What’s the answer to this? Please send help

Answer:

6.3 cm

Step-by-step explanation:

The distance from each centimeter is divided into 10 parts.  Point A starts at 0 and goes until right before 6.5.  The big line between each whole number signifies that you are halfway through the centimeter.  As you can see, point B is right before a big line, so can't be bigger than 6.5 nor equal.  The only option that fits this is 6.3 cm

The answer is 6.3 cm

If helpful, brainliest please !

Answer:

5d = 30

Step-by-step explanation:

1. first you need to add 5 to both sides

   d-4+5 = 2+5

2. then you need to combine like terms

   d+1 = 7

3. after that you have to multiply both sides by 5

   5(d+1) = 7(5)

4. simplify

   5d + 5 = 35

         -5     -5

   5d = 30

Answer:

[tex]5. \: \: 8 + 5(7) = 8 + 35 = 43[/tex]

I hope I helped you^_^

Answer:

about 48 adults , because you have to divide the 477 by 10

Step-by-step explanation:

I got this question on my test and i chose this and i got it right.

I hope this helps!! :)

48..................

Answer:

[tex]\frac{(a+b)}{a^{2} -b^{2} }[/tex] + [tex]\frac{(a-b)}{a^{2} -b^{2} }[/tex] = [tex]\frac{2a}{a^{2} -b^{2} }[/tex]

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{ \sqrt{a + b} }{ \sqrt{a - b} } + \frac{ \sqrt{a - b} }{ \sqrt{a + b} } \\ squaring \: on \: both \: sides \\ \frac{a + b}{a - b} + \frac{a - b}{a + b} \\ \frac{(a + b) \times (a + b) + (a - b)(a - b)}{(a - b)(a + b)} \\ \frac{ {(a + b)}^{2} + {(a - b)}^{2} }{ {a}^{2} - {b}^{2} } \\ remaining \: in \: attachment[/tex]

[tex]thank \: you[/tex]

Answer:

Perimeter is (8x + 4) units.

Step-by-step explanation:

[tex]{ \sf{perimeter = side + side + side}} \\ { \sf{p = (2x + 1) + (7x - 2) + (5 - x)}} \\ { \sf{p = (2x + 7x - x) + (1 - 2 + 5)}} \\ { \sf{p = 8x + 4}}[/tex]

-9 - 9 is the same that -9 + (-9)

√8 < √9 = 3

and

√42 > √36 = 6

which means the positive integers between √8 and √42 are 3, 4, 5, and 6, and their sum is 18.

Answer: (1, -2)

Concept:

There are three general ways to solve the system of equations:

Here, we are going to use the elimination method to solve.

Solve:

Given

[tex]\left \{ {{y=-5x+3} \atop {2x-3y=8}} \right.[/tex]

Convert the first equation's arrangement to correlate with the second equation

[tex]\left \{ {{5x + y=3} \atop {2x-3y=8}} \right.[/tex]

Multiply 3 on both sides in the first equation

[tex]\left \{ {{15x + 3y=9} \atop {2x-3y=8}} \right.[/tex]

Eliminate [y] by adding the two equations

[tex]17x = 17[/tex]

Divide both sides by 17

[tex]17x / 17=17/17[/tex]

[tex]x=1[/tex]

[tex]y=-5x+3=-5(1)+3=-5+3=-2[/tex]

[tex](1, -2)[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

wheres the file or question?

Answer:

Step-by-step explanation:

x-intercept(s):  

( − 4 , 0 ) , ( 6 , 0 )

y-intercept(s):  

( 0 , − 24 )

Answer:1 and 2

Step-by-step explanation:right on edge

Answer:

midpoint formula: (x₁ + x₂)/2, (y₁ + y₂)/2

distance: √[(x₂ - x₁)² + (y₂ - y₁)²]

Step-by-step explanation:

What points are you trying to calculate the distance and the midpoint for?

Answer:

2

Step-by-step explanation:

x:14 = 1:7

x/14 = 1/7

x = 14/7

=> x = 2

Answer:

h = (3×V)/ (pi×r²)

Step-by-step explanation:

[tex]v = \frac{\pi {r}^{2} h}{3} [/tex]

[tex]3 \times v = \pi {r}^{2} h[/tex]

[tex]h = \frac{3v}{\pi {r}^{2} } [/tex]

Answer:

ans is 0

mark me as brainliest

Answer:

TR = 23

Step-by-step explanation:

first we have to find TS, so we subtract 16 from 4 to get 12. then we can add 12 and 11 to get TR

We have that the Polynomial is named as a  Quintic polynomial

From the Question we are told that

Polynomial=[tex]X^4-3x^2+7x^5[/tex]

We note that the Polynomial is of degree 5 as its highest Sum of its exponent is a

Quintic polynomial

Therefore

The Polynomial is named as a  Quintic polynomial

In conclusion

For every Polynomial at degree five that is a greatest power of 5 (e^5) the accurate name for this polynomial is called a Quintic Polynomial

For more information on this visit

https://brainly.com/question/11536910?referrer=searchResults

Step-by-step explanation:

At Bob's binders, the unit price = $4.20 ÷ 3

= $1.40

At Pam's Paper Place the unit price = $5.20 ÷ 4 = $1.30

the better buy is at Pam's Paper place

Answer:

y-intercept is (0, -8)

Step-by-step explanation:

[tex]y = {x}^{2} + 2x - 8[/tex]

At y-intercept, x is zero

substitute x as zero:

[tex]y = {(0)}^{2} + 2(0) - 8 \\ y = 0 + 0 - 8 \\ y = - 8[/tex]

Answer:

5,000

Step-by-step explanation:

Solve using a weighted average like so:

{ (6 days)($34,000) + (4 days)($45,000) }/(6 days + 4 days) = $38,400

It doesn't appear as if the correct answer is listed in the choices? You can tell from the information given that the answer must be between $34,000 & $45,000!

