frac{8.2}{\sqrt{34}} = 2.76[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 69 - 2.76 = 66.24 ounces

The upper end of the interval is the sample mean added to M. So it is 69 + 2.76 = 71.76 ounces.

The 95% confidence interval for the true population mean textbook weight is between 66.24 and 71.76 ounces.

Answer:

600 nickels

Step-by-step explanation:

Answer:

C. It the correct answer

Answer: 8 is the value for y.

since x=16 as answered in the previous question, then 10x-3+(3y-1)=180 being in a straight line.

Answer:

x = 14

Step-by-step explanation:

Please note, the word trapezium is a synonym for the word trapezoid.

This problem gives one the area of the trapezoid, a well as one of the measurements of a base and the height of the figure. One is asked to find the length of the other base. This can be done by using the formula to find the area of a trapezoid. This formula is the following,

[tex]A=(h)(\frac{b_1+b_2}{2})[/tex]

Where (A) represents the area of a trapezoid, ([tex]b_1[/tex]) and ([tex]b_2[/tex]) represents the bases and (h) represents the height. Substitute in the given values and solve for the unknown base.

[tex]b_1=7\\h=6\\A=84[/tex]

[tex]A=(h)(\frac{b_1+b_2}{2})\\[/tex]

Substitute,

[tex]84=6(\frac{7+b_2}{2})\\[/tex]

Inverse operations,

[tex]84=6(\frac{7+b_2}{2})[/tex]

[tex]14=\frac{7+b_2}{2}[/tex]

[tex]28=7+b_2[/tex]

[tex]14=b_2[/tex]

Answer:

AC = 28

Step-by-step explanation:

Ok, we know that:

Points A, B, and C are collinear.

Point B is between A and C.

We want to find the length AC (distance between A and C), if we know that:

AB = 16

BC = 12

Ok, knowing that B is between the other points, we know that:

AB + BC

defines the total length of the segment that connects the 3 points.

Thus, if we define this segment as a length, we only use the endpoints, A and C.

Then we have that:

AB + BC = AC

now we can solve this:

16 + 12 = AC

28 = AC

Answer:

[tex]{ \tt{3 \frac{4}{9} \div (5 \frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{31}{12} ) + \frac{59}{10} }} \\ \\ { \tt{ = \frac{4}{3} + \frac{59}{10} }} \\ \\ { \bf{ = \frac{217}{30} }} \\ \\ { \boxed{ \tt{answer : 7 \frac{7}{30} }}} \\ \\ { \underline{ \blue{ \tt{becker ⚜jnr}}}}[/tex]

Answer:

[tex]7 \frac{7}{30}[/tex]

Step-by-step explanation:

[tex]3 \frac{4}{9} \div ( 5\frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10}\\\\\frac{31}{9} \div (\frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} \\\\\\Solving \ using \ BODMAS\\\\First \ Solve \ expression \ inside \ Bracket \\\\\frac{31}{9} \div (\frac{(16 \times 4) - ( 11 \times 3)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div (\frac{64- 33)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div \frac{31}{12} + \frac{59}{10} \\\\\\ \\\\\\Next \ solve \ Dvision \\\\\frac{\frac{31}{9}}{\frac{31}{12}} + \frac{59}{10}\\\\[/tex]

[tex](\frac{31}{9}} \times {\frac{12}{31}) + \frac{59}{10}[/tex]

[tex]\frac{4}{3} + \frac{59}{10}\\\\ Now \ solve \ final \ expression \\\\\\\frac{(4 \times 10) + ( 59 \times 3)}{30}\\\\\frac{40 + 177}{30}\\\\\frac{217}{30}\\\\7 \frac{7}{30}[/tex]

Answer:

y = 1.19x

Step-by-step explanation:

y is the dependent variable (total cost)

x is the independent variable (number of pounds)

Answer:

k>1.25

Step-by-step explanation:

The given quadratic equation is :

(k – 1)x² + x + 1 = 0

We need to find all values of k for which the above equation has two real and unequal roots.

For a quadratic equation ax²+bx+c=0, for real and unequal roots,

b²-4ac>0

Here, a = (k-1), b = 1 and c = 1

Put all the values,

1²-4×(k-1)1>0

1-4k+4>0

5-4k>0

k>1.25

S, k can take values more than 1.25. Hence, it can take values 1.5, 1.75.

Step-by-step explanation:

Since the two triangles are similar

Then the ratio of sides are equal

Then MK:ML =JH:JI

Sub in this and you will get x =64.1

Answer:

B

Step-by-step explanation:

Hi there!

TL;DR: Observe the vertices of the shapes inside the circles and their relationship with the circle.

For the first figure, the rectangle has 4 vertices and there are 4 dots on the perimeter of the circle.

For the second figure, the triangle has 3 vertices and there are 3 dots on the perimeter of the circle.

For the third figure, the line has 2 points and there are 2 dots on the perimeter of the circle.

For the fourth figure, there would most likely be only one dot on the perimeter of the circle (4, 3, 2, 1). The only option that shows this is B.

I hope this helps!

Answer:

Well, 10% of 6640 is $664, and $332 is half of that, so 5%

Missing: ​$9850 ‎​$591.

Step-by-step explanation:

Answer:

espero ayudarte ..............