What is the wavelength of a sound wave
with a speed of 331 m/s and a frequency
of 500 Hz?

Answers

Answer 1

Answer:

0.777m

Explanation:

The sound wave has a wavelength of 0.773m.

Explanation:

To solve this problem we have to use the wave equation that is given below:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for  

λ :

λ = v f

Let's plug in our given values and see what we get!

λ = 340 m s

440 s − 1

λ = 0.773 m

Hope this helps, Mark as brainliest if u want

Answer 2

The wavelength of the sound wave is 0.662 m.

Explanation:

Given that,

The speed of a sound wave, v = 331 m/s

The frequency of the wave, f = 500 Hz

To find,

The wavelength of the sound wave.

Solution,

The speed of wave in terms of wavelength and frequency is given by :

[tex]v=f\lambda[/tex]

Where

[tex]\lambda[/tex] is the wavelength

Rearranging for [tex]\lambda[/tex],

[tex]\lambda=\dfrac{v}{f}[/tex]

Put all the values,

[tex]\lambda=\dfrac{331}{500}\\\\\lambda=0.662\ m[/tex]

So, the wavelength of the sound wave is 0.662 m.

Reference,

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Related Questions

who won the 2020-2021 Nfl Mvp Award

Answers

Answer:

During a star-studded but socially safe ceremony for the 10th Annual NFL Honors, Green Bay Packers quarterback Aaron Rodgers earned the prestige of being the 2020 NFL Most Valuable Player (MVP).

Which is used to zero a triple beam balance
A.
the pan
B.
a rider
C.
a beam
D.
the tare knob

Answers

The answer is the sliders on the valence beam when the pan is empty

What is the color of lava at its hottest? Help asap

Answers

yellow !!!!!!!!!!!!!!!!

Which of the following ways of writing 1000w is incorrect?
1) 1 kW
2) 1 x 10³ W
3) 10 x 10³ W
4) 1.0 x 10³ W

Answers

Answer:

the third one is incorrect

Explanation:

10 x 10³= 10^1 x 10^3 = 10^4

Question 5 of 10
What are two things that happen when a home computer scanner uses
electromagnetic waves?
A. Red light shines on patterns of black and white, recording the
pattern of reflected light.
B. Objects are exposed to X-rays, which either pass through or are
absorbed by the objects.
C. A silicon chip releases electrons by the photoelectric effect,
producing an image.
D. A charge-coupled device captures visible light that is reflected off
an object

Answers

Answer: B. Objects are exposed to X-rays, which either pass through or are

absorbed by the objects.

C. A silicon chip releases electrons by the photoelectric effect,

producing an image.

Explanation:

answer is bbbbbbbbbb

A roller coaster has a mass of 250 kg,
and is 50 meters above the ground, what
is the potential energy?

Answers

Potential Energy = mass x gravity x height
PE = mgh
PE = 250kg x 9.8 m/s^2 x 50m
PE = 118,750 joules = 118kJ

A roller coaster has a mass of 250 kg, and it is 50 meters above the ground, then the potential energy will be equal to 122.5 KJ.

What is Potential energy?

Potential energy is a type of energy stored that depends on the interaction between various substances. A spring's energy rises when it is crushed or expanded. A steel ball has more energy stored if it is lifted just above the floor as contrasted to dropping to the ground. As raised, it can do greater labor.

Instead of being a property of specific entities or atoms, potential energy is a property of systems. For instance, a system made up of Earth and the raised ball has far more stored energy as they move apart.

In system components, where the configurations, or spatial arrangements, dictate the magnitude of the forces that apply against one another, potential energy arises.

From the data given in the question,

Mass, m = 250 kg

Height, h = 50 meters and,

g = 9.8 m/s²

[tex]Potential energy(PE)=mgh[/tex]

PE = 250 × 50 × 9.8

PE = 122500 J or,

PE = 122.5 KJ.

To know more about Potential energy:

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Imagine you leave the dock on a fishing boat that travels east for 30 kilometers when the captain realizes he left the fishing rods on the dock. It takes him 40 minutes to travel out against the current but only 20 minutes to return to the dock.

Answers

Answer:

Average speed is 60 km/hr whereas average velocity is 0 km/ hr.

Explanation:

The average speed of the boat is 60 km/ hr while on the other hand, the average velocity of the boat is 0 km/ hr because average speed is the total distance covered by the boat in total time and average velocity is the displacement covered by the boat in total time. The total distance covered by the boat is 60 km and the total time is 60 minutes which is equals to one hour so the answer is 60 km/hr whereas the displacement is the shortest distance between initial and final position which is 0 in this case so 0 divided by 60 minutes or one hour is also 0.

