what of the following functions is graphed below
being timed help quickly will mark brainliest !!!
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Related Questions
Triangle A'B'C' is the image of triangle ABC after a dilation with a scale factor of 1/2 and centered at point A. Is triangle ABC congruent to triangle A'B'C'? Explain your answer.
Answers
Answer:
See below
Step-by-step explanation:
Congruent means having the same size and shape.
If triangle A'B'C' is the image of triangle ABC after a dilation with a scale factor of 1/2 then the two triangles will not acquire the same size
This is because when a shape undergoes a dilation the dilated image is either larger or smaller and can therefore not maintain the same size as the pre image. Hence the triangles are not congruent.
Triangle ABC is not congruent to triangle A'B'C'
How to determine the congruent statement?The triangles are given as:
Triangle ABC and A'B'C'
The other parameters are:
Scale factor, k = 1/2
Center = Point A
Since the scale factor is not 1, then the triangles would not be congruent; but they would be similar
Hence, triangle ABC is not congruent to triangle A'B'C'
Read more about dilation at:
https://brainly.com/question/9791066
If a star is 5,699,999,999,999,999 meters from earth, how long does it take light to travel from earth to the star?
Answers
Answer
19.013.153,42629466 giây
Step-by-step explanati
van toc ánh sán =299.792.458 m/s
s= v*t
t=s/v
t= 5.699.999.999.999.999/299.792.458= 19.013.153,42629466 giây
Given F ( x ) = -2/3 x - 4 What is the zero of this function?
Answers
Answer:
-4
Step-by-step explanation:
f(0)=(-2/3)(0) - 4
= - 4
Match the statement using the diagram
Answers
9514 1404 393
Answer:
d, b, c, a, e
Step-by-step explanation:
The order of the letters in the congruence statement tells you ...
ΔQOP ≅ ΔABC
∠Q ≅ ∠A
∠O ≅ ∠B ≅ 115°
∠P ≅ ∠C
QO ≅ AB = 5 m
OP ≅ BC = 8 m
PQ ≅ CA
i need help w this pls
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Answer and Step-by-step explanation:
The answer is the second answer choice. y = 2x + 1
By looking at the graph, we see that there is a y-intercept at (0, 1), and it has a positive slope of 2.
#teamtrees #PAW (Plant and Water)
The shortest route from London to Edinburgh is 400 miles.
A lorry is expected to take 10 hours to travel this route.
The lorry actually travels by a different route which increases the distance by 15%, but it still arrives in 10 hours.
By how many more mph than the expected speed does the lorry travel?
Answers
Answer:
The lorry travels by 6 mph more than the expected speed.
Step-by-step explanation:
Velocity formula:
Velocity is distance divided by time, that is:
[tex]v = \frac{d}{t}[/tex]
Shortest route:
400 miles in 10 hours, which means that [tex]d = 400, v = 10[/tex]. So
[tex]v = \frac{d}{t} = \frac{400}{10} = 40[/tex]
In mph.
The lorry actually travels by a different route which increases the distance by 15%, but it still arrives in 10 hours.
Distance is multiplied by 100% + 15% = 115% = 1.15, so:
[tex]d = 1.15*400 = 460[/tex]
Then
[tex]v = \frac{d}{t} = \frac{460}{10} = 46[/tex]
46 mph
By how many more mph than the expected speed does the lorry travel?
46 - 40 = 6 mph
The lorry travels by 6 mph more than the expected speed.
Assuming p: she is beautiful,q :she is clever,the verbal form of ~p^ (~q) is she is beautiful but not clever. she is beautiful and clever she is not beautiful and not clever.she is beautiful or not clever.
Answers
Answer:
C. she is not beautiful and not clever.
Step-by-step explanation:
A. she is beautiful but not clever. B. she is beautiful and clever
C. she is not beautiful and not clever.
D. she is beautiful or not clever.
p: she is beautiful
q :she is clever
~p^ (~q) in verbal form
~p = she is not beautiful
~q = she is not clever
~p^ (~q) = she is not beautiful and not clever.
