What type of line is PQ?
A. angle bisector
B. median
C. altitude
D. side bisector

Answer:

I really can't read this

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

the answer is A and not C. equation in form of y=mx+b

so start off by (0,2) and you can see the graph go by 1 x and 1 y.

C=n+2

Answer:

A

Step-by-step explanation:

its starting point is 2 up to +2 and it goes up at out by 1 so n also ik this was already answered but i want the brainly points

Answer:

ask ya fadaaaaaaaaàaaa

Step-by-step explanation:

guvdhcjnhcxh

Answer:

5√3 / 2

Step-by-step explanation:

tan 30 = ( 5 / 2 ) / y

1 / √3 = 5 / 2y

2y = 5√3

y = 5√3 / 2

Answer:

The diameter is 6. The radius is 3. For the half of the orange circle.

The area of the half of the small orange circle is = pi*r*r = pi*3*3.

The diameter is 24. The radius is 12.

The area of the half of the light orange circle and the other colors is = pi*r*r = pi*12*12

The area of dark orange, light blue, purple and green figures = pi*12*12 – pi*3*3 = 135*pi

To get the area of the blue figure we need to divide 135*pi into ¼ and you will get the area of the blue figure.

The area of the blue figure =( ¼ )*135*pi *(1/2) = ¼ *1/2 = 1/8

The area of the blue figure is = 135pi / 8

B) outside perimeter of the window frame = 28 +pi*14 = 71.98

Hope this helps you :)

Answer:

f(x) + f(4)

Step-by-step explanation:

TRUST ME DO THIS PROCESS

Step-by-step explanation:

here's the answer to your question

Answer:

p=-7

Step-by-step explanation:

5p=-35

Divide both sides by 5

5p/5 =-35/5

therefore p=-7

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{5p= -35}\\\\\underline{\huge\text{DIVIDE 5 BOTH SIDES}}\\\\\mathsf{\dfrac{5p}{5p}= \dfrac{-35}{5}}\\\\\large\text{CANCEL out: }\dfrac{5}{5}\large\text{ because that gives you 1}\\\large\text{KEEP: }\dfrac{-35}{5}\large\text{ because that gives you the value of p.}\\\\\large\textsf{p = }\mathsf{\dfrac{-35}{5}}\\\\\mathsf{-35\div5= p}\\\\\large\text{Simplify above and you have your result to the p-value.}\\\\\boxed{\boxed{\huge\text{Therefore your answer is: \textsf{p = -7}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

x  ≈  0.13893498

Step-by-step explanation:

here is the answer to your question

Answer:

1217

Step-by-step explanation:

Given

[tex]Subjects = 2353[/tex]

[tex]Improvement = 1136[/tex]

Required

The number that didn't improve --- missing from the question.

Let the unimproved be represented as x.

So, we have:

[tex]x + Improvement = Subjects[/tex]

Substitute known values

[tex]x + 1136 = 2353[/tex]

Solve for x

[tex]x =- 1136 + 2353[/tex]

[tex]x =1217[/tex]

Terms given

No of terms=8

We know

[tex]\boxed{\sf Mean=\dfrac{Sum\;of\:terms}{No\;of\:terms}}[/tex]

[tex]\\ \sf\longmapsto Mean=\dfrac{40+35+32+39+34+35+35+37}{8}[/tex]

[tex]\\ \sf\longmapsto Mean=\dfrac{270}{8}[/tex]

[tex]\\ \sf\longmapsto Mean=35[/tex]

Final Answer:

35

Step-by-step explanation:

-median is the middle number in the data set-

arrange the data set from least to greatest:

40, 30, 32, 39, 34, 35, 35, 37 ⇒ 30, 32, 34, 35, 35, 37, 39, 40

we start from the lowest number and the highest  number and work your way to the middle:

30, 32, 34, 35, 35, 37, 39, 40

notice that there is no middle number:

30, 32, 34, 35, ?, 35, 37, 39, 40

so what we do is add both 35's and then divide it by 2

35 + 35 = 70 ÷ 2 = 35

median: 35

Answer:

The lines are:

and

Since after multiplying by -3 the equations sum to 0, the equations are same.

