What must be the reaction force when someone hits a tree with an axe?

Answer:

c and d

Explanation:

obviously kksxsxksxkskxkskxksxksxsxsxsxsxsxsxs

Answer:

3012.012m

Explanation:

s=it +1/2(10.8)(16.7)^2

Answer:

The final translational seed at the bottom of the ramp is approximately 4.84 m/s

Explanation:

The given parameters are;

The radius of the sphere, R = 2.50 cm

The mass of the sphere, m = 4.75 kg

The translational speed at the top of the inclined plane, v = 3.00 m/s

The length of the inclined plane, l = 2.75 m

The angle at which the plane is tilted, θ = 22.0°

We have;

[tex]K_i[/tex] + [tex]U_i[/tex] = [tex]K_f[/tex] + [tex]U_f[/tex]

K = (1/2)×m×v²×(1 + I/(m·r²))

I = (2/5)·m·r²

K =  (1/2)×m×v²×(1 + 2/5) = 7/10 × m×v²

U = m·g·h

h = l×sin(θ)

h = 2.75×sin(22.0°)

∴ 7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) = 7/10 × 4.75×[tex]v_f[/tex]² + 0

7/10×4.75×3.00² + 4.75×9.81×2.75×sin(22.0°) ≈ 77.93

∴ 77.93 ≈ 7/10 × 4.75×[tex]v_f[/tex]²

[tex]v_f[/tex]² = 77.93/(7/10 × 4.75)

[tex]v_f[/tex] ≈ √(77.93/(7/10 × 4.75)) ≈ 4.84

The final translational seed at the bottom of the ramp, [tex]v_f[/tex] ≈ 4.84 m/s.

Answer:

14 years

Explanation:

because the light will take four years to reach the earth. And the star is four light years away from the earth.

An imaginary star is four light years from earth. The star has a planet, upon which a large mirror has been installed. The mirror faces earth. A ten year old boy aims his telescope at the mirror,then the boy would be 14 years old when he will see his own reflection.

It can be defined as the distance travelled by the light in one year .it is represented in units of distance such as miles or km.

1 light year is calculated by multiplying the speed of light with the time of one year

1 light year = speed of light × one year time period

1 light year = 3×10⁸ ×(365×24×60×60)

                  =9.461× 10¹⁵ meter

As given in the problem 10 year old boy aims his telescope at the mirror which is 4 light years away then the light has to travel four years to reach the boy ,then the boy would be 14 year old when he would see his own reflection.
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Answer:

Uniform motion is a type of motion that is characterized as the motion of an object wherein the object moves in a straight line and its velocity remains unchanged along that line, regardless of the duration of time, as it occupies equal distances at equal time interval and Non-uniform motion is described as the motion of an object wherein the object moves at different speeds and does not cover the same distance at equal time intervals, regardless of the duration of the time interval.

Answer:

hope it's help you

Explanation:

In Uniform motion, the movement of a body is along the straight line with constant speed. In non uniform motion, the movement of a body is along the straight line with variable speed. In uniform motion, the body covers equal distance in an equal interval of time.

Explanation:

Could you also show the diagram

The average acceleration of the bike is 2.2 m/s²

Acceleration, rate at which velocity changes with time, in terms of both speed and direction.

A point or an object moving in a straight line is accelerated if it speeds up or slows down.

According to the question,

Given, initial velocity, u=3.0m/s and final velocity v=8.5 m/s

Time = 2.5 seconds

If a be the acceleration.

a = [tex]\frac{v-u}{t}[/tex]

a = [tex]\frac{8.5 - 3.0}{2.5s}[/tex]

⟹ a=2.2 m/s²

So, The average acceleration of the bike is 2.2 m/s²

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Answer:

electric current=ampere(A)

force=Newton (N)

area=metres square(m^2)

power=watt(w)

density=kg/m3 

amount of substance =mole per cubic meter (mol/m3).

volume=cubic meter (m3),

Answer:

thanks for brainlist brother.........

The property that the elements in each column of the representative elements series of the periodic table have in common is: number of valence electrons.

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.

Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

Periodic table is an organized tabular array of all the chemical elements arranged in order of increasing atomic number (in rows).

Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.

In the periodic table, chemical elements that are having the same number of valence electrons are found in the same column.

This ultimately implies that, all the chemical elements such as Hydrogen, Sodium, etc., with one (1) valence electrons in their outermost shell (S-orbital) are found in the first (1st) column of the periodic table.

