Answer:
-13
Step-by-step explanation:
f(-2) = 3(-2) - 7
f(-2) = -6 - 7
f(-2) = -13
f(-2) means to replace x with -2 in the equation and solve:
3(-2) - 7 = -6 - 7 = -13
The answer is -13
Which expression, in exponential form, is equivalent to 26x3y 47z5r3 A) ( 26x3y 47z5r3 )2 B) (26xy) 1 2 (47zr) 1 2 C) 26 1 2 x 3 2 y 1 2 47 1 2 z 5 2 r 3 2 D) 26x 3 2 y 1 2 47z 5 2 r 3 2
Answer:
The answer is "all the choices were wrong"
Step-by-step explanation:
Given value:
[tex]\bold{26x^3y 47z^5r^3}[/tex]
In the given question all the choices were wrong because it is not equivalent to given equation:
In choice A) [tex]( 26x^3y 47z^5r^3 )^2[/tex] in the value is whole squared, that's why it is wrong.
In choice B) [tex](26xy)^{12} (47zr)^{12}[/tex] when we open its value it will give different values, that's why it is wrong.
In option C and D( [tex]26^{12} x^{32} y^{12} 47^{12} z^{52} r^{32}[/tex] and [tex]26x^{32} y^{12}47z^{52} r^{32}[/tex]) both values will give different values.
Answer:
it's C
Step-by-step explanation:
I just did it
Ncluding a 6% sales tax, a new stereo costs $492.9. Find the cost of the stereo before tax. A) First write an equation you can use to answer this question. Use x x as your variable and express any percents in decimal form in the equation. (1)
Answer:
1.06x = 429.9
Cost of stereo before sales tax = $405.6
Step-by-step explanation:
Given the following :
Full cost of stereo(cost after sales tax) :
(cost before sales tax + sales tax)
Sales tax = 6%
Cost after sales tax = $492.9
Take the cost before sales tax as 'x'
Therefore, cost after sales tax:
x + 6% of x = $492.9
Equation to solve the problem :
x + 0.06x = 429.9
1.06x = 429.9 - - - (1)
We can then solve for x:
1.06x = 429.9
x = 429.9 / 1.06
x = $405.56603
x = $405.6
A pet store is offering a $5 in-store coupon for every person who buys a flea control product. If the flea control products range from $29.53 to $56.15, which compound inequality represents this situation?
Question 19 options:
29.53 ≤ x + 5 ≤ 56.15
29.53 ≤ x/5x ≤ 56.15
29.53 ≤x5≤ 56.15
29.53 ≤ 5 x – 5 ≤ 56.15
Answer:
29.53 ≤ x + 5 ≤ 56.15
Step-by-step explanation:
A $5 in-store coupon for every person who buys a flea control product which ranges between $29.53 to $56.15. This means that if you bought a flea control product you would be given an additional $5 that means that for buying a flea product, $5 is given to you. If you have $x, and you bought a flea product you would have x + 5. The inequality that represents this situation is given as:
29.53 ≤ x + 5 ≤ 56.15
PLZ HELP !!!!!! ASAP!!!
Part (a)
BC = opposite side (furthest leg from the reference angle)
AB = adjacent side (closest leg from the reference angle)
AC = hypotenuse (always opposite the 90 degree angle)
=============================================
Part (b)
i. False. Angle B is 90 degrees as shown by the square angle marker.
ii. False. Side AB is opposite angle C. Note how "C" is part of "BC", so that means we cannot have BC be opposite C.
iii. True. Leg AB is the closer leg to angle A. We have "A" in "AB" to see this without having to draw the diagram. Refer to part (a) above.
iv. False. The longest side of any right triangle is always the hypotenuse. The longest side of any triangle is always opposite the largest angle.
==============================================
Part (c)
cos(theta) = adjacent/hypotenuse = AB/AC
tan(theta) = opposite/adjacent = BC/AB
Refer back to part (a) to determine the opposite,adjacent and hypotenuse side lengths.
