What is the volume of a rectangular prism with a length of 2 1/2 inch width of 4 inches, and a height of 3 inches? * 21: 36 cu, in O 30 cu in 9.5 cu in 0 26 cu.in​

Answers

Answer 1

Answer:

30 cubic inch

Step-by-step explanation:

What Is The Volume Of A Rectangular Prism With A Length Of 2 1/2 Inch Width Of 4 Inches, And A Height

Related Questions

HELP WILL GIVE BRANLIEST

Answers

Answer:

the answer is b

Step-by-step explanation:

Answer:

Last Choice

Step-by-step explanation:

No time to explain I am 100 % sure its correct i had same problem

14. On Monday, a work group eats at Ava's café,
where a lunch special is $8 and a dessert is
$2. The total is $108. On Friday, the group
eats at Bo's café, where a lunch special Is
$6 and a dessert is $3. The total is $90. Each
time, the group orders the same number of
lunches and the same number of desserts.
How many lunches and desserts are
ordered?
what the x and y value.

Answers

Answer:

no. who eat lunch special = 12

no. who eat dessert = 6

Step-by-step explanation:

Let x = no. who eat lunch special

y = no. who eat dessert

(1)    8x + 2y = 108             (2)    6x + 3y = 90

 Divide thru by 2                         Divide thru by 3

      4x + y = 54                          2x + y = 30

     -2x - y = -30

       2x = 24

         x = 12                               2(12) + y = 30

                                                    24 + y = 30

                                                            y = 6

                                                 

The coordinates of a rectangle, LMNO, are L(- 1,3), M(2,3), N(2, - 5), and 0(- 1,- 5).
a. What is the length and width of this rectangle?
b. What is the perimeter of the rectangle?
c. What is the area of the rectangle?

Answers

Answer:

length = 8; width = 3

perimeter = 22

area = 24

Step-by-step explanation:

L(- 1,3), M(2,3)

LM = |-1 - 2| = 3

M(2,3), N(2, - 5)

MN = |-5 - 3| = 8

length = 8; width = 3

perimeter = 2(L + W) = 2(8 + 3) = 22

area = LW = 8 × 3 = 24

HELP PLEASE ILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

50%
- Animals
Home
Economics -
20%
30%
- Farm Mechanics
There were 2500 entries at the county fair. The circle graph tells what types of entries were made.
How many were Farm Mechanics entries?

Answers

180 is the answer pls don’t get mad if i get it wrong

Answer:

750 were Farm Mechanics.

Step-by-step explanation:

30% of 2500 is 750.

Hope this helps

You have been given the task of designing a study concerning the lifetimes of five different types of electric motor. The initial question to be addressed is whether there are differences in mean lifetime among the five types. There are 20 motors, four of each type, available for testing. A maximum of five motors can be tested in a day. The ambient temperature differs from day to day, and this can affect motor lifetime.
a. Describe how you would choose the five motors to test each day. Would you use a completely randomized design? Would you use any randomization at all?
b. If X;j represents the measured lifetime of a motor of type i tested on day j, express the test statistic for testing the null hypothesis of equal lifetimes in terms of the Xir

Answers

Answer:

a-As the only factor of interest is type of electric motor, thus instead of using 1-factor randomization, a randomized block design is used where at maximum one motor of each type is tested every day.

b- The test statistic is given as

[tex]F_{I-1,(I-1)(J-1)}=\dfrac{12\left(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}\right) }{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}[/tex]

Step-by-step explanation:

a-

This is done such that the days are considered as blocks and the randomization is only occuring within the block. The order of testing is random. However the condition is implemented such that one motor of each type is tested each day.

b-

The F-Value is given as

[tex]F-Value=\dfrac{MSA}{MSAB}[/tex]

Here MSA is given as

[tex]MSA=\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}[/tex]

Here

I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex]

Similarly MSAB is given as

[tex]MSAB=\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}[/tex]