Same equations produce overlapping lines, hence you can see one line only.

Divide second equation by 3

LInes are same so you can see only one line

Answer:

8 pieces.

Step-by-step explanation:

12 / 1.5

= 24 / 3

= 8.

Answer:

34

Step-by-step explanation:

let the missing value is x

(25+x) /2 = 29.5

25+x = 29.5(2)

25+x = 59

x = 59-25

x = 34

Problem 1

The idea here is to follow PEMDAS in reverse to undo what is happening to the variable b, so we can isolate it.

-11b + 7 = 40

-11b = 40-7

-11b = 33

b = 33/(-11)

b = -3

To check this value, plug it back into the original equation. You should get 40 on each side to help confirm the answer.

=====================================================

Problem 2

There are two ways we can solve. One method is to use the hint your teacher gave you. So we'll distribute first and then follow the same idea as problem 1

9(p-4) = -18

9p-36 = -18

9p = -18+36

9p = 18

p = 18/9

p = 2

Another method you can use is to follow these steps

9(p-4) = -18

p-4 = -18/9

p-4 = -2

p = -2+4

p = 2

Either way, we get the same result. To check the answer, replace every p with 2 in the original equation. You should get -18 on the left side after simplifying.

Answer:

r^9/r^3 = r^9-3 = r^6

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]r^6[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Simplifying...}}\\\\\frac{r^9}{r^3} \\--------------\\\\\text{Recall the quotient rule:}} \frac{a^x}{a^y}=a^{x-y}\\\\\rightarrow \frac{r^9}{r^3}\\\\\rightarrow r^{9-3}\\\\\rightarrow \boxed{r^6}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

B. 2/5

Step-by-step explanation:

Answer:

Time and rate is 4 years and 4% respectively.

Step-by-step explanation:

P = Rs 66000

so

T = R

I = 10560

so

I = PTR/100

Rs 10560 = (66000*T^2)/100

or, Rs 1056000 = 66000*T^2

or. 1056000/66000 = T^2

or, 16 = T^2

OR, T =√16

so T = 4

Then

T = R

so, R = 4

Answer:

m = 4

k = 25.56

b = 20

The differential equation for damping motion is:

where,

Substitute the values in the differential equation and consider x" = r², x' =r and solve:

Therefore, solution is given by:

at t = 0, x = 1

at t = 0

x' =0

Step-by-step explanation:

Answer:

-6

Step-by-step explanation:

f(x) = -2x - 7 and g(x) = -4x + 6

Find f(-5)

f(-5) = -2(-5) -7 = 10-7 = 3

The find g(3)

g(3) = -4(3) +6

     = -12 +6 =-6

g(f(-5)) = -6

Answer:

y = 2x - 4

Step-by-step explanation:

The equations are put in slope intercept form

Slope intercept form: y = mx + b

Where m = slope and b = y intersect

So in order to find the equation of the data represented by the table we will have to find the slope and y intercept

Let's begin!

First let's find the slope

We can find the slope by using the slope formula

m = (y2 - y1) / (x2 - x1) where the x and y values are derived from coordinates from the table

The points chosen may vary but I have chosen the points (0,-4) and (1,-2)

Now that we have chosen the points we will use to find the slope let's define the variables

remember coordinates are written like this: (x,y)

The x value of the second coordinate is 1 so x2 = 1

The x value of the first coordinate is 0

So x1 = 0

The y value of the second coordinate is -2 so y2 = -2

The y value of the first coordinate is -4

So y1 = -4

Now that we have defined each variable let's plug in the values into the formula

Formula: m = (y2 - y1) / (x2 - x1)

Variables: x2 = 1, x1 = 0, y2 = -2, y1 = -4

Substitute values

m = (-2 - (-4) / ( 1 - 0 )

