What is the value of y?

       There are two different ways we can solve this problem. We could use brute force, or we can use some equations to solve the problem. We can start by defining Pamela and Jiri's ages differently. If Jiri is j, and Pamela is p, we can say that p = j + 8, because Jiri + 8 years is Pamela's age.

       Now, using our values for Pamela and Jiri, we can say that (j + 8) + j = 102. Now we just solve like a normal equation, so 2j = 94, and j = 47, so Jiri is 47 years old.

Answer:

J = 47

Step-by-step explanation:

P = Pamela

J = Jiris

P = 8 + J ;- Equation 1

P + J = 102 ;- Equation 2

Substitute equation 1 into 2 to get:

J + 8 + J =102

2J = 102 - 8

2J = 94

J = 47

So Jiris is 47 years old

Answer:

A.*-3 and 2x2 + 4x2 - 4x+

Step-by-step explanation:

A.*-3 and 2x2 + 4x2 - 4x+

A.*-3 and 2x2 + 4x2 - 4x+

A.*-3 and 2x2 + 4x2 - 4x+

A.*-3 and 2x2 + 4x2 - 4x+

A.*-3 and 2x2 + 4x2 - 4x+

A.*-3 and 2x2 + 4x2 - 4x+

A.*-3 and 2x2 + 4x2 - 4x+

A.*-3 and 2x2 + 4x2 - 4x+

9514 1404 393

Answer:

  -13/11

Step-by-step explanation:

Straightforward evaluation of the expression at x=1 gives (1 -1)/(1 -1) = 0/0, an indeterminate form. So, L'Hopital's rule applies. The ratio of derivatives is ...

  [tex]\displaystyle\lim_{x\to 1}\dfrac{n}{d}=\dfrac{n'}{d'}=\left.\dfrac{\dfrac{4}{3\sqrt[3]{4x-3}}-\dfrac{7}{2\sqrt{7x-6}}}{\dfrac{5}{2\sqrt{5x-4}}-\dfrac{2}{3\sqrt[3]{2x-1}}}\right|_{x=1}=\dfrac{4/3-7/2}{5/2-2/3}=\dfrac{8-21}{15-4}\\\\=\boxed{-\dfrac{13}{11}}[/tex]

Answer:

[tex]41.89\ cm^2[/tex]

Step-by-step explanation:

[tex]We\ are\ given:\\In\ two\ concentric\ circles,\\OD=3\ cm\\BC=4\ cm\\\angle DOB=\angle AOC=120\\Now,\\We\ know\ that:\\Area\ of\ a\ sector\ with\ a\ central\ angle\ \theta\ and\ a\ radius\ r\ is:\\A=\frac{\theta}{360}* \pi r^2\\Here,\\Area\ between\ the\ sectors=Area\ of\ Larger\ Sector - Area\ of\ smaller\ sector=\frac{\theta}{360}*\pi(R^2-r^2),\ where\ R\ and\ r\ are\ radii\ of\ the\ respective\ circles\ and\\ \theta\ is\ the\ common\ central\ angle.\\Here,\\R=4+3=7\ cm\\r=3\ cm\\ \theta=120\\ Hence,[/tex]

[tex]Area\ of\ the\ shaded\ region=\frac{120}{360}*\pi(7^2-3^2)=\frac{1}{3}*\pi(49-9)=\frac{1}{3}*\pi(40) \approx 41.89\ cm^2[/tex]

Given:

The figures of two polygons.

To find:

Whether the polygons are similar and then find the scale factor (if similar).

Solution:

From the given figures it is clear that both polygons are rectangles and their all interior angles are right angles.

The ratio of their longer sides:

[tex]\dfrac{32}{26}=\dfrac{16}{13}[/tex]

The ratio of their shorter sides:

[tex]\dfrac{18}{12}=\dfrac{3}{2}[/tex]

Since the ratio of their corresponding sides are not equal, therefore the two polygons are not similar.