==============================================
Part (d)
The reference angle has changed, so the opposite and adjacent sides swap. The hypotenuse remains the same regardless of what reference angle you pick.
sin(C) = opposite/hypotenuse = AB/AC
cos(C) = adjacent/hypotenuse = BC/AC
tan(C) = opposite/adjacent = AB/BC
Note the tangent ratio is the reciprocal of what we found back in part (c).
Answer & Step-by-step explanation:
(a)
The hypotenuse is on line CA (the hypotenuse is always opposite the 90° angle (marked by a little square))
The adjacent is on the line BA (adjacent is next to the given angle, but NOT the hypotenuse)
The opposite is on the line CB (this is opposite the given angle)
(b)
i. false (b is a right angle)
ii. false (the side opposite C is BA)
iii. true
iv. false (the side opposite B is the hypotenuse, and the hypotenuse is always the longest side in a triangle)
(c)
cosine ratio: [tex]cos=\frac{adjacent}{hypotenuse}[/tex]
tangent ratio: [tex]tan=\frac{opposite}{adjacent}[/tex]
The cosine and tangent ratios of the given angle:
[tex]cos0=\frac{AB}{CA} \\\\tan0=\frac{CB}{AB}[/tex]
(d)
Remember SOH-CAH-TOA:
Sine=Opposite/Hypotenuse
Cosine=Adjacent/Hypotenuse
Tangent=Opposite/Adjacent
Using the angle C, plug in the appropriate sides:
[tex]sinC=\frac{BA}{CA}\\\\ cosC=\frac{CB}{CA}\\\\ tanC=\frac{BA}{CB}[/tex]
:Done
2 divided by 3 + 2 divedes by 3 +3 divided by 3 =?
Answer:
1/5
Step-by-step explanation:
1/5
2/3+3/3+4/3
=2/5*3/6
= 1/5
I'm not sure.
Answer:
The answer should be 0.022
I NEED HELP ASAP PLEASE!!!
Q2 If 2w + 7 = ─9, what is the value of 15 – 4w? (4 is negative)
Q3 Solve the following equations: a) 3/4(16m − 24) = –48 (24 is negative) b) –20 = 1/6(36 + 12g)
Answer:
Q2: -17
Q3: a) -5/2 b) g = -13
Step-by-step explanation:
2w+7 = -9
2w = -9 - 7
w = -16/2
w = -8
---
15 - 4w
= 15 - 4(-8)
= 15 - 32
= -17
----------------------
Q3:
a) 3/4(16m-24) = -48
16m -24 = -48 ÷ 3/4
16m = -64 + 24
16m = -40
m = -5/2
b) -20 = 1/6(36+12g)
-20 = 1/6 × 6(6+2g)
(cross out the 6 from 1/6 and 6)
-20 = 6 + 2g
-20-2g= 6
-2g = 6+20
-2g = 26
g = 26/-2
g = -13
What is the product?
8.25 x
1
5
0.82
O 1.65
0 8.25
16.5
Answer:
Answers
product, and assign a number to each person. ... 0.82. 12–13. 9. 0.18. 1.00. Total. 50. 1.00. F requency. 0. 1. 2. 3. 4. 5. 6. 7. 8 ... 3.12 (a) x = 25661.3333, ˜x = 25514.5 (b) Skewed ... N(8.25, 0.0002857).
Answer:
the answer is c
Step-by-step explanation:
i just took the test
what is -7 + 11 - 14 + 3 + 12
Answer:
5
Step-by-step explanation:
Answer:
5 (Follow PEMDAS left—>right)
the product of 5 and z
Answer:
5z
Step-by-step explanation:
As product = multiplication =>
5 x z --> 5(z)
[tex]\text{Find the product of 5 and z}\\\\\text{The key term in this questions is product, and in math it translates to}\\\text{the answer when multiplled}\\\\\text{In this case, you would multiply them together to get your "product"}\\\\\text{Solve:}\\\\5\cdot z\\\\\boxed{5z}[/tex]
A box contain 12 balls in which 4 are white 3blue and 5 are red.3 balls are drawn at random from the box. Find the chance that all three balls are of different colour
Answer:
white: 1/3, blue: 1/4, red: 5/12
Step-by-step explanation:
Take the amount of balls each color has and divide by 12.
