What number, divided by 3/7 , will result in a value of 2 1/3?

Answers

Answer 1
bro you still in school??

Related Questions

PLEASE HELP! PLEASE SHOW WORK
Use the following expression to answer this three part question:
f(x) = 2x2 + 4x − 6

Part A: What are the x-intercepts of the graph of f(x)? Show your work.

Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work.

Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph.

Answers

Answer:

Step-by-step explanation:

The graph of a quadratic function is a U-shaped curve called a parabola. One important feature of the graph is that it has an extreme point, called the vertex. If the parabola opens up, the vertex represents the lowest point on the graph, or the minimum value of the quadratic function.

Write down five numbers so that:the mean is 6,the median is 5 and the mode is 4

Answers

Answer:

4 , 4 , 5 , 6 , 11

Step-by-step explanation:

Mode = 4

So at least two times 4 should be there in the data.

And median is 5. So the middle term ( 3rd term} should 5.

Let x and y be the 4th term and 5th term

Data set:

4 , 4 , 5 , x , y

Mean =6

[tex]\frac{4+4+5+x+y}{5}=6\\[/tex]

4+4+5 +x + y = 6*5

13 + x + y = 30

     x + y = 30 - 13

     x + y = 17

x ,y can be any numbers that sum up to 17.

x , y  can be  10 , 7   or  6, 11

Data set: 4 , 4 , 5 , 6, 11

instructions: state what additional information is required in order to know that the triangle in the image below are congruent for the reason given.

Given: AAS

Answers

Answer:

QP ≈ HG

Common side between those angles are QP and HG

so, they should be congruent to prove AAS

Answered by GAUTHMATH

Jack plants a vegetable garden. The garden is the shape of a rectangle. He wants to put a fencing around the entire garden

Answers

Step-by-step explanation:

you need to find the lenght and breadth of the rectangle

During a month, the average temperature in day time of a placewas 430C. The average temperature during night was recorded to be -30C. Find the difference between the average day temperature and the average night temperature.

Answers

Answer:

Difference between average day temperature and average night temperature = 70°

Step-by-step explanation:

Given;

Average day temperature = 43° C

Average night temperature = -30° C

Find:

Difference between average day temperature and average night temperature

Computation:

Difference between average day temperature and average night temperature = Average day temperature - Average night temperature

Difference between average day temperature and average night temperature = 43 - (-30)

Difference between average day temperature and average night temperature = 70°

what is the value of b in this equation?

A. -20
B. -6
C. 6
D. 20

Answers

Answer:

Step-by-step explanation:

a- 12

b- 2

c- 11

and the next part is

x- 6

y- 18

Answer:

B

Step-by-step explanation:

Using the rules of exponents

[tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]

[tex]a^{-m}[/tex] = [tex]\frac{1}{m}[/tex]

Then

[tex](y^b)^{4}[/tex] = [tex]\frac{1}{y^{24} }[/tex]

[tex]y^{4b}[/tex] = [tex]y^{-24}[/tex]

Equate the exponents

4b = - 24 ( divide both sides by 4 )

b = - 6 → C

Será - 12 esta noche. El meteorólogo predice que mañana al mediodía hará 25 ° más de temperatura. ¿Cuál será la temperatura mañana al mediodía?

Answers

Respuesta:

13 °

Explicación paso a paso:

La temperatura de esta noche = - 12

La temperatura prevista para mañana = 25 ° más cálida que la temperatura de esta noche

La temperatura prevista para mañana será;

La temperatura de esta noche + 25 °

Temperatura prevista para mañana = (-12 ° + 25 °)

Temperatura prevista para mañana = 13 °

Choose the smallest number. 3/18 10/3

Answers

Answer:

3/18

Step-by-step explanation:

3/18= 0.16

10/3= 3.33

Answer:

3/18

Step-by-step explanation:

3/18 , 10/3

Simplify it to the smallest size

3/18 , 10/3

1/6 , 10/3

1/6 = 3/18

Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. How many months will it take for the second phone to be less expensive than the first phone?

The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is
.

The solution to the inequality is
.

Sal’s mother would have to keep the second cell phone plan for at least
months in order for it to be less expensive.

Answers

Answer:

It will take 13 months for the second phone to be less expensive than the first phone.

Step-by-step explanation:

Since Sal is trying to determine which cell phone and service plan to buy for his mother, and the first phone costs $ 100 and $ 55 per month for unlimited usage, while the second phone costs $ 150 and $ 51 per month for unlimited usage, to determine how many months will it take for the second phone to be less expensive than the first phone, the following calculation must be performed:

100 + (55 x 10) = 100 + 550 = 650

150 + (51 x 10) = 150 + 510 = 660

100 + (55 x 12) = 100 + 660 = 760

150 + (51 x 12) = 150 + 612 = 762

100 + (55 x 13) = 100 + 715 = 815

100 + (51 x 13) = 150 + 663 = 813

Therefore, it will take 13 months for the second phone to be less expensive than the first phone.