C. she is not beautiful and not clever.
Calculate the mean,median and mode.(3 points each)
1. 1,2,3,4,5
2. 2,3,4,5,6,6
3. 6,7,5,4,5,6,2,5
Answers
Answer:
1. The first set of number is
1,2,3,4,5
Mean= 1+2+3+4+5/5
= 15/5
= 3
Median= 3
Mode= N/A
The next set of numbers is
2,3,4,5,6,6
Mean= 2+3+4+5+6+6/6
= 26/6
= 4.3
Median=4+5/2
= 9/2
= 4.5
Mode= 6
The next set of number is
6,7,5,4,5,6,2,5
Mean= 2+4+5+5+5+6+6+7/8
= 40/8
= 5
Median= 5+5/2
= 10/2
= 5
Mode= 5
Determine the perimeter of the figure below
Answers
Answer:
39 feet
Step-by-step explanation:
p = 15 + 8 + 10 + 6
p = 39
39 feet
I took 18 pencils from the box. this is equivalent to 2/5 of the total number of pencils.
How many pencils were there in the box originally. Show your work.
Answers
if 18 is 2/5, than 9 is 1/5. That means that 5/5 is 45.
Hope this helps!
Answer: 45 pencils were in the box originally
Step-by-step explanation:
Suppose there were x pencils in the box originally. Since 18 pencils is equal to 2/5 of the total number of pencils in the box originally, set 18 equal to 2/5x or
18=2/5x
Now solve
x = 18x5/2 = 45
Find the volume of a sphere with a diameter of 4 inches. Use 3.14 for π
.
Round your answer to the nearest hundredth.
The volume of the sphere is cubic inches.
Answers
Answer:
33.51 cubic inches
Step-by-step explanation:
Formula for volume of a sphere is V= 4 /3 · π · r3
We know the diameter is 4, and the radius is half the diameter, so the radius is 2.
V = 4 /3 · π · [tex]2^{3}[/tex]
≈ 33. 51032
Rounded to the nearest hundreth is 33.51.
Is this right help me PLEASE
Answers
Answer:
Letter B, C and E are correct
Step-by-step explanation:
hope this helps
tell if you got it right
Answer:
Letter B, C and E are correct
Step-by-step explanation:
hope this helps
Dannette and Alphonso work for a computer repair company. They must include the time it takes to complete each repair in their repair log book. The dot plots show the number of hours each of their last 12 repairs took. Part a. Calculate the median, mean, IQR, and standard deviation of each data set. Part b. Which measure of central tendency and spread should you use to compare the two data sets? Explain your reasoning. Part c. Determine whether there are any outliers in either data set. Dannette's Repair Times х х X X X X Х Х + 9 + 1 0 Relations 2 3 4 8 10 12 5 6 7 Repair Time (hours) Geometry Alphonso's Repair Times Groups X Trigonometry X Х X X X х X х Statistics 7 X + 3 10 9 0 4 12 Series 8 1 2 5 7 Repair Time (hours) Greek
PLZ HELP
Answers
Answer:
(a):
Dannette Alphonso
[tex]\bar x_D = 4.33[/tex] [tex]\bar x_A = 5.17[/tex]
[tex]M_D = 2.5[/tex] [tex]M_A = 5[/tex]
[tex]\sigma_D = 3.350[/tex] [tex]\sigma_A = 1.951[/tex]
[tex]IQR_D = 7[/tex] [tex]IQR_A = 1.5[/tex]
(b):
Measure of center: Median
Measure of spread: Interquartile range
(c):
There are no outliers in Dannette's dataset
There are outliers in Alphonso's dataset
Step-by-step explanation:
Given
See attachment for the appropriate data presentation
Solving (a): Mean, Median, Standard deviation and IQR of each
From the attached plots, we have:
IQR_A = 1.5 ---- Dannette
[tex]A = \{3,4,4,4,4,5,5,5,5,6,6,11\}[/tex] ---- Alphonso
n = 12 --- number of dataset
Mean
The mean is calculated
[tex]\bar x = \frac{\sum x}{n}[/tex]
So, we have:
[tex]\bar x_D = \frac{1+1+1+1+2+2+3+7+8+8+9+9}{12}[/tex]
[tex]\bar x_D = \frac{52}{12}[/tex]
[tex]\bar x_D = 4.33[/tex] --- Dannette
[tex]\bar x_A = \frac{3+4+4+4+4+5+5+5+5+6+6+11}{12}[/tex]
[tex]\bar x_A = \frac{62}{12}[/tex]
[tex]\bar x_A = 5.17[/tex] --- Alphonso
Median
The median is calculated as:
[tex]M = \frac{n + 1}{2}th[/tex]
[tex]M = \frac{12 + 1}{2}th[/tex]
[tex]M = \frac{13}{2}th[/tex]
[tex]M = 6.5th[/tex]
This implies that the median is the mean of the 6th and the 7th item.
