Answer:
A black hole is a region of spacetime where gravity is so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it.[1] The theory of general relativity predicts that a sufficiently compact mass can deform spacetime to form a black hole.[2][3]
The boundary of the region from which no escape is possible is called the event horizon. Although the event horizon has an enormous effect on the fate and circumstances of an object crossing it, according to general relativity it has no locally detectable features.[4] In many ways, a black hole acts like an ideal black body, as it reflects no light.[5][6] Moreover, quantum field theory in curved spacetime predicts that event horizons emit Hawking radiation, with the same spectrum as a black body of a temperature inversely proportional to its mass. This temperature is on the order of billionths of a kelvin for black holes of stellar mass, making it essentially impossible to observe directly.
Objects whose gravitational fields are too strong for light to escape were first considered in the 18th century by John Michell and Pierre-Simon Laplace.[7] The first modern solution of general relativity that would characterize a black hole was found by Karl Schwarzschild in 1916, although its interpretation as a region of space from which nothing can escape was first published by David Finkelstein in 1958. Black holes were long considered a mathematical curiosity; it was not until the 1960s that theoretical work showed they were a generic prediction of general relativity. The discovery of neutron stars by Jocelyn Bell Burnell in 1967 sparked interest in gravitationally collapsed compact objects as a possible astrophysical reality.
Black holes of stellar mass are expected to form when very massive stars collapse at the end of their life cycle. After a black hole has formed, it can continue to grow by absorbing mass from its surroundings. By absorbing other stars and merging with other black holes, supermassive black holes of millions of solar masses (M☉) may form. There is consensus that supermassive black holes exist in the centers of most galaxies.
The presence of a black hole can be inferred through its interaction with other matter and with electromagnetic radiation such as visible light. Matter that falls onto a black hole can form an external accretion disk heated by friction, forming quasars, some of the brightest objects in the universe. Stars passing too close to a supermassive black hole can be shred into streamers that shine very brightly before being "swallowed."[8] If there are other stars orbiting a black hole, their orbits can be used to determine the black hole's mass and location. Such observations can be used to exclude possible alternatives such as neutron stars. In this way, astronomers have identified numerous stellar black hole candidates in binary systems, and established that the radio source known as Sagittarius A*, at the core of the Milky Way galaxy, contains a supermassive black hole of about 4.3 million solar masses.
On 11 February 2016, the LIGO Scientific Collaboration and the Virgo collaboration announced the first direct detection of gravitational waves, which also represented the first observation of a black hole merger.[9] As of December 2018, eleven gravitational wave events have been observed that originated from ten merging black holes (along with one binary neutron star merger).[10][11] On 10 April 2019, the first direct image of a black hole and its vicinity was published, following observations made by the Event Horizon Telescope in 2017 of the supermassive black hole in Messier 87's galactic centre.[12][13][14]
Blackness of space with black marked as center of donut of orange and red gases
The supermassive black hole at the core of supergiant elliptical galaxy Messier 87, with a mass about 7 billion times that of the Sun,[15] as depicted in the first false-colour image in radio waves released by the Event Horizon Telescope (10 April 2019).[16][12][17][18] Visible are the crescent-shaped emission ring and central shadow,[19] which are gravitationally magnified views of the black hole's photon ring and the photon capture zone of its event horizon. The crescent shape arises from the black hole's rotation and relativistic beaming; the shadow is about 2.6 times the diameter of the event horizon.[12]
Schwarzschild black hole
Simulation of gravitational lensing by a black hole, which distorts the image of a galaxy in the background
Gas cloud being ripped apart by black hole at the centre of the Milky Way (observations from 2006, 2010 and 2013 are shown in blue, green and red, respectively).[20]
Which of the following statements about infrared telescopes is NOT true?
a. They are typically operated at lower temperatures.
b. They are especially helpful for viewing cool or obscured astronomical objects.
c. They were first built in the 1960s.
d. They are often placed on mountaintops.
e. They do not work well at high altitudes.
