What was the independent variable in Mendel's pea plant experiment?

A.The temperature
B.Cross-pollination
C.Type of plant
D.Characteristic of the offspring

Answers

Answer 1
The answer for this is “D” I do believe

Related Questions

what characteristics of a metallic bond explains some of the properties of metals

Answers

Answer:

See Explanation

Explanation:

Metallic bonds involve attraction between electrons and positively charged metal ions. The metals are ionized and electrons form a sea of valence electrons. These loosely bound electrons surround the nuclei of the metals.

The presence of this sea of electrons explains the fact that metals conduct electricity and heat due to the free valence electrons.

Due to the nature of the bonding between metal atoms,metals are malleable and ductile.

Due to the strong electrostatic interaction between metal ions and electrons, the metallic bond is very strong and is very difficult to break thereby accounting for the greater strength of metals as the size of the metallic ion decreases.

What is the energy of a photon?
A. A photon has no energy.
B. The energy of a photon is hxc.
c. The energy of a photon is hx 2.
D. The energy of a photon is h* f.

Answers

D, the energy of a photon is h times f

g A student determines the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while the crucible is empty, then reweighing the crucible and lid with a sample of the hydrate, heating the crucible and lid with a Bunsen burner and then reweighing the crucible and lid with the sample after cooling to room temperature. Which error will result in too high a value for the amount of water of hydration

Answers

The question is incomplete, the complete question is;

A student determines the number of moles of water in a

hydrated metal oxide by weighing a clean, dry crucible

and lid while the crucible is empty, then reweighing the

crucible and lid with a sample of the hydrate, heating the

crucible and lid with a Bunsen burner and then

reweighing the crucible and lid with the sample after

cooling to room temperature. Which error will result in

too high a value for the amount of water of hydration?

(A) The heating is conducted only once instead of the

three times recommended by the procedure.

(B) The lid is left off the crucible when it is weighed

with the hydrated oxide.

(C) The metal oxide reacts partially with oxygen in the

air, forming a compound in a higher oxidation state.

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Answer:

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Explanation:

It is possible to determine the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while the crucible is empty, then reweighing the crucible and lid with a sample of the hydrate. The crucible and lid with the sample are heated, cooled and reweighed.

As this process is going on, suppose some of the heated oxide is spilled from the crucible, then the mass of heated or anhydrous oxide decreases leading to a consequent increase in the number of moles of water in the hydrated metal oxide, hence the answer above.

The too high a value for the amount of water of hydration error is occur due to heating of given hydrated sample.

What is hydrated compounds?

Hydrated compounds are those compounds in which water molecule is present with the normal compound.

To get the correct value of weight of hydrated compound, first we have to weigh the empty crucible and lid and then with sample of compound in the crucible and lid. After this substract empty weigh of crucible & lid from the sample-crucible-lid weigh. If we substract the weigh from heated sample crucible and lid, then we get the error because the hydrated water molecule may decompose due to heating and moles of water increases.

Hence, error will occur if we heat the sample.

To know more about hydrated compound, visit the below link:

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Describe the effects lenses have on light and their possible technological applications.

Answers

Answer:

lenses is used to refract light inward or outward

there are two type of lenses. Concave and convex lense

Convex lense converge ray of light

Concave lense diverge ray of light

useful application =:

=> camera

=> flashlight

=> lasers

=> Binoculars and Telescope

hope it helps

Answer:

Explanation:

Lenses are made of glass or other transparent materials for light. They are optically dense so light slows down on entering it. It is called refraction which bends the light on entering and leaving the lenses.

Refraction by lenses can be used for all kinds of optical applications, e.g. camera, telescope, magnifying glasses, solar heating.

Excessive use of chemical fertilizer causes chemical pollution.how?​

Answers

Answer:

Chemical fertilizers contain various chemicals that cause harm to soil and water.

Explanation:

Chemical fertilizers contain various chemicals such as phosphates, nitrates which can cause water pollution. Eutrophication caused by the environmental nitrogen and phosphorous that causes rich minerals and chemicals in the water.

These can cause excessive growth of the algae and phytoplankton that will cause depletion of the oxygen from the water body and organisms will die due to this.