White:
4/12 = 1/3
Blue:
3/12 = 1/4
Red:
5/12 (can't simplify)
Answer:
3/44 or 0.068
Step-by-step explanation:
(3/12 × 2/11 × 1/10)+(5/12 × 4/11 × 3/10)+(4/12 × 3/11 × 2/10)
=3/44
Nijah has 45 stickers.
She gives 2/5 to her sister.
She gives 1/3 of her remaining stickers to Brett.
How many stickers does Nijah have left?
Answer:
Nijah has 6 stickers left.
Step-by-step explanation:
Starting stickers:
45
2/5 are given away:
[tex]\frac{2}{5}[/tex] * 45
[tex]\frac{2}{5}[/tex] * [tex]\frac{45}{1}[/tex]
[tex]\frac{90}{5}[/tex]
18
1/3 of the remaining are given away:
[tex]\frac{1}{3}[/tex] * 18
[tex]\frac{1}{3}[/tex] * [tex]\frac{18}{1}[/tex]
[tex]\frac{18}{3}[/tex]
6
Nijah has 6 stickers left.
Answer:
18
Step-by-step explanation:
Find the part she gave to her sister
45 *2/5 = 18
The part remaining is
45 - 18 = 27
She gives 1/3 to Brett
27 * 1/3 = 9
She has 27 - 9 = 18
She has 18 remaining
Angles θ and φ are angles in standard position such that:
sinθ = -5/13 and θ terminates in Quadrant III
tanφ = -8/15 and φ terminates in Quadrant II
Find sin(θ + φ).
When [tex]\theta[/tex] terminates in quadrant III, both [tex]\cos\theta[/tex] and [tex]\sin\theta[/tex] are negative, and
[tex]\sin^2\theta+\cos^2\theta=1\implies\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac{12}{13}[/tex]
When [tex]\varphi[/tex] terminates in quadrant II, [tex]\cos\varphi[/tex] is negative and [tex]\sin\varphi[/tex] is positive, so
[tex]1+\tan^2\varphi=\sec^2\varphi\implies\sec\varphi=-\dfrac{17}{15}[/tex]
which gives
[tex]\cos\varphi=\dfrac1{-\frac{17}{15}}=-\dfrac{15}{17}[/tex]
[tex]\tan\varphi=\dfrac{\sin\varphi}{\cos\varphi}=-\dfrac8{15}\implies\sin\varphi=\dfrac8{17}[/tex]
Now,
[tex]\sin(\theta+\varphi)=\sin\theta\cos\varphi+\cos\theta\sin\varphi=-\dfrac{21}{221}[/tex]
Please answer this question now
Answer:
76 degrees.
Step-by-step explanation:
Let as consider O is the center of the circle . So from the figure it is clear that
[tex]\angle AOB=44^{\circ}[/tex]
[tex]\angle COD=118^{\circ}[/tex]
By central angle theorem, central angle subtended by an arc is twice of inscribed angle of the same arc.
We know that, [tex]\angle BAD=97^{\circ}[/tex] and angle BOD is the central angle subtended by arc BD.
[tex]\angle BOD=2\times \angle BAD[/tex]
[tex]\angle BOD=2\times 97^{\circ}[/tex]
[tex]\angle BOD=194^{\circ}[/tex]
Now,
[tex]\angle BOD=\angle BOC+\angle COD[/tex]
[tex]194^{\circ}=\angle BOC+118^{\circ}[/tex]
[tex]194^{\circ}-118^{\circ}=\angle BOC[/tex]
[tex]76^{\circ}=\angle BOC[/tex]
[tex]m(arc(BC))=76^{\circ}[/tex]
Therefore, the measure of arc BC is 76 degrees.
PLEASE HELP ME REALLY QUICK!
Answer:
90 degrees
Step-by-step explanation:
Add them together. 58+32=90
90 degrees
add them togather
Nadiya determines that there are no fractions equivalent to StartFraction 2 Over 10 EndFraction with a denominator greater than 10, but less than 20, that have a whole number numerator and denominator. Is Nadiya correct?
Yes, Nadiya is correct. By multiplying the numerator and denominator by 2, the first fraction equivalent to StartFraction 2 Over 10 EndFraction is StartFraction 4 Over 20 EndFraction.
