Answer:
20
Explanation:
Gas Laws
Assignment Active
Applying Gas Laws to Aerosol Can D
(国座
Explain why it is not a good idea to throw an
aerosol can into a fire. Which gas law applies?
DONE
Answer:
Ideal Gas Law
PV = nRT
Explanation:
Pressure is proportional to temperature;
The heat of the fire would cause increased pressure inside the closed aerosol vessel, eventually resulting in explosion of the vessel, once the temperature rises enough.
A student dissolves 20g of potassium chloride in 100cm³ of water in a beaker. What is the concentration of the solution in g/dm³?
Answer:
The concentration of the solution is 2 g/dm³
Explanation:
The equation used to find the concentration of a solution is "c = m/v"
C= concentration
M= mass
V= volume
The question asks for the answer to be in decimeters, so you need to 100 cm³ to dm³. To do this, you divide 100 by 10, giving you 10 cm³. Then you just plug in your numbers into the formula: c = 20g/10dm³.
The concentration of the potassium chloride solution has been [tex]\rm 2\;\times\;10^-^3\;g/dm^3[/tex].
The concentration has been defined as the mass of sample present in a definite volume of the solution. The concentration has been given by the moles, molarity, g/ml, g/L etc.
The concentration attained by the student has been by dissolving 20 g of KCl in [tex]\rm 100\;cm^3[/tex] water has been given in [tex]\rm g/cm^3[/tex] as:
[tex]\rm \dfrac{g}{cm^3}=\dfrac{20\;g}{100\;cm^3}\\ \dfrac{g}{cm^3}=0.2\;g/cm^3[/tex]
The concentration of the solution obtained by the student has been [tex]\rm 0.2\;g/cm^3[/tex].
The conversion of [tex]\rm cm^3\;to\;dm^3[/tex] has been given as:
[tex]\rm 1\;g/cm^3=0.001\;g/dm^3[/tex]
The concentration of [tex]\rm 0.2\;g/cm^3[/tex] solution has been given as:
[tex]\rm 1\;g/cm^3=0.001\;g/dm^3\\0.2\;g/cm^3=0.2\;\times\;0.001\;g/dm^3\\0.2\;g/cm^3=2\;\times\;10^-^3\;g/dm^3[/tex]
The concentration of the potassium chloride solution has been [tex]\rm 2\;\times\;10^-^3\;g/dm^3[/tex].
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Which is the best example of the use of imagery in a sentence?
Answer:
Explanation: As the good witch Azura said when she was in the bog of immediate regret I challenge you to a witches duel.
im sorry if that was bad i got nothing lol
also took it from The Owl House
Oxygen decays to form nitrogen.
3
150
->
19N + e
8
1
This type of nuclear decay is called
Answer:
Radioactive isotopes ranging from 11O to 26O have also been characterized, all short-lived. The longest-lived radioisotope is 15O with a half-life of 122.24 seconds, while the shortest-lived isotope is 12O with a half-life of 580(30)×10−24 seconds (the half-life of the unbound 11O is still unknown).
what is the molarity of 2.3 mol of Kl dissolved in 0.5 L of water
Answer:
[tex]4.6\,\,moL\,\,L^{-1}[/tex]
Explanation:
Molarity refers to a measure of concentration.
Molarity = moles of solute/Litres of solution
Molarity refers to number of moles of solute present in this solution.
In order to find a solution's molarity, use value for the number of moles of solute and the total volume of the solution expressed in liters
As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,
Molarity = [tex]\frac{2.3}{0.5} =4.6\,\,moL\,\,L^{-1}[/tex]
What mass of sulfuric acid (H2SO4) is contained in 50.00 mL of a 5.85 M solution? grams
Answer:
28.69 grams
Explanation:
To find the mass, we first need to find the moles. Once we have the moles, it is easy to use the molar mass of H2SO4 to find its mass.
To find the moles, remember that molarity (M) is equal to the moles divided by the volume (L). The volume HAS TO be converted to liters!
