Answer:
New force = 9(initial force)
Explanation:
The force between two charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Where
d is the original distance
Let d' is the new distance such that, r' = r/3
New force,
[tex]F'=\dfrac{kq_1q_2}{r'^2}\\\\F'=\dfrac{kq_1q_2}{(\dfrac{r}{3})^2}\\\\F'=9\times \dfrac{kq_1q_2}{r^2}\\\\F'=9F[/tex]
So, the new force becomes 9 times the initial force.
What is another name for constructive interference?
A. Up
B. Down
C. Reinforcement
D. Cancellation
What is the highest Mountain, and where is it?
Answer:
Mount Everest is Earth's highest mountain above sea level, located in the Mahalangur Himal sub-range of the Himalayas. The China–Nepal border runs across its summit point. Its elevation of 8,848.86 m was most recently established in 2020 by the Nepali and Chinese authorities.
Explanation:
How are frequency, wavelength, and energy related? Choose all that apply.
Explanation:
The energy of a wave is given by :
[tex]E=\dfrac{hc}{\lambda}[/tex]
Where
h is Planck's constant
c is the speed of light
[tex]\lambda[/tex] is wavelength
Energy is inversely proportional to wavelength. Also, the relation between frequency and wavelength is inverse.
If the frequency is high, the wavelength will be shorter.
Hence, the correct options are :
Higher frequencies have shorter wavelengths.
Shorter wavelengths have lower energy.
Lower frequencies have lower energy.
A fall thrown vertically upwards with a speed
of 20 ms-¹ from the top of a tower reaches
the earth in 8seconds. find the height of the
tower.
take g= 10ms-²
Answer:
Height of tower = 480 meter
Explanation:
Given:
Initial velocity = 20 m/s
Time taken to reach ground = 8 second
So,
Final velocity = 0 m/s
Acceleration due to gravity = 10 m/s²
Find:
Height of tower
Computation:
s = ut + (1/2)(g)(t)²
s = (20)(8) + (1/2)(10)(8)²
s = 160 + (1/2)(10)(64)
s = 160 + (10)(32)
s = 160 + 320
s = 480 meter
Height of tower = 480 meter
Dr. Kirwan is preparing a slide show that he will present to the executive board at tonight's committee meeting. He places a 3.50-cm slide behind a lens of 20.0 cm focal length in the slide projector. A) How far from the lens should the slide be placed in order to shine on a screen 6.00 m away? B) How wide must the screen be to accommodate the projected image?
Answer:
A) d_o = 20.7 cm
B) h_i = 1.014 m
Explanation:
A) To solve this, we will use the lens equation formula;
1/f = 1/d_o + 1/d_i
Where;
f is focal Length = 20 cm = 0.2
d_o is object distance
d_i is image distance = 6m
1/0.2 = 1/d_o + 1/6
1/d_o = 1/0.2 - 1/6
1/d_o = 4.8333
d_o = 1/4.8333
d_o = 0.207 m
d_o = 20.7 cm
B) to solve this, we will use the magnification equation;
M = h_i/h_o = d_i/d_o
Where;
h_o = 3.5 cm = 0.035 m
d_i = 6 m
d_o = 20.7 cm = 0.207 m
Thus;
h_i = (6/0.207) × 0.035
h_i = 1.014 m
A 1500 kg car accelerats from 55.0 m/s to 90.0 m/s. Calculate the impulse experienced by the car
Answer:
The impulse experienced by the car is 52,500 kg.m/s.
Explanation:
Given;
mass of the car, m = 1500 kg
initial velocity of the car, u = 55 m/s
final velocity of the car, v = 90 m/s
The impulse experienced by the car is the change in linear momentum, calculated as follows;
J = ΔP = mv - mu
ΔP = m(v - u)
ΔP = 1500(90 - 55)
ΔP = 52,500 kg.m/s
Therefore, the impulse experienced by the car is 52,500 kg.m/s.