What is the Same about carbohydrates, proteins , and fats ?

Answers

Answer:

The main similarity between carbohydrates, proteins and fats is that they are all used for energy.

Explanation:

I hope this helps, have a blessed day.

How does publishing in scientific journals help ensure that science leads to
reliable results?
A. It allows results to be reviewed and reproduced by other
scientists.
B. It allows the public to decide if science is worthwhile.
C. It shows which experiments are the most popular with scientists.
D. It gives scientists a reason to do more experiments.

Answers

Answer:

A. it allows results to be reviewed and reproduced by other scientists.

Terry, a student, performs a titration. He completes these steps as part of his titration procedure: 1. He cleans and rinses a burette with standardized base. 2. He fills the burette with standardized base solution. 3. He reads and records the initial burette volume. 4. He adds a base from the burette to an acid. 5. He observes a color change in the Erlenmeyer flask. 6. He stops the addition of base from the burette. 7. He reads and records the final burette volume. Which steps will provide information needed to calculate the volume of base needed to reach the equivalence point? A. 1 and 6 B. 3 and 7 C. 3, 4, and 6 D. 1, 2, and 7

Answers

Answer:

D

Explanation:

D is the answer because 2 is needed to know

Answer:

B) 3 and 7

Explanation:

i just took the test

What will change more solid NiCl2 is added

Answers

The Molarity will increase.

A saline solution, NaCl in water, is 0.92 % (m/v). How many grams of NaCl are required to prepare 35.0 mL of this solution?

Answers

Answer:

0.322 g

Explanation:

Since our concentration is given in mass per volume percent % (m/v)

% (m/v) = mass of solute in g/volume of solution in mL × 100%

Since % (m/v) = 0.92 and volume of the required solution is 35.0 mL, we find the mass of NaCl from

mass of NaCl = % (m/v)/100 % × volume of solution

= 0.92 % (m/v)/100 %× 35 mL

= 0.0092 × 35

= 0.322 g

The study of a chemical is called chemistry.

The correct answer is 0.322 g

The saline is said that the amount of salt present in the solution. The formula used to solve the question is as follows:-

[tex]\frac{m}{v} = \frac{mass \ of\ solute}{volume\ of\ solution} * 100[/tex]

The data is given as follows:-

0.92 %(m/v)Volume is 35.0 mL,

Mass of NaCl is as follows:-

 [tex]\frac{0.92}{100} * 35 mL[/tex]

[tex]0.0092 * 35\\= 0.322 g[/tex]

Hence, the correct answer is 0.322g.

For more information, refer to the link:-

https://brainly.com/question/14698383

Select the correct answer.
What is the molecularity of this elementary step?
A+ A+B-->C+D
A.
unimolecular
B.
bimolecular
c.
trimolecular
D.
tetramolecular

Answers

Answer: C not really sure thoo

Please someone answer this asap

Answers

Answer:

b or c but I would just pick c

Answer:

C

Explanation:

Sun is an energy source not a matter.

When 15. 3 g NaCl reacts with 81.70 g Pb(NO3)2, sodium chloride is the limiting reactant, according to the balanced equation below. How many grams of lead (II) nitrate will remain after the reaction stops?

2 NaCl + 1 Pb(NO3)2 → 2 NaNO3 + 1 PbCl2

Answers

Answer:

[tex]m_{Pb(NO_3)_2}^{leftover}=38.34g[/tex]

Explanation:

Hello there!

In this case, given the chemical reaction by which the sodium chloride reacts with lead (II) nitrate and the former is the limiting reactant, it is possible to calculate the mass of lead (II) nitrate that are actually consumed according to the 2:1 mole ratio between them:

[tex]m_{Pb(NO_3)_2}=15.3gNaCl*\frac{1molNaCl}{58.44gNaCl}*\frac{1molPb(NO_3)_2}{2molNaCl} *\frac{331.21gPb(NO_3)_2}{1molPb(NO_3)_2} \\\\m_{Pb(NO_3)_2}=43.36gPb(NO_3)_2[/tex]

Thus, the leftover of lead (II) nitrate is:

[tex]m_{Pb(NO_3)_2}^{leftover}=81.70g-43.36g\\\\m_{Pb(NO_3)_2}^{leftover}=38.34g[/tex]

Best regards!