M = moles / V
5.85 M = moles / 0.05 L
moles = 0.2925
Now we know that we have 0.2925 moles of sulfuric acid. The molar mass of sulfuric acid is 98.08 g/mol.
0.2925 moles * (98.08 g / mol) = 28.69 grams
Make sense? If you have any questions, don't hesitate to ask!
En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L alcancen el equilibrio a 150°C. ¿Cuáles son las presiones parciales de equilibrio de IBr, I2 y Br2?
Answer:
P IBr: 15.454atm
I₂: 0.923 atm
P Br₂: 0.923atm
Explanation:
Basados en la reacción:
I₂(g) + Br₂(g) ⇄ 2 IBr(g)
La constante de equilibrio, Keq, es definida como:
[tex]Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}[/tex]
Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio
Usando PV = nRT, la presión inicial de IBr es:
P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = 17.3 atm
Siendo las presiones en equilibrio:
P IBr: 17.3 - 2X
P I₂: X
P Br₂: X
Donde X representa el avance de reacción.
Remplazando en Keq:
280 = (17.3 - 2X)² / X²
280X² = 4X² - 69.2X + 299.29
0 = -276X² - 69.2X + 299.29
Resolviendo para X:
X = -1.174 → Solución falsa. No existen presiones negativas
X = 0.923 → Solución real
Así, las presiones parciales en equilibrio de cada compuesto son:
P IBr: 17.3 - 2X = 15.454atm
P I₂: X = 0.923atm
P Br₂: X = 0.923atm
Answer:
[tex]p_{I_2}=0.926atm\\p_{Br_2}=0.926atm\\p_{IBr}=15.5atm[/tex]
Explanation:
Hello,
In this case, given the initial load of 0.500 mol of IBr in the 1.00-L, we compute its initial concentration:
[tex][IBr]_0=\frac{0.500mol}{1.00L}=0.500M[/tex]
Hence, by knowing the original reaction, we should invert it as IBr will produce iodine and bromine considering the initial load:
[tex]2IBr(g)\rightleftharpoons I_2(g) + Br_2(g)[/tex]
Therefore, the equilibrium constant should be inverted:
[tex]K'=\frac{1}{Keq}=\frac{1}{280}=3.57x10^{-3}[/tex]
So we write the law of mass action:
[tex]K'=\frac{[I_2][Br_2]}{[IBr]^2}[/tex]
That in terms of the change [tex]x[/tex] due to the reaction extent turns out:[tex]3.57x10^{-3}=\frac{(x)(x)}{(0.500-2x)^2}[/tex]
In such a way, solving by using solver or quadratic equation we obtain:
[tex]x_1=-0.0339M\\x_2=0.0267M[/tex]
Clearly, the solution is 0.0267M, thus, the equilibrium concentrations are:
[tex][I_2]=x=0.0267M[/tex]
[tex][Br_2]=x=0.0267M[/tex]
[tex][IBr]=0.5M-2x=0.5M-2*0.0267M=0.447M[/tex]
Thus, with the given temperature (150+273.15=423.15K), we compute the partial pressures by using the ideal gas equation:
[tex]p_{I_2}=[I_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{I_2}=0.926atm\\\\p_{Br_2}=[Br_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{Br_2}=0.926atm\\\\p_{IBr}=[IBr]RT=0.447\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{IBr}=15.5atm[/tex]
Best regards.
Particles of the substance have the most kinetic energy when the substance is(a)_______. The part of the graph that represents where the substance has the least amount of potential energy is labeled(b)_______.
multiple choice answers available.