Answer:

1) 100 + 55x > 150 + 51x

2) x > 12.5

3) 13

Step-by-step explanation:

Got it right on Edge :D

1
What is the value of x in the equation x - y = 30, when y = 152
200

Answers

[tex]\displaystyle\bf 1) \ if\ y=152 \Longrightarrow x=30+152=182 \\\\2) \ if \ y =200 \Longrightarrow x=200+30=230\\\\3) \ if \ y=80 \Longrightarrow x=30+80=110\\\\4) \ if \ y=4 \Longrightarrow x=4+30=34 \\\\5)\ if \ y=8 \Longrightarrow x=30+8=38[/tex]

Analyzing Speed Yohan Blake ran the 100-meter race in the 2012 Olympics in 9.75 seconds. Compare the speeds if he ran the 200-meter race in 19.5 seconds. round to the nearest hundredth.​

Answers

Answer:

The two speeds are equal

Step-by-step explanation:

The speed is the distance divided by the time

100 meters / 9.75 seconds = 10.25641026 meters per second

Rounded to the nearest hundredth  10.26 meters per second

200 meters / 19.5 seconds = 10.25641026 meters per second

Rounded to the nearest hundredth  10.26 meters per second

The two speeds are equal

[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]

⠀Analyzing Speed Yohan Blake ran the 100-meter race in the 2012 Olympics in 9.75 seconds.⠀⠀⠀he ran the 200-meter race in 19.5 seconds. round to the nearest hundredth.

[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]

Compare the speeds⠀⠀⠀⠀

[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]

we know that,

[tex]\boxed{\sf{speed=\dfrac{distance}{time}} }[/tex]

In the 100-meter race in the 2012 Olympics he takes 9.75 sec

speed=100/9.75speed =10.2564...speed=10.26

BUTTT,

he ran the 200-meter race in 19.5 seconds.

speed=200/19.5speed=10.2564..speed=10.26

According to the question,

we have to compare the speed

100-meter race in the 2012 Olympics he takes 9.75 sec=200-meter race in 19.5 seconds.

10.26=10.26

the speeds are equal

⠀⠀⠀

[tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]

The two speeds are equal of Yohan Blake.

Calculate the sum of the integers from 52 to 108

Answers

Answer:

4560

Step-by-step explanation:

____ more than 3455 is two hundred seventy -eight thousand five hundred eighty three​

Answers

278, 538 is the answer

Answer:

275 128

Step-by-step explanation:

You have to subtract 3455 from two hundred seventy eight thousand five hundred eighty three(278 583) so you will get the answer 275 128.

278 583-3455=275 128

I'm sure with this answer

to make sure you can add 3455 to 275 128 and you will get the answer as 278 583

Solve for x. Round to the nearest tenth, if necessary.

Answers

Hi there!

1. Trigonometric Ratio

For this question, we will be knowing legs or sides of the right triangle and its ratio. Trigonometric Ratio or Trigonometry is very useful when it comes to solve for legs or sides. Because it has something to do with angles.

Currently, there are 6 Trigonometric Ratios. 2 ratios are the main topic which are sine and cosine. Both can be shortened as sin, cos. While the other 4 ratios are defined by these two ratios.

2. Adjacent, Hypotenuse, Opposite

There are 3 sides in a right triangle. Opposite is a side or length of a triangle that is opposite of a specific angle. For example in the picture. CD is opposite of 65 degrees. ED is opposite of angle C.Adjacent is a leg or we can call it a base of right triangle.Hypotenuse is the longest side of right triangle according to Pythagorean Theorem. It is also the opposite of right angle.

3. Using Cosine Ratio

Cosine Ratio is defined as adjacent to hypotenuse or adjacent/hypotenuse. Since we focus on the 65 degree. We can conclude that the adjacent side is x and the hypotenuse side is 7.

Cosine Ratio is:

[tex] \large \boxed{ \tt{ cos 65 \degree= \frac{x}{7} }}[/tex]

For this part, use the calculator to find the value of cos65 degrees. When you put cos65 degree in a calculator, you should get 0.42261826... round to the nearest tenth as we get 0.4

Hence, the new equation is:

[tex] \large{0.4 = \frac{x}{7} }[/tex]

4. Solve The Equation

The best way to deal with decimal number when solving the equation is to multiply the whole equation by 10. Because we want to turn 0.4 to 4 which will be easier in solving the equation.

[tex] \large{0.4 \times 10 = \frac{x}{7} \times 10} \\ \large{4 = \frac{10x}{7} }[/tex]

Multiply 7 both sides to get rid of the denominator.