Therefore the required solutions are:

Similar : No

Similarity statement : None

Scale factor : None

Answer:

30 in²

Step-by-step explanation:

Parallelogram height is,

6/2 (since it's a 30°-60°-90° triangle)

= 3

Area = base × height

= 10×3 in²

= 30 in²

Answered by GAUTHMATH

Full question:

Zoe is a party planner. She orders cupcakes and sheet cakes from Creative Cakes whenever she needs beautiful cakes to serve. One sheet cake serves 24 people and 2 dozen cupcakes serve 24 people. For the Benson's bridal shower she ordered 10 dozen cupcakes and 4 sheet cakes and paid $186.44. For the Nygaard's 50th wedding anniversary she ordered 2 dozen cupcakes and 15 sheet cakes and paid $259.66. She is planning a graduation party for her niece's high school class. She wants the party to be nice but she offered to pay for the she wants to choose the most economical plan. Zoe estimates 250 people will attend the party

Select the most economical choice below:

Zoe should buy sheet cakes because they cost $12.38 for one sheet cake.

Zoe should buy sheet cakes because they cost $15.66 for one sheet cake.

Zoe should buy cupcakes because they cost $12.38 for one dozen cupcakes.

Zoe should buy cupcakes because they cost $15.66 for one dozen cupcakes.

Zoe should buy cupcakes because they cost $12.38 for two dozen cupcakes.

Answer:

Zoe should buy cupcakes because they cost $12.38 for two dozen cupcakes.

Explanation:

If there are 250 people attending the high school class graduation party, then 24 people each within 250 people in total would get 2 dozen cupcakes worth $12.38 each.

Therefore there are 250/24 = 10.41 groups (10 groups approximately or 10.41×2=20.82 dozens of cupcakes required)

Zoe would need to spend 10.41×$12.38= $128.88 to buy the cupcakes for the party

Answer:

g(4)  = 7 and f(g(4)) = 43

Step-by-step explanation:

First find g:

g(x) = 3x-5

g(x) = 3(4) - 5

g(x) = 12 - 5

g(x) = 7

Plug in:

f(g(4))

f(7)

Now, find f:

7^2 - 7 + 1

49 - 7 + 1

42 + 1

f(x) = 43

Answer:

15,300 units

Step-by-step explanation:

First, find how many units of Product B were sold:

34,000(0.3)

= 10,200

Find how many units of Product A were sold:

10,200(1.5)

= 15,300

So, 15,300 units of Product A were sold.

Product A  sold 15,300 units that is 1.5 times more than product B

Given :

Product A sells 1.5 times more than Product B. Product B sells 70% less than Product C.

Product C sold 34,000 units this month

Product C sold = 34000

Product B is 70% less than product C

So, product B is 100-70% =30% of product C

[tex]Product B=\frac{30}{100} \cdot 34000\\Product B \; sold = 10200[/tex]

Lets find out product A sold

Product A sold = 1.5 times more than product B

[tex]Product A= 1.5 \cdot product B\\Product A=1.5 \cdot 10200=15300[/tex]

15,300 units of product A were sold.

Learn more :  brainly.com/question/18958901

Answer:

D

Step-by-step explanation:

Answer:

2.2 x 100 = 220%

Step-by-step explanation:

To convert from decimal to percent, just multiply the decimal value by 100. In this example we have: 2.2 × 100 = 220% (answer). ➥ The ease way: 1) Move the decimal point two places to the right: 2.2 → 22 → 220.

I hope this will help you

9514 1404 393

Answer:

  C)  462

Step-by-step explanation:

The presenters can be chosen 11C6 = 462 different ways.

__

If the teacher were concerned about the order of the presentations, the number of possibilities goes up to 11P6 = 332,640 different ways.

Answer:

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\sf Speed = 44.44 \ m/s}[/tex]

Step-by-step explanation:

Speed = 160 km / hr

To convert km/hr to m/s, we multiply it by [tex]\sf \frac{10}{36}[/tex]

Hence,

[tex]\displaystyle Speed = 160 \times \frac{10}{36} \ m/s\\\\Speed = \frac{1600}{36} \ m/s\\\\Speed = 44.44 \ m/s\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

9514 1404 393

Answer:

Step-by-step explanation:

At $12 per gigabyte, the data charge will be 12g where g is the number of gigabytes. Then the total charge is ...

  C = 12g +20

__

If C = 116, the value of g is found from ...

  116 = 12g +20

  96 = 12g . . . . . . . subtract 20

  8 = g . . . . . . . . . . divide by 12

The amount of data used is 8 gigabytes if the charge is $116.

