What volume will 28 grams of nitrogen gas occupy at 27 Celsius and a
pressure of 785 mm Hg?

Answers

Answer 1

Answer: [tex]2.49\ m^3[/tex]

Explanation:

Given

Mass of nitrogen present [tex]m=28\ g[/tex]

Temperature [tex]T=27^{\circ}C\equiv 300\ K[/tex]

Pressure [tex]P=785\ mm\ \text{of}\ Hg\ \text{or}\ 1.032\ atm[/tex]

The molar mass of Nitrogen [tex]M=28\ g/mol[/tex]

No of moles of nitrogen present

[tex]n=\dfrac{m}{M}\\\\n=\dfrac{28}{28}\\\\n=1[/tex]

Using [tex]PV=nRT[/tex]

[tex]\Rightarrow 1.032\times V=1\times 8.314\times 300\\\\\Rightarrow V=\dfrac{2494.2}{1.032}\\\\\Rightarrow V=2494.2\ L\ \text{or}\ 2.49\ m^3[/tex]


Related Questions

describe two sources of energy and explain how they work

please help me (50points)​

Answers

Solar energy:-

In this way the energy generated through sun light with the help of solar panels and to be used in many works.

Wind energy:-

This is generated by moving turbines with windmills .It is used to create electric energy

a. Explain why the pie pans flew off the van de Graaf generator
b. Give a detailed explanation of why the rabbit fur and the plastic rod were attracted to each other after we rubbed them together but not before
c. Describe two things you could change to increase the force of electrical attraction between two objects (this is about Coluomb's Law).

Answers

Answer:

Static energy is an energy between two charges.

Explanation:

a). A van de Graff generator builds up a positive electric charge on the dome by separating the negative static electric charges from the positive static charge using a quickly moving belt. The positive charge collects on the large metal dome of the generator. When the charge builds up is large enough, a lighting like spark can shoot from the dome to a grounded discharge rod.

             Like electric charges always repel each other, and oppositely electric charges will attract each other. When the aluminum pans are being charged by the van de Graff generator, then each of them attain the same positive polarity similar with the dome. Thus,  positive charge starts to accumulate over the surface of each of the pie pan. Each aluminum pan repels the others. These repulsive forces between the pans are so strong that they succeed in overcoming the gravity force and thus the top of the pan is pushed away from the generator's dome.

b). Static electricity is produced by a concentration of negative and positive electric charges. Like charges pushes away each other while unlike charges pulls each other.

            Objects generally have same numbers of positive charges as well as negative charges. And if there is any small imbalance in numbers of the charges on the object, it is charged.

            Negative charges easily torn away from the materials like the fur or hair. Also, the negative charges are held on other materials like the plastics. If we rub a plastic rod with fur, the negative charges will get transferred from fur to rod. The rod gets negatively charged and the fur is positively charged. As a result, the rabbit fur and the plastic rod were attracted to each other.

c). Coulomb's law stated that :

  [tex]$F=\frac{KQ_1Q_2}{d^2}$[/tex]    .............(i)

where, [tex]$Q_1$[/tex]  and [tex]$Q_2$[/tex] are the charges of two objects d is the distance between two objects.

As from the above equation, we can say that force of electrical attraction between two objects depends on the charges and the distance between objects.

1. The electrical force between two charged object is inversely proportional to the distance of separation between two objects.

Decreasing separation distance (d) between the objects will increase its attraction force.

2. And, increasing the charges of two objects(+ve and -ve) increases the force of attraction between two objects.

Soil comes in different colors.

Answers

Answer: yes they come in different colors.

Explanation:

Most shades of soil is mostly black,brown,red,gray,and white the color of soil and other properties including texture, structure, and consistency are used to distinguish and identify soil.

Based on the molar masses. how can you tell that an equation is balanced

Answers

You can tell if each side of the equation has the same molar mass.

Final volume of a .50 M H3PO4 solution prepared from 50 mL of a 6 M H3PO4 solution

Answers

Answer:

600 mL

Explanation:

From the question given above, the following data were obtained:

Initial concentration (C₁) = 6 M

Initial volume (V₁) = 50 mL

Final concentration (C₂) = 0.5 M

Final volume (V₂) =?

Using the dilution formula (i.e C₁V₁ = C₂V₂) we can obtain the final volume as illustrated below:

C₁V₁ = C₂V₂

6 × 50 = 0.5 × V₂

300 = 0.5 × V₂

Divide both side by 0.5

V₂ = 300 / 0.5

V₂ = 600 mL

Thus, the final volume is 600 mL

A sample of polonium-210 has an initial mass of 390 milligrams (mg). If the half-life of polonium-210 is 36 days, how many mg of the sample remains after 36 days?