(a)
1. A gas
2. A solid
3. Melting
4. vaporizing
(b)
1. Solid
2. Vaporizing
3. melting
4.liquid
5.gas
Answer: 1- gas 2- solid
Explanation:
Give the molecular geometry and number of electron groups for sf4. give the molecular geometry and number of electron groups for . square planar, 6 electron groups square pyramidal, 6 electron groups t-shaped, 5 electron groups octahedral, 6 electron groups seesaw, 5 electron groups
Answer:
5 electron groups, see saw
Explanation:
During the formation of SF4, the sulfur atom usually bonds with each of four fluorine atoms where 8 of valence electrons are used. The four fluorine atoms have 3 lone pairs of electrons in its octet which will further utilize 24 valence electrons. In addition, two electrons are present as a lone pair on the sulfur atom. We can determine sulfur’s hybridization state by counting of the number of regions of electron density on sulphur (the central atom in the molecule). When bonding takes place there is a formation of 4 single bonds to sulfur and it has 1 lone pair. Looking at this, we can say that the number of regions of electron density is 5. The hybridization state is sp3d.
SF4 molecular geometry is seesaw with one pair of valence electrons. The molecule is polar. The equatorial fluorine atoms have 102° bond angles instead of the actual 120° angle. The axial fluorine atom angle is 173° instead of the actual 180° bond angle.
Have scientists found any reliable predictors for earthquakes, like radon gas release or weird animal behavior?
Answer:
The "Parkfield earthquake prediction experiment" was the most heralded scientific earthquake prediction ever. It was based on an observation that the Parkfield segment of the San Andreas Fault breaks regularly with a moderate earthquake of about M 6 every several decades: 1857, 1881, 1901, 1922, 1934, and 1966.
Explanation:
this is the best I could come up with. luv u.
What conclusion can you draw from the heating curve?
Answer:A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.
A container contakns 5.3×10^12 particles of H2O how many moles is this
The number of particles in a substance can be calculated by multiplying the number of moles of the substance by Avogadro's Number ~ 6.02 × 10²³ particles/mol. Therefore to find the number of moles based on the number of particles, you would divide the number of moles by Avogadro's Number.
Since # of particles of H₂O = 5.3×10¹² particles
then # of moles of H₂O = 5.3×10¹² particles ÷ 6.02 × 10²³ particles/mol
= 8.804 × 10⁻¹² moles
what is the type of bonding for ammonium lauryl sulfate?
Answer:
Hydrogen bonding.
Explanation:
Ammonium lauryl sulfate is also known as ammonium dodecyl sulfate there are two parts in Ammonium lauryl sulfate one is nonpolar hydrocarbon and other part polar sulfate group.
Due to polarity of sulfate group its form hydrogen bond very easily.
It is mainly used as foaming agent the main reason of its use is very much soluble in water and making hydrogen bond with water.
calculate the density of a solid that has a volume of 2cm3 and a mass of 3g
Answer:
The density is 6
Explanation:
p = m × v
p = 3 × 2
p = 6
Hope this helped! :)
The density of the substance depends on the mass and the volume of the substance or object. It is given by the ratio of mass and volume. The density of 3 gm solid is 1.5 g/cm³.
What is density?In chemistry and physics, density is a quantitative measurement that tells about the tightness of the substance packed in an area. It relates to two parameters that include mass and volume.
The density can be said to have a proportion of mass to the volume of the substance. The mass can be in grams or kilograms, while volume can be in a liter, cubic meter, and cubic centimeter.
Given,
Mass of solid (M) = 3 gm
The volume of solid (V) = 2 cm³
Density (ρ) is calculated as:
ρ = M ÷ V
= 3 ÷ 2
= 1.5 gm/cm³
Therefore, 1.5 gm/cm³ is the density of 3 gm solid.
Learn more about density here:
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A group of tissues working together is?
Answer:
An organ
Explanation:
An organ is one or more tissues that work together to form a specific function.
- Hope that helps! Please let me know if you need further explanation.
C2H6O(g) + 3O2(g) 2CO2(g) + 3H2O(g) Inside the piston of an automobile engine, 0.461 g of ethanol (C2H6O) gas reacts with 0.640 grams of oxygen gas to produce carbon dioxide and water, according to the balanced equation shown above. What is the limiting reagent?