How many liters would you need to make a 0.8 M solution with 20 grams of lithium chloride?

Answers

Answer:

0.5875L

Explanation:

concentration = mole/ volume

n(LiCl) = 20 / (7 + 35.5) = 0.47 mol

volume = mole / conc.

volume = 0.47 /0.8

= 0.5875 dm³ = 0.5875L

classify each of the following reactions when only the reactants are given and fill in the products.

explain your answer for brainliest.

Answers

Answer:

CO2 + MgO

Explanation:

We want the number of each element on the Reactants (Left side) to be equal to the number of each element on the Product side (Right side).

The pressure on 200 milliliters of a gas at constant
temperature is changed from 380 torr to 760 torr. The new
volume of the gas is

Answers

answerA) 100 mL

Explanation:

At constant temperature and number of moles, Using Boyle's law  

Given ,  

V₁ = 200 mL

V₂ = ?

P₁ = 60 kPa

P₂ = 120 kPa

The new volume of the gas is 100mL

Boyle's law is use to calculate the volume of a gas in relation with its pressure. The Boyle's law equation is as follows:

P1V1 = P2V2

Where;

P1 = initial pressure of the gas (torr)

P2 = final pressure of the gas (torr)

V1 = initial volume of the gas (mL)

V2 = final volume of the gas (mL)

According to the information of this question, the pressure on 200mL of a gas changed from 380 torr to 760 torr. Hence;

V1 = 200mL

V2 = ?

P1 = 380torr

P2 = 760torr

Using P1V1 = P2V2

V2 = P1V1/P2

V2 = (380 × 200) ÷ 760

V2 = 76000 ÷ 760

V2 = 100mL

Hence, the new volume of the gas is 100mL

Learn more: https://brainly.com/question/22467228

Which statement describes the best way to determine how different levels of light affect the growth of seedling plants?

Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.

Choose five different light levels, and place one identical plant under each of the light levels for exactly one week.

Choose four different light levels, and place eight different plant types under the light levels, two under each one, and observe them every day.

Choose one type of light and one type of plant, and then observe the plant for at least four weeks, measuring it each day.

Answers

Answer:

Choose three different light levels, and place four identical plants under each light level to observe the light’s effect on multiple plants.

Explanation:

करताह!
गर्मियों में घड़े का जल ठंडा क्यों होता है?

Answers

Answer:

I don't understand the question

Explanation:

what is your name

My swimming pool is rectangular (16 feet by 34 feet) and has a depth of 6 feet. Lets imagine that my pool water is full to the top and is heated by a laser that emits photons with a wavelength of 520 nm. The starting temperature of my pool is a chilly 52 degrees Celsius. How many moles of photons would be required to heat the pool to a balmy 80 degrees Celsius

Answers

Answer:

Number of moles of photons required = 5.04 × 10⁴ moles

Explanation:

The energy of a photon can be calculated from Planck's equation E = hc/λ

Where h = 6.63 × 10-³⁴ Js and c, the velocity of light = 3.0 × 10⁸ m/s

Energy of one mole of photons = N₀ × hc/λ

wavelength of photon, λ = 520 nm = 5.20 × 10-⁷ m

Energy of one mole of photons = 6.02 × 10²³ × 6.63 × 10−³⁴ × 3 × 10⁸/5.20 × 10-⁷

Energy of one mole of photons = 2.30 × 10⁵ J/mol

Energy required to raise the temperature of a given mass of a substance, E = mcΔT

Where m is mass of substance,  c is specific heat capacity,  ΔT is temperature difference

Mass ofnwternin the pool = volume × density

Volume of water = Volume of swimming pool

Volume of water = 16 × 34 × 6 ft³ = 3264 ft³

1 ft³ = 28316.8 cm³; 3264 ft³ = 28316.8 × 3264 = 92426035.2 cm³

Density of water = 1 g/cm³

Mass of water = 92426035.2 cm³ × 1 g/cm³ = 92426035.2g

ΔT = 80°C - 50°C = 30°C, c = 4.18 J/g/K

Energy required to raise 92426035.2 g water by 30° C = 92426035.2 × 4.18 × 30

Energy required = 1.16 × 10¹⁰ J

Hence, number of moles of photons required = 1.16 × 10¹⁰ J/2.30 × 10⁵ J/mol

Number of moles of photons required = 5.04 × 10⁴ moles

Help please asap will mark brainliest!

