what’s the answer to this ?

Answer:

Step-by-step explanation:

(√63 + 144)/5 = (3√7 + 144)/5 = 0.6√7 + 28.8

Answer:

m BC = 100

Step-by-step explanation:

Since the angle is at the center, the arc has the same measurement as the angle

m BC = 100

Answer:

-5/13

Step-by-step explanation:

sin theta = opp / hyp

sin theta = -12 /13

we can find the adj side by using the pythagorean theorem

adj^2 + opp ^2 = hyp^2

adj^2 +(-12)^2 = 13^2

adj^2 +144 =169

adj^2 = 169-144

adj^2 = 25

Taking the square root of each side

adj = ±5

We know that it has to be negative since it is in the third quad

adj = -5

cos theta = adj / hyp

cos theta = -5/13

Answer:

B) -5/13

Step-by-step explanation:

i hope it will help

plzz mark as brainliest if you want

Answer:

12

Step-by-step explanation:

Add 10l to 12l to13l to11l to 14l=60l the divide 60l by the number of houses which will be 12 and there is your correct answer

Answer:

i think you just extend the coordinates to the side, except the right point, by 3, and then the bottom ones go down by 3, and the top one goes up by 3

Step-by-step explanation:

Answer:

-12x-9+50-5=0

-12x+41-5=0

-12x+36=0

-12x=0-36

x= -36/-12

x = 3 Answer...

hope it helps

Answer:

[tex]x=3[/tex]

Step-by-step explanation:

[tex]3(-4x - 3) + 50 - 5= 0[/tex]

⇒ Subtract 50- 5 from both sides:-

[tex]3\left(-4x-3\right)+50-5-\left(50-5\right)=0-\left(50-5\right)[/tex]

[tex]3\left(-4x-3\right)=-45[/tex]

⇒ Divide both sides by 3:-

[tex]\frac{3\left(-4x-3\right)}{3}=\frac{-45}{3}[/tex]

[tex]-4x-3=-15[/tex]

⇒ Add 3 to both sides:-

[tex]-4x-3+3=-15+3[/tex]

[tex]-4x=-12[/tex]

⇒ Divide both sides by -4:-

[tex]\frac{-4x}{-4}=\frac{-12}{-4}[/tex]

[tex]x=3[/tex]

OAmalOHopeO

[tex] \large \tt{{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]

[tex] \large{ \tt{❁ \:x + x + 98 = 180 \degree \: [ Sum\: of \: angle \: of \: a \: triangle ]}}[/tex]

[tex] \large{ \tt{⟶2x + 98 \degree= 180 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 180 \degree - 98 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: 2x = 82 \degree}}[/tex]

[tex] \large{ \tt{ ⟶x = \frac{82 \degree}{2} }}[/tex]

[tex] \large{ \tt{⟶ \: x = 41 \degree}}[/tex]

[tex] \large{ \tt{ ↔\angle \: 1 = x \degree = \boxed{41 \degree}}}[/tex] [ Being alternate angles ]

- Alternate angles are the non-adjacent interiors pair of angles lying to the opposite side of a transversal when it intersects two straight line segments. Alternate angles form ' Z ' shape.

Part 1

[tex]\left(\frac{g}{h}\right)(x) = \frac{g(x)}{h(x)}\\\\\left(\frac{g}{h}\right)(x) = \frac{3x-5}{-2x^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{3(3)-5}{-2(3)^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{4}{-11}\\\\\left(\frac{g}{h}\right)(3) = -\frac{4}{11}\\\\[/tex]

Answer:  -4/11

====================================================

Part 2

Set the denominator function equal to zero and solve for x to find which values to kick out of the domain.

[tex]h(x) = 0\\\\-2x^2+7 = 0\\\\7 = 2x^2\\\\2x^2 = 7\\\\x^2 = 7/2\\\\x^2 = 3.5\\\\x = \sqrt{3.5} \ \text{ or } x = -\sqrt{3.5}\\\\[/tex]

This shows that if x is equal to either of those values, then the denominator h(x) will be zero. These are the values to kick out of the domain to prevent a division by zero error. Any other value of x is valid in the domain.