Here

I is the number of types which is 5J is the number of motors of each type which is 4[tex]\bar{X}_{i.}[/tex] is the row-wise mean which is given as [tex]\bar{X}_{i.}=\dfrac{1}{J}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{..}[/tex] is the sample grand mean which is given as [tex]\bar{X}_{..}=\dfrac{1}{IJ}\Sigma^I_{i=1}\Sigma^J_{j=1}X_{ij}[/tex][tex]\bar{X}_{.j}[/tex] is the column-wise mean which is given as [tex]\bar{X}_{.j}=\dfrac{1}{I}\Sigma^I_{i=1}X_{ij}[/tex][tex]X_{ij}[/tex] is the any motor j of type i

By putting these values and simplifying, equation becomes:

[tex]F-Value=\dfrac{MSA}{MSAB}\\\\F-Value=\dfrac{\dfrac{J\Sigma^I_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{I-1}}{\dfrac{\Sigma^I_{i=1}\Sigma^J_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(I-1)(J-1)}}\\\\F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{5-1}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{(5-1)(4-1)}}\\\\[/tex]

This is further simplified as

[tex]F-Value=\dfrac{\dfrac{4\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{4}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{\Sigma^5_{i=1}(\bar{X}_{i.}-\bar{X}_{..})^2}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\[/tex]

The numerator can be written as

[tex]F-Value=\dfrac{\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..}}{\dfrac{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}{12}}\\\\F-Value=\dfrac{12(\Sigma^{5}_{i=1}\bar{X}^{2}_{i.}-IJ\bar{X}^2_{..})}{{\Sigma^5_{i=1}\Sigma^4_{j=1}\left(X_{ij}-\bar{X}_{i.}-\bar{X}_{.j}+\bar{X}_{..}\right)^2}}\\[/tex]

The catapults are 14.5 m, end text apart, as shown. From catapult A, there is a 96 degree angle between catapult B and the target. From catapult B, there is a 58°degree angle between catapult A and the target.

How far should catapult B throw the snowball to reach the target?
Do not round during your calculations. Round your final answer to the nearest tenth of a meter.


Thank you very much.

Answers

Answer:32.9 m

Step-by-step explanation:

What are some of the applications for exponential functions?
Designing identification tags
Conversion of measurements
Assigning phone numbers
Finding perimeter
Determining the number of subsets in a given set

Answers

Answer:

Option B and D are correct

Step-by-step explanation:

Exponential functions are really useful in the real world situation. They can be used to solve following

a) Population Models

b) Determination of area and perimeters

c) Determine time related things such as half life, time of happening of an event etc.

d) Useful for solving financial problems such as computing investments etc.

Hence, option B and D

Using the product of the means equals the product of the extremes, solve for x, to the nearest tenth. 4:9=x:6​

Answers

Cross multiply:

4 x 6 = 9x

24 = 9x

Divide both sides by 9

X = 24/9

X = 2.7 ( rounded to the nearest tenth)

Find the volume of a pyramid with a square base, where the perimeter of the base is 16.1 ft and the height of the pyramid is 12.1 ft. Round your answer to the nearest tenth of a cubic foot?

Answers

Answer: V= 65.3 ft^3

hey I need help with my coordinates ​

Answers

Ok send the picture so I can help you.

Answer:

what is the question? I can help

Step-by-step explanation:

A Solve each problem.
1. Henry flies his plane at 240 mph for 3 hours. How far does he travel?​

Answers

Distance = speed x time

Distance = 240 x 3 = 720 miles

Answer:

henry doesn't travel but plane travel

Step-by-step explanation:

240m×3hour240m×60×60sec2592000m/s

What is the average rate of change for the function f(x) = 3x2 – 5 on the interval –3 < x < -1​

Answers

Answer:

Algebra Examples

Popular Problems Algebra Graph f(x)=3x^2-5

f

(

x

)

=

3

x

2

5

Find the properties of the given parabola.

Tap for more steps...

Direction: Opens Up

Vertex:  

(

0

,

5

)

Focus:  

(

0

,

59

12

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

61

12

Select a few  

x

values, and plug them into the equation to find the corresponding  

y

values. The  

x

values should be selected around the vertex.

Tap for more steps...

x

y

2

7

1

2

0

5

1

2

2

7

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:  

(

0

,

5

)

Focus:  

(

0

,

59

12

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

61

12

x

y

2

7

1

2

0

5

1

2

2

7

image of graph

Step-by-step explanation:

find the area of the triangle ! be sure to include the correct unit with the answer. (yd) , (yd2) , (yd3) .