Answers

Answer:

28.466256

Explanation:

what happens to gas molecules as the pressure is increased while the temperature and volume of the container remain constant according to the kinetic molecular theory

Answers

Answer:

According to the kinetic molecular theory of gases, the average speed and kinetic energy of gas molecules would INCREASE.

Explanation:

In the kinetic molecular theory of gases, assumptions were made based on macroscopic properties of gas (pressure, volume and temperature) which are as a result of the microscopic properties like the position and the speed of the gas molecules. The kinetic molecular theory explains the behaviour of gases through the following 5 assumptions made about an ideal gas;

--> Molecules of a gas are in constant and rapid motion in straight lines until they collide with one another and with the walls of their containers.

--> The actual volume occupied by the had is negligible compared with the volume of the container.

--> Forces of attraction or repulsion between the molecules of a gas are negligible

--> The collision between the molecules is perfectly elastic.

--> The average kinetic energy of the gas molecules is proportional to the temperature of the gas.

Because gas molecules are in constant motion, it has kinetic energy which can be altered when there is increase in pressure. An increase in pressure will cause gas molecules to collide more frequently with one another. This in turn leads to increase in average speed and the kinetic energy of the individual molecules.

I need to know what the question is asking please help

Answers

it’s the elements that weigh the most are created when the events!
u on canvas?

Answer: What events create the heaviest elements?

I would Select:

Neutron Star Collissions

Supernova

A chemistry student heated 2.255 g of oxygen gas in the presence of 5.145

Answers

Answer:

a

Explanation:

The answer to your question is 6.21 L

If there are 1.55 x 1024 molecules of hydrogen peroxide (H2O2), what is the mass of the
sample? ​

Answers

Answer:

87.54 g of H₂O₂

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 1.55×10²⁴ molecules

Mass of H₂O₂ =.?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of H₂O₂

Next, we shall determine the mass of 1 mole of H₂O₂. This can be obtained as follow:

1 mole of H₂O₂ = (2×1) + (2×16)

= 2 + 32

= 34 g

Thus,

6.02×10²³ molecules = 34 g of H₂O₂

Finally, we shall determine mass of H₂O₂ that contains 1.55×10²⁴ molecules. This can be obtained as follow:

6.02×10²³ molecules = 34 g of H₂O₂

Therefore,

1.55×10²⁴ molecules

= (1.55×10²⁴ × 34)/6.02×10²³

1.55×10²⁴ molecules = 87.54 g of H₂O₂

Thus, 87.54 g of H₂O₂ contains 1.55×10²⁴ molecules.

If 7.4 moles of carbon dioxide is produced in this reaction, how many moles of oxygen gas would be needed?

1 C7H16 + 11 O2 = 7 CO2 + 8 H2O

Answers

Answer:

11.6 mol O₂

Explanation:

C₇H₁₆ + 11 O₂ → 7 CO₂ + 8 H₂O

In order to solve this problem we need to convert moles of carbon dioxide (CO₂) into moles of oxygen gas (O₂). To do so we'll use a conversion factor containing the stoichiometric coefficients of the balanced reaction:

7.4 mol CO₂ * [tex]\frac{11molO_2}{7molCO_2}[/tex] = 11.6 mol O₂

Calculate the final concentration of each of the following:

2.0 L of a 6.0 M HCl solution is added to water so that the final volume is 6.0 L
--
Water is added to 0.50 L of a 12 M NaOH solution to make a 3.0 L of a diluted NaOH solution

Answers

Answer:

1. 2 M

2. 2 M

Explanation:

1. Determination of the final concentration.

Initial Volume (V₁) = 2 L

Initial concentration (C₁) = 6 M

Final volume (V₂) = 6 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

6 × 2 = C₂ × 6

12 = C₂ × 6

Divide both side by 6

C₂ = 12 / 6

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

2. Determination of the final concentration.

Initial Volume (V₁) = 0.5 L

Initial concentration (C₁) = 12 M

Final volume (V₂) = 3 L

Final concentration (C₂) =?