7. Thermal energy depends upon the______ and _____ of an object?

Answers

:

Please give me brainly,

The thermal energy of an object depends on three things: 4 the number of molecules in the object 4 the temperature of the object (average molecular motion) 4 the arrangement of the object's molecules (states of matter). The more molecules an object has at a given temperature, the more thermal energy it has.

Mass and Temperarture

I am pretty sure that is right if Not sorry

Have a great day.

Define the term kinetic frictional force​

Answers

Answer:Kinetic friction is defined as a force that acts between moving surfaces. A body moving on the surface experiences a force in the opposite direction of its movement. The magnitude of the force will depend on the coefficient of kinetic friction between the two material.

Explanation:

The semi-major axis of this ellipse is 8.8 cm, and the distance from one of the foci to the
center is 4.4 cm. What is the eccentricity of the ellipse?

Answers

The eccentricity is 0.5

Is sodium chloride a reactant

Answers

Answer:

yes it is a reactant

how do you select the appropriate tools for caregiving rated task effectively?​

Answers

Answer:

Care giving tools like medical devices or any medical supplies which aid the effectiveness of care for the patient will help the quality of work of care giving. ... All of the care giving tool should also be efficient and effective

is there a photo or a passage for this question?

John has an object suspended in the air. It has a mass of 50 kilograms and is 50 meters above the ground. Calculate the object's potential energy?

Answers

Answer is: 24500 J.
m(object) = 50 kg.
h(object) = 50 m.
g = 9,8 m/s².
E(object) = m·g·h.
E(object) = 50 kg · 9,8 m/s² · 50 m.
E(object) = 24500 N·m = 24500 J = 24,5 kJ.
g - the acceleration of free fall.
mg - weight of the object.

A man's higher initial acceleration means that a man can outrun a horse over a very short race. A simple - but plausible - model for a sprint by a man and a horse uses the following assumptions: The man accelerates at 6.0 m/s2for 1.8 s and then runs at a constant speed. A horse accelerates at a more modest 5.0 m/s2 but continues accelerating for 4.8 s and then continues at a constant speed. A man and a horse are competing in a 200 m race. The man is given a 100 m head start, so he begins 100 mfrom the finish line.

How much time does it take the man to finish the race? The horse? Who wins?

Answers

Answer:

 t_man = 10.16 s,   t_horse = 10.73 s,  the winner is the man

Explanation:

To solve this problem we are going to find the time of each one separately.

Man we look for distance and time during acceleration

         x₁ =  v₀ t₁ + ½ a₁ t₁²

as it comes out of rest its initial velocity is zero

        x₁ = ½ a₁ t₁²

        x₁ = ½ 6.0 1.8²

        x₁ = 9.72 m

at this point its speed is

        v₁ = v₀ + a t

        v₁ = 0 + 6  1.8

        v₁ = 10.8 m / s

From here on it continues at constant speed, the distance that the man needs to travel from the point where the man leaves at 100m is

        x₂ = 100 - x₁

        x₂ = 100- 9.72

        x₂ = 90.28 m

the time for this part is

        v₁ = x₂ / t₂

         t₂ = x₂ / v₂

         t₂ = 90.28 / 10.8

         t₂ = 8.36 s

the total time for the man is

        t_man = t₁ + t₂

        t _man = 1.8 + 8.36

        t_man = 10.16 s

We repeat the calculation for the horse

distance traveled during the acceleration period

         x₃ = v₀ t + ½ a₂ t₃²

as part of rest its initial velocity is zero

        x₃ = ½  a₂ t₃²

        x₃ = ½  5.0  4.8²

        x₃ = 57.6 m

the velocity at this point is

         v₃ = v₀ + a₂ t₃

         v₃ = 0 + 5  4.8

         v₃ = 24 m / s

the rest of the route is at constant speed, the remaining distance

         x₄ = 200 - x₃

         x₄ = 200 - 57.6

         x₄ = 142.4 m

the time to go through it is

         t₄ = x₄ / v₃

         t₄ = 142.4 / 24

         t₄ = 5.93 s

the total time for the horse is

         t_horse = t₃ + t₄

         t_horse = 4.8 + 5.93

         t_horse = 10.73 s

when we compare the times we see that the man arrives a little before the horse, the winner is the man

A 20-gram bullet traveling at 250 m/s strikes a block of wood that weighs 2 kg. With what velocity will the block and bullet move after the collision? [convert g to kg]

Answers

Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

velocity of the bullet, v₀ = 250 m/s

mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

5 + 0 = v(2.02)

5 = 2.02v

v = 5/2.02

v = 2.48 m/s

Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

Can someone please help me with science.