HELP PLEASE ! i really need it . thank you

Answers

Answer:

70 yd²

Step-by-step explanation:

Area of triangle = (1/2)(base)(perpendicular height)

= (1/2)(20)(7)

= 70 yd²

1. Find (f(g(2)) for f(x)= 3x² and g(x)= 5 - x.

Answers

Answer: 27

Step-by-step explanation:

Question 9 of 10
True or False? A circle could be circumscribed about the quadrilateral below.

Answers

Answer:

t

Step-by-step explanation:

A circle can be circumscribed about the given quadrilateral, the answer is: A. True.

We know that,

To circumscribe a circle about a quadrilateral means to place the quadrilateral inside the circle, such that the four vertices of the quadrilateral touches the circumference of the circle.

Opposite angles of a circumscribed polygon are supplementary.

Therefore, a circle can be circumscribed about the given quadrilateral, the answer is: A. True.

Learn more about circumscribed polygon on:

brainly.com/question/1423054

#SPJ7

3. A website allows users to download individual songs or whole albums.
All songs cost the same price to download. All albums cost the same price
to download, Karim pays $30 to download 5 songs and 2 albums.
Kimberlyn pays $26 for download 3 songs and 2 albums. What is the cost
to download 1 song? 1 album?

Answers

Answer:

Each song costs $2 and each album costs $10.

Step-by-step explanation:

Since a website allows users to download individual songs or whole albums, and all songs cost the same price to download and all albums cost the same price to download, and Karim pays $ 30 to download 5 songs and 2 albums while Kimberlyn pays $ 26 for download 3 songs and 2 albums, to determine what is the cost to download 1 song and the cost to download 1 album, the following calculations must be made:

5X + 2Y = 30

3X + 2Y = 26

(30 - 26) / (5 - 3) = X

4/2 = X

2 = X

Therefore, each song has a cost of $ 2.

Thus, to know the cost of each album (knowing that both downloaded the same amount, that is, 2), the following calculation must be performed:

5x2 + 2Y = 30

10 + 2Y = 30

2Y = 30 - 10

2Y = 20

Y = 20/2

Y = 10

Therefore, each album has a cost of $ 10.

What shape can be created by the given net? triangular pyramid wedge triangular prism cone

Answers

Answer:

your awnser would be option A. triangular prism

Step-by-step explanation:

Answer:

triangular prism

Step-by-step explanation:

Which expression best matches the statement:
Twelve less than the product of three and a number.
12 - 3n
3n - 12
3 + 7 - 12
12 - 3 + n

Answers

Answer: 3n - 12

Product means multiplication. So the 3 and n are being multiplied. If 12 is less than, then that means it is being subtracted from 3n, not the other way around.

A sweater costs $25. The store marks up the price by 85%. What is the selling price of the sweater?

Answers

21.25 because $25x85%=21.25

Help ASAP
What is the highest common factor of 180 and 168

Answers

Answer:

Its 12

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

make a factor tree, find the product of the prime factors, it will be 12.

A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 : Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective. Using the data, construct the 80% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places.

Answers

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that [tex]n = 1067, \pi = \frac{74}{1067} = 0.069[/tex]

80% confidence level

So [tex]\alpha = 0.2[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.2}{2} = 0.9[/tex], so [tex]Z = 1.28[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079[/tex]

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

What is 1 and 7/10
as a decimal?
0.17
1.7
th
0.7
7.1
1.07

Answers

1.7 is the answer to the question

If a team of minors drill a hole 50.4 m into a rock formation and drill at a steady rate of 2.8 m/min. how long does it take to drill the hole

Answers

Answer:

t = 18 minutes.