Evaluate

The negative signs cancel out on top and it changes to +4

m = (-2 + 4)/(1-0)

Add top values

m = 2/(1-0)

Subtract bottom numbers

m = 2/1

Simplify fraction

m = 2

So we can conclude that the slope (m) = 2

Now let's find the y intercept or "b"

The y intercept is the value of y when x = 0

If you look at the table when x = 0 y = -4 meaning that the y intercept or "b" is -4

Now that we have found everything let's find the equation of the data represented by the table

The equation is in slope intercept form

y = mx + b

Define variables

m = 2 and b = -4

Substitute values

y = 2x - 4

The equation is y = 2x - 4

Answer:

a. x = 3/a

Step-by-step explanation:

Add all like terms on left hand side of the equation:

5 ax + 3 ax => 8 ax

Bring like term 4ax on left hand side

8ax - 4ax

=> 4ax

Therefore we get 4ax = 12

ax = 12/4

ax = 3

x = 3/a

Answer:

D

Step-by-step explanation:

f(x) = -3x^3 + x^2 – 3       f(2) means that wherever you see a x, put in a 2.

f(2)= -3(2)^3 + (2)^2 - 3

f(2) = -3*8 + 4 - 3

f(2) = - 24 + 1

f(2) = - 23

[tex]\\ \sf \longmapsto f(2)[/tex]

[tex]\\ \sf \longmapsto -3(2)^3+(2)^2-3[/tex]

[tex]\\ \sf \longmapsto -3(8)+4-3[/tex]

[tex]\\ \sf \longmapsto -24+1[/tex]

[tex]\\ \sf \longmapsto -23[/tex]

Answer:

False

Step-by-step explanation:

The point that is equidistant from the vertices of a triangle is called the circumcenter.

9514 1404 393

Answer:

  False

Step-by-step explanation:

The incenter is the center of the inscribed circle, which is tangent to all of the sides of the triangle. The incenter is equidistant from the sides, not the vertices.

_____

Additional comment

The circumcenter is the center of the circumscribing circle. Each of the vertices of the triangle is on the circumcircle, so the circumcenter is equidistant from the vertices.

The incenter is located at the intersection point of the angle bisectors. The circumcenter is located at the intersection point of the perpendicular bisectors of the sides.

Answer:

4.2

Step-by-step explanation:

Constant of proportionality = y/x = 8.4 / 2 = 4.2

Distance:-

[tex]\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]\\ \sf\longmapsto \sqrt{(3+2)^2+(7-5)^2}[/tex]

[tex]\\ \sf\longmapsto \sqrt{5^2+2^2}[/tex]

[tex]\\ \sf\longmapsto \sqrt{25+4}[/tex]

[tex]\\ \sf\longmapsto \sqrt{29}[/tex]

[tex]\\ \sf\longmapsto 5.2[/tex]

[tex]\begin{gathered} {\underline{\boxed{ \rm {\red{Distance \: = \: \sqrt{(x_2 - x_1) \: + \: (y_2 - y_1)} }}}}}\end{gathered}[/tex]

[tex] \begin{cases}\large\bf{\blue{ \implies}} \tt \: Distance \: = \: \sqrt{ \bigg(3 - [ - 2] \bigg) \: + \: (7 - 5)}\\ \\ \large\bf{\blue{ \implies}} \tt \: Distance \: = \: \sqrt{ (3 + 2 ) \: + \: (7 - 5)} \\ \\ \large\bf{\blue{ \implies}} \tt \: Distance \: = \: \sqrt{ {5} \: ^{2} + \: {2}^{2} } \\ \\ \large\bf{\blue{ \implies}} \tt \: Distance \: = \: \: \sqrt{25 \: + \: 4} \\ \\ \large\bf{\blue{ \implies}} \tt \: Distance \: = \: \: \ \sqrt{29} \\ \\\large\bf{\blue{ \implies}} \tt \: Distance \: = \: \:5.38 \: \: units \end{cases}[/tex]