Answers

On the dog's return trip (between t = 10 and t = 12.5 seconds), the slope of the position function is steeper than during the first 5 seconds, which means the dog ran home faster. The only option that captures this is D.

You can check to make sure that the dog indeed runs twice as fast on the return trip. The slope of the position function during the first 5 seconds is

(change in position) / (change in time) = (5 - 0) / (5 - 0) = 5/5 = 1

while during the return trip, it is

(0 - 5) / (12.5 - 10) = -5/2.5 = -2

Ignoring the sign (which only indicates the direction in which the dog was running), we see that the dog's speed on the return trip was indeed twice as high as during the first 5 s.

A 2.0 kg sphere with a velocity of 6.0 m/s collides head-on and elastically with a stationary 10 kg sphere

Answers

Question: A 2.0 kg sphere with a velocity of 6.0 m/s collides head-on and elastically with a stationary 10 kg sphere, What is thier velocities after collision.

Answer:

v = 6 m/s, v' = 0 m/s

Explanation:

From the question,

For Elastic collision,

mu+m'u' = mv+m'v'......................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, v = final veolocity of the first sphere, v' = final velocity of the second sphere.

Also,

The relative velocity before collision = relative velocity after collision

u-u' = v-v'............................ Equation 2

Given:  m = 2 kg, m' = 10 kg, u = 6 m/s, u' = 0 m/s

Substitute into equation 1 and 2

2(6)+10(0) = 2v+10v'

2v+10v' = 12.............. Equation 3

6-0 = v-v'

v-v' = 6 ................... Equation 4

Solve equation 3 and 4 simultaneously.

v = 6+v'............. Equation 5

Substitute equation 5 into equation 3

2(6+v')+10v' = 12

12+2v'+10v' = 12

12v' = 12-12

v' = 0/12

v' = 0 m/s.

Also substitute the value of v' into equation 5

v = 6+0

v = 6 m/s

Energy can come from electricity, but it
can also come from water
false
true

Answers

Answer:

the answer is truth

Explanation:

Answer:

I think it might be true...

If spring has a spring constant of 500 N/m and is stretched .50 meters,how much energy is stored in the spring ((show work for full credit, show equation))

Answers

Answer:

The energy stored is: 62.5 Joules

Explanation:

Given

[tex]k = 500N/m[/tex] --- spring constant

[tex]x = 0.5m[/tex] --- stretch

Required

The amount of energy

This is calculated as:

[tex]U = \frac{1}{2} kx^2[/tex]

[tex]U = \frac{1}{2} * 500N/m * (0.5m)^2[/tex]

[tex]U = 250N/m * (0.5m)^2[/tex]

[tex]U = 62.5\ J[/tex]

Please help please real quick

Answers

Answer:

1. (a) The final velocity is 20 m/s

(b) The distance travelled is20 meters

2. The distance travelled by the train in the 30 seconds is 825 meters

3. The most correct option is;

(d) 53 km

4. The heat, developed by the electric iron is 15,000 joules

5. a) In the first network the resistance between A and B is 2 Ω

b) In the second network the resistance between A and B is 4Ω

c) In the third network the resistance between A and B is 6Ω

d) In the fourth network the resistance between A and B is 2Ω

Explanation:

1. (a) The parameters of the cheetahs motion are;

The initial motion (velocity) of the cheetah = 0 m/s (The cheetah starts from rest)

The acceleration of the cheetah, a = 2 m/s²

The duration of the acceleration of the cheetah, t = 10 seconds

The kinematic equation of the motion of uniform acceleration, of the cheetah can be written in the following form;

v = u + a·t

s = u·t + 1/2·a·t²

Where;

v = The final velocity

u = The initial velocity = 0 m/s

a = The acceleration of the cheetah = 2 m/s²

s = The distance traveled

∴ v = 0 + 2 × 10 = 20

The final velocity, v = 20 m/s

(b) From s = u·t + 1/2·a·t², we have;

s = 0 × 10 + 1/2 × 10 × 2² = 20

The distance travelled, s = 20 meters

2. The given details of the motion of the train are;

The initial velocity of the train, u = 20 m·s⁻¹

The acceleration of the train, a = 0.5 m·s⁻²

The duration of the train's acceleration, t = 30 seconds

Therefore, the distance travelled, 's', is given by; s = u·t + 1/2·a·t²

∴ s = 20 × 30 + (1/2) × 0.5 × 30² = 825

The distance travelled by the train in the 30 seconds, s = 825 meters

3. The given distance the truck covers with the average speed of 80 km/h, d₁ = 40 km

The distance the truck then covers with the average speed of 40 km/h, d₂ = 40 km

[tex]Average \ speed = \dfrac{Total \ distance}{Time}[/tex]