Answer: [tex]x = \sqrt{3.5} \text{ and } x = -\sqrt{3.5}\\\\[/tex]

Answer:

The additive inverse of -61 is 61. For additive inverse just reverse the sign.

Answer:

b or d

Step-by-step explanation:

igxgkztjsy,hfzfjzitzgmzfjztzutzjvahfzgkzjrJt

Answer:

A

Step-by-step explanation:

A mode is the value that appears most frequently in the data set because there is not more than one of any number the data set has no mode.

(a) The IQR for the males' data is 12, because Q3 is at 15 and Q1 is at 3.

(b) The difference between the median values of each data set is 4 because 10-6 = 4

(c) For the males' data, the median would be a better measure of center, since the data is skewed right. For the females' data, the mean would be a better measure of center, because the data is pretty balanced (except for the outlier).

(d) Maybe a superhero movie had their opening night one day of this month, which would explain the outlier.

The net cost after discounts will be $ 2,450.

Given that Economy Hardware Store ordered items retailing for $ 2,500, and they received a chain discount of 5/20/2, the following calculation must be performed to find the net cost, knowing that the net cost is equal to the initial cost minus the discounts made about it:

First, the discount percentage must be calculated.

5/20/2 = X

4/2 = X

2 = X

Then, this percentage must be subtracted from the initial value.

2500 x (1-0.02) = X

2500 x 0.98 = X

2450 = X

Therefore, the net cost after discounts will be $ 2,450.

Learn more in https://brainly.com/question/17003148.

Answer:

30 =x

Step-by-step explanation:

The angles are correcting angle and corresponding angles are equal when the lines are parallel

55 = x+25

Subtract 25 from each side

55-25 = x+25

30 =x

Answer:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:

1) [tex]\frac{a + i\,b}{c + i\,d}[/tex]   Given.

2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.

3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex]   Existence of additive inverse/Definition of division.

4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex]   [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]  

5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex]  Distributive and commutative properties.

6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.

7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.

8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

they don't share any points

that's one thing, but I don't know what your options are of course.

see screenshot for illustration of the inequalities

Answer:

30.80

Step-by-step explanation:

We can use a ratio to solve

4 tickets              7 tickets

-------------------  = ----------------

17.60 dollars           x dollars

Using cross products

4x = 17.60 * 7

4x =123.2

Divide each side by 4

4x/4 = 123.2/4

x=30.8

since in a cube length, width and height are equal,

h = 6

w = 6

l = 6

and volume is 6³ = 216cm³

hope it helps :)

First go to the y intercept (or the b in y=mx+b) look for the slope and plot the points on the graph they're talking about e.g. #23 the y-intercept is 6 go to the 6 on the y axis, and then look at the slope (x), so it goes up and over to the right since it's positive by 1

This triangle has base 16 therefore the sides must be 17cm and 17 cm

When we make a altitude it divides it into two right triangles and there is a property in which the altitude of the isoceles triangle divides the base in 2 equal halves

So the side of the right triangle will be x , 8 , 17

Using pythgoreus theorem

x²+8²=17²

x = √225

x = 15

So the altitude is 15 cm

Must click thanks and mark brainliest

Answer:

x=1

Step-by-step explanation:

log_4(x + 3) + log_4x = 1

We know that loga(b) + loga(c) = loga(bc)

log_4(x + 3)x = 1

Raise each side to the base of 4

4^log_4(x + 3)x = 4^1

(x+3)x = 4

x^2 +3x = 4

Subtract 4 from each side

x^2 +3x -4 = 0

Factor

(x+4) (x-1) =0

Using the zero product property

x= -4  x=1

But x cannot be negative since logs cannot be negative

x=1

Answer:

A..  x = 1.

Step-by-step explanation:

log_4(x + 3) + log_4x = 1

log_4 x(x + 3) = log_4 4

Removing the logs:

x(x + 3) = 4

x^2 + 3x - 4 = 0

(x + 4)(x - 1) = 0

x = 1, -4.