Yes, Nadiya is correct. By multiplying the whole fraction by any whole number, each equivalent fraction will continue to have a denominator of 10.
No, Nadiya is incorrect. She could multiply both the numerator and denominator of the unit fraction equivalent to StartFraction 2 Over 10 EndFraction by 3 and arrive at the equivalent fraction StartFraction 3 Over 15 EndFraction.
No, Nadiya is incorrect. She could add any number between 1 and 8 to the numerator and denominator and arrive at an equivalent fraction with a denominator greater than 10 but less than 20.
Answer:
3 Over 15
Step-by-step explanation:
i got 100.
Answer:
yes
Step-by-step explanation:
it is c,
Determine the most precise name for KIET (parallelogram,rhombus,rectangle or square.) you must use slope or length. K(0,0) I(2,2) T(5,-5) E(7,-3)
Answer: rectangle.
Step-by-step explanation:
Given points: K(0,0) I(2,2) T(5,-5) E(7,-3)
Distance formula to find distance between [tex]A(a,b)[/tex] and [tex]B(c,d)[/tex]: [tex]AB=\sqrt{(d-b)^2+((c-a)^2}[/tex]
[tex]KI=\sqrt{(2-0)^2+(2-0)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]
[tex]KT=\sqrt{(5-0)^2+(-5-0)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]
[tex]TE=\sqrt{(7-5)^2+(-3+5)^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\ units[/tex]
[tex]IE=\sqrt{(7-2)^2+(-3-2)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\ units[/tex]
i.e. KI = TE and KT= IE, so opposite sides equal.
It can be a parallelogram or rectangle. [if all sides are equal it would be square or rhombus]
[tex]IT=\sqrt{(5-2)^2+(-5-2)^2}=\sqrt{3^2+7^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]
[tex]KE=\sqrt{(7-0)^2+(-3-0)^2}=\sqrt{7^2+3^2}=\sqrt{9+49}=\sqrt{58}\ units[/tex]
IT= KE, i.e. diagonals are equal.
It means KIET is a rectangle.
41 =12d-7 d= Math is not my strong suit. I love to read and write but I can not do math without a little bit of help.
Answer:
[tex]\huge\boxed{d = 4 }[/tex]
Step-by-step explanation:
41 = 12d - 7
Adding 7 to both sides
41+7 = 12d
48 = 12 d
Dividing both sides by 12
4 = d
OR
d = 4
Answer:
[tex]\large \boxed{{d=4}}[/tex]
Step-by-step explanation:
[tex]41 =12d-7[/tex]
Add 7 on both sides.
[tex]41 +7=12d-7+7[/tex]
[tex]48=12d[/tex]
Divide both sides by 12.
[tex]\displaystyle \frac{48}{12} =\frac{12d}{12}[/tex]
[tex]4=d[/tex]
Please answer. I need this to be done, Thanks. Will give brainliest
Answer:
The answer is s^26/pq59
Step-by-step explanation:
Answer:
p^ -1 q ^ -59 s ^26
or without negative exponents
s^ 26 /(p q^ 59)
Step-by-step explanation:
When multiplying , we can add the exponents when the bases are the same
p^0 q ^ -60 r^-1 s^25 * p^-1 qrs
When there is no exponent written, there is an implied 1
p^ (0+-1) q^(-60+1) r ^( -1 +1) s ^ ( 25+1)
p^ -1 q ^ -59 r ^0 s ^26
r^0 = 1
p^ -1 q ^ -59 s ^26
If you need the negative exponents written as positive
a^-b = 1/ a^b
s^ 26 /(p q^ 59)
What are the zeros of this function?