So, we have:
[tex]M_D = \frac{2+3}{2}[/tex]
[tex]M_D = \frac{5}{2}[/tex]
[tex]M_D = 2.5[/tex] ---- Dannette
[tex]M_A = \frac{5+5}{2}[/tex]
[tex]M_A = \frac{10}{2}[/tex]
[tex]M_A = 5[/tex] ---- Alphonso
Standard Deviation
This is calculated as:
[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]
So, we have:
[tex]\sigma_D = \sqrt{\frac{(1 - 4.33)^2 +.............+(9- 4.33)^2}{12}}[/tex]
[tex]\sigma_D = \sqrt{\frac{134.6668}{12}}[/tex]
[tex]\sigma_D = 3.350[/tex] ---- Dannette
[tex]\sigma_A = \sqrt{\frac{(3-5.17)^2+............+(11-5.17)^2}{12}}[/tex]
[tex]\sigma_A = \sqrt{\frac{45.6668}{12}}[/tex]
[tex]\sigma_A = 1.951[/tex] --- Alphonso
The Interquartile Range (IQR)
This is calculated as:
[tex]IQR =Q_3 - Q_1[/tex]
Where
[tex]Q_3 \to[/tex] Upper Quartile and [tex]Q_1 \to[/tex] Lower Quartile
[tex]Q_3[/tex] is calculated as:
[tex]Q_3 = \frac{3}{4}*({n + 1})th[/tex]
[tex]Q_3 = \frac{3}{4}*(12 + 1})th[/tex]
[tex]Q_3 = \frac{3}{4}*13th[/tex]
[tex]Q_3 = 9.75th[/tex]
This means that [tex]Q_3[/tex] is the mean of the 9th and 7th item. So, we have:
[tex]Q_3 = \frac{1}{2} * (8+8) = \frac{1}{2} * 16[/tex] [tex]Q_3 = \frac{1}{2} * (5+6) = \frac{1}{2} * 11[/tex]
[tex]Q_3 = 8[/tex] ---- Dannette [tex]Q_3 = 5.5[/tex] --- Alphonso
[tex]Q_1[/tex] is calculated as:
[tex]Q_1 = \frac{1}{4}*({n + 1})th[/tex]
[tex]Q_1 = \frac{1}{4}*({12 + 1})th[/tex]
[tex]Q_1 = \frac{1}{4}*13th[/tex]
[tex]Q_1 = 3.25th[/tex]
This means that [tex]Q_1[/tex] is the mean of the 3rd and 4th item. So, we have:
[tex]Q_1 = \frac{1}{2}(1+1) = \frac{1}{2} * 2[/tex] [tex]Q_1 = \frac{1}{2}(4+4) = \frac{1}{2} * 8[/tex]
[tex]Q_1 = 1[/tex] --- Dannette [tex]Q_1 = 4[/tex] ---- Alphonso
So, the IQR is:
[tex]IQR = Q_3 - Q_1[/tex]
[tex]IQR_D = 8 - 1[/tex] [tex]IQR_A = 5.5 - 4[/tex]
[tex]IQR_D = 7[/tex] --- Dannette [tex]IQR_A = 1.5[/tex] --- Alphonso
Solving (b): The measures to compare
Measure of center
By observation, we can see that there are outliers is the plot of Alphonso (because 11 is far from the other dataset) while there are no outliers in Dannette plot (as all data are close).
Since, the above is the case; we simply compare the median of both because it is not affected by outliers
Measure of spread
Compare the interquartile range of both, as it is arguably the best measure of spread, because it is also not affected by outliers.
Solving (c): Check for outlier
To check for outlier, we make use of the following formulas:
[tex]Lower =Q_1 - 1.5 * IQR[/tex]
[tex]Upper =Q_3 + 1.5 * IQR[/tex]
For Dannette:
[tex]Lower = 1 - 1.5 * 7 = -9.5[/tex]
[tex]Upper = 8 + 1.5 * 7 = 18.5[/tex]
Since, the dataset are all positive, we change the lower outlier to 0.
So, the valid data range are:
[tex]Valid = 0 \to 18.5[/tex]
From the question, the range of Dannette's dataset is: 1 to 9. Hence, there are no outliers in Dannette's dataset
For Alphonso:
[tex]Lower = 4 - 1.5 * 1.5 =1.75[/tex]
[tex]Upper = 5.5 + 1.5 * 1.5 =7.75[/tex]
So, the valid data range are:
[tex]Valid = 1.75\to 7.75[/tex]
From the question, the range of Alphonso's dataset is: 3 to 11. Hence, there are outliers in Alphonso's dataset
Review the graph of complex number z. On a coordinate plane, the y-axis is labeled imaginary and the x-axis is labeled real. Point z is at (negative 3, 1). What is the modulus of z?