Answer:
Oxygen is the limiting reactant.
Explanation:
Hello,
In this case, given the reaction:
[tex]C_2H_6O(g) + 3O_2(g)\rightarrow 2CO_2(g) + 3H_2O(g)[/tex]
Hence, given the masses of both ethanol and oxygen, we are able to compute the available moles ethanol by:
[tex]n_{C_2H_6O}^{available}=0.461g*\frac{1mol}{46g}=0.01mol C_2H_6O[/tex]
Next, we compute the moles of ethanol that react with the 0.640 grams of oxygen considering their 1:3 molar ratio in the chemical reaction:
[tex]n_{C_2H_6O}^{consumed\ by\ O_2}=0.64gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6O}{3molO_2} =0.0067molC_2H_6O[/tex]
In such a way, since there are 0.01 available moles of ethanol but just 0.0067 moles are reacting, we evidence ethanol is in excess, therefore the oxygen is the limiting reactant.
Best regards.
Answer:
Oxygen O₂ will be the limiting reagent.
Explanation:
C₂H₆O(g) + 3 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(g)
First of all you must know by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction) how much mass of each compound reacts. First of all, being:
C: 12 g/moleH: 1 g/moleO: 16 g/molethe molar mass of each reagent is:
C₂H₆O: 2*12 g/mole + 6* 1 g/mole + 16 g/mole= 46 g/moleO₂: 2*16 g/mole= 32 g/moleThen, since 1 mol of C₂H₆O and 3 moles of O₂ react by stoichiometry, the amount of mass that reacts is:
C₂H₆O: 1 mole* 46 g/mole= 46 gO₂: 3* 32 g/mole= 96 gNow you apply a rule of three as follows: if 46 g of C₂H₆O reacts with 96 g of O₂ by stoichiometry, 0.461 g of C₂H₆O with how much mass of O₂ will they react?
[tex]mass of O_{2} =\frac{0.461 grams of C_{2}H_{6} O*96 grams ofO_{2} }{46 grams of C_{2}H_{6} O}[/tex]
mass of O₂= 0.962 grams
But 0.962 grams of O₂ are not available, 0.640 grams are available. Since you have less mass than you need to react with 0.461 g of C₂H₆O, oxygen O₂ will be the limiting reagent.
All chemicals pollute the environment.
True
False
Answer:
False,not all chemicals pollute the enviorment
Explanation:
Hope this helps!
Brainliest?
Answer:
False
Explanation:
Oxygen?
What is frequency and what unit is it measured in?
Answer: The rate at which a vibration occurs that constitutes a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light), usually measured per second. Also it is measured in Hertz.
Explanation:
Answer frequency is the number of occurrences of a repeating event per unit of time. Frequency is measured in Hertz. Unit frequency is measured as the number of wave cycles that occur in one second.
The unit of frequency measurement is hertz
Explanation:
A reaction starts with 20.0 grams of lithium hydroxide (LiOH) and produces 31.0 grams of lithium chloride (LiCl), what is the percent yield of lithium chloride (LiCl)? *
LiOH + KCl - LiCl + KOH
A) 64.5%
B) 88.6%
C) 81.5%
D) 92.8%
Answer:
B) 88.6%
Explanation:
Percent yield equals actual yield divided by theoretical yield
actual yield is 31.0g
theoretical yield is 35g
percent yield was 88.57 which rounds up to 88.6%
How many joules of heat are needed to raise the temperature of 1.5 g of aluminum at 45°C, if the specific heat of aluminum is 0.75 J/g°C? Group of answer choices
Answer:
50.6 J
Explanation:
We have to use the formula
H= mcθ
Where
H= quantity of heat absorbed in joules
m= mass of aluminum= 1.5g
c= specific heat capacity of aluminum= 0.75 J/g°C
θ= rise in temperature of aluminum = 45°C
Substituting into H= mcθ
We have ;
H= 1.5g × 0.75 J/g°C × 45°C
H= 50.6 J
How many copper atoms are in a 70g copper
Answer:
[tex]x = 6.634\times 10^{23}\,atoms[/tex]
Explanation:
The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:
[tex]x = \left(\frac{70\,g}{63.546\,\frac{g}{mol}} \right)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)[/tex]
[tex]x = 6.634\times 10^{23}\,atoms[/tex]
Answer:
6.64x10^23 atoms.
Explanation:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.
1 mole of Cu = 63.5g
If 63.5g of Cu contains 6.02x10^23 atoms,
Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.
Therefore, there are 6.64x10^23 atoms in 70g oh Cu
HELP PLZZZ !!!!!!!!!!!!
Answer:
1/ 421.2 g KNO3
2/ 66.6 g S
3/ 275.0 g CO2
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
Assuming a car (with a 70-L) gas tank can hold approximately 50,000 (5.00 * 10^4) g of octane(C8H18) or 50,000 (5.00 * 10^4) g of ethanol (C2H6O). How much carbon dioxide (CO2), in grams, is produced in one tank of gas from the combustion of each amount?
Answer:
- From octane: [tex]m_{CO_2}=1.54x10^5gCO_2[/tex]
- From ethanol: [tex]m_{CO_2}=9.57x10^4gCO_2[/tex]
Explanation:
Hello,
At first, for the combustion of octane, the following chemical reaction is carried out:
[tex]C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O[/tex]
Thus, the produced mass of carbon dioxide is:
[tex]m_{CO_2}=5.00x10^4gC_8H_{18}*\frac{1molC_8H_{18}}{114gC_8H_{18}}*\frac{8molCO_2}{1molC_8H_{18}}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=1.54x10^5gCO_2[/tex]
Now, for ethanol:
[tex]C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O[/tex]
[tex]m_{CO_2}=5.00x10^4gC_2H_6O*\frac{1molC_2H_6O}{46gC_2H_6O}*\frac{2molCO_2}{1molC_2H_6O}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=9.57x10^4gCO_2[/tex]
Best regards.
ANSWER IT PLEASE!!!!! A virus is a genome, or set of chromosomes, contained inside a protein capsule called a capsid. A virus can be either a single or double strand of RNA or DNA. Although viruses are made of genetic information, they do not have cells. They also need to attach to a host cell in order to live and reproduce. Host cells can be from animals, plants and even bacteria and fungi. Scientists debate whether or not viruses are considered living organisms. Most agree that viruses are not living.
Which of these statements is true based on the information in the passage?
Answer:
?
Explanation:
What are the statements? You've given the passage but not the statements
Which is the control center for the endrocrine system?
Answer:
hypothalamus
Explanation:
Which statements describe gridlines on a map? Select three options. They are measured in degrees. They set up a reference system. They make straight lines on a globe. They run north to west and south to east. They divide Earth into four equal parts.
Answer:
The options that apply to the description of grid-lines of the map are;
They are measured in degrees
They set up a reference system
They divide Earth into four equal parts
FIRST OPTION , SECOND OPTION and FIFTH OPTION are correct.
Explanation:
FIRST OPTION gave the describtion that the grid-lines of the map are measure in degrees,this option is applied to the gridlines on a map because the grid are lined as a result of angular measurement which makes it to makes the unit to be measured degrees and angles.
SECOND OPTION described it as been set up by a reference system which let us know that the area that are plotted were all grid as a result of the size
FIFTH OPTION also applied to the
description of the gridlines on a map because the Earth is divided into 4 equal parts through the Prime Meridian i.e the latitudinal line and longitudinal line .
.
Answer:
They are measured in degrees.
They set up a reference system.
They divide Earth into four equal parts.
Explanation:
i took the test
Calculate the hyrdrogen ion concentration [h+] for the aquesous solution in which [oh-] is 1 x 10-2 mol/l.Is the solution acidic,basic,or neutral? Show your work
Answer:
- [tex][H^+]=1x10^{-12}[/tex]
- Basic.
Explanation:
Hello,
In this case, given the concentration of hydroxyl ions, one could compute the pOH as shown below:
[tex]pOH=-log([OH^-])=pOH=-log(1x10^{-2})=2[/tex]
Then, since the pOH and the pH are related by:
[tex]pH+pOH=14[/tex]
One computes the pH:
[tex]pH=14-pOH=14-2=12[/tex]
Now, we compute the concentration of hydronium by:
[tex][H^+]=10^{-pH}=10^{-12}[/tex]
[tex][H^+]=1x10^{-12}[/tex]
Finally, since the pH is greater than 7 (neutral point) we conclude that the solution is basic.
Best regards.
Answer:
A. Hydrogen ion concentration, [H+] is 1x10^–12 mol/L
B. Since the pH is 12, the solution is basic.
Explanation:
Data obtained from the question. This includes the following:
Concentration of Hydroxide ion, [OH-] = 1x10^–2 mol/L
Concentration of Hydrogen ion, [H+] =.?
pH =..?
A. Determination of the hydrogen ion concentration, [H+] .
The hydrogen ion concentration, [H+] can be obtained as follow:
[H+] x [OH-] = 1x10^–14
[OH-] = 1x10^–2
[H+] x 1x10^–2 = 1x10^–14
Divide both side by 1x10^–2
[H+] = 1x10^–14 / 1x10^–2
[H+] = 1x10^–12 mol/L
B. Determination of the pH of the solution.
The pH of the solution can be obtained as follow:
pH = –Log [H+]
[H+] = 1x10^–12 mol/L
pH = –Log 1x10^–12
pH = 12.
Then pH of a solution ranges between 0 and 14.
A pH reading between 0 and 6 is termed an acidic solution, a pH reading of 7 is termed a neutral solution and a pH reading between 8 and 14 indicates an alkaline or a basic solution.
The higher the pH value, the more alkaline or basic the solution becomes.
Since the pH is 12, the solution is basic.
Can someone answer these questions for me please?
15. Use bond energies to determine the ∆H for the combustion of methane (CH₄).
16. Use Hess's law to determine the ∆H for the combustion of liquid methanol (CH₃OH).
17. Using your answers from question 16, how much energy will you get from burning 245.0 g of methanol in excess oxygen?
18. The ∆S is 209.6 J/K for the following reaction:
C₂H₄ (g) + 3O₂ (g) → 2CO₂ (g) + 2H₂O (g)
• What is the absolute entropy of O₂ (g)?
19. What is ∆G for the following reaction at 298 K?
2C₆H₆ (l) + 150₂ (g) → 12CO₂ (g) + 6H₂O (g)
20. If a reaction has a ∆H of -120.0 kj/mole and is spontaneous for all temperatures less than 200.0 K, what is ∆S?
Answer:
wowits too long
Explanation:
Zinc reacts with iodine in a synthesis reaction: Zn + I2 → Znl2. What is the theoretical yield of Znl2, if 1.912 mol of zinc is used?
Answer:
610.3g
Explanation:
Zn:
m = 1.912
Zn : ZnI₂
1 : 1
1.912 : 1.912
ZnI₂:
m = 1.912 Mr = 65.4 + 2(126.9) = 319.2
mass = m×Mr:
mass = 1.912×319.2
mass = 610.3104 → 610.3g
The theoretical yield of Znl2, if 1.912 mol of zinc is used is 610.3g
Calculation of theoretical yield:Since Zinc reacts with iodine in a synthesis reaction: Zn + I2 → Znl2
And, there is 1.912 mol of zinc
So,
Zn : ZnI₂
1 : 1
And,
1.912 : 1.912
For
ZnI₂:
m = 1.912 Mr = 65.4 + 2(126.9) = 319.2
Now
mass = m×Mr:
= 1.912×319.2
= 610.3104
= 610.3g
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how many number of electrons are in nitrogen and aluminium in their ionic States?
