Answer:
welcome
Explanation:
Uses of Rutherfordium
Because rutherfordium is made within the lab, there are not very many uses for this element commercially. On the other hand, rutherfordium has been used within the laboratory setting to conduct research. Most elements that are highly radioactive are used for nuclear power and medicinal purposes.
If 4.04g of h2 gas react with oxygen gas to create 36.36g of water, how many grams of oxygen reacted?
Answer:
gO₂ = 32.32 g
Explanation:
In this case, let's write the general equation:
2H₂ + O₂ -------> 2H₂O
In this case, we can use the 1° law, which is mass conservation. If the product has 36.36 g of water, then in the reactants we should have the same 36.36 g.
According to this, we already have 4.04 of hydrogen, then the remaining to reach the 36.36 g would be:
gO₂ = 36.36 - 4.04
gO₂ = 32.32 gHope this helps
Sample A has a mass of 40g and a volume of 10cm^3. Sample B has a volume of 15cm^3 and a mass of 45g. Which sample has a greater density? Show your work.
The Answer Is Sample A
Density -
[tex]density = \frac{mass}{volume} [/tex]
Input The Formula For Both Equations To Find Density.
Sample A -
[tex]d = \frac{40}{10} [/tex]
[tex]d = 4[/tex]
Sample B -
[tex]d = \frac{45}{15} [/tex]
[tex]d = 3[/tex]
i hate chemistry but someone help please, no links or you’ll be reported
Answer:
A, D, E
Explanation:
Si la masa de una muestra de un compuesto Y es de 196 gramos y contiene 2 mol, la masa molar de Y es
Answer:
98 g/mol
Explanation:
La masa molar de un compuesto es la cantidad de materia (medida como masa) que hay en 1 mol de dicho compuesto. Por lo tanto, puede calcularse como sigue:
masa molar = masa/número moles
Tenemos los siguientes datos del compuesto Y:
masa Y = 196 g
número de moles de Y = 2 mol
Entonces, podemos calcular la masa molar de Y de la siguiente manera:
masa molar Y = (masa Y)/(número de moles de Y) = 196 g/2 mol = 98 g/mol
Which two moon phases can occur while the
relative positions of the sun, Earth, and moon
form a straight line?
Answer:
its the lunar and solar eclipse
Explanation:
the solar eclipse happens when the moon is in between the sun and earth
Cuando se trata Ca3P2 con agua, los productos son Ca(OH)2 y PH3. Calcular el peso máximo obtenido al reaccionar 2 g de Ca3P2 con 1 g de H2O.
Answer:
0.629 gramos de PH3 es la máxima de cantidad que puede ser producida.
Explanation:
¡Hola!
En este caso, dado que tenemos la siguiente reacción química, la cual se puede balancear directamente:
[tex]Ca_3P_2+6H_2O\rightarrow 3Ca(OH)_2+2PH_3[/tex]
Podemos calcular la masa máxima de cualquier producto, digamos PH3, al comparar la masa de este, que 2 g the Ca3P2 y 1 g de H2O producen por separado y de acuerdo a la estequiometría:
[tex]2gCa_3P_2 *\frac{1molCa_3P_2 }{182.18gCa_3P_2 }*\frac{2molPH_3}{1molCa_3P_2 } *\frac{34gPH_3}{1molPH_3 } =0.747gPH_3\\\\1gH_2O *\frac{1molH_2O }{18.02gH_2O}*\frac{2molPH_3}{6molH_2O} *\frac{34gPH_3}{1molPH_3 } =0.629gPH_3[/tex]
De este modo, infermos que solamente 0.629 gramos the PH3 pueden ser obtenidos al ser el agua el reactivo límite.
¡Saludos!
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14. An AREA which drains into a common river system.
watershed
tributary
drainage divide
riparian zone