A.
48.75 mg

B.
392 mg

C.
97.5 mg

D.
195 mg

Answers

Answer:

d

Explanation:

4. Calculate the final temperature of 75.4 g water originally at 12.6 °C after it absorbs 3.85 kcal
of heat.

Answers

Answer:

63.7 °C

Explanation:

Step 1: Given and required data

Mass of water (m): 75.4 gInitial temperature (T₁): 12.6 °CAbsorbed heat (Q): 3.85 kcalSpecific heat capacity of water (c): 1 cal/g.°C

Step 2: Calculate the final temperature of the water (T₂)

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = Q/c × m + T₁

T₂ = 3.85 × 10³ cal/(1 cal/g.°C) × 75.4 g + 12.6 °C = 63.7 °C

The more energy that particles have, the ___ they move.

Answers

The more energy that particles have, the more they move.

where do you think water vapor in air comes from?

Answers

Heat from the Sun causes water to evaporate from the surface of lakes and oceans. This turns the liquid water into water vapor in the atmosphere. Plants, too, help water get into the atmosphere through a process called transpiration

At a certain temperature the rate of this reaction is first order in HI with a rate constant of 0.0632 s
2HI g = H2 g + I2 g
Suppose a vessel contains HI at a concentration of 1.28M. Calculate how long it takes for the concentration of HI to decrease to 17.0% of its initial value.

Answers

Answer:

[tex]28.037\ \text{s}[/tex]

Explanation:

[tex][A]_0[/tex] = Initial concentration = 1.28 M

[tex][A][/tex] = Final concentration = [tex]0.17[A]_0[/tex]

k = Rate constant = 0.0632 s

t = Time taken

For first order reaction we have the relation

[tex]kt=\ln\dfrac{[A]_0}{[A]}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{[A]}}{k}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{0.17[A]_0}}{0.0632}\\\Rightarrow t=28.037\ \text{s}[/tex]

Time taken to reach the required concentration would be [tex]28.037\ \text{s}[/tex].

Answer the above pic

i bet no one can solve this correctly with steps​

Answers

Answer:

solution given:

log k=4-[tex] \frac{200}{t} [/tex]

so,

On comparison

∆S°/R = 4

∆ S° = 4R

mousam brother is correct

hope it helps you have a good day

WHAT IS A ROCK?

Please put the answer below


DO ITTT NOWWWWWWWWWWWWWW


|

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Answers

A rock is any naturally occurring solid mass or aggregate of minerals or mineraloid matter. It is categorized by the minerals included, its chemical composition and the way in which it is formed
A rock is any naturally occurring solid mass or aggregate of minerals or mineraloid matter. It is categorize by the minerals included, it’s chemical composition and the way in which it is formed.

What is the difference between chemical change and physical change

Answers

In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed. Hope this helps!

Answer:

In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.

100.0 g of water was placed in a simple, constant-pressure calorimeter. The temperature of the water was recorded as 295.0 K. A 20.0 g copper block was heated to 353.0 K and then dropped into the water in the calorimeter. What was the final temperature of the water if the specific heat capacities of copper is 0.385 J/g K

Answers

Answer:

[tex]296.05\ \text{K}[/tex]

Explanation:

[tex]m_w[/tex] = Mass of water = 100 g

[tex]c_w[/tex] = Specific heat of water = [tex]4.184\ \text{J/g K}[/tex]

[tex]m_c[/tex] = Mass of copper = 20 g

[tex]c_c[/tex] = Specific heat of copper = [tex]0.385\ \text{J/g K}[/tex]

[tex]\Delta T_w[/tex] = Temperature change in water = [tex](T-295)[/tex]

[tex]\Delta T_c[/tex] = Temperature change in cooper = [tex](353-T)[/tex]

T = Final temperature of the system

The heat balance of the system is given by

[tex]m_wc_w\Delta T_w=m_cc_c\Delta T_c\\\Rightarrow 100\times 4.184\times (T-295)=20\times 0.385\times (353-T)\\\Rightarrow 418400\left(T-295\right)=7700\left(353-T\right)\\\Rightarrow 418400T-123428000=2718100-7700T\\\Rightarrow T=\frac{1261461}{4261}\\\Rightarrow T=296.05\ \text{K}[/tex]

The final temperature of the water is [tex]296.05\ \text{K}[/tex].