[tex] \large{4 \times 7 = \frac{10x}{7} \times 7} \\ \large{28 = 10x}[/tex]

Divide both sides by 10 so we can finally isolate x.

[tex] \large{ \frac{28}{10} = \frac{10x}{10} } \\ \large{ \frac{28}{10} = x}[/tex]

Since the denominator is 10. We can convert to the decimal as 2.8

[tex] \large \boxed{ \tt{2.8 = x}}[/tex]

Because you want the nearest tenth then 2.8 is your answer!

5. Final Answer

x = 2.8

Solve the equation to find a positive value of c: 3^2 + 4^2 = c^2

Answers

Answer:

The answer is c=5,-5

c= -5, 5

3^2 + 4^2 = c^2
9 + 16 = c^2
25= c^2
then you square each side and you should get c= -5, 5

6. The coordinates of the vertices of triangle CDE are C(3, - 2), D(5, 2) , and E(7, 0) The figure is rotated 90about the origin . What are the vertices of the resulting image, Figure C'D'E?

Answers

Answer:

Step-by-step explanation:

if it is rotated in clockwise direction then C'(-2,-3),D'(2,-5),E'(0,-7)

if rotated in anticlockwise direction C'(2,3),D'(-2,5),E'(0,7)

simplify 2a+5b/4+3a+2b/8​

Answers

Answer:

Step-by-step explanation:

Combine like terms

[tex]2a + \frac{5b}{4}+3a + \frac{2b}{8}=2a + 3a +\frac{5b}{4}+\frac{2b}{8}\\\\ = 2a + 3a + \frac{5b}{4}+\frac{b}{4}\\\\= 5a + \frac{5b+b}{4}\\\\= 5a +\frac{6b}{4}\\\\= 5a + \frac{3b}{2}[/tex]

Answer:

[tex]2a+5\frac{b}{4}+3a+2\frac{b}{8}[/tex]

First multiply by 8

[tex]2\cdot8a+5\cdot8\cdot\frac{b}{4}+3\cdot8\cdot a+2\frac{b}{8}\cdot8[/tex]

We multiple and divide where we can

[tex]16a+10b+24a+2b[/tex]

And now it's simple

30a+12b

y = RootIndex 3 StartRoot x EndRoot. y = negative (0.4) RootIndex 3 StartRoot x minus 2 EndRoot
Which of the following describes the graph of the transformed function compared with the parent function? Select all that apply.

Answers

Answer:

- Reflected over the x-axis  

- Compressed by a factor of 0.4.

- Translated 2 units left

Step-by-step explanation:

Given

[tex]y = \sqrt[3]{x}[/tex]

[tex]y' = -(0.4)\sqrt[3]{x-2}[/tex]

Required

The transformation from y to y'

First, y is reflected over the x-axis.

The transformation rule is:

[tex](x,y) \to (x,-y)[/tex]

So, we have:

[tex]y = \sqrt[3]{x}[/tex] becomes

[tex]y' = -\sqrt[3]{x}[/tex]

Next, it was compressed by a scale factor of 0.4

The rule is:

[tex]y' = k * y[/tex]

Where k is the scale factor (i.e. k = 0.4)

So, we have:

[tex]y' = 0.4 * -\sqrt[3]{x}[/tex]

[tex]y' = -(0.4)\sqrt[3]{x}[/tex]

Lastly, the function is translated 2 units left;

The rule is:

[tex](x,y) \to (x-2,y)[/tex]

So, we have:

[tex]y' = -(0.4)\sqrt[3]{x - 2}[/tex]

Answers:

-reflected over the x-axis

-translated 2 units right

-compressed by a factor of 0.4

If (2x - 3) is a factor of mx^2 - 11x - 6, find the other factor.​

Answers

Answer:

(2x - 3) ^2 - 11x - 6

Step-by-step explanation:

What is 1,485÷ 0.09 answer please let me y

Answers

Answer:

16,500

Step-by-step explanation:

Just use a calculator-simple

What do you mean "let me y"?

Answer:

the answer is 16500 or sixteen thousand five hundred

Step-by-step explanation:

:)

Carlos and Maria drove a total of 197 miles In 3.8 hours. Carlos drove the first part of the trip and averaged 55 miles per hour. Maria drove the
remainder of the trip and averaged 47 miles per hour. For approximately how many hours did Maria drive? Round your answer to the nearest tenth if
necessary.

Answers

Answer:

1.5 hours

Step-by-step explanation:

Carlos = x

Maria = y

55x + 47y = 197

x + y = 3.8

x = 3.8 - y

55(3.8 - y) + 47y = 197

209 - 55y + 47y = 197

-8y = -12

y = 3/2 = 1.5

A line has slope 3 and y–intercept 4.

Which answer is the equation of the line?