Hi! I'm happy to help!

To first solve this, we need to make those mixed numbers improper fractions.

To make 4 1/2 an improper fraction, you have to turn 4 into halves (multiply four by 2) then add the extra half, giving you 9/2.

[tex]\frac{9}{2}[/tex]​ ÷(−1[tex]\frac{3}{7}[/tex]​ )

Now, we turn 1 3/7 into an improper fraction. We turn 1 into sevenths (multiply 1 by 7) then add the other 3 sevenths, giving you 10/7.

[tex]\frac{9}{2}[/tex]​ ÷(−[tex]\frac{10}{7}[/tex]​ )

From here, we need to turn this problem into a multiplication problem in order to solve. Since multiplication is the opposite of division, we need to get the opposite of something, so we use our second fraction and flip it.

[tex]\frac{9}{2}[/tex]​ ×(−[tex]\frac{7}{10}[/tex]​ )

Now, we multiply the top by the top, and the bottom by the bottom. (any positive multiplied by a negative gives a negative)

-[tex]\frac{63}{20}[/tex]

Since we cannot simplify, our final answer is -63/20.

I hope this was helpful, keep learning! :D

Answer:

Chim is 34 years old, and Jared is 8 years old.

Step-by-step explanation:

Let c be Chim's age and j be Jared's age.

Chim's age after five years (c + 5)

is 3 times Jared's age after five years (3 * (j+5) )

#1: c + 5 = 3(j+5)

We can add Chim's age and Jared's age to get 42 (the "sum"):

#2: c + j = 42

This is a system of equations that we can solve through substitution:

c + 5 = 3(j+5)

c + j = 42

In Equation #2, we can subtract j from both sides:

c = 42 - j

Then replace c with 42 - j in the first equation

(42 - j) + 5 = 3(j+5)

47 - j = 3j + 15

32 = 4j

j = 32/4 = 8

Plug j = 8 into the second equation, then solve for c.

c + 8 = 42

c = 42 - 8 = 34

c = 34, j = 8

Check our work by plugging in c = 34 and j = 8 into the first equation:

34 + 5 = 3(8+5)

39 = 3*13

39 = 39

Plug c and j into the second equation:

34 + 8 = 42

42 = 42

Chim is 34 years old, Jared is 8 years old.

Answer:

hope this helps you

have a great day

Answer:

Distance btw (-2, -2) and (8, -6) is (10, -4)

Step-by-step explanation:

I. Give (-2, -2) is A and (8, -6) is B

                     B - A = 8 - (-2) in x

                              = -6 - (-2) in y

                    So B - A = 10, -4

II. You can prove the answer by A.value + (10, -4) = B.value

Hope that help :D

Hi ;-)

[tex]\text{A}=(-2,-2) \ \text{and} \ \text{B}=(8,-6)\\\\|AB|=\sqrt{(8-(-2))^2+(-6-(-2))^2}\\\\|AB|=\sqrt{(8+2)^2+(-6+2)^2}\\\\|AB|=\sqrt{10^2+(-4)^2}\\\\|AB|=\sqrt{100+16}\\\\|AB|=\sqrt{116}\rightarrow\boxed{|AB|=2\sqrt{29}} \ (\text{because} \ 116=4\cdot29)[/tex]

Answer:

here's the answer to your question

The Sequence:

1 , 1+2 , 1+2+3 , 1+2+3+4, ...

here, every term is an AP. finding the general formula for the sum of the elements of each term is:

Sₙ = [tex]\frac{x}{2}(2a + (x-1)d)[/tex]        [where x = number of term, a = first term and d = common difference]

here, the first term is always 1 and so is the common difference.

Sₙ = [tex]\frac{x}{2}(2 +x-1)[/tex]

Sₙ = [tex]\frac{x}{2}(1 +x)[/tex] = [tex]\frac{1}{2}(x + x^{2})[/tex]

which is the formula for a general term in our series

now, we need to find the sum of the first n terms of this series

[tex]\displaystyle\sum_{x=1}^{n} [\frac{1}{2}(x + x^{2})][/tex]

[tex]\displaystyle\frac{1}{2} [\sum_{x=1}^{n} (x) + \sum_{x=1}^{n}(x^{2})][/tex]

in this formula, for the first term, it's just an AP from x = 1 to x = n

for the second term, we have a general formula [tex]\frac{n(n+1)(2n+1)}{6}[/tex]

[tex]\frac{1}{2}[\frac{n}{2}(2a + (n-1)d)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

in this AP (first term), the first term and the common difference is 1 as well

[tex]\frac{1}{2}[\frac{n}{2}(2 + n-1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex]\frac{1}{2}[\frac{n}{2}(n+1)+ \frac{n(n+1)(2n+1)}{6} ][/tex]

[tex][\frac{n}{4}(n+1)+ \frac{n(n+1)(2n+1)}{12} ][/tex]

[tex]\frac{n}{4}(n+1) [1+\frac{(2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(3+2n+1)}{3} ][/tex]

[tex]\frac{n}{4}(n+1) [\frac{(2n+4)}{3} ][/tex]

[tex]\frac{n}{2}(n+1) [\frac{(n+2)}{3} ][/tex]

[tex]\frac{n(n+1)(n+2)}{6}[/tex]

which is the sum of n terms of the given sequence