What’s the value of X????

Answer:

umm not sure on this one either 9328.71

Step-by-step explanation:

Step-by-step explanation:

Given: [∀x(L(x) → A(x))] →

[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for

arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof

technique.

Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

We need to show that the above expression is unsatisfiable (False).

¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))

∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))

E.I with respect to x,

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))

E.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b

U.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Since P ∧ Q is P, drop L(a) from the above expression.

(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Apply distribution

(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))

Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to

(L(b) ∧ H(a, b) ∧ ¬A(b))

U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace

¬A(b) in the above expression with ¬L(b). Thus, we get,

(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.

This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows

from the premise.

15

Answer:

both apply

Step-by-step explanation:

i guessed just do it

Step-by-step explanation:

we can simplify the stuff inside the parentheses to

[tex] \frac{ {x}^{3} }{2y} [/tex]

now we need to multiply it with itself, giving us

[tex] \frac{ {x}^{6} }{4 {y}^{2} } [/tex]

so yeah, D is the correct answer

See the graph in the attached image.

Answer:

[tex]\displaystyle x \approx 9.9[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 64°

Opposite Leg = x

Hypotenuse = 11

Step 2: Solve for x

Answer:

Step-by-step explanation:

The ways that they are the same are.

Answer:

The opposite of a number is the number on the other side of 0 number line, and the same distance from 0.

Answer:

320 square feet.

Step-by-step explanation:

For the moment, let's put the square back in place. That would make the length 16 + 8 = 24 and the width 16.

L = 24

W = 16

Area = L * W

Area = 24 * 16

Area = 384

Now the next step is to take out the square. It is 8 * 8 = 64

The area of the figure = 384 - 64 = 320 square feet, and that's the answer.

Answer:

320 in^2

Step-by-step explanation:

we need to find the area of this figure

Firstly divide above picture in two parts

1st figure = (16*16)in.

2nd figure = (8*8)in.

Area of 1st figure = 16*16 = 256 in^2

Area of 2nd figure = 8*8 = 64 in^2

Area of whole figure = ( 256 + 64 )in^2

= 320 in^2

Let q be the number of quarts of pure antifreeze that needs to be added to get the desired solution.

8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.

The new solution would have a total volume of 8 + q quarts, and it would contain a total amount of 3.2 + q quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means

(3.2 + q) / (8 + q) = 0.60

Solve for q :

3.2 + q = 0.60 (8 + q)

3.2 + q = 4.8 + 0.6q

0.4q = 1.6

q = 4

Answer:

Option 4) -$45 per month; the amount of money withdrawn per month.

Step-by-step explanation:

The rate of change is 45. Before he began taking money out to pay for his classes[month 0], he had $190. Since then, every month, $45 have been withdrawn.

Answer:

[tex]\triangle FED\sim \triangle JEH[/tex]

Step-by-step explanation:

Both pairs of vertical angles formed at point E are equal. Therefore, the two triangles share two angles. If two triangles share two angles, they must also share the third angle, since the sum of the interior angles of a triangle add up to 180 degrees. Therefore, all three angles of the two triangles are equal, which is a proof of similarity. [tex]\implies \boxed{\triangle FED\sim \triangle JEH}[/tex]

9514 1404 393

Answer:

  ΔDEF ~ ΔHEJ

Step-by-step explanation:

The vertical angles at E are congruent, and the marked angles at F and J are congruent. The two triangles are similar by the AA postulate.

The given portion of the similarity statement names the angles in the order "unspecified", "vertical", and "50°". If we name those angles in the same order in the other triangle, the similarity statement becomes ...

  ΔDEF ~ ΔHEJ

Answer:

Option(A)

Step-by-step explanation:

y=4x+2

When you replace the value of x in the equation you get the value of y

Answer:

the answer is A since if we lay it out we will get y

-6=-2*4+2

2=0*4+2

6=1*4+2

Answer:

90

Step-by-step explanation:

there is 6 sides of box

2 bigger and 4 smaller

area of bigger side is 5×5 = 25 this is the area of one side as we have 2 sides so are of both sides is 25 + 25 = 50

now come to the smaller sides ( we have 4 here)

are of one side is 2× 5 = 10

so are of all 4 sides is 10× 4 = 40

now we get area of 4 smaller sides and 2 bigger sides

total area of box is 40+ 50 = 90

hope you understand

Answer:

11.7

Step-by-step explanation:

39.1 - 9.2 = 29.9

29.9 - 18.2 = 11.7

Complete question is;

Assume the random variable X is normally distributed with mean μ = 50 and standard deviation σ = 7. What is the probability P (X > 42)?

