What properties can be used to identify substance and why?

Answers

Answer 1

Answer:

All substances can be characterized by their unique sets of physical and chemical properties. Properties that can be determined without changing the composition of a substance are referred to as physical properties. Characteristics such as melting point, boiling point, density, solubility, color, odor, etc.


Related Questions

How many atoms are in 490 moles of barium?

Answers

Answer:

2.95 * 10^23 atoms

Explanation:

The number of atoms in a mole is always equal to Avogadro's constant, which is 6.02214076×10²³ mol⁻¹.

To find the number of atoms in 0.490 moles of barium, multiply it with Avogadro's constant:

0.490 mol * 6.02214076×10²³ mol⁻¹ ≈ 2.9508 * 10^23

Convert to SigFigs (if necessary):

2.95 * 10^23

Jason combines the two intermediate steps shown. 2 equations. First: upper N subscript 2 (g) plus upper O subscript 2 (g) right arrow 2 upper N upper O (g). Second: 2 upper N upper O (g) plus upper O subscript 2 (g) right arrow 2 upper N upper O subscript 2 (g). Which best describes what Jason should do with the oxygen molecules?

Answers

Answer:

The molecules of oxygen should be placed as reactants in the equation.

Explanation:

1:      N₂ + O₂ → 2NO

2:     2NO + O₂ → 2NO₂

complete reaction:

N₂ + 2O₂ → 2NO₂

In both intermediate equations' oxygen is used as reactant because the end product is the product of the combination of nitrogen and oxygen. So in the  complete or overall reaction, oxygen should also be placed as reactant.

We can not place oxygen at the side of products neither we can cancel it because, products can only be obtained at the end of the reaction but according to the equations' oxygen is not the end product of the reaction. But the addition into the reaction (Eq. 2) to make the new product.

Also, we can not cancel it because to cancel out molecules of oxygen should be present at the both sides with same amount in the stoichiometric equation.

Hence, in a balanced chemical equation, oxygen should be written as a reactant by using the correct number of moles.

Which two of the following changes of state involve solids?
Select two (2) answers


A. melting

B. boiling

C. freezing

D. evaporating

Answers

Answer:

Answer is A... Melting and freezing

What does a low number on the pH scale say about a solution?
A. The solution is neutral.
B. The solution is a base.
C. The solution is changing.
D. The solution is an acid.

Answers

Answer:

d. the solution is a acid

Answer:D The solution is an acid

Explanation:The lower the pH of a substance the stronger the acidic level.

Which of the following is not a reason why actual yield is less than theoretical yield?

A. presence of impure reactants

B. conservation of mass

C. competing side reactions

D. loss of product during purification

Answers

Your answer is B, conservation of mass


Recall that percent yield is given by: %Yeild = actual yeild/theoretical yeild x100

During experiments, there are errors made:

• uncertainty in measurements

• losses of reactants and products

• impurity in reactants

• losses during separation (e.g. filtration or purification)

• Some side reactions might also happen.



Among the given options, only conservation of mass does not contribute to a lower actual yield compared to the theoretical yield.

The option that isn't a reason why the actual yield is less than theoretical yield is B. conservation of mass.

It should be noted that the formula for the percent yield is given as:

= Actual yield / Theoretical Yield × 100

The actual yield is experimentally determined, and it's the quantity of a product that is gotten from a chemical reaction.

The theoretical yield is the amount of product that can be obtained from a reaction when the reactants are changed to products.

Actual yield can be less than theoretical yield due to the presence of impure reactants ,competing side reactions, and loss of product during purification.

In conclusion, the correct option is B.

Read related link on:

https://brainly.com/question/23854893

Boyle's Law Problems
Charles' Law Problems ​

Answers

Answer:

here are the answers babe. Feel free to ask for more

HELP! HELP! Calculate the value of ΔS⁰ at 298 K.

Answers

Answer:

ΔS⁰ = -181.1J/molK

Explanation:

ΔS⁰ of a reaction is defined as the sum of the entropies of the reactants times its reaction coefficient minus the sum of the entropies of the products times its reaction coefficient. For the reaction in the problem:

ΔS⁰ = 2*S{NaCl(s)} - (2*S{Na(s)}+S{Cl2(g)})

ΔS⁰ = 2*72.1J/molK - (2*51.1J/molK + 223.1J/molK)

ΔS⁰ = -181.1J/molK

help me with this attachment please​

Answers

Answer:

See explanation

Explanation:

Let us recall that the basic rule in writing balanced chemical reaction equations is that the number of atoms of each element on the right hand side of the reaction equation is the same of the number of atoms of the same element on the left hand side of the reaction equation.

The reaction of red hot iron and steam is written as follows;

3Fe + 4H2O → Fe3O4 + 4H2.

The decomposition reaction of ammonium dichromate is written as;

(NH4)2Cr2O7 → N2 + Cr2O3 + 4H2O

Reaction of aluminium, sodium hydroxide and water is as follows,

2Al + 2NaOH + 2H2O ----> 2NaAlO2 + 3H2

Reaction of potassium bicarbonate with sulphuric acid;

2KHCO3 + H2SO4 -------> K2SO4 + 2H2O + 2CO2

Reaction of zinc and sodium hydroxide is as follows;

Zn + 2NaOH→Na2ZnO2 + H2

What point A on the phase diagram called?
liquid
(374°C/218 atm)
A
solid
pressure (atm)
gas
temperature (°C)
OA.
the melting point
OB.
the boiling point
Ос.
the freezing point
OD
the critical point
OE.
the triple point

Answers

Answer:

D) the critical point

Explanation:

Point A is the critical point in phase diagram. This is the highest temperature and pressure at which a pure material can exist in vapor/liquid equilibrium. Pretty cool!

name the gas which is formed when coal is heated in the absense of air​

Answers

Answer:

Coke

Explanation:

A solid fuel formed by heating coal in the absence of air is coke. Coke is black colored, tough porous substance. It is pure carbon.

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