Edge
Answers
Answer:
The modulus of z is [tex]\sqrt{10}[/tex]
Step-by-step explanation:
Complex number:
A complex number, given by:
[tex]z = x + iy[/tex]
Can be represented also as a point (x,y).
The modulus is given by:
[tex]|z| = \sqrt{x^2 + y^2}[/tex]
Point z is at (negative 3, 1). What is the modulus of z?
[tex]x = -3, y = 1[/tex]. So
[tex]|z| = \sqrt{x^2 + y^2} = \sqrt{(-3)^2+1^2} = \sqrt{10}[/tex]
The modulus of z is [tex]\sqrt{10}[/tex]
Answer:
-2
Step-by-step explanation:
if this is the right problem it is -2
HELP PLEASE WITH THESE IM SO LOST AND NEED HELP! 1-4!
Answers
Answer:
1.tenisha
2.1\5+1\3=1\×
3.n-12=1\3(n+2)
4.500×=120
Triangle ABC will be translated right 3 units and down 5 units to create triangle A'B'C'. What are the coordinates of B'?
Answers
Answer:
B'(4, 0)
Step-by-step explanation:
B (1, 5)
it translated right 3 units => x'=x+3
down 5 units => y'= y-5
Find the area of the figure below. ANSWER in NUMBER ONLY
Answers
==================================================
Work Shown:
area = base*height
area = 8*10
area = 80 square cm
The slanted sides aren't used. We only use the horizontal base 8 and vertical height 10. The base and height are always perpendicular to one another.
What is the area of the triangle formed from (0,-3), (0,4), and (4,-3)?
O A. 14 square units
O B. 6 square units
O c. 48 square units
O D. 24 square units
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which ordered pair is a solution to the system of inequalities graphed here?
Answers
Step-by-step explanation:
-3,4 Is the answer Is it right or wrong if it is true plz mark me as brainliest
Answer:
Ano is correct
Step-by-step explanation:
-3,4is theoretically correct answer
What number must you add to complete the square? x^2+26x=11
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Answer:
[tex] {x}^{2} + 26x = 11 \\ x = 0.4 \: and \: - 26.4[/tex]
109.06 in scientific notation is
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2,45,250 students appeared for an entrance examination. If 94,750 students did not get admission, find how many students got admission.
can i please get the answer
Answers
Answer:
2.45.250- 94.750
= 92. 2975. this is the learners who got the admission
Answer:
1,50,500 students
Step-by-step explanation:
Hope this helps... vote as brainliest
HELP ASAP I WILL GIVE BRAINLIST
A = {1, 3, 4, 5, 7, 9}
B = {1, 2, 4, 6, 8, 10}
List the outcomes of A ∪ B? What does this represent?
List the outcomes of A ∪ B? What does this represent?
Answers
Answer:
A U B={1,2,3,4,5,6,7,8,9,10} represents A union B
(includes all the members of set Sand the members of set Bout together, do not repeat anyone that comes twice)
A n B={1,4} represents A interception B( this refers to the members that sets A and B have in common)
Answer:
A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 }
Step-by-step explanation:
A = { 1 , 3 , 4 , 5 , 7 , 9 }
B = { 1 , 2 , 4 , 6 , 8 , 10 }
A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 }
It represents the whole numbers between 0 and 11
[ A ∪ B is the elements of both A and B , without any repetition ]
A ∩ B = { 1 , 4 }
It represents the common numbers in both A and B
Of the animals at a pet show, 3/8 were cats and 4/8 were dogs. The rest of the animals were rabbits. What fraction of the animals were rabbits?
Answers
Answer:
1/8 Of the animals are rabbits.
Step-by-step explanation:
3/8 Cats + 4/8 Dogs = 7/8
1/8 Is all you have room left for so 1/8 would be rabbits.
Answer:
1/8.
Step-by-step explanation:
Fraction of rabbits = 1 - (3/7 + 4/8)
= 1 - 7/8
= 8/8 - 7/8
= 1/8.