Answer:
a. They are typically operated at lower temperatures.
a. They are typically operated at lower temperatures.b. They are especially helpful for viewing cool or obscured astronomical objects.
An apple in a tree has a mass of 0.21 kg. If it is 7.2 meters above the ground, how much potential energy does it have?
Answer:
14.8J
Explanation:
PE=MGH
M=0.21
G=9.8m/s
H= 7.2 m
0.21x7.2x9.8= 14.8176 J
What is radioactive dating? How is it used to determine age of something?
answer 2 question basically please Help!!!
Answer:
Technique of comparing abundance ratio between radioactive isotopes to a reference isotope to determine the age of a material called radioactive dating. It determines the age by having a more abundance of isotopes in the cellular being.
A 120 Ω resistor, a 60 Ω resistor, and a 40 Ω resistor are connected in parallel and placed across a potential difference of 12.0 V. What is the equivalent resistance of the parallel circuit?
Answer:
The equivalent resistance of the parallel circuit would be 20 Ω
Explanation:
To calculate the resistance of resistors connected in parallel, the formula to be used is
1/R = 1/R₁ + R₂ + R₃ + R₄...
1/R = 1/120 + 1/60 + 1/40
1/R = (1 + 2 + 3)/120
1/R = 6/120
1/R = 1/20 Ω
This can be rewritten or cross-multiplied to be
R × 1 = 20 × 1
R = 20 Ω
The equivalent resistance (R) would then be 20 Ω
What is the electric potential at a distance of 1.2 m from a 7.5 UC point charge?
5.6 x 104 v
8.1 x 104 V
5.6 % 1010 V
8.1 x 1010 V
Answer:
5.6x10^4
Explanation:
use the equation V=kq/d
k is the constant 8.99x10^9
V=(8.99x10^9)q/d
q is the charge, 7.5 micro coulombs, but to get coulombs, multiply by 10^-6
V=(8.99x10^9)(7.5x10^-6)/d
And from the problem, we know that the distance is 1.2 meters
V=(8.99x10^9)(7.5x10^-6)/1.2
This simplifies to 5.6x10^4
The electric potential is 5.6 x 10⁴ v.
To find the electric potential the distance = 1.2 m
Charge q = 7.5 UC
What is electric potential and find the value?The amount of work needed to move a unit charge from the known point to some unknown point against the electric field is said to be electric potential.
Formula of an electric potential is
V = k ( q/r) volt
V - electric potential
k - Coulomb constant (8.99x10^9)
q - charge
r- distance of separation
V = (8.99x10⁹) (q/d)
q = 7.5 UC ( micro coulomb) 10⁻⁶ C
V=(8.99x10⁹)(7.5x10⁻⁶)/d
Substituting the values,
V=(8.99x10⁹)(7.5x10⁻⁶)/1.2
V = 5.6x10⁴ v
Thus, option A is correct.
Learn more about the electric potential,
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State the lows of reflection
Answer:
The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.
Explanation:
Answer: The law of reflection states that when a ray of light reflects off a surface, the angle of incidence is equal to the angle of reflection.
A tractor trailer truck traveling at a speed of 105 feet/second skids to a stop in 12 seconds. Determine the skidding distance of the truck.
Please help.
Answer:
1260ft
Explanation:
Given parameters:
Speed = 105ft/s
Time = 12s
Unknown:
Skidding distance of the truck = ?
Solution:
To solve this problem:
Distance = speed x time
Now insert the parameters and solve;
Distance = 105 x 12 = 1260ft
help!! what are the blanks???
The earth receives energy from the sun in one day than all the energy consumed by humans in one year.
Amount of energy received from the sun
The sun provides around 174 petawatts of energy to Earth, of which 89 petawatts is absorbed by the planet.
The Global energy consumption is roughly 15 terawatts annually.
Thus, we can conclude that, the earth receives energy from the sun in one day than all the energy consumed by humans in one year.
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Most metals have...
a. Atoms that are spread out, and low specific heats
b. Atoms that are close, and low specific heats
c. Atoms that are spread out, and high specific heats
d. Atoms that are close, and high specific heats