Answer:

P(X > 42) = 0.1271

Step-by-step explanation:

We are given;

mean; μ = 50

Standard deviation; σ = 7

Formula for the z-score is;

z = (x - μ)/σ

Thus;

z = (42 - 50)/7

z = -1.14

Since we are looking for P (X > 42), then let's look up this z-value from the z-distribution table attached.

We have;

P(X > 42) = 0.1271

Answer:

Hi, there the answer is

These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Hope This Helps :)

Step-by-step explanation:

First degree equations

A first degree equation has the form

ax + b = 0

There are some special cases where the equation can have one, infinitely many or no solution

If , the equation has exactly one solution

If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0

If a=0 and  the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.

We have been given some equations, we only need to put them in standard form

-5x + 12 = –12x – 12

Rearranging

7x + 24 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x + 12

Rearranging

-10x + 0 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x – 5

Rearranging

-10x + 17 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = -5x – 12

Rearranging

0x + 24 = 0

It has no solution, no matter what the value of x is, it's impossible that 24=0

Answer: These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Answer:

y - 2 = 1/3(x - 3)

Step-by-step explanation:

Point slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Plug in the slope:

y - y1 = m(x - x1)

y - y1 = 1/3(x - x1)

Plug in the given point:

y - y1 = 1/3(x - x1)

y - 2 = 1/3(x - 3)

So, the correct answer is y - 2 = 1/3(x - 3)

Answer:

Y: 0, x:0

Y:1, x: 3

Y: 2, x: 6

Y: 3, x:9

Step-by-step explanation:

Plug in the x to get the y

Answer:

Step-by-step explanation:

Given that:

[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]

at point (0, -2)

[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]

Taking the differential from the equation above with respect to x;

[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]

Collect like terms

[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

Hence, the slope of the tangent line m can be said to be:

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

At point (0,-2)

[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]

[tex]\dfrac{dy}{dx}= 0[/tex]

m = 0

So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:

(y - y₁ = m(x - x₁))

y + 2 = 0(x - 0)

y + 2 = 0

y = -2

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Answer:

  55°

Step-by-step explanation:

Adjacent angles in a parallelogram are supplementary.

  m∠GDE = 180° -m∠FGD = 180° -125°

  m∠GDE = 55°

Answer:

=−2r3+4r2

Step-by-step explanation:

r2−2r3+3r2

=r2+−2r3+3r2

=r2+−2r3+3r2

=(−2r3)+(r2+3r2)

=−2r3+4r2

Step-by-step explanation:

the answer is in the above image

pls give me BRAINLIEST

9514 1404 393

Answer:

  ΔWZT ~ ΔWXY

Step-by-step explanation:

Angle XWY and angle ZWT are vertical angles, so congruent.

The sides on either side of those angles are proportional:

  WZ/WX = WT/WY

  11/22 = 10/20 = 1/2

so, we can claim similarity by the SAS Theorem.

  ΔWZT ~ ΔWXY

[tex] \large \boxed{(f + g)(x) = f(x) + g(x)}[/tex]

Use the following property above to find the value. Substitute f(x) and g(x) in.

[tex] \large{(2x + 3) + ( {x}^{2} - 8)} \\ \large{2x + 3 + {x}^{2} - 8}[/tex]

Evaluate/Combine like terms.

[tex] \large{2x + {x}^{2} - 5}[/tex]

This step is optional but it's the best to arrange the degree.

[tex] \large{ {x}^{2} + 2x - 5} \\ \large{(f + g)(x) = {x}^{2} + 2x - 5}[/tex]

Answer

Let me know if you have any doubts!

Answer:

[tex]Pr =\frac{1}{3}[/tex]

Step-by-step explanation:

Given

[tex]S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)[/tex]

[tex](3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)[/tex]

[tex](5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}[/tex] --- sample space

First, list out all outcomes whose sum is divisible by 5

[tex]A = \{(4,6), (5,5),(6,4)\}[/tex]

So, we have:

[tex]n(A) = 3[/tex]

Next, list out all outcomes that has an outcome of 5 in both rolls

[tex]B = \{(5,5)\}[/tex]

[tex]n(B) =1[/tex]

The required conditional probability is:

[tex]Pr =\frac{n(B)}{n(A)}[/tex]

[tex]Pr =\frac{1}{3}[/tex]