In conclusion, property that the chemical elements in each column of the representative elements series of the periodic table have in common is number of valence electrons.

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Explanation:

M₂ = Fr²/GM₁

M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]

M₂ = (7.79N*m²)/(7.84*10^-7N*m²)

M₂ = 9.94*10^6 kg

Answer:

It means that person can do work or can posses energy at a rate of 550 watts.

Or : can posses energy of 550 joules in one second.

Explanation:

[tex]{ \bf{power = \frac{work}{time} }}[/tex]

The frequency of the wave for the stone thrown in the pond is 0.5Hertz.

The question does not specify what to calculate but we can look for the frequency of the wave.

Frequency is the number of oscillations completed in one second. This is interpreted as:

x oscillations = 1second

If Five waves were made from the same source in 10 seconds for a stone that is thrown inside the pond, then:

5 oscillations = 10seconds

Divide both expressions to get x (the required frequency)

x/5 =1/10

Cross multiply

10x = 5

Divide both sides by 10

10x/10 = 5/10

x = 1/2

x = 0.5Hertz

Hence the frequency of the wave is 0.5Hertz.

NB: The period of the wave is simply the reciprocal of the frequency.

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Answer:

1845.26 ?

Explanation:

18.46 × 99.96= 1845.2616 = 1845.26

im not entirely sure though

Answer:

A. Contains DNA

C. Contains ribosomes

F. Lacks a nucleus

Explanation:

Explanation:

If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. ... A changing magnetic field through a coil of wire therefore must induce an emf in the coil which in turn causes current to flow.

Due to the flow of the current run, the coil magnetic field is produced. Magnetic fields result in magnetic force.

The electric force between the two charges is directly propotional to the product of the charge and inversly propotional to the square of the distance between them.

A current will be generated in a wire coil if it is put in a changing magnetic field. As a result, a changing magnetic field through a coil of wire must create an emf in the coil, causing the current to flow.

A current is induced in a coil of wire when it is put in a changing magnetic field. Something generates an electric field that drives the charges around the wire, causing the current to flow.

Hence due to the flow of the current in the coil magnetic field is produced.

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(a) The recoil or backward velocity of the gun is 8 m/s.

(b) The bullet cannot penetrate the plank of the wood completely.

The given parameters include;

(a) The backward or recoil velocity of the gun is calculated by applying the principle of conservation of linear momentum.

m₁u₁  + m₂u₂ = 0

m₂u₂ = -m₁u₁

[tex]u_2 = -\frac{m_1u_1}{m_2} \\\\u_2 = - \frac{0.1 \times 400}{5} \\\\u_2 = -8 \ m/s[/tex]

Thus, the recoil or backward velocity of the gun is 8 m/s.

(b) determine if the bullet can penetrate the plank of the wood completely

the acceleration of the bullet is calculated as;

v² = u₁² + 2as

2as = v² - u²

[tex]a = \frac{v^2 -u_1^2}{2s} \\\\a = \frac{(266.67)^2 -(400)^2}{2\times 0.04} = -1.111 \times 10^6 \ m/s^2[/tex]

Finally, determine the distance traveled by the bullet when it comes to a complete stop, that is the final velocity = 0

[tex]v_f^2 = v^2 + 2ad\\\\2ad = v_f^2 - v^2\\\\d = \frac{v_f^2 - v^2}{2a} \\\\d = \frac{(0) - (266.67)^2}{2(-1.111\times 10^6)} \\\\d = 0.032 \ m[/tex]

d = 3.2 cm

The total distance traveled by the bullet inside the plank = 4 cm + 3.2 cm = 7.2 cm

Therefore, the bullet cannot penetrate the plank completely.

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Answer: I hope you find it useful

Explanation: Group 2 elements have two valence electrons. The two valence electrons are easily lost in the formation of chemical bonds. Once the two electrons are lost, the atom then has a full outer shell and is therefore more stable.

so,  if an atom has valency 2 , then it means that the atom can combine with 2 other atoms .

Answer:

Normal force

Explanation:

Calculating :-

We know

[tex]\boxed{\sf F_c=\dfrac{mv^2}{r}}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{2000}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=500N[/tex]

Answer:

Mercury is the only one in liquid state at room temperature

Answer:

The mechanical energy of the cardboard box, M.E. = K.E. + P.E.