We can ignore the -4 as there is no log of a negative.

Answer:

[tex]\angle 1 + \angle 2 = 180^o[/tex]

Step-by-step explanation:

Given

[tex]\angle 1[/tex] and [tex]\angle 2[/tex]

Required

The relationship between them [tex]\angle 1[/tex] and [tex]\angle 2[/tex]

From the question, we understand that [tex]\angle 1[/tex] and [tex]\angle 2[/tex] are supplementary

Supplementary angles add up to 180.

So, the relationship between [tex]\angle 1[/tex] and [tex]\angle 2[/tex] is:

[tex]\angle 1 + \angle 2 = 180^o[/tex]

Answer:

In 26 seconds to complete a transaction, 2 products are being purchased.

Step-by-step explanation:

1 item  = 9 seconds

Time taken in all to check out = 8 seconds

Time taken to shop = 26 seconds

Now as check out process takes 8 seconds, so the

Time left to ACTUALLY SHOP =  Total Time  - Time Used to check out

                                                  = 26 seconds = 8 seconds = 18 seconds

Shopping of 1 item = 8 seconds

Shopping of 2 items  = 2 x ( Time taken in 1 item) = 2 x  9 = 18 seconds

So, in 18 seconds, 2 clothing item can be selected.

Hence,in 26 seconds to complete a transaction, 2 products are being purchased.

Answer:

7

Step-by-step explanation:

[tex]s = {a}^{2} \: thus \: a = \sqrt{s } = \sqrt{49} = 7[/tex]

In the diagram, ∠5 is adjacent to ∠EHD.

Angle

Angles are formed when two rays intersect at a point. An angle is also formed when to lines intersect each other, thereby the two lines share a common endpoint.

Adjacent angles are two angles that have a common side and a common vertex (corner point). They are placed side by side to each other.

In the diagram, ∠5 is adjacent to ∠EHD.

Find out more on Angle at: https://brainly.com/question/25770607

Answer:

x = 55°

Step-by-step explanation:

The sum of the angles in a triangle is 180°.

x + 75 + 50 = 180

x + 125 = 180

x = 55

Therefore, x = 55°.

Answer:

x = 55

Step-by-step explanation:

the angles of a triangle add up to 180 degrees. So far we have 125 taken up.

We do 180 - 125 = 55.

x = 55

Answer:

all real numbers greater than or equal to 11

Answer:

-26 sqrt(3)

Step-by-step explanation:

-12 sqrt(12) - 2 sqrt(3)

Rewriting

-12 sqrt(4*3) - 2 sqrt(3)

We know sqrt(ab) = sqrt(a)sqrt(b)

-12 sqrt(4)sqrt(3) - 2 sqrt(3)

-12 (2) sqrt(3) - 2 sqrt(3)

-24 sqrt(3) - 2 sqrt(3)

-26 sqrt(3)

Answer:

4, 8, 16, 32, 64

Step-by-step explanation:

The nth term of a geometric sequence is

[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]

Given

a₇ = 256 and a₁₀ = 2048 , then

a₁ [tex]r^{6}[/tex] = 256 → (1)

a₁ [tex]r^{9}[/tex] = 2048 → (2)

Divide (2) by (1)

[tex]\frac{a_{1}r^{9} }{a_{1}r^{6} }[/tex] = [tex]\frac{2048}{256}[/tex]

r³ = 8 ( take the cube root of both sides )

r = [tex]\sqrt[3]{8}[/tex] = 2

Substitute r = 2 into (1)

a₁ × [tex]2^{6}[/tex] = 256

a₁ × 64 = 256 ( divide both sides by 64 )

a₁ = 4

Then

a₁ = 4

a₂ = 2a₁ = 2 × 4 = 8

a₃ = 2a₂ = 2 × 8 = 16

a₄ = 2a₃ = 2 × 16 = 32

a₅ = 2a₄ = 2 × 32 = 64

Answer:

18.45

Step-by-step explanation:

I used a calculator