PLS HELP I WILL GIVE BRAINLIEST
Answers
Answer:
a) correct
b) 70 degrees
Step-by-step explanation:
since in the triangle BXC the sides BX and XC have the same length, they must also have the same angles with the baseline BC.
so, we know, XBC = 55 degrees.
and therefore BCX = 55 degrees.
the sum of all angles in a triangle is always 180 degrees.
so,
BXC = 180 - 55 - 55 = 70 degrees
Choose the function whose graph is given by: A. y=tan(x+1)-pi B. y=tan(x-pi)-1 C. y=tan(x-pi)+1 D. y=tan(2(x+pi))-1
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Aver si le entiendes bro
PLEASE HELP ME WILL MARK YPU IF YOU HELP ME
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ok check image file in the image is answers with color code
What are the four answers?
Answers
Answer:
CLAE
Step-by-step explanation:
1=43
2=28
3=24
4=83
What is the first step to solve the equation 12z - 21 = 92?
Answers
12z - 21 = 92
12z - 21 + 21 = 92 + 21
12z = 113
z = 113/12
A 20-year loan of 1000 is repaid with payments at the end of each year. Each of the first ten payments equals 150% of the amount of interest due. Each of the last ten payments is X. The lender charges interest at an annual effective rate of 10%. Calculate X.
Answers
Answer:
[tex]x = 97[/tex]
Step-by-step explanation:
Given
[tex]t = 20[/tex] --- time (years)
[tex]A =1000[/tex] --- amount
[tex]r = 10\%[/tex] --- rate of interest
Required
The last 10 payments (x)
First, calculate the end of year 1 payment
[tex]y_1(end) = 10\% * 1000 * 150\%[/tex]
[tex]y_1(end) = 150[/tex]
Amount at end of year 1
[tex]A_1=A - y_1(end) - r * A[/tex]
[tex]A_1=1000 - (150 - 10\% * 1000)[/tex]
[tex]A_1 =1000 - (150- 100)[/tex]
[tex]A_1 =950[/tex]
Rewrite as:
[tex]A_1 = 0.95 * 1000^1[/tex]
Next, calculate the end of year 1 payment
[tex]y_2(end) = 10\% * 950 * 150\%[/tex]
[tex]y_2(end) = 142.5[/tex]
Amount at end of year 2
[tex]A_2=A_1 - (y_2(end) - r * A_1)[/tex]
[tex]A_2=950 - (142.5 - 10\%*950)[/tex]
[tex]A_2 = 902.5[/tex]
Rewrite as:
[tex]A_2 = 0.95 * 1000^2[/tex]
We have been able to create a pattern:
[tex]A_1 = 1000 * 0.95^1 = 950[/tex]
[tex]A_2 = 1000 * 0.95^2 = 902.5[/tex]
So, the payment till the end of the 10th year is:
[tex]A_{10} = 1000*0.95^{10}[/tex]
[tex]A_{10} = 598.74[/tex]
To calculate X (the last 10 payments), we make use of the following geometric series:
[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + r)^n[/tex]
[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + 10\%)^n[/tex]
[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + 0.10)^n[/tex]
[tex]Amount = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]
The amount to be paid is:
[tex]Amount = A_{10}*(1 + r)^{10}[/tex] --- i.e. amount at the end of the 10th year * rate of 10 years
[tex]Amount = 1000 * 0.95^{10} * (1+r)^{10}[/tex]
So, we have:
[tex]Amount = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]
[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+r)^{10}[/tex]
[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+10\%)^{10}[/tex]
[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+0.10)^{10}[/tex]
[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1.10)^{10}[/tex]
The geometric sum can be rewritten using the following formula:
[tex]S_n = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]
[tex]S_n =\frac{a(r^n - 1)}{r -1}[/tex]
In this case:
[tex]a = x[/tex]
[tex]r = 1.10[/tex]
[tex]n =10[/tex]
So, we have:
[tex]\frac{x(r^{10} - 1)}{r -1} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]
[tex]\frac{x((1.10)^{10} - 1)}{1.10 -1} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]
[tex]\frac{x((1.10)^{10} - 1)}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]
[tex]x * \frac{1.10^{10} - 1}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]
So, the equation becomes:
[tex]x * \frac{1.10^{10} - 1}{0.10} = 1000 * 0.95^{10} * (1.10)^{10}[/tex]
Solve for x
[tex]x = \frac{1000 * 0.95^{10} * 1.10^{10} * 0.10}{1.10^{10} - 1}[/tex]
[tex]x = 97.44[/tex]
Approximate
[tex]x = 97[/tex]