Answer:

x^2 + 91x + 2500

-----------------------------------------------------------------------------

x^2 + 3x + 50

(x-r)(x-s)

-> x^2-(r+s)x+rs

rs = 50, r + s = -3

-> (rs)^2 = 2500

(r+s)^2 = 9

-> r^2 + 2rs + s^2 = 9

-> r^2 + 2(50) + s^2 = 9

-> r^2 + s^2 + 100 = 9

-> r^2 + s^2 = -91

(x-r^2)(x-s^2)

-> x^2-(r^2+s^2)x+(rs)^2

-> x^2 - (-91)x + 2500

x^2 + 91x + 2500

Answer:

Ture

Step-by-step explanation:

The rates of the same participatant are paired.

Answer:

80x

Step-by-step explanation:

Bracket first

5 x 2 = 10

8x x 10 = 80x

(Unless the 'x' next to the 8 is the term for multiplying:

8 x 10 = 80)

Answer:

80

Step-by-step explanation:

8 x (5 x 2)

8 x 10

Answer = 80

Answer:

i doesn,t understand this language

Answer:

65 m

Step-by-step explanation:

u = 6 m/s

v = 20 m/s

t = 5 s

[tex]s=\frac{1}{2} (6+20)5[/tex]

[tex]s=\frac{1}{2} (26)5[/tex]

[tex]s=(13)5[/tex]

[tex]s=65[/tex]

Hey there!

1/2(6 + 20)(5)

= 1/2 (26)(5)

1/2(26) = 13

= 13(5)

= 65

Therefore, your answer is most likely: 65m

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

The probability is zero (0)

Step-by-step explanation:

Given;

interval of numbers to be chosen = 0, 1, 2, 3 , 4, 5, 6, 7, 8, 9 , 10

total possible outcome = 11

The possible numbers whose absolute difference is greater than ¹/₄ includes the following;

(0,1), (1,2), (2,3), (3,4), (4,5), (5,6), (6,7), (7,8), (8,9), (9,10), (10,0)

The probability of this = 11 / 11 = 1

The probability that the absolute value of the difference between their two numbers is less than 1/4

[tex]P(less \ than \ \frac{1}{4} ) = 1 - P(greater \ than \ \frac{1}{4} )\\\\P(less \ than \ \frac{1}{4} ) = 1 - 1 \\\\P(less \ than \ \frac{1}{4} ) = 0[/tex]

C.

Observe that the roots of polynomial are [tex]-3,2,5[/tex]

We have a polynomial in a factored form,

[tex](x+3)(x-2)(x-5)[/tex]

If you substitute x for any of [tex]-3,2,5[/tex] the product will always equal to zero that is these numbers are roots of polynomial.

Hope this helps :)

Answer:

their distance is increasing at the rate of 41.6 miles/hr

Step-by-step explanation:

Given the data in the question;

first we determine the distance travelled by the first boat in 10 min when the second boat was crossing its path;

⇒ ( 30/60 ) × 10 = 5 miles

so as illustrated in the diagram below;

y² = x² + ( x + 5 )²

2y[tex]\frac{dy}{dt}[/tex] = 2x[tex]\frac{dx}{dt}[/tex] + 2(x+5)[tex]\frac{dx}{dt}[/tex]

y[tex]\frac{dy}{dt}[/tex] = ( 2x + 5 ) ][tex]\frac{dx}{dt}[/tex]

[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]   ------ let this be equation 1

Now, given that, [tex]\frac{dx}{dt}[/tex]  = 30 miles/hr, when x = 10

so

y = √( 10² + 15² ) = √325

so from equation 1

[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]

we substitute

[tex]\frac{dy}{dt}[/tex] = [( 2(10) + 5 ) / √325 ]30

[tex]\frac{dy}{dt}[/tex] = [ 25 / √325 ] × 30

[tex]\frac{dy}{dt}[/tex] = 41.6 miles/hr

Therefore, their distance is increasing at the rate of 41.6 miles/hr

(n/3) + 5 - 8 = 2

First add the constants (+5 and -8) on LHS.

(n/3) - 3 = 2

Transfer -3 to RHS, by changing its sign.

n/3 = 2 + 3

Now add the constants (2 and 3) on RHS.

n/3 = 5

Transfer 3 to RHS by changing division to multiplication

n = 5 × 3

Finally multiply the constants (5 and 3) on RHS

n = 15

[tex]\\ \sf\longmapsto 5+n>2[/tex]

[tex]\\ \sf\longmapsto n>2-5[/tex]

[tex]\\ \sf\longmapsto n>-3[/tex]