The final concentration can be obtained as follow:

C₁V₁ = C₂V₂

12 × 0.5 = C₂ × 3

6 = C₂ × 3

Divide both side by 3

C₂ = 6 / 3

C₂ = 2 M

Therefore, the final concentration of the solution is 2 M

A scientist observes the cells of a newly discovered animal under a
microscope. Which of the following cell parts is the scientist likely to find?
A. Cell membrane, chloroplasts, and a nucleus
B. Cell wall, cell membrane, and ribosomes
O C. Cell wall, chloroplasts, and lysosomes
D. Cell membrane, ribosomes, and a nucleus​

Answers

Answer:

D

Explanation:

The rest have characteristics of a plant cell

Consider the following data on some weak acids and weak bases:
acid base
name formula Ka name formula Kb
hydrocyanic acid HCN 4.9 x 10^-10 hydroxylamine HONH2 1.1 x 10^-1
hypochlorous acid HCIA 3.0 x 10^-18 ethylamine C2H5NH2 6.4 x 10^-4
Use this data to rank the following solutions in order of increasing pH. In other words, select a '' next to the solution that will have the lowest pH, a '' next to the solution that will have the next lowest pH, and so on.
a. 0.1 M HONH3Br
b. 0.1 M NaNO3
c. 0.1 M C2H5NH3Cl
d. 0.1 M NaF

Answers

Answer:

a < c < b < d

Explanation:

The weak acid with the lowest pKa will be the most acidic. In the other way, the conjugate base which the acid is weakest will be strongest.  

The weak base with the lowest pKb will be the most basic. And the conjugate base of the weakest base will be a strongest acid.

Using the values:

Ka HCN = 4.9x10⁻¹⁰

Kb HONH2 = 1.1x10⁻⁸

Ka HClA 3.0x10⁻⁸

Kb C2H5NH2 = 6.4x10⁻⁴

The NaNO3 is the conjugate base of a strong acid as HNO3. That means its solutions are almost neutral

The HONH3Br is the conjugate acid of a weak base. Its solutions will be acidics

C2H5NH3Cl is the conjugate acid of a weak base as ethylamine, its solutions will be acidic.

As ethylamine has a lower pkb than hydroxylamine, the conjugate acid of hydroxylamine will be more acidic.

NaF is the conjugate base of a weak acid as HF. Its solutions will be basics

The order in increasing pH is:

HONH3Br < C2H5NH3Cl < NaNO3 < NaF

a < c < b < d

Why is it important to make sure that the endpoint is noted accurately in titration?

Answers

There should be no air bubbles, as a bubble bursting can affect the volume measurement and disrupt the accuracy of the experiment.

20.00 mL of a 0.077 M solution of silver nitrate, AgNO3, is mixed with 30.00 mL of a 0.043 M solution of sodium acetate, NaC2H3O2. Does a precipitate form? The Ksp of AgC2H3O2 is 2.5*10^-3.

Answers

Answer:

No, no precipitate is formed.

Explanation:

Hello there!

In this case, since the reaction between silver nitrate and sodium acetate is:

[tex]AgNO_3(aq)+NaC_2H_3O_2(aq)\rightarrow AgC_2H_3O_2(s)+NaNO_3(aq)[/tex]

In such a way, we can calculate the concentration of silver and acetate ions in the solution as shown below, and considering that the final total volume is 50.00 mL or 0.0500 L:

[tex][Ag^+]=\frac{20.00mL*0.077M}{50.00mL}=0.0308M[/tex]

[tex][C_2H_3O_2^-]=\frac{30.00mL*0.043M}{50.00mL}=0.0258M[/tex]

In such a way, we can calculate the precipitation quotient by:

[tex]Q=[Ag^+][C_2H_3O_2^-]=0.0308*0.0258=7.95x10^{-4}[/tex]

Which is smaller than Ksp and meaning that the precipitation does not occur.

Regards!

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