[tex]\therefore time, \, t = \dfrac{Total \ distance}{Average \ speed}[/tex]

The time it takes the truck to cover the 40 km at 80 km/h = 40 km/(80 km·h) t₁ = 0.5 hour

The time it takes the truck to cover the 40 km at 80 km/h = 40 km/(40 km·h) t₂ = 1 hour

The total time taken to cover both 40 km distances, t = t₁ + t₂

∴ The total time taken to cover both 40 km distances, t = (0.5 + 1) hour = 1.5 hours

The total distance covered at both speeds, d = d₁ + d₂

∴ d = 40 km + 40 km = 80 km

The average speed of the truck for the total distance, [tex]v_{average}[/tex] = d/t

∴ [tex]v_{average}[/tex] = 80 km/1.5 hours = 53.[tex]\overline 3[/tex] km/h ≈ 53 km/h

The average speed of the truck for the total distance, [tex]v_{average}[/tex] ≈ 53 km/h

The correct option is (d) 53 km

4. The heat, 'H', developed by the electric iron is given by the following formula;

H = I²·R·t

Where;

I = The current flowing in the electric iron = 5 A

R = The resistance of the iron = 20Ω

t = The time duration of the flow of the current = 30 s

∴ H = (5 A)² × 20 Ω × 30 s = 15,000 joules

The heat, developed by the electric iron, H = 15,000 joules

5. Let 'R' represent the resistance between A and B in each network

a) For the first network, we have;

1/R = 1/(2 + 2) + 1/(2 + 2) = 1/4 + 1/4 = 1/2

∴ R = 2 Ω

∴ The resistance between A and B is 2 Ω

b) For the second network, we have;

R = 1/(1/2 + 1/2) + 3 = 4

R = 4Ω

∴ The resistance between A and B is 4 Ω

c) For the third network, we have;

R = 2 + 1/(1/4 + 1/4) + 2 = 6

R = 6Ω

∴ The resistance between A and B is 6 Ω

d) For the fourth network, we have;

R = 1/(1/2 + 1/2) + 1/(1/2 + 1/2) = 2

R = 2Ω

∴ The resistance between A and B is 2 Ω

The equivalent resistance in a series circuit is found by ____
the resistances of all the resistors.

A. multiplying
B. comparing
C. adding the reciprocals of
D. adding​

Answers

Explanation:

In a series circuit the equivalent resistance is the algebraic sum of the resistances.

takes 5 seconds and 2,000 J for a crane to lift a very heavy object. Which of these correctly describes power and energy for this action?

2,000 J of energy was converted into some other energy, requiring 10,000 W of power.
2,000 J of energy was converted into some other energy each second, requiring 400 W of power
2,000 J of power was converted into 400 W of energy.
2,000 J of power was converted into some other power every second, requiring 10,000 W of energy.

Answers

A crane takes 5 s and 2,000 J to lift an object. That is, 2,000 J of energy was converted into some other energy each second, requiring 400 W of power.

What is power?

In physics, power is the amount of energy transferred or converted per unit time.

A crane uses 2,000 J of energy (E) to perform work (W) is 5 s (t). Let's calculate the power used (P).

P = W / t = 2,000 J / 5 s = 400 W

Which of these correctly describes power and energy for this action?

2,000 J of energy was converted into some other energy, requiring 10,000 W of power. No, the required power was 400 W.2,000 J of energy was converted into some other energy each second, requiring 400 W of power. Yes.2,000 J of power was converted into 400 W of energy. No, energy cannot be converted into power.2,000 J of power was converted into some other power every second, requiring 10,000 W of energy. No, the required power was 400 W.

A crane takes 5 s and 2,000 J to lift an object. That is, 2,000 J of energy was converted into some other energy each second, requiring 400 W of power.

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A Yellow Giant is a luminous giant star of approximately 85 times brighter than the surface of the Earth’s Sun. The color is Orange and have a surface temperature of 5400 K. True or false? Answer Fast Please.