Step-by-step explanation:

We can find the time by using the following kinematic equation:

[tex] y_{f} - y_{0} = v_{0}t + \frac{1}{2}at^{2} [/tex]  

[tex] \Delta y = v_{0}t + \frac{1}{2}at^{2} [/tex]  

Where:  

Δy: is the difference between the initial and the final height = 50.4 m

t: is the time  

a: is the acceleration

v₀: is the velocity of the drill = 2.8 m/min

Since the speed of perforation is constant, the acceleration is zero so:

[tex]\Delta y = v_{0}t[/tex]    

Then, by solving the above equation for "t" we have:

[tex] t = \frac{\Delta y}{v_{0}} = \frac{50.4 m}{2.8 m/min} = 18 min [/tex]

Therefore, it takes 18 minutes to drill the hole.  

I hope it helps you!    

Convert 400 meters (m) to feet (ft). Round your answer to two decimal places. (1 metre = 3.28084 feet)

Answers

Answer:

1m----------3.28084ft

400m---------xft

x=(400*3.28084)/1

x=1,312.33 ft

Step-by-step explanation:

Pls help me if u can

Answers

Answer:

523.33 cm³

Step-by-step explanation:

Formula of volume of sphere

[tex] = \frac{4}{3} \pi {r}^{3} [/tex]

The volume of the sphere

[tex] = \frac{4}{3} \times 3.14 \times {5}^{3} [/tex]

[tex] = \frac{1570}{3} [/tex]

[tex] = 523.3333333...[/tex]

= 523.33 cm³ (rounded to the nearest hundredth)

Stacia buys 6 yards of ribbon to make a costume. She has 2 feet of ribbons left over. How many feet of ribbon did Stacia use to make the costume? Explain your work.
ANSWER WITH WORDS

Answers

Answer:

16 feet

Step-by-step explanation:

6 yards of ribbon = 6 x 3 =18 feet

ribbon used = 18 -2 = 16 feet

Someone PLease help me

Answers

I’m pretty sure the answer is the last one. Playing football and soccer combined. If you look really closely you can see playing the piano takes up 1/4 of Brad’s time. And if you combine football and soccer you get about 1/4. Hope this helps

Which side lengths form a right triangle?

Answers

Answer:

Answer:[tex] \huge\mathfrak\pink{S} \huge\mathfrak\purple{o} \huge\mathfrak\blue{l} \huge\mathfrak\red{u} \huge\mathfrak\green{t} \huge\mathfrak\pink{i}\huge\mathfrak\purple{o}\huge\mathfrak\red{n}\huge\mathfrak\orange{➔}\ [/tex] Pythagoras law:h²=p²+b²

needed to apply

4²+√8²=24²

24≠576

not a right angled triangle

again

5²+√5²=5²

50≠25

side are not a right angled triangle

again

4²+7.5²=(8.5)²

72.25=72.25

side are a right angled triangle

What is sec 0 when cot 0 = -4/2?

Answers

Answer:

[tex]sec 0=\frac{\sqrt{66} }{8}[/tex]

Step-by-step explanation:

[tex]Cot0=-4\sqrt{2}[/tex]

[tex]sec0=\frac{\sqrt{33} }{4\sqrt{2} }[/tex]

[tex]=\frac{\sqrt{33} }{4\sqrt{4} } *\frac{4\sqrt{2} }{4\sqrt{2} }[/tex]

[tex]=\frac{4\sqrt{66} }{32}[/tex]

[tex]=\frac{\sqrt{66} }{8}[/tex]

--------------------

hope it helps...

have a great day!!

A psychologist has designed a questionnaire to measure individuals' aggressiveness. Suppose that the scores on the questionnaire are normally distributed with a standard deviation of 80. Suppose also that exactly 15% of the scores exceed 700. Find the mean of the distribution of scores. Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place.

Answers

Answer:

The mean score is of 617.4.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Suppose that the scores on the questionnaire are normally distributed with a standard deviation of 80.

This means that [tex]\sigma = 80[/tex]

Suppose also that exactly 15% of the scores exceed 700.

This means that when X = 700, Z has a pvalue of 0.85. So X when X = 700, Z = 1.033. We use this to find [tex]\mu[/tex]

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.033 = \frac{700 - \mu}{80}[/tex]

[tex]700 - \mu = 80*1.033[/tex]

[tex]\mu = 700 - 80*1.033[/tex]

[tex]\mu = 617.4[/tex]

The mean score is of 617.4.

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