Where;

P.E. = The potential energy of the cardboard box = m·g·h

K.E. = The kinetic energy of the cardboard box = (1/2)·m·v²

Where;

m = Mass of the cardboard box

g = The (constant) acceleration due to gravity ≈ 9.81 m/s²

h = The height of the cardboard box

v = The velocity of the cardboard box

At the top of the fall, where h = The height of the platform = [tex]h_{platform}[/tex], and v = 0 (the box is initially at rest at the top), the M.E. is given as follows;

[tex]M.E._{top}[/tex] = P.E. + K.E. = m·g·[tex]h_{platform}[/tex] + (1/2) × m × 0² = m·g·[tex]h_{platform}[/tex]

However, at the bottom of the fall, the height of the box, h = 0, the velocity of the box, v = 0, therefore, the total energy at the bottom, after the box comes to rest, [tex]M.E._{bottom}[/tex] = 0

Therefore;

The total energy of the box at the top of the fall, .[tex]M.E._{top}[/tex] = m·g·[tex]h_{platform}[/tex] was more than the total energy of the box at the bottom of the fall,

[tex]M.E._{bottom}[/tex] = 0

Explanation:

Answer:

A

The upthrust on a floating body is in upwards direction and is equal to the weight of the liquid displaced

B

The upthrust is directly proportional to the density of the liquid in which the solid is immersed

C

The upthrust is directly proportional to the volume of the fluid displaced by a solid

The upthrust acts on the body in upward direction at the center of buoyancy.

Upthrust is equal to the weight of liquid displaced by object and weight of liquid will depend on its density.

Upthrust is F=Vρg ,where V is the volume of liquid displaced and ρ is the density of fluid.

The total lateral pressure acting on an immersed object on one side is equal and in opposite direction to the total lateral pressure acting on the other side.

Answer:

The laws of liquid pressure are  

(i) Pressure inside the liquid increases with the depth from the free surface of the liquid.

(ii) Pressure is same at all points on a horizontal plane, in case of stationary liquid.

(iii) Pressure is same in all directions about a point inside the liquid.

(iv) Pressure at same depth is different in different liquids. It increases with the increase in the density of the liquid.

(v) A liquid will always seek its own level.

A Fluid is any liquid or gas or generally any material that cannot sustain a tangential, or shearing, force when at rest.  

Explanation:

Answer:

Explanation:

(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.

Hence, his average velocity is 300m/150s=2ms^−1

(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.

Therefore, his average speed for this journey is 400m210s=1.9ms−1.

For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.

Hence, his average velocity for this case is 200m/210s=0.95ms^−1

Answer:

5 m/s²

Explanation:

Use the acceleration formula: [tex]a=\frac{v_f-v_i}{t}[/tex]

Based on the information given to us by the prompt, we know:

Substitute these values for the variables to calculate the acceleration:

[tex]a=\frac{30-10}{4}\\\\a=\frac{20}{4}\\\\a=5[/tex]

Therefore, the acceleration of the bus is 5 m/s².

Answer:

hi

Explanation:

pls mark as a BRAINLIST

Answer:

     i =[tex]- \frac{r \ A'}{2 \ rho}[/tex] ,  i =  0.92   A

Explanation:

This exercise asks for the electromotive force, which can be calculated with Faraday's law

          fem = [tex]- \frac{d \Phi_B }{dt}[/tex]

where the magnetic flux

          Ф = B. A

bold letters indicate vectors. We can write this equation

          Ф = B A cos θ

In this case the magnetic field is perpendicular to the page and the normal to the loop of the loop is also parallel to the page, therefore the angle is zero and the cosine is 1

the loop is

          A = π r²

we substitute in the first equation

          fem = - π r² [tex]\frac{dB}{dt}[/tex]

we substitute the values

          fem = -π r² 1

          fem = - π r²

to calculate the current let's use ohm's law

           V = i R

            R = ρ L / A'

where A 'is the area of ​​the wire and L is the length of the loop

            L = 2π r

            V = i (ρ 2π r / A ')

            I = [tex]\frac{V \ A'}{2\pi \ r \ rho}[/tex]

In this case

           V = fem

           I = fem / R            

           i =[tex]- \frac{r \ A'}{2 \ rho}[/tex]

In order to complete the calculation, you need the radius of the loop and / or the wire cutter.

if we assume that the loop has a radius of r = 1 cm = 0.01 m and an area of ​​the wire   A'= π 10⁻⁶ m²   a radius of the wire 1 mm

           i = - 10⁻² π 10⁻⁶ / ( 2 1.7 10-8)

           i =  0.92   A