Answers

Answer:

the statement is FALSE

Explanation:

To answer this question we use that thermodynamic energy is

           E = K T

also according to the Planck relation

          E = h f

the speed of light et related to frequencies and wavelength

          c = λ f

          f = c /λ

we substitute

           hc /λ = KT

           λ= hc / k T

calculate us

           lam = 6.62 10⁻³⁴ 3 10⁸ / 1.381 10⁻²³ 5400

           lam = 2,663 10⁻⁸ m

let's reduce to num

         lam = 2,663 10  

         lam = 26,63 nm

This wavelength is in the farultraviolet, therefore the statement is FALSE

1. What is the magnitude of the force on a charge of +40 μC that is 0.6 m from a charge of - 80 μC?

Answers

Answer:

The magnitude of the force is 79.893 N.

Explanation:

The magnitude of the electrostatic force between the two particles is determined by Coloumb's Law, whose formula is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex] (1)

Where:

[tex]\kappa[/tex] - Electrostatic constant, in newtons-square meters per square coulomb.

[tex]q_{A}, q_{B}[/tex] - Electric charges, in coulombs.

[tex]r[/tex] - Distance, in meters.

If we know that [tex]\kappa = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}[/tex], [tex]q_{A} = +40\times 10^{-6}\, C[/tex], [tex]q_{B} = - 80\times 10^{-6}\, C[/tex] and [tex]r = 0.6\,m[/tex], then the magnitude of the force is:

[tex]F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}[/tex]

[tex]F = 79.893\,N[/tex]

The magnitude of the force is 79.893 N.

If a body carries a charge of +3 C, then which of the following is true?
а) It has an excess of 4.8 x 10^19 electrons
b) It has an excess of 1.87 x 10^19 electrons *1019
C) It is deficit of 1.87 x 10^19 electrons
d) It is deficit of 4.8 x 10^19 electrons​

Answers

Answer: C) it is deficit of 1.87 x 10^19 electrons

Explanation:

A car hits a wall with a force of 80 N and
has a mass of 4.5 kg. What was the
acceleration of the car?

Answers

Formula for acceleration: A=Force/Mass
A=F/M
A=80N/4.5kg
A=17.7 m/s^2

Unit for A is meters per second (m/s^2)
Hope this helps :)

Which of the following best describes the circuit shown below?

A. Short
B. Combination
C. Series
D. Parallel

Answers

Answer:

The answer is C. Series.

Which of the following skills that you learn while participating in a team sport is also a life skill that employers look for?
A.
Showing respect to others
B. Working well with others
c.
Problem solving
D
All of the above

Answers

Answer:

The answer is all of the above

Explanation:

Answer:

D

Explanation:

a transfer of energy without a transfer of mass describes what?

Answers

Explanation:

Wave motion

ex...longitudinal wave.

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.48 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1840 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.19 V/m, (b) in the negative z direction and has a magnitude of 5.19 V/m, and (c) in the positive x direction and has a magnitude of 5.19 V/m

Answers

Answer:

a)   F = 15.6 10⁻¹⁹  k^   N,  b)  F = -1  10⁻¹⁹  k^   N,

c)  F = (8.3 i^ + 73 k^) 10⁻¹⁹ N

Explanation:

In this exercise we calculate the magnetic and electric force separately.

Let's start by calculating the magnetic force

       F_m = q v x B

where bold letters indicate vectors, the modulus of this expression is

       F_m = q v B

the direction is given by the right hand rule, where the thumb points in the direction of velocity, the fingers are extended in the direction of the magnetic field and the palm is in the directional ne force if the charge is positive

let's calculate the magnitude

      F_m = 1.6 10⁻¹⁹  1840  2.48 10⁻³

      F_m = 7.3 10⁻¹⁹ N

we calculate the direction, the thumb is in the direction of + y,

fingers extended in the direction of -ax

the palm remains + z

therefore the magnetic force is in the direction of the positive side of the z axis

The electric force is

        F_e = q E

give several possibilities for the electric field

a) electric field E = 5.19 V / m in the direction of + z

we calculate

        F_e = 1.6 10⁻¹⁹ 5.19

        F_e = 8.3 10⁻¹⁹ N

the total force is

       F = F_m + F_e

       F = (8.3 k ^ + 7.3 k ^) 10⁻¹⁹

       F = 15.6 10⁻¹⁹  k^   N

b) in the -z direction

       F_e = -8.3 10⁻¹⁹ k^   N

       F = Fm + Fe

       F = (-8.3 k ^ + 7.3 k ^) 10⁻¹⁹

       F = -1  10⁻¹⁹  k^   N

c) in the + x direction

       F_e = 8.3 10⁻¹⁹  i^   N

the total force is

       F = (8.3 i^ + 73 k^) 10⁻¹⁹ N

Other Questions
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