Answers

Answer:

y= 3x+4

Step-by-step explanation:

Slope-intercept form of an equation is

y=mx+b

m=slope

b=y-intercept

Just plug the values in and you get y=3x+4

What is the value of cose in the diagram below?

Answers

Answer:

[tex]cos \theta = 0.6[/tex]

Step-by-step explanation:

Draw a line from point ( 0.6, 0.8 ) to the X - axis, forming a right triangle with hypotenuse = r = 1 , adjacent = 0.6,  opposite = 0.8

[tex]cos \theta = \frac{adjacent}{hypotenuse} , \ where \ adjacent = 0.6 ,\ hypotenuse \ = r= 1[/tex]

[tex]cos \theta = \frac{0.6}{1}\\\\cos \theta = 0.6\\\\\theta = cos^{-1} \ 0.6\\\\\theta = 53.13^\circ[/tex]

The value of cos θ is,

⇒ cos  θ = 0.6

What is mean by Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Now, We can Draw a line from point ( 0.6, 0.8 ) to the X - axis, forming a right triangle with hypotenuse = r = 1 , adjacent = 0.6,  opposite = 0.8

Hence, We can formulate;

⇒ cos θ = 0.6 / 1

⇒ θ = cos ⁻¹ 0.6

⇒ θ = 53.13°

Thus, The value of cos θ is,

⇒ cos  θ = 0.6

Learn more about the circle visit:

https://brainly.com/question/24810873

#SPJ7

Examine the equation.
-2(-x + 9) = 2(x - 9)

2x - 18 = 2x - 18
This equation has:
1. One solution
2. Infinity many solutions
3. No solution

Answers

Infinity many solutions

Need help on this question asap pleasee :)

Answers

Answer:

1/4

Step-by-step explanation:

Which property of math is the young student learning with the following equation? 3 x (4 + 7) = (3 x 4) + (3 x 7)

Answers

The property of math they are learning is the distributive property

Which of the following is a radical equation?

Answers

Answer:

[tex]\sqrt{x} +3 =13[/tex]

Step-by-step explanation:

A radical equation is any equation in which a variable is under a root. This is the only equation in which x is under the square root, so this is the radical equation.

17.27. How many Social Security numbers (see Exercise 8.12) have their nine digits in strictly increasing order

Answers

Answer:

"10 possibilities" is the appropriate response.

Step-by-step explanation:

The numbers will be:

⇒ [tex]123 \ 456 \ 789[/tex]

Now anyway we commence with right and afterwards remove nine from eight and seeing as maintain the sequence growing.

then,

[tex]012345678[/tex][tex]012345679[/tex][tex]012345689[/tex][tex]012345789[/tex][tex]012346789[/tex][tex]012356789[/tex][tex]012456789[/tex][tex]013456789[/tex][tex]023456789[/tex]

Thus, the above is the correct answer.

URGENT PLS ANSWER QUICKLY​

Answers

Answer:

5 is 14cm . 14 is 2pie r. 6 is 120

Answer:

Question 5 = 14

Question 6 = 120

I hope this helped!

A claim is reviewed for MOHS surgery on the foot that was performed in 1 stage with 6 tissue blocks. The claim was reported with 17311, 17312-51, 17312-51. Is this correct

Answers

Answer:

17311, 17315  

Step-by-step explanation:

Explanation,

Mohs surgery, also known as chemosurgery, created by a general surgeon, Dr. Frederic E. Mohs, is performed to remove complex or ill-defined cutaneous malignancy.

List Of CPT Codes For Mohs Surgery

CPT Code 17311 and CPT Code 17313 are the base codes for the range of this surgery. CPT Code 17312, CPT Code 17314, and CPT Code 17315 are the add-on codes for this range.

Description Of CPT Code 17311

Moh’s micrographic technique, including removal of all gross tumor, surgical excision to tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stain(s) (eg. Hematoxylin and eosin, toluidine blue), head, neck, hands, feet genitalia, or any location with surgery directly involving muscle, cartilage, bone, tendon, major nerves, or vessels; first stage, up to 5 tissue blocks

Description Of CPT Code 17315 (addon)

CPT Code 17315 may be used to report each block after the first 5 blocks for any single-stage.

Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), each additional block after the first 5 tissue blocks, any stage (List separately in addition to code for primary procedure)

Extras

Description Of CPT Code 17312 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure)

Description of CPT Code 17313

Moh’s micrographic technique, including removal of all gross tumor, surgical excision of tissue specimens, mapping, color coding of specimens, microscopic examination of specimens by the surgeon, and histopathologic preparation including routine stains(s) (eg. Hematoxylin and eosin, toluidine blue), of the trunk, arms, or legs; first stage, up to 5 tissue blocks

Description Of CPT Code 17314 (addon)

Each additional stage after the first stage, up to 5 tissue blocks (List separately in addition to code for primary procedure).

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