The final temperature of the water when placed in a calorimeter is 296.05K

HOW TO CALCULATE FINAL TEMPERATURE:

The final temperature of water placed in a calorimeter can be calculated using the following expression:

Q(water) = - Q(copper)

(m × c × ∆T) water = - {m × c × ∆T} copper

Where;

Mass of water = 100 gSpecific heat of water = 4.184 J/g KMass of copper = 20 gSpecific heat of copper = 0.385 J/g KTemperature change in water = T - 295KTemperature change in copper = T - 353K

100 × 4.184 × (T - 295) = - {20 × 0.385 × (T - 353)}

418.4T - 123428 = - (7.7T - 2718.1)

418.4T - 123428 = -7.7T + 2718.1

418.4T + 7.7T = 123428 + 2718.1

426.1T = 126146.1

T = 126146.1 ÷ 426.1

T = 296.05K

Therefore, the final temperature of the water when placed in a calorimeter is 296.05K.

Learn more at: https://brainly.com/question/10987564?referrer=searchResults

how many atoms are in 14 moles of cadium

Answers

Answer:

14x6.02x10^23=8.428x10^23 atoms

Answer:

atoms are in 14 moles of cadmium. Cadmium is present in some foods and is emitted when fossil fuels like as coal and oil is used, smoking cigarettes. It is used in craft glazes, metal batteries, and coatings. We know that 1 mole of Cadmium (Cd contains) 6.023*1023 atoms, which is Avogadro's number

Explanation:

Calculate the mass of 0.900 mol of lithium thiocyanate. ​

Answers

Answer:

58.6 g.

Explanation:

Hello there!

In this case, since the molecular formula of lithium thiocyanate is LiCNS and therefore its molar mass is 65.1 g/mol, it possible to perform the calculation of the mass of 0.900 moles of this substance by recalling the following equivalence statement:

1 mol =  65.1 g.

Thereby, we can calculate the required mass as shown below:

[tex]0.900mol*\frac{ 65.1g}{1mol}\\\\58.6 g[/tex]

Best regards!

Mechanical digestion begins in the_____ and involves physical processes, such as chewing.​

Answers

Answer:

begins in the mouth

A 3mL sample of a 200 Molar solution is left open on a lab
counter for two weeks, after which the concentration of the solution is 6 M. What is the new volume of the solution?

Answers

Answer: New volume of the solution is 100 mL.

Explanation:

Given: [tex]V_{1}[/tex] = 3 mL,     [tex]M_{1}[/tex] = 200 M

[tex]M_{2}[/tex] = 6 M,     [tex]V_2[/tex] = ?

Formula used to calculate the new volume of solution is as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]M_{1}V_{1} = M_{2}V_{2}\\200 M \times 3 mL = 6 M \times V_{2}\\V_{2} = \frac{200 M \times 3 mL}{6 M}\\= 100 mL[/tex]

Thus, we can conclude that new volume of the solution is 100 mL.

But Are Punnett square percentages always correct?

Answers

Answer:

yes

Explanation:

cuz is a square and if all angles are equal of a square then it is correct

Cuo
+ H2 → → Cu + + H20
colorless
water
black
powder
reddish
solid
gas
vapor

Answers

Explanation:

because there is 2 hydrogen atoms in the reactions side of the equation (you can tell because the H has a 2 in the subscript) you have to have 2 hydrogen atoms in the reactants side to help balance out the equation. and since the copper and oxygen atoms are already balanced there is no coefficient needed.

What is the empirical formula for a compound if a 2.50g sample contains 0.900g of calcium and 1.60g
of chlorine? (3pts]

Answers

Answer:

CaCl₂

Explanation:

First we convert the given masses of elements into moles, using their respective molar masses:

0.900 g Ca ÷ 40 g/mol = 0.0225 mol Ca1.60 g Cl ÷ 35.45 g/mol = 0.045 mol Cl

Now we divide those numbers of moles by the lowest value among them:

0.0225 mol Ca / 0.0225 mol = 10.045 mol Cl / 0.0225 mol = 2

Meaning the empirical formula for the compound is CaCl₂.

Help me please jus tell me 1 2 3 etc for the answers thank you!

Answers

Answer:

1. lakes and rivers 2. groundwater 3. watershed 4. pollution

Explanation:

If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?

Answers

Answer:

412 g Cl₂

General Formulas and Concepts:

Atomic Structure

Reading a Periodic TableMolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

Step 3: Convert

[DA] Set up:                                                                                                       [tex]\displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})[/tex][DA] Divide/Multiply [Cancel out units]:                                                           [tex]\displaystyle 412.072 \ g \ Cl_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

412.072 g Cl₂ ≈ 412 g Cl₂

A 25.0 mL NaOH solution of unknown concentration was titrated with a 0.189 M HCl solution. 19.6 mL HCl was required to reach the equivalence point. In a separate titration, a 10.0 mL H3PO4 solution was titrated with the same NaOH solution. This time, 34.9 mL NaOH was required to reach the equivalence point. What is the concentration of the H3PO4 solution

Answers

Answer:

0.172 M

Explanation:

The reaction for the first titration is:

HCl + NaOH → NaCl + H₂O

First we calculate how many HCl moles reacted, using the given concentration and volume:

19.6 mL * 0.189 M = 3.704 mmol HCl

As one HCl mol reacts with one NaOH mol, there are 3.704 NaOH mmoles in 25.0 mL of solution. With that in mind we determine the NaOH solution concentration:

3.704 mmol / 25.0 mL = 0.148 M

As for the second titration:

H₃PO₄ + 3NaOH → Na₃PO₄ + 3H₂O

We determine how many NaOH moles reacted:

34.9 mL * 0.148 M = 5.165 mmol NaOH

Then we convert NaOH moles into H₃PO₄ moles, using the stoichiometric coefficients:

5.165 mmol NaOH * [tex]\frac{1mmolH_3PO_4}{3mmolNaOH}[/tex] = 1.722 mmol H₃PO₄

Finally we determine the H₃PO₄ solution concentration:

1.722 mmol / 10.0 mL = 0.172 M

What dosage in grams per kilogram of body weight does a 134 lb woman receive if she takes two 275 mg tablets of penicillin?
How many 150. mg tablets should a 31 lb child take to receive the same dosage?

Answers

Answer:

The dosage is 0.0906 g/kgThe child should take 8.5 tablets to receive the same dosage

Explanation:

First we convert 134 lb into kg:

1 lb = 0.453 kg134 lb * [tex]\frac{0.453kg}{1lb}[/tex] = 60.702 kg

Then we convert 275 mg into g:

1000 mg = 1 g275 mg * [tex]\frac{1g}{1000mg}[/tex] = 0.275 g

Now we can calculate the dosage in grams per kilogram of body weight, keeping in mind that two tablets are consumed:

(0.275 g) * 2 / 60.702 kg = 0.0906 g/kg

As for the second part, first we convert 31 lb into kg:

31 lb * [tex]\frac{0.453 kg}{1lb}[/tex] = 14.043 kg

Now we calculate how many penicillin grams should be consumed:

14.043 kg * 0.0906 g/kg = 1.27 g

We convert 1.27 g of penicilin into mg:

1.27 g * 1000 = 1270 mg

Finally we calculate how many 150 mg tables should be taken:

1270 mg / 150 mg = 8.5 tablets

A sample of polonium-210 has an initial mass of 390 milligrams (mg). If the half-life of polonium-210 is 36 days, how many mg of the sample remains after 72 days?

A.
392 mg

B.
195 mg

C.
97.5 mg

D.
48.75 mg

Answers

Answer:

C

Explanation:

I got this question right on my test.

Given that the nucleophilic substitution reaction used 5.0 mL of t-pentyl alcohol and 12.0 mL of conc. hydrochloric acid to produce t-pentyl chloride, what is the theoretical yield of t-pentyl chloride, in grams

Answers

Answer:

4.90 g

Explanation:

Given that:

volume of t-pentyl alcohol = 5 mL

the standard density of t-pentyl alcohol = 0.805 g/mL

Recall that:

density = mass(in wt) /volume

mass = density × volume

mass = 0.805 g/mL × 5 mL

mass = 4.03 g

Volume of HCl used = 12 mL

The reaction for this equation is shown in the image attached below.

From the reaction,

88.15 g of t-pentyl alcohol reacts with concentrated HCl to yield 106.59 g pf t-pentyl chloride.

4.03 g of t-pentyl alcohol forms,

[tex]= \dfrac{106.59 \ g \times 4.03 \ g}{88.15 \ g}[/tex] of t-pentyl chloride.

Therefore,

Theoretical yield of t-pentyl chloride = 4.90 g

If 1.00 g of KCl is completely dissolved in 24.5 g of water, what is the percent composition (by mass) of the solution that is formed?

Answers

Answer:

3.92%

Explanation:

The solution that is formed is of KCl in water. This means that the percent composition by mass is given by the formula:

Mass of KCl / Mass of Solution * 100%

We now calculate the mass of solution:

Mass of Solution = Mass of KCl + Mass of Water = 1.00 g + 24.5 gMass of Solution = 25.5 g

Finally we calculate the percent composition:

1.00 g / 25.5 g * 100% = 3.92%

Laughing gas can decompose into nitrogen and oxygen

Answers

Nitrous oxide decomposes into nitrogen and oxygen, according to 2 N2O (g) -> 2 N2 (g) + O2 (g). ... In an experiment, a stream of N2O is passed through a tube 25 mm in diameter and 20 cm long. The flow rate of the gas is 0.75 L/min.

Carbon-11 decays by position emission.The nuclide formed product is

Answers

Answer:

They demonstrated that carbon-11 decays by positron emission to the stable nuclide 11B [Eq. (1)].

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