A. X= 2 and x = -6
B. x= 0 and x = -6
C. X= 0 and x = 5
D. X = 0 and x= -5
Answer:
I think its C because if I remember correctly zero of the function is just the x intercept
This is the new one! Please help I’m so lost
Answer:
(a) (f o g)(x) = x^2 - 15x + 54
(b) (g o f)(x) = x^2 + 3x - 9
(c) (f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x
(d) (g o g)(x) = x - 18
Step-by-step explanation:
f(x) = x^2 + 3x
g(x) = x - 9
(a)
(f o g)(x) = f(g(x)) = (g(x))^2 + 3(g(x)) = (x - 9)^2 + 3(x - 9)
(f o g)(x) = x^2 - 18x + 81 + 3x - 27
(f o g)(x) = x^2 - 15x + 54
(b)
(g o f)(x) = g(f(x)) = f(x) - 9 = x^2 + 3x - 9
(c)
(f o f)(x) = f(f(x)) = (x^2 + 3x)^2 + 3(x^2 + 3x)
(f o f)(x) = x^4 + 6x^3 + 9x^2 + 3x^2 + 9x
(f o f)(x) = x^4 + 6x^3 + 12x^2 + 9x
(d)
(g o g)(x) = g(g(x)) = x - 9 - 9 = x - 18
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
Answer:
a) From A ∩ A' = ∅, we have;
A ∩ (A' ∪ B) = A ∩ B
b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;
A ∩ (A ∪ B)' = ∅
Step-by-step explanation:
a) By distributive law of sets, we have;
A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)
From the complementary law of sets, we have;
A ∩ A' = ∅
Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have
A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)
A ∩ A' = ∅ (complementary law of sets)
Therefore;
(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B) = (A ∩ B) (Addition to zero identity property)
∴ A ∩ (A' ∪ B) = A ∩ B
b) By De Morgan's law
(A ∪ B)' = A' ∩ B'
Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')
By associative law of sets, we have;
A ∩ (A' ∩ B') = (A ∩ A') ∩ B'
A ∩ A' = ∅ (complementary law of sets)
Therefore, (A ∩ A') ∩ B' = ∅ ∩ B' = ∅
Which gives;
A ∩ (A ∪ B)' = ∅.
hi there can you please help me
[tex]t = \sqrt{ \frac{ab - s}{r + ak} } [/tex]
[tex]t=\sqrt{\dfrac{ab-s}{r+ak}}\\\\t^2=\dfrac{ab-s}{r+ak}\\\\rt^2+akt^2=ab-s\\\\akt^2-ab=-rt^2-s\\\\a(kt^2-b)=-(rt^2+s)\\\\a=-\dfrac{rt^2+s}{kt^2-b}\\\\a=-\dfrac{rt^2+s}{-(b-kt^2)}\\\\a=\dfrac{rt^2+s}{b-kt^2}[/tex]
The members of an Olympiad team contributed
a total of $ 1.69 for refreshments for their
weekly practices. Each member contributed the
same amount and paid for his or her share in
five coins. How many nickels were contributed
by all of the members?
Answer:
26 nickels
Step-by-step explanation:
Given that
Total contributed = $1.69
Number of coins = 5
based on the above information,
The number of nickels to be contributed is
Here first we have to determine the prime factors of 169 i.e 13 and 13
This represents that there are 13 member gives their $0.13 per person so it would be $1.69
Also there are 13 cents out of which 3 cents would be 3 pennies the remaining 10 cents would be 2 nickels
So the 13 people contributed to 2 nickels
Therefore, it would be
= 13 × 2
= 26 nickels
How many cubes with side lengths of \dfrac12 \text{ cm} 2 1 cmstart fraction, 1, divided by, 2, end fraction, start text, space, c, m, end text does it take to fill the prism? Cubes
Answer:
24
Step-by-step explanation:
Answer
24!
Step-by-step explanation:
Person above me is correct :)
m∠QPSm, is a straight angle m∠RPS=6x+11 m∠QPR=7x+143 ;Find RPS
Answer:
23
Step-by-step explanation:
6x + 11 + 7x + 143 = 180
13x + 154 = 180
13x = 26
x = 2
m<RPS = 6(2) + 11 = 23
Which transformation shows a reflection across the y-axis? A) A B) B C) C D) D
Answer:
The answer is A
Step-by-step explanation:
This shows a mirroring effect over the vertical y axis.
Choices B and C are a translation (aka shifting)
Choice D is a reflection but over the horizontal x axis.
Sagan scored 1200 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 980 and standard deviation 100. Andrea scored 27 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 20 and standard deviation 5. Who performed better on the standardized exams and why? Sagan scored higher than Andrea. Sagan's standardized score was 2.2, which is 2.2 standard deviations above the mean and Andrea's standardized score was 1.4, which is 1.4 standard deviations above the mean. Sagan scored higher than Andrea. Sagan's score was a 1200, which is greater than Andrea's score of 27. Andrea scored higher than Sagan. Andrea's standardized score was 1.4, which is 1.4 standard deviations above the mean, but closer to the mean than Sagan's standardized score of 2.2 standard deviations above the mean. Sagan scored higher than Andrea. Sagan's score was 220 points above the mean of 980, and Andrea's was 7 points above the mean of 20. Andrea scored higher than Sagan. Andrea is only 9 points from the top score of 36 on the ACT, and Sagan is 400 points from the top score of 1600 on the SAT.
Answer:
A
Step-by-step explanation:
Option A is correct. Sagan scored higher than Andrea. Sagan's standardized score was 2.2, which is 2.2 standard deviations.
Answer: Correct
Sagan scored higher than Andrea. Sagan's standardized score was 2.2, which is 2.2 standard deviations above the mean and Andrea's standardized score was 1.4, which is 1.4 standard deviations above the mean.
Step-by-step explanation: No clue:)
what is the value of this expression when g= -3.5?
8-|2g-5|
a. 20
b. 10
c. 6
d. -4
Answer:
d. -4
Step-by-step explanation:
Let's plug in g
8 - |2(-3.5) - 5|
8 - |-7-5|
8 - |-12|
The absolute value is always positive of any number,
8 - 12
= -4
Answer:
D. -4
Step-by-step explanation:
We are given this expression:
[tex]8-|2g-5|[/tex]
and asked to evaluate when g= -3.5 Therefore, we must substitute -3.5 in for g.
[tex]8-|2(-3.5)-5|[/tex]
First, multiply 2 and -3.5
2 * -3.5 = -7
[tex]8-|-7-5|[/tex]
Next, subtract 5 from -7.
-7-5= -12
[tex]8-|-12|[/tex]
Next, evaluate the absolute value of -12. The absolute value is how far away a number is from 0, and it is always positive. The absolute value of -12 is 12.
[tex]8-12[/tex]
Subtract 12 from 8.
[tex]-4[/tex]
The value of the expression is -4 and D is the correct answer.
Two of the lights at the local stadium are flickering. They both just flickered at the same time.
One of the lights flickers every 7 seconds and the other light flickers every 8 seconds.
How many seconds until both lights will flicker at the same time again?
seconds
Answer:
56
Step-by-step explanation:
you have to find the LCM of 7 AND 8.
which is 56
Answer:
The answer is 56
Step-by-step explanation:
You are the owner of Decorama Flooring Tod and Claudia have asked for an estimate 15 feet*23 feet dinning room 12ft*18 kitchen 9ft*11 ft and 10ft*12 ft how many square ft required(multipy length by the width)
Answer:
Step-by-step explanation:
The question is not properly written. Here is the correct question.
You are the owner of Decorama Flooring. Tod and Claudia have asked you to give an estimate for tiling four rooms of their house. The living room is 15 feet*23 feet, dinning room is 12ft*18ft, the kitchen is 9ft*11 ft and the study room is 10ft*12 ft how many square ft of tiles are required for each room. (multiply length by the width).
We must understand that a floor tile is rectangular in nature.
Area of a rectangle = Length * width
To get the amount of square feet required for each room, we must multiply the length and width of each of the rooms together as shown.
For the living room;
Length = 15 feet and Width = 23 feet
Amount of square feet of tiles needed for the living room = 15feet * 23 feet
= 345 ft²
For the dining room;
Length = 12 feet and Width = 18 feet
Amount of square feet of tiles needed for the dining room = 12feet * 18 feet
= 216 ft²
For the kitchen;
Length = 9 feet and Width = 11 feet
Amount of square feet of tiles needed for the kitchen = 11feet *9feet
= 99 ft²
For the study room;
Length = 10 feet and Width = 12 feet
Amount of square feet of tiles needed for the study room = 10feet * 